how to fix undefined index $user = $_GET['user']; [duplicate]
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This question already has an answer here:
“Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP
28 answers
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
This is the PHP code in the database and need to use get method. the error shows undefined index : $user = $_GET['user']; when I run it shows this error. How to fix it?
php
edited Nov 20 at 6:08
akshaypjoshi
5371216
asked Nov 20 at 5:50
yangmy
83
marked as duplicate by Progrock, Nigel Ren php
Users with the php badge can single-handedly close php questions as duplicates and reopen them as needed.
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Nov 20 at 7:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
up vote
1
down vote
favorite
This question already has an answer here:
“Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP
28 answers
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
This is the PHP code in the database and need to use get method. the error shows undefined index : $user = $_GET['user']; when I run it shows this error. How to fix it?
php
edited Nov 20 at 6:08
akshaypjoshi
5371216
asked Nov 20 at 5:50
yangmy
83
marked as duplicate by Progrock, Nigel Ren php
Users with the php badge can single-handedly close php questions as duplicates and reopen them as needed.
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Nov 20 at 7:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 at 6:11
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 at 7:17
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
This question already has an answer here:
“Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP
28 answers
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
This is the PHP code in the database and need to use get method. the error shows undefined index : $user = $_GET['user']; when I run it shows this error. How to fix it?
php
edited Nov 20 at 6:08
akshaypjoshi
5371216
asked Nov 20 at 5:50
yangmy
83
This question already has an answer here:
“Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP
28 answers
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
This is the PHP code in the database and need to use get method. the error shows undefined index : $user = $_GET['user']; when I run it shows this error. How to fix it?
This question already has an answer here:
“Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP
28 answers
php
php
edited Nov 20 at 6:08
akshaypjoshi
5371216
asked Nov 20 at 5:50
yangmy
83
edited Nov 20 at 6:08
akshaypjoshi
5371216
asked Nov 20 at 5:50
yangmy
83
edited Nov 20 at 6:08
akshaypjoshi
5371216
edited Nov 20 at 6:08
akshaypjoshi
5371216
edited Nov 20 at 6:08
akshaypjoshi
5371216
5371216
asked Nov 20 at 5:50
yangmy
83
asked Nov 20 at 5:50
yangmy
83
asked Nov 20 at 5:50
yangmy
83
83
marked as duplicate by Progrock, Nigel Ren php
Users with the php badge can single-handedly close php questions as duplicates and reopen them as needed.
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Nov 20 at 7:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Progrock, Nigel Ren php
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Nov 20 at 7:23
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 at 6:11
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 at 7:17
add a comment |
1
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 at 6:11
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 at 7:17
1
1
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 at 6:11
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 at 6:11
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 at 7:17
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 at 7:17
add a comment |
3 Answers
3
active
oldest
votes
up vote
0
down vote
accepted
You can fix this issue by add isset in $_GET['user'] and check its empty or not
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if( isset($_GET['user']) && $_GET['user']!='' ){
$user = $_GET['user'];
}else{
$user='';
}
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
Another way is that you can add @ in front of $_GET['user']
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
@$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 at 7:15
F5 Buddy
3024
add a comment |
up vote
0
down vote
I added the IF condition in below code you can check it. By adding this condition you are able to solve the undefine index issue
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if(!isset($_GET['user']) && empty($_GET['user']))
return false;// this will send back if data or index is not found and also solve the undefine index problem
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 at 6:15
pawansgi92
19912
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 at 17:22
add a comment |
up vote
-1
down vote
There are many ways to check if an array's index is undefined. The example below uses two methods: isset and empty.
The call to isset returns true if the array has the specified key.
The call to empty will return true if the value for the specified index is "empty" (null, empty string, zero, empty array, etc...) or if the specified key does not exist.
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = isset($_GET['user'])&&!empty($_GET['user']) ? $_GET['user'] : NULL;
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
edited Nov 22 at 21:15
Bryce Siedschlaw
2,92911729
answered Nov 20 at 6:22
Howee
1
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 at 7:20
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
You can fix this issue by add isset in $_GET['user'] and check its empty or not
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if( isset($_GET['user']) && $_GET['user']!='' ){
$user = $_GET['user'];
}else{
$user='';
}
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
Another way is that you can add @ in front of $_GET['user']
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
@$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 at 7:15
F5 Buddy
3024
add a comment |
up vote
0
down vote
accepted
You can fix this issue by add isset in $_GET['user'] and check its empty or not
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if( isset($_GET['user']) && $_GET['user']!='' ){
$user = $_GET['user'];
}else{
$user='';
}
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
Another way is that you can add @ in front of $_GET['user']
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
@$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 at 7:15
F5 Buddy
3024
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
You can fix this issue by add isset in $_GET['user'] and check its empty or not
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if( isset($_GET['user']) && $_GET['user']!='' ){
$user = $_GET['user'];
}else{
$user='';
}
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
Another way is that you can add @ in front of $_GET['user']
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
@$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 at 7:15
F5 Buddy
3024
You can fix this issue by add isset in $_GET['user'] and check its empty or not
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if( isset($_GET['user']) && $_GET['user']!='' ){
$user = $_GET['user'];
}else{
$user='';
}
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
Another way is that you can add @ in front of $_GET['user']
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
@$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
enter code here
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 at 7:15
F5 Buddy
3024
answered Nov 20 at 7:15
F5 Buddy
3024
answered Nov 20 at 7:15
F5 Buddy
3024
answered Nov 20 at 7:15
F5 Buddy
3024
3024
add a comment |
add a comment |
up vote
0
down vote
I added the IF condition in below code you can check it. By adding this condition you are able to solve the undefine index issue
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if(!isset($_GET['user']) && empty($_GET['user']))
return false;// this will send back if data or index is not found and also solve the undefine index problem
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 at 6:15
pawansgi92
19912
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 at 17:22
add a comment |
up vote
0
down vote
I added the IF condition in below code you can check it. By adding this condition you are able to solve the undefine index issue
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if(!isset($_GET['user']) && empty($_GET['user']))
return false;// this will send back if data or index is not found and also solve the undefine index problem
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 at 6:15
pawansgi92
19912
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 at 17:22
add a comment |
up vote
0
down vote
up vote
0
down vote
I added the IF condition in below code you can check it. By adding this condition you are able to solve the undefine index issue
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if(!isset($_GET['user']) && empty($_GET['user']))
return false;// this will send back if data or index is not found and also solve the undefine index problem
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 at 6:15
pawansgi92
19912
I added the IF condition in below code you can check it. By adding this condition you are able to solve the undefine index issue
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
if(!isset($_GET['user']) && empty($_GET['user']))
return false;// this will send back if data or index is not found and also solve the undefine index problem
$user = $_GET['user'];
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
answered Nov 20 at 6:15
pawansgi92
19912
answered Nov 20 at 6:15
pawansgi92
19912
answered Nov 20 at 6:15
pawansgi92
19912
answered Nov 20 at 6:15
pawansgi92
19912
19912
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 at 17:22
add a comment |
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 at 17:22
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 at 11:15
after i add the if statement. it return empty. nothing show.
– yangmy
Nov 20 at 11:15
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 at 17:22
means you are not getting any value in GET. Can you print $_GET and paste the print string here so i can check
– pawansgi92
Nov 20 at 17:22
add a comment |
up vote
-1
down vote
There are many ways to check if an array's index is undefined. The example below uses two methods: isset and empty.
The call to isset returns true if the array has the specified key.
The call to empty will return true if the value for the specified index is "empty" (null, empty string, zero, empty array, etc...) or if the specified key does not exist.
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = isset($_GET['user'])&&!empty($_GET['user']) ? $_GET['user'] : NULL;
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
edited Nov 22 at 21:15
Bryce Siedschlaw
2,92911729
answered Nov 20 at 6:22
Howee
1
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 at 7:20
add a comment |
up vote
-1
down vote
There are many ways to check if an array's index is undefined. The example below uses two methods: isset and empty.
The call to isset returns true if the array has the specified key.
The call to empty will return true if the value for the specified index is "empty" (null, empty string, zero, empty array, etc...) or if the specified key does not exist.
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = isset($_GET['user'])&&!empty($_GET['user']) ? $_GET['user'] : NULL;
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
edited Nov 22 at 21:15
Bryce Siedschlaw
2,92911729
answered Nov 20 at 6:22
Howee
1
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 at 7:20
add a comment |
up vote
-1
down vote
up vote
-1
down vote
There are many ways to check if an array's index is undefined. The example below uses two methods: isset and empty.
The call to isset returns true if the array has the specified key.
The call to empty will return true if the value for the specified index is "empty" (null, empty string, zero, empty array, etc...) or if the specified key does not exist.
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = isset($_GET['user'])&&!empty($_GET['user']) ? $_GET['user'] : NULL;
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
edited Nov 22 at 21:15
Bryce Siedschlaw
2,92911729
answered Nov 20 at 6:22
Howee
1
There are many ways to check if an array's index is undefined. The example below uses two methods: isset and empty.
The call to isset returns true if the array has the specified key.
The call to empty will return true if the value for the specified index is "empty" (null, empty string, zero, empty array, etc...) or if the specified key does not exist.
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: GET, POST, PATCH, PUT, DELETE, OPTIONS');
header('Access-Control-Allow-Headers: Origin, Content-Type, X-Auth-Token');
header("Content-Type: application/json; charset=UTF-8");
include("global.php");
$conn = new mysqli(server, dbuser, dbpw, db);
$user = isset($_GET['user'])&&!empty($_GET['user']) ? $_GET['user'] : NULL;
//$customer = $_GET['customer'];
$querystring = "";
$querystring = "SELECT email, password, firstname, lastname from user ";
$result = $conn->query($querystring);
$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "[") {$outp .= ",";}
$outp .= '{"email":"' . $rs["email"] . '",';
$outp .= '"password":"' . $rs["password"] . '",';
$outp .= '"firstname":"' . $rs["firstname"] . '",';
$outp .= '"lastname":"' . $rs["lastname"]. '"}';
}
$outp .="]";
$conn->close();
echo($outp);
?>
edited Nov 22 at 21:15
Bryce Siedschlaw
2,92911729
answered Nov 20 at 6:22
Howee
1
edited Nov 22 at 21:15
Bryce Siedschlaw
2,92911729
edited Nov 22 at 21:15
Bryce Siedschlaw
2,92911729
edited Nov 22 at 21:15
Bryce Siedschlaw
2,92911729
2,92911729
answered Nov 20 at 6:22
Howee
1
answered Nov 20 at 6:22
Howee
1
answered Nov 20 at 6:22
Howee
1
1
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 at 7:20
add a comment |
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 at 7:20
2
2
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 at 7:20
Can you add some explanation to your code such that others can learn from it?
– Nico Haase
Nov 22 at 7:20
add a comment |
1
Clear this line-> $user = $_GET['user']; ..You don't us of $user variable.
– pedram shabani
Nov 20 at 6:11
Test using isset($_GET['user']) before using.
– SPlatten
Nov 20 at 7:17