Scraping and printing titles from Craigslist











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I've written a very tiny script using class to scrape some titles of products from craigslist. My intention is to make use of __str__() method so that my script can print the result without explicitly calling that very method.



However, when I execute my script in the following way, I get the desired results.



Is this the only way I can print the result or there is anything better to print the result through dunder str method?



import requests
from bs4 import BeautifulSoup

URL = "http://bangalore.craigslist.co.in/search/rea?s=120"

class DataSourcer:

def __init__(self,link):
self.link = link
self.datalist =

def fetch(self):
res = requests.get(self.link)
soup = BeautifulSoup(res.text,"lxml")
for ilink in soup.select("li.result-row a[data-id]"):
self.datalist.append(ilink.text)

# return self.datalist #I do not wish to return "self.datalist" here

def __str__(self):
return self.datalist

if __name__ == '__main__':
crawler = DataSourcer(URL)
crawler.fetch()
print(crawler.__str__()) #I found it working this way









share|improve this question
























  • I'm not entirely sure what you're asking, but: print(crawler.__str__()) should be print(str(crawler)).
    – Dair
    7 hours ago










  • That is exactly what you have surmised already I'm asking. Your suggested approach threw this error TypeError: __str__ returned non-string (type list) @Dair . Thanks.
    – MITHU
    7 hours ago






  • 2




    You should instead do return str(self.datalist). def __str__ should return a string type. Instead, you have returned a list. You can convert the list to a string by calling str, so return str(self.datalist).
    – Dair
    7 hours ago










  • Yep, this leads me to a better approach @Dair. Is there any way I can print the result in regular strings other than the list. I know I'm wrong but I tried it for item in crawler: print(item) and failed miserably. However, I get the result when i try like this (in my existing script) for item in crawler.__str__(): print(item). Thanks.
    – MITHU
    7 hours ago

















up vote
0
down vote

favorite












I've written a very tiny script using class to scrape some titles of products from craigslist. My intention is to make use of __str__() method so that my script can print the result without explicitly calling that very method.



However, when I execute my script in the following way, I get the desired results.



Is this the only way I can print the result or there is anything better to print the result through dunder str method?



import requests
from bs4 import BeautifulSoup

URL = "http://bangalore.craigslist.co.in/search/rea?s=120"

class DataSourcer:

def __init__(self,link):
self.link = link
self.datalist =

def fetch(self):
res = requests.get(self.link)
soup = BeautifulSoup(res.text,"lxml")
for ilink in soup.select("li.result-row a[data-id]"):
self.datalist.append(ilink.text)

# return self.datalist #I do not wish to return "self.datalist" here

def __str__(self):
return self.datalist

if __name__ == '__main__':
crawler = DataSourcer(URL)
crawler.fetch()
print(crawler.__str__()) #I found it working this way









share|improve this question
























  • I'm not entirely sure what you're asking, but: print(crawler.__str__()) should be print(str(crawler)).
    – Dair
    7 hours ago










  • That is exactly what you have surmised already I'm asking. Your suggested approach threw this error TypeError: __str__ returned non-string (type list) @Dair . Thanks.
    – MITHU
    7 hours ago






  • 2




    You should instead do return str(self.datalist). def __str__ should return a string type. Instead, you have returned a list. You can convert the list to a string by calling str, so return str(self.datalist).
    – Dair
    7 hours ago










  • Yep, this leads me to a better approach @Dair. Is there any way I can print the result in regular strings other than the list. I know I'm wrong but I tried it for item in crawler: print(item) and failed miserably. However, I get the result when i try like this (in my existing script) for item in crawler.__str__(): print(item). Thanks.
    – MITHU
    7 hours ago















up vote
0
down vote

favorite









up vote
0
down vote

favorite











I've written a very tiny script using class to scrape some titles of products from craigslist. My intention is to make use of __str__() method so that my script can print the result without explicitly calling that very method.



However, when I execute my script in the following way, I get the desired results.



Is this the only way I can print the result or there is anything better to print the result through dunder str method?



import requests
from bs4 import BeautifulSoup

URL = "http://bangalore.craigslist.co.in/search/rea?s=120"

class DataSourcer:

def __init__(self,link):
self.link = link
self.datalist =

def fetch(self):
res = requests.get(self.link)
soup = BeautifulSoup(res.text,"lxml")
for ilink in soup.select("li.result-row a[data-id]"):
self.datalist.append(ilink.text)

# return self.datalist #I do not wish to return "self.datalist" here

def __str__(self):
return self.datalist

if __name__ == '__main__':
crawler = DataSourcer(URL)
crawler.fetch()
print(crawler.__str__()) #I found it working this way









share|improve this question















I've written a very tiny script using class to scrape some titles of products from craigslist. My intention is to make use of __str__() method so that my script can print the result without explicitly calling that very method.



However, when I execute my script in the following way, I get the desired results.



Is this the only way I can print the result or there is anything better to print the result through dunder str method?



import requests
from bs4 import BeautifulSoup

URL = "http://bangalore.craigslist.co.in/search/rea?s=120"

class DataSourcer:

def __init__(self,link):
self.link = link
self.datalist =

def fetch(self):
res = requests.get(self.link)
soup = BeautifulSoup(res.text,"lxml")
for ilink in soup.select("li.result-row a[data-id]"):
self.datalist.append(ilink.text)

# return self.datalist #I do not wish to return "self.datalist" here

def __str__(self):
return self.datalist

if __name__ == '__main__':
crawler = DataSourcer(URL)
crawler.fetch()
print(crawler.__str__()) #I found it working this way






python object-oriented python-3.x web-scraping






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edited 25 mins ago









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asked 7 hours ago









MITHU

320110




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  • I'm not entirely sure what you're asking, but: print(crawler.__str__()) should be print(str(crawler)).
    – Dair
    7 hours ago










  • That is exactly what you have surmised already I'm asking. Your suggested approach threw this error TypeError: __str__ returned non-string (type list) @Dair . Thanks.
    – MITHU
    7 hours ago






  • 2




    You should instead do return str(self.datalist). def __str__ should return a string type. Instead, you have returned a list. You can convert the list to a string by calling str, so return str(self.datalist).
    – Dair
    7 hours ago










  • Yep, this leads me to a better approach @Dair. Is there any way I can print the result in regular strings other than the list. I know I'm wrong but I tried it for item in crawler: print(item) and failed miserably. However, I get the result when i try like this (in my existing script) for item in crawler.__str__(): print(item). Thanks.
    – MITHU
    7 hours ago




















  • I'm not entirely sure what you're asking, but: print(crawler.__str__()) should be print(str(crawler)).
    – Dair
    7 hours ago










  • That is exactly what you have surmised already I'm asking. Your suggested approach threw this error TypeError: __str__ returned non-string (type list) @Dair . Thanks.
    – MITHU
    7 hours ago






  • 2




    You should instead do return str(self.datalist). def __str__ should return a string type. Instead, you have returned a list. You can convert the list to a string by calling str, so return str(self.datalist).
    – Dair
    7 hours ago










  • Yep, this leads me to a better approach @Dair. Is there any way I can print the result in regular strings other than the list. I know I'm wrong but I tried it for item in crawler: print(item) and failed miserably. However, I get the result when i try like this (in my existing script) for item in crawler.__str__(): print(item). Thanks.
    – MITHU
    7 hours ago


















I'm not entirely sure what you're asking, but: print(crawler.__str__()) should be print(str(crawler)).
– Dair
7 hours ago




I'm not entirely sure what you're asking, but: print(crawler.__str__()) should be print(str(crawler)).
– Dair
7 hours ago












That is exactly what you have surmised already I'm asking. Your suggested approach threw this error TypeError: __str__ returned non-string (type list) @Dair . Thanks.
– MITHU
7 hours ago




That is exactly what you have surmised already I'm asking. Your suggested approach threw this error TypeError: __str__ returned non-string (type list) @Dair . Thanks.
– MITHU
7 hours ago




2




2




You should instead do return str(self.datalist). def __str__ should return a string type. Instead, you have returned a list. You can convert the list to a string by calling str, so return str(self.datalist).
– Dair
7 hours ago




You should instead do return str(self.datalist). def __str__ should return a string type. Instead, you have returned a list. You can convert the list to a string by calling str, so return str(self.datalist).
– Dair
7 hours ago












Yep, this leads me to a better approach @Dair. Is there any way I can print the result in regular strings other than the list. I know I'm wrong but I tried it for item in crawler: print(item) and failed miserably. However, I get the result when i try like this (in my existing script) for item in crawler.__str__(): print(item). Thanks.
– MITHU
7 hours ago






Yep, this leads me to a better approach @Dair. Is there any way I can print the result in regular strings other than the list. I know I'm wrong but I tried it for item in crawler: print(item) and failed miserably. However, I get the result when i try like this (in my existing script) for item in crawler.__str__(): print(item). Thanks.
– MITHU
7 hours ago

















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