Tic-Tac-Toe with React Hooks
$begingroup$
I have found similar posts which has some optimizations on Winning-checking logic: React Tic Tac Toe
My primary focus for this post is about hook setters
being asynchronous. So to check if anyone wins, I used useEffect
to listen to the board.
useEffect(
() => {
if (winning()) {
setMessage(`Player ${turn % 2 ? 1 : 2} wins!`);
setGameState("stopped");
} else {
setTurn(turn + 1);
}
},
[board]
);
When the move is made, the turn number won't increase when the game is finished.
However this makes the initial "turn number" 0 (so the effect adds to it to get 1).
Should I make the board update synchronous before calling the setters? (like using a tempBoard = {...board, (new move)}
and check there instead?
Full code (Click handler is step
)
import React, { useState, useEffect } from "react";
import ReactDOM from "react-dom";
import "./styles.css";
function App() {
const [turn, setTurn] = useState(0);
const [message, setMessage] = useState("");
const [gameState, setGameState] = useState("playing");
const [board, setBoard] = useState({});
const winning = _ => {
return (
(board[0] &&
board[1] &&
board[2] &&
board[0] === board[1] &&
board[1] === board[2]) ||
(board[3] &&
board[4] &&
board[5] &&
board[3] === board[4] &&
board[4] === board[5]) ||
(board[6] &&
board[7] &&
board[8] &&
board[6] === board[7] &&
board[7] === board[8]) ||
(board[0] &&
board[3] &&
board[6] &&
board[0] === board[3] &&
board[3] === board[6]) ||
(board[1] &&
board[4] &&
board[7] &&
board[1] === board[4] &&
board[4] === board[7]) ||
(board[2] &&
board[5] &&
board[8] &&
board[2] === board[5] &&
board[5] === board[8]) ||
(board[0] &&
board[4] &&
board[8] &&
board[0] === board[4] &&
board[4] === board[8]) ||
(board[2] &&
board[4] &&
board[6] &&
board[2] === board[4] &&
board[4] === board[6])
);
};
useEffect(
() => {
if (winning()) {
setMessage(`Player ${turn % 2 ? 1 : 2} wins!`);
setGameState("stopped");
} else {
setTurn(turn + 1);
}
},
[board]
);
const step = (n, turn) => {
if (gameState === "playing" && !board[n]) {
setBoard({ ...board, [n]: turn % 2 ? "x" : "o" });
}
};
return (
<div className="App">
Turn {turn}
<div className="container">
{[0, 1, 2, 3, 4, 5, 6, 7, 8].map(n => (
<div key={"b" + n} className={"b" + n}>
<button onClick={_ => step(n, turn)}>{board[n] || " "}</button>
</div>
))}
</div>
{message}
</div>
);
}
const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);
CodeSandbox
tic-tac-toe react.js
New contributor
$endgroup$
add a comment |
$begingroup$
I have found similar posts which has some optimizations on Winning-checking logic: React Tic Tac Toe
My primary focus for this post is about hook setters
being asynchronous. So to check if anyone wins, I used useEffect
to listen to the board.
useEffect(
() => {
if (winning()) {
setMessage(`Player ${turn % 2 ? 1 : 2} wins!`);
setGameState("stopped");
} else {
setTurn(turn + 1);
}
},
[board]
);
When the move is made, the turn number won't increase when the game is finished.
However this makes the initial "turn number" 0 (so the effect adds to it to get 1).
Should I make the board update synchronous before calling the setters? (like using a tempBoard = {...board, (new move)}
and check there instead?
Full code (Click handler is step
)
import React, { useState, useEffect } from "react";
import ReactDOM from "react-dom";
import "./styles.css";
function App() {
const [turn, setTurn] = useState(0);
const [message, setMessage] = useState("");
const [gameState, setGameState] = useState("playing");
const [board, setBoard] = useState({});
const winning = _ => {
return (
(board[0] &&
board[1] &&
board[2] &&
board[0] === board[1] &&
board[1] === board[2]) ||
(board[3] &&
board[4] &&
board[5] &&
board[3] === board[4] &&
board[4] === board[5]) ||
(board[6] &&
board[7] &&
board[8] &&
board[6] === board[7] &&
board[7] === board[8]) ||
(board[0] &&
board[3] &&
board[6] &&
board[0] === board[3] &&
board[3] === board[6]) ||
(board[1] &&
board[4] &&
board[7] &&
board[1] === board[4] &&
board[4] === board[7]) ||
(board[2] &&
board[5] &&
board[8] &&
board[2] === board[5] &&
board[5] === board[8]) ||
(board[0] &&
board[4] &&
board[8] &&
board[0] === board[4] &&
board[4] === board[8]) ||
(board[2] &&
board[4] &&
board[6] &&
board[2] === board[4] &&
board[4] === board[6])
);
};
useEffect(
() => {
if (winning()) {
setMessage(`Player ${turn % 2 ? 1 : 2} wins!`);
setGameState("stopped");
} else {
setTurn(turn + 1);
}
},
[board]
);
const step = (n, turn) => {
if (gameState === "playing" && !board[n]) {
setBoard({ ...board, [n]: turn % 2 ? "x" : "o" });
}
};
return (
<div className="App">
Turn {turn}
<div className="container">
{[0, 1, 2, 3, 4, 5, 6, 7, 8].map(n => (
<div key={"b" + n} className={"b" + n}>
<button onClick={_ => step(n, turn)}>{board[n] || " "}</button>
</div>
))}
</div>
{message}
</div>
);
}
const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);
CodeSandbox
tic-tac-toe react.js
New contributor
$endgroup$
add a comment |
$begingroup$
I have found similar posts which has some optimizations on Winning-checking logic: React Tic Tac Toe
My primary focus for this post is about hook setters
being asynchronous. So to check if anyone wins, I used useEffect
to listen to the board.
useEffect(
() => {
if (winning()) {
setMessage(`Player ${turn % 2 ? 1 : 2} wins!`);
setGameState("stopped");
} else {
setTurn(turn + 1);
}
},
[board]
);
When the move is made, the turn number won't increase when the game is finished.
However this makes the initial "turn number" 0 (so the effect adds to it to get 1).
Should I make the board update synchronous before calling the setters? (like using a tempBoard = {...board, (new move)}
and check there instead?
Full code (Click handler is step
)
import React, { useState, useEffect } from "react";
import ReactDOM from "react-dom";
import "./styles.css";
function App() {
const [turn, setTurn] = useState(0);
const [message, setMessage] = useState("");
const [gameState, setGameState] = useState("playing");
const [board, setBoard] = useState({});
const winning = _ => {
return (
(board[0] &&
board[1] &&
board[2] &&
board[0] === board[1] &&
board[1] === board[2]) ||
(board[3] &&
board[4] &&
board[5] &&
board[3] === board[4] &&
board[4] === board[5]) ||
(board[6] &&
board[7] &&
board[8] &&
board[6] === board[7] &&
board[7] === board[8]) ||
(board[0] &&
board[3] &&
board[6] &&
board[0] === board[3] &&
board[3] === board[6]) ||
(board[1] &&
board[4] &&
board[7] &&
board[1] === board[4] &&
board[4] === board[7]) ||
(board[2] &&
board[5] &&
board[8] &&
board[2] === board[5] &&
board[5] === board[8]) ||
(board[0] &&
board[4] &&
board[8] &&
board[0] === board[4] &&
board[4] === board[8]) ||
(board[2] &&
board[4] &&
board[6] &&
board[2] === board[4] &&
board[4] === board[6])
);
};
useEffect(
() => {
if (winning()) {
setMessage(`Player ${turn % 2 ? 1 : 2} wins!`);
setGameState("stopped");
} else {
setTurn(turn + 1);
}
},
[board]
);
const step = (n, turn) => {
if (gameState === "playing" && !board[n]) {
setBoard({ ...board, [n]: turn % 2 ? "x" : "o" });
}
};
return (
<div className="App">
Turn {turn}
<div className="container">
{[0, 1, 2, 3, 4, 5, 6, 7, 8].map(n => (
<div key={"b" + n} className={"b" + n}>
<button onClick={_ => step(n, turn)}>{board[n] || " "}</button>
</div>
))}
</div>
{message}
</div>
);
}
const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);
CodeSandbox
tic-tac-toe react.js
New contributor
$endgroup$
I have found similar posts which has some optimizations on Winning-checking logic: React Tic Tac Toe
My primary focus for this post is about hook setters
being asynchronous. So to check if anyone wins, I used useEffect
to listen to the board.
useEffect(
() => {
if (winning()) {
setMessage(`Player ${turn % 2 ? 1 : 2} wins!`);
setGameState("stopped");
} else {
setTurn(turn + 1);
}
},
[board]
);
When the move is made, the turn number won't increase when the game is finished.
However this makes the initial "turn number" 0 (so the effect adds to it to get 1).
Should I make the board update synchronous before calling the setters? (like using a tempBoard = {...board, (new move)}
and check there instead?
Full code (Click handler is step
)
import React, { useState, useEffect } from "react";
import ReactDOM from "react-dom";
import "./styles.css";
function App() {
const [turn, setTurn] = useState(0);
const [message, setMessage] = useState("");
const [gameState, setGameState] = useState("playing");
const [board, setBoard] = useState({});
const winning = _ => {
return (
(board[0] &&
board[1] &&
board[2] &&
board[0] === board[1] &&
board[1] === board[2]) ||
(board[3] &&
board[4] &&
board[5] &&
board[3] === board[4] &&
board[4] === board[5]) ||
(board[6] &&
board[7] &&
board[8] &&
board[6] === board[7] &&
board[7] === board[8]) ||
(board[0] &&
board[3] &&
board[6] &&
board[0] === board[3] &&
board[3] === board[6]) ||
(board[1] &&
board[4] &&
board[7] &&
board[1] === board[4] &&
board[4] === board[7]) ||
(board[2] &&
board[5] &&
board[8] &&
board[2] === board[5] &&
board[5] === board[8]) ||
(board[0] &&
board[4] &&
board[8] &&
board[0] === board[4] &&
board[4] === board[8]) ||
(board[2] &&
board[4] &&
board[6] &&
board[2] === board[4] &&
board[4] === board[6])
);
};
useEffect(
() => {
if (winning()) {
setMessage(`Player ${turn % 2 ? 1 : 2} wins!`);
setGameState("stopped");
} else {
setTurn(turn + 1);
}
},
[board]
);
const step = (n, turn) => {
if (gameState === "playing" && !board[n]) {
setBoard({ ...board, [n]: turn % 2 ? "x" : "o" });
}
};
return (
<div className="App">
Turn {turn}
<div className="container">
{[0, 1, 2, 3, 4, 5, 6, 7, 8].map(n => (
<div key={"b" + n} className={"b" + n}>
<button onClick={_ => step(n, turn)}>{board[n] || " "}</button>
</div>
))}
</div>
{message}
</div>
);
}
const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);
CodeSandbox
tic-tac-toe react.js
tic-tac-toe react.js
New contributor
New contributor
New contributor
asked 10 mins ago
Sunny PunSunny Pun
1012
1012
New contributor
New contributor
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
});
});
}, "mathjax-editing");
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "196"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sunny Pun is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f213781%2ftic-tac-toe-with-react-hooks%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Sunny Pun is a new contributor. Be nice, and check out our Code of Conduct.
Sunny Pun is a new contributor. Be nice, and check out our Code of Conduct.
Sunny Pun is a new contributor. Be nice, and check out our Code of Conduct.
Sunny Pun is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f213781%2ftic-tac-toe-with-react-hooks%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown