Converting entire column to time












0















I have following dataframe which has 3 columns (id, startTime, endTime). I want to convert startTime column to time and create a new column.



  id           startTime             endTime      
1 1 2018/10/01 10:00:00 2018/10/01 10:00:06
2 2 2018/10/01 10:00:01 2018/10/01 10:00:07
3 3 2018/10/01 10:00:02 2018/10/01 10:00:08
4 4 2018/10/01 10:00:03 2018/10/01 10:00:09
5 5 2018/10/01 10:00:04 2018/10/01 10:00:10
6 6 2018/10/01 10:00:05 2018/10/01 10:00:11


I tried



df$ST <- as.POSIXct(df["startTime"]) 


and I got following error.



Error in as.POSIXct.default(df["startTime"]) : 
do not know how to convert 'df["startTime"]' to class “POSIXct”


and then tried



df$ST <- as.Date.POSIXct(df["startTime"]) 


and got following error.



Error in unclass(x)/86400 : non-numeric argument to binary operator


How can I do this?










share|improve this question


















  • 6





    Common error, solution: as.POSIXct(df[["startTime"]]). Or as.POSIXct(df[, "startTime"]). To know why see what are class(df["startTime"]) and class(df[["startTime"]]).

    – Rui Barradas
    Nov 23 '18 at 22:11


















0















I have following dataframe which has 3 columns (id, startTime, endTime). I want to convert startTime column to time and create a new column.



  id           startTime             endTime      
1 1 2018/10/01 10:00:00 2018/10/01 10:00:06
2 2 2018/10/01 10:00:01 2018/10/01 10:00:07
3 3 2018/10/01 10:00:02 2018/10/01 10:00:08
4 4 2018/10/01 10:00:03 2018/10/01 10:00:09
5 5 2018/10/01 10:00:04 2018/10/01 10:00:10
6 6 2018/10/01 10:00:05 2018/10/01 10:00:11


I tried



df$ST <- as.POSIXct(df["startTime"]) 


and I got following error.



Error in as.POSIXct.default(df["startTime"]) : 
do not know how to convert 'df["startTime"]' to class “POSIXct”


and then tried



df$ST <- as.Date.POSIXct(df["startTime"]) 


and got following error.



Error in unclass(x)/86400 : non-numeric argument to binary operator


How can I do this?










share|improve this question


















  • 6





    Common error, solution: as.POSIXct(df[["startTime"]]). Or as.POSIXct(df[, "startTime"]). To know why see what are class(df["startTime"]) and class(df[["startTime"]]).

    – Rui Barradas
    Nov 23 '18 at 22:11
















0












0








0








I have following dataframe which has 3 columns (id, startTime, endTime). I want to convert startTime column to time and create a new column.



  id           startTime             endTime      
1 1 2018/10/01 10:00:00 2018/10/01 10:00:06
2 2 2018/10/01 10:00:01 2018/10/01 10:00:07
3 3 2018/10/01 10:00:02 2018/10/01 10:00:08
4 4 2018/10/01 10:00:03 2018/10/01 10:00:09
5 5 2018/10/01 10:00:04 2018/10/01 10:00:10
6 6 2018/10/01 10:00:05 2018/10/01 10:00:11


I tried



df$ST <- as.POSIXct(df["startTime"]) 


and I got following error.



Error in as.POSIXct.default(df["startTime"]) : 
do not know how to convert 'df["startTime"]' to class “POSIXct”


and then tried



df$ST <- as.Date.POSIXct(df["startTime"]) 


and got following error.



Error in unclass(x)/86400 : non-numeric argument to binary operator


How can I do this?










share|improve this question














I have following dataframe which has 3 columns (id, startTime, endTime). I want to convert startTime column to time and create a new column.



  id           startTime             endTime      
1 1 2018/10/01 10:00:00 2018/10/01 10:00:06
2 2 2018/10/01 10:00:01 2018/10/01 10:00:07
3 3 2018/10/01 10:00:02 2018/10/01 10:00:08
4 4 2018/10/01 10:00:03 2018/10/01 10:00:09
5 5 2018/10/01 10:00:04 2018/10/01 10:00:10
6 6 2018/10/01 10:00:05 2018/10/01 10:00:11


I tried



df$ST <- as.POSIXct(df["startTime"]) 


and I got following error.



Error in as.POSIXct.default(df["startTime"]) : 
do not know how to convert 'df["startTime"]' to class “POSIXct”


and then tried



df$ST <- as.Date.POSIXct(df["startTime"]) 


and got following error.



Error in unclass(x)/86400 : non-numeric argument to binary operator


How can I do this?







r






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 23 '18 at 22:07









MalinthaMalintha

1,32462652




1,32462652








  • 6





    Common error, solution: as.POSIXct(df[["startTime"]]). Or as.POSIXct(df[, "startTime"]). To know why see what are class(df["startTime"]) and class(df[["startTime"]]).

    – Rui Barradas
    Nov 23 '18 at 22:11
















  • 6





    Common error, solution: as.POSIXct(df[["startTime"]]). Or as.POSIXct(df[, "startTime"]). To know why see what are class(df["startTime"]) and class(df[["startTime"]]).

    – Rui Barradas
    Nov 23 '18 at 22:11










6




6





Common error, solution: as.POSIXct(df[["startTime"]]). Or as.POSIXct(df[, "startTime"]). To know why see what are class(df["startTime"]) and class(df[["startTime"]]).

– Rui Barradas
Nov 23 '18 at 22:11







Common error, solution: as.POSIXct(df[["startTime"]]). Or as.POSIXct(df[, "startTime"]). To know why see what are class(df["startTime"]) and class(df[["startTime"]]).

– Rui Barradas
Nov 23 '18 at 22:11














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