Assigning exprtk variables as vector members
I asked very specific question here but I realized where the problem is and it's slightly more general.
Seeing ALL exprtk examples and code pieces, everyone uses exprtk's basic metod add_variable as
double variab;
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab);
and never as
std::vector<double> variab{0.};
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab[0]);
Is there a reason? I cannot find anything on exprtk's readme.txt, it is just never mentioned, they switch immediately on adding a vector in the string expression corresponding to a c++ vector, which is not the case I want.
In my case I have several variables on the string with a random name and I want to match them on double variables inside a container . The example in the question linked seems to suggest that this doesn't work.
Any ideas?
c++ vector exprtk
add a comment |
I asked very specific question here but I realized where the problem is and it's slightly more general.
Seeing ALL exprtk examples and code pieces, everyone uses exprtk's basic metod add_variable as
double variab;
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab);
and never as
std::vector<double> variab{0.};
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab[0]);
Is there a reason? I cannot find anything on exprtk's readme.txt, it is just never mentioned, they switch immediately on adding a vector in the string expression corresponding to a c++ vector, which is not the case I want.
In my case I have several variables on the string with a random name and I want to match them on double variables inside a container . The example in the question linked seems to suggest that this doesn't work.
Any ideas?
c++ vector exprtk
my_symbol_table.add_variable("name_of_variable", variab[0]);
seems correct. Care to not resize vector, invalidating pointer.
– Jarod42
Nov 26 '18 at 10:22
You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.
– Bagnarol
Nov 26 '18 at 22:10
add a comment |
I asked very specific question here but I realized where the problem is and it's slightly more general.
Seeing ALL exprtk examples and code pieces, everyone uses exprtk's basic metod add_variable as
double variab;
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab);
and never as
std::vector<double> variab{0.};
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab[0]);
Is there a reason? I cannot find anything on exprtk's readme.txt, it is just never mentioned, they switch immediately on adding a vector in the string expression corresponding to a c++ vector, which is not the case I want.
In my case I have several variables on the string with a random name and I want to match them on double variables inside a container . The example in the question linked seems to suggest that this doesn't work.
Any ideas?
c++ vector exprtk
I asked very specific question here but I realized where the problem is and it's slightly more general.
Seeing ALL exprtk examples and code pieces, everyone uses exprtk's basic metod add_variable as
double variab;
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab);
and never as
std::vector<double> variab{0.};
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab[0]);
Is there a reason? I cannot find anything on exprtk's readme.txt, it is just never mentioned, they switch immediately on adding a vector in the string expression corresponding to a c++ vector, which is not the case I want.
In my case I have several variables on the string with a random name and I want to match them on double variables inside a container . The example in the question linked seems to suggest that this doesn't work.
Any ideas?
c++ vector exprtk
c++ vector exprtk
edited Dec 1 '18 at 10:47
Cœur
18.2k9108148
18.2k9108148
asked Nov 26 '18 at 10:13
BagnarolBagnarol
14
14
my_symbol_table.add_variable("name_of_variable", variab[0]);
seems correct. Care to not resize vector, invalidating pointer.
– Jarod42
Nov 26 '18 at 10:22
You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.
– Bagnarol
Nov 26 '18 at 22:10
add a comment |
my_symbol_table.add_variable("name_of_variable", variab[0]);
seems correct. Care to not resize vector, invalidating pointer.
– Jarod42
Nov 26 '18 at 10:22
You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.
– Bagnarol
Nov 26 '18 at 22:10
my_symbol_table.add_variable("name_of_variable", variab[0]);
seems correct. Care to not resize vector, invalidating pointer.– Jarod42
Nov 26 '18 at 10:22
my_symbol_table.add_variable("name_of_variable", variab[0]);
seems correct. Care to not resize vector, invalidating pointer.– Jarod42
Nov 26 '18 at 10:22
You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.
– Bagnarol
Nov 26 '18 at 22:10
You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.
– Bagnarol
Nov 26 '18 at 22:10
add a comment |
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my_symbol_table.add_variable("name_of_variable", variab[0]);
seems correct. Care to not resize vector, invalidating pointer.– Jarod42
Nov 26 '18 at 10:22
You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.
– Bagnarol
Nov 26 '18 at 22:10