Assigning exprtk variables as vector members












0















I asked very specific question here but I realized where the problem is and it's slightly more general.
Seeing ALL exprtk examples and code pieces, everyone uses exprtk's basic metod add_variable as



double variab;
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab);


and never as



std::vector<double> variab{0.};
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab[0]);


Is there a reason? I cannot find anything on exprtk's readme.txt, it is just never mentioned, they switch immediately on adding a vector in the string expression corresponding to a c++ vector, which is not the case I want.



In my case I have several variables on the string with a random name and I want to match them on double variables inside a container . The example in the question linked seems to suggest that this doesn't work.



Any ideas?










share|improve this question

























  • my_symbol_table.add_variable("name_of_variable", variab[0]); seems correct. Care to not resize vector, invalidating pointer.

    – Jarod42
    Nov 26 '18 at 10:22











  • You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.

    – Bagnarol
    Nov 26 '18 at 22:10
















0















I asked very specific question here but I realized where the problem is and it's slightly more general.
Seeing ALL exprtk examples and code pieces, everyone uses exprtk's basic metod add_variable as



double variab;
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab);


and never as



std::vector<double> variab{0.};
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab[0]);


Is there a reason? I cannot find anything on exprtk's readme.txt, it is just never mentioned, they switch immediately on adding a vector in the string expression corresponding to a c++ vector, which is not the case I want.



In my case I have several variables on the string with a random name and I want to match them on double variables inside a container . The example in the question linked seems to suggest that this doesn't work.



Any ideas?










share|improve this question

























  • my_symbol_table.add_variable("name_of_variable", variab[0]); seems correct. Care to not resize vector, invalidating pointer.

    – Jarod42
    Nov 26 '18 at 10:22











  • You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.

    – Bagnarol
    Nov 26 '18 at 22:10














0












0








0








I asked very specific question here but I realized where the problem is and it's slightly more general.
Seeing ALL exprtk examples and code pieces, everyone uses exprtk's basic metod add_variable as



double variab;
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab);


and never as



std::vector<double> variab{0.};
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab[0]);


Is there a reason? I cannot find anything on exprtk's readme.txt, it is just never mentioned, they switch immediately on adding a vector in the string expression corresponding to a c++ vector, which is not the case I want.



In my case I have several variables on the string with a random name and I want to match them on double variables inside a container . The example in the question linked seems to suggest that this doesn't work.



Any ideas?










share|improve this question
















I asked very specific question here but I realized where the problem is and it's slightly more general.
Seeing ALL exprtk examples and code pieces, everyone uses exprtk's basic metod add_variable as



double variab;
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab);


and never as



std::vector<double> variab{0.};
exprtk::symbol_table<double> my_symbol_table;
my_symbol_table.add_variable("name_of_variable", variab[0]);


Is there a reason? I cannot find anything on exprtk's readme.txt, it is just never mentioned, they switch immediately on adding a vector in the string expression corresponding to a c++ vector, which is not the case I want.



In my case I have several variables on the string with a random name and I want to match them on double variables inside a container . The example in the question linked seems to suggest that this doesn't work.



Any ideas?







c++ vector exprtk






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 1 '18 at 10:47









Cœur

18.2k9108148




18.2k9108148










asked Nov 26 '18 at 10:13









BagnarolBagnarol

14




14













  • my_symbol_table.add_variable("name_of_variable", variab[0]); seems correct. Care to not resize vector, invalidating pointer.

    – Jarod42
    Nov 26 '18 at 10:22











  • You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.

    – Bagnarol
    Nov 26 '18 at 22:10



















  • my_symbol_table.add_variable("name_of_variable", variab[0]); seems correct. Care to not resize vector, invalidating pointer.

    – Jarod42
    Nov 26 '18 at 10:22











  • You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.

    – Bagnarol
    Nov 26 '18 at 22:10

















my_symbol_table.add_variable("name_of_variable", variab[0]); seems correct. Care to not resize vector, invalidating pointer.

– Jarod42
Nov 26 '18 at 10:22





my_symbol_table.add_variable("name_of_variable", variab[0]); seems correct. Care to not resize vector, invalidating pointer.

– Jarod42
Nov 26 '18 at 10:22













You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.

– Bagnarol
Nov 26 '18 at 22:10





You got it, that was exactly the problem. Thanks a lot, ten points to Gryffindor.

– Bagnarol
Nov 26 '18 at 22:10












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