how to call another php file with parameters?

up vote
-1
down vote

favorite

i want to export two different type of xlsx file based on radio button .

    $sel = $_POST['sel'];

       echo $sel;



    if(isset($_POST['search'])){



        if($sel == 'board')

        {

         header('Location: export_data1.php? 

       num='.$_POST['staff']);  

       die(); 

        }

       else

       {



         header('Location: export_data2.php? 

          num='.$_POST['desg']);

         die(); 



        }

       }

how to call another php file based on my radio button.Is there any other alternate way to call php file with passing arguments?

edited Nov 20 at 5:57

asked Nov 20 at 5:48

antony

possible duplicate of stackoverflow.com/questions/5678567/…
– Jacob Nelson
Nov 20 at 6:47

i try that method not working in my form
– antony
Nov 20 at 7:41

An alternative could be to have bog standard links to your files.
– Progrock
Nov 20 at 8:05

What's the problem here, what isn't working?
– Progrock
Nov 20 at 8:07

An aside: you might want to url encode your query string. See url_encode and/or http_build_query.
– Progrock
Nov 20 at 8:10

|
show 2 more comments

up vote
-1
down vote

favorite

i want to export two different type of xlsx file based on radio button .

    $sel = $_POST['sel'];

       echo $sel;



    if(isset($_POST['search'])){



        if($sel == 'board')

        {

         header('Location: export_data1.php? 

       num='.$_POST['staff']);  

       die(); 

        }

       else

       {



         header('Location: export_data2.php? 

          num='.$_POST['desg']);

         die(); 



        }

       }

how to call another php file based on my radio button.Is there any other alternate way to call php file with passing arguments?

edited Nov 20 at 5:57

asked Nov 20 at 5:48

antony

possible duplicate of stackoverflow.com/questions/5678567/…
– Jacob Nelson
Nov 20 at 6:47

i try that method not working in my form
– antony
Nov 20 at 7:41

An alternative could be to have bog standard links to your files.
– Progrock
Nov 20 at 8:05

What's the problem here, what isn't working?
– Progrock
Nov 20 at 8:07

An aside: you might want to url encode your query string. See url_encode and/or http_build_query.
– Progrock
Nov 20 at 8:10

|
show 2 more comments

up vote
-1
down vote

favorite

i want to export two different type of xlsx file based on radio button .

    $sel = $_POST['sel'];

       echo $sel;



    if(isset($_POST['search'])){



        if($sel == 'board')

        {

         header('Location: export_data1.php? 

       num='.$_POST['staff']);  

       die(); 

        }

       else

       {



         header('Location: export_data2.php? 

          num='.$_POST['desg']);

         die(); 



        }

       }

how to call another php file based on my radio button.Is there any other alternate way to call php file with passing arguments?

edited Nov 20 at 5:57

asked Nov 20 at 5:48

antony

i want to export two different type of xlsx file based on radio button .

    $sel = $_POST['sel'];

       echo $sel;



    if(isset($_POST['search'])){



        if($sel == 'board')

        {

         header('Location: export_data1.php? 

       num='.$_POST['staff']);  

       die(); 

        }

       else

       {



         header('Location: export_data2.php? 

          num='.$_POST['desg']);

         die(); 



        }

       }

how to call another php file based on my radio button.Is there any other alternate way to call php file with passing arguments?

php

edited Nov 20 at 5:57

asked Nov 20 at 5:48

antony

edited Nov 20 at 5:57

asked Nov 20 at 5:48

antony

edited Nov 20 at 5:57

asked Nov 20 at 5:48

antony

asked Nov 20 at 5:48

antony

asked Nov 20 at 5:48

antony

possible duplicate of stackoverflow.com/questions/5678567/…
– Jacob Nelson
Nov 20 at 6:47

i try that method not working in my form
– antony
Nov 20 at 7:41

An alternative could be to have bog standard links to your files.
– Progrock
Nov 20 at 8:05

What's the problem here, what isn't working?
– Progrock
Nov 20 at 8:07

An aside: you might want to url encode your query string. See url_encode and/or http_build_query.
– Progrock
Nov 20 at 8:10

|
show 2 more comments

possible duplicate of stackoverflow.com/questions/5678567/…
– Jacob Nelson
Nov 20 at 6:47

i try that method not working in my form
– antony
Nov 20 at 7:41

An alternative could be to have bog standard links to your files.
– Progrock
Nov 20 at 8:05

What's the problem here, what isn't working?
– Progrock
Nov 20 at 8:07

An aside: you might want to url encode your query string. See url_encode and/or http_build_query.
– Progrock
Nov 20 at 8:10

possible duplicate of stackoverflow.com/questions/5678567/…
– Jacob Nelson
Nov 20 at 6:47

i try that method not working in my form
– antony
Nov 20 at 7:41

An alternative could be to have bog standard links to your files.
– Progrock
Nov 20 at 8:05

What's the problem here, what isn't working?
– Progrock
Nov 20 at 8:07

An aside: you might want to url encode your query string. See url_encode and/or http_build_query.
– Progrock
Nov 20 at 8:10

|
show 2 more comments

1 Answer
1

active

oldest

votes

up vote
0
down vote

Your page of form where you will create form

<!DOCTYPE html>

<html>

<head>

    <title></title>

</head>

<body>

<form action="<?= $_SERVER['PHP_SELF'] ?>"method="post">

    <!-- radio button -->

    <input type="radio" name="sel" value="board">

    <input type="radio" name="sel" value="your_other_value">

    <!-- radio button -->

   <!-- Drop Down -->

    <input type="option" name="boardlist" value="board">

    <input type="option" name="desgwise" value="Designation">

    <!-- radio button -->



    <input type="hidden" name="staff">

    <input type="hidden" name="desg">

    <input type="submit" name="search">

</form>

</body>

</html>

This is your export_data1.php file

<?php

if(isset($_POST['search'])){

    if($sel == 'board'){

        header('Location: export_data.php?num='.$_POST['boardlist'];

    } else {

        header('Location: export_data1.php?num='.$_POST['desgwise'];

    }

}

?>

export_data & export_data1 have different format for export xlsx file

edited Nov 20 at 10:29

Hola Soy Edu Feliz Navidad

3,32932339

answered Nov 20 at 8:01

F5 Buddy

3024

Is this Jeopardy? What's different with this approach here? What's $sel?
– Progrock
Nov 20 at 8:04

I assume the difference here is that instead of having two separate export scripts, you are merging them into one script. I think I prefer the separation of responsibility, unless the code is practically identical. Differentiated URLs could also be a good thing.
– Progrock
Nov 20 at 8:17

i separate into two files. action="export_data1.php?desg=<?php echo $desg ?>" is it correct method to passing parameters
– antony
Nov 20 at 8:58

add a comment |

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1 Answer
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active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
0
down vote

Your page of form where you will create form

<!DOCTYPE html>

<html>

<head>

    <title></title>

</head>

<body>

<form action="<?= $_SERVER['PHP_SELF'] ?>"method="post">

    <!-- radio button -->

    <input type="radio" name="sel" value="board">

    <input type="radio" name="sel" value="your_other_value">

    <!-- radio button -->

   <!-- Drop Down -->

    <input type="option" name="boardlist" value="board">

    <input type="option" name="desgwise" value="Designation">

    <!-- radio button -->



    <input type="hidden" name="staff">

    <input type="hidden" name="desg">

    <input type="submit" name="search">

</form>

</body>

</html>

This is your export_data1.php file

<?php

if(isset($_POST['search'])){

    if($sel == 'board'){

        header('Location: export_data.php?num='.$_POST['boardlist'];

    } else {

        header('Location: export_data1.php?num='.$_POST['desgwise'];

    }

}

?>

export_data & export_data1 have different format for export xlsx file

edited Nov 20 at 10:29

Hola Soy Edu Feliz Navidad

3,32932339

answered Nov 20 at 8:01

F5 Buddy

3024

Is this Jeopardy? What's different with this approach here? What's $sel?
– Progrock
Nov 20 at 8:04

I assume the difference here is that instead of having two separate export scripts, you are merging them into one script. I think I prefer the separation of responsibility, unless the code is practically identical. Differentiated URLs could also be a good thing.
– Progrock
Nov 20 at 8:17

i separate into two files. action="export_data1.php?desg=<?php echo $desg ?>" is it correct method to passing parameters
– antony
Nov 20 at 8:58

add a comment |

up vote
0
down vote

Your page of form where you will create form

<!DOCTYPE html>

<html>

<head>

    <title></title>

</head>

<body>

<form action="<?= $_SERVER['PHP_SELF'] ?>"method="post">

    <!-- radio button -->

    <input type="radio" name="sel" value="board">

    <input type="radio" name="sel" value="your_other_value">

    <!-- radio button -->

   <!-- Drop Down -->

    <input type="option" name="boardlist" value="board">

    <input type="option" name="desgwise" value="Designation">

    <!-- radio button -->



    <input type="hidden" name="staff">

    <input type="hidden" name="desg">

    <input type="submit" name="search">

</form>

</body>

</html>

This is your export_data1.php file

<?php

if(isset($_POST['search'])){

    if($sel == 'board'){

        header('Location: export_data.php?num='.$_POST['boardlist'];

    } else {

        header('Location: export_data1.php?num='.$_POST['desgwise'];

    }

}

?>

export_data & export_data1 have different format for export xlsx file

edited Nov 20 at 10:29

Hola Soy Edu Feliz Navidad

3,32932339

answered Nov 20 at 8:01

F5 Buddy

3024

Is this Jeopardy? What's different with this approach here? What's $sel?
– Progrock
Nov 20 at 8:04

I assume the difference here is that instead of having two separate export scripts, you are merging them into one script. I think I prefer the separation of responsibility, unless the code is practically identical. Differentiated URLs could also be a good thing.
– Progrock
Nov 20 at 8:17

i separate into two files. action="export_data1.php?desg=<?php echo $desg ?>" is it correct method to passing parameters
– antony
Nov 20 at 8:58

add a comment |

up vote
0
down vote

Your page of form where you will create form

<!DOCTYPE html>

<html>

<head>

    <title></title>

</head>

<body>

<form action="<?= $_SERVER['PHP_SELF'] ?>"method="post">

    <!-- radio button -->

    <input type="radio" name="sel" value="board">

    <input type="radio" name="sel" value="your_other_value">

    <!-- radio button -->

   <!-- Drop Down -->

    <input type="option" name="boardlist" value="board">

    <input type="option" name="desgwise" value="Designation">

    <!-- radio button -->



    <input type="hidden" name="staff">

    <input type="hidden" name="desg">

    <input type="submit" name="search">

</form>

</body>

</html>

This is your export_data1.php file

<?php

if(isset($_POST['search'])){

    if($sel == 'board'){

        header('Location: export_data.php?num='.$_POST['boardlist'];

    } else {

        header('Location: export_data1.php?num='.$_POST['desgwise'];

    }

}

?>

export_data & export_data1 have different format for export xlsx file

edited Nov 20 at 10:29

Hola Soy Edu Feliz Navidad

3,32932339

answered Nov 20 at 8:01

F5 Buddy

3024

Your page of form where you will create form

<!DOCTYPE html>

<html>

<head>

    <title></title>

</head>

<body>

<form action="<?= $_SERVER['PHP_SELF'] ?>"method="post">

    <!-- radio button -->

    <input type="radio" name="sel" value="board">

    <input type="radio" name="sel" value="your_other_value">

    <!-- radio button -->

   <!-- Drop Down -->

    <input type="option" name="boardlist" value="board">

    <input type="option" name="desgwise" value="Designation">

    <!-- radio button -->



    <input type="hidden" name="staff">

    <input type="hidden" name="desg">

    <input type="submit" name="search">

</form>

</body>

</html>

This is your export_data1.php file

<?php

if(isset($_POST['search'])){

    if($sel == 'board'){

        header('Location: export_data.php?num='.$_POST['boardlist'];

    } else {

        header('Location: export_data1.php?num='.$_POST['desgwise'];

    }

}

?>

export_data & export_data1 have different format for export xlsx file

edited Nov 20 at 10:29

Hola Soy Edu Feliz Navidad

3,32932339

answered Nov 20 at 8:01

F5 Buddy

3024

edited Nov 20 at 10:29

Hola Soy Edu Feliz Navidad

3,32932339

edited Nov 20 at 10:29

Hola Soy Edu Feliz Navidad

3,32932339

edited Nov 20 at 10:29

Hola Soy Edu Feliz Navidad

3,32932339

answered Nov 20 at 8:01

F5 Buddy

3024

answered Nov 20 at 8:01

F5 Buddy

3024

answered Nov 20 at 8:01

F5 Buddy

3024

Is this Jeopardy? What's different with this approach here? What's $sel?
– Progrock
Nov 20 at 8:04

I assume the difference here is that instead of having two separate export scripts, you are merging them into one script. I think I prefer the separation of responsibility, unless the code is practically identical. Differentiated URLs could also be a good thing.
– Progrock
Nov 20 at 8:17

i separate into two files. action="export_data1.php?desg=<?php echo $desg ?>" is it correct method to passing parameters
– antony
Nov 20 at 8:58

add a comment |

Is this Jeopardy? What's different with this approach here? What's $sel?
– Progrock
Nov 20 at 8:04

I assume the difference here is that instead of having two separate export scripts, you are merging them into one script. I think I prefer the separation of responsibility, unless the code is practically identical. Differentiated URLs could also be a good thing.
– Progrock
Nov 20 at 8:17

i separate into two files. action="export_data1.php?desg=<?php echo $desg ?>" is it correct method to passing parameters
– antony
Nov 20 at 8:58

Is this Jeopardy? What's different with this approach here? What's $sel?
– Progrock
Nov 20 at 8:04

I assume the difference here is that instead of having two separate export scripts, you are merging them into one script. I think I prefer the separation of responsibility, unless the code is practically identical. Differentiated URLs could also be a good thing.
– Progrock
Nov 20 at 8:17

i separate into two files. action="export_data1.php?desg=<?php echo $desg ?>" is it correct method to passing parameters
– antony
Nov 20 at 8:58

add a comment |

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