Generating all numbers between 2 dates saved as [day, hour]
I am given 2 dates, which is saved as 2 numbers [hour, weekday], where hour can be 0-23 and weekday can be 1-7. I am then trying to generate all the hours inbetween, such that e.g. [13, 2] and [2, 3] would generate:
[13,2]
[14,2]
[15,2]
...
[0,3]
[1,3]
[2,3]
I also have the 2 dates as datetimes, but I don't know if it is easier to use those. There is never more than a few days between the 2 dates, and they never cross the end of the week.
javascript
asked Nov 25 '18 at 20:50
LindaLinda
13210
add a comment |
I am given 2 dates, which is saved as 2 numbers [hour, weekday], where hour can be 0-23 and weekday can be 1-7. I am then trying to generate all the hours inbetween, such that e.g. [13, 2] and [2, 3] would generate:
[13,2]
[14,2]
[15,2]
...
[0,3]
[1,3]
[2,3]
I also have the 2 dates as datetimes, but I don't know if it is easier to use those. There is never more than a few days between the 2 dates, and they never cross the end of the week.
javascript
asked Nov 25 '18 at 20:50
LindaLinda
13210
add a comment |
I am given 2 dates, which is saved as 2 numbers [hour, weekday], where hour can be 0-23 and weekday can be 1-7. I am then trying to generate all the hours inbetween, such that e.g. [13, 2] and [2, 3] would generate:
[13,2]
[14,2]
[15,2]
...
[0,3]
[1,3]
[2,3]
I also have the 2 dates as datetimes, but I don't know if it is easier to use those. There is never more than a few days between the 2 dates, and they never cross the end of the week.
javascript
asked Nov 25 '18 at 20:50
LindaLinda
13210
I am given 2 dates, which is saved as 2 numbers [hour, weekday], where hour can be 0-23 and weekday can be 1-7. I am then trying to generate all the hours inbetween, such that e.g. [13, 2] and [2, 3] would generate:
[13,2]
[14,2]
[15,2]
...
[0,3]
[1,3]
[2,3]
I also have the 2 dates as datetimes, but I don't know if it is easier to use those. There is never more than a few days between the 2 dates, and they never cross the end of the week.
javascript
javascript
asked Nov 25 '18 at 20:50
LindaLinda
13210
asked Nov 25 '18 at 20:50
LindaLinda
13210
asked Nov 25 '18 at 20:50
LindaLinda
13210
asked Nov 25 '18 at 20:50
LindaLinda
13210
asked Nov 25 '18 at 20:50
LindaLinda
13210
13210
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
You can define a next date function that relies on % to select the next hour and day, and then you can generate all dates within a range with a simple while loop:
function next([hour, day]) {
let nextHour = (hour + 1) % 24;
let nextDay = nextHour === 0 ? (day % 7) + 1 : day;
return [nextHour, nextDay];
}
function range([h1, d1], [h2, d2]) {
let res = , ch = h1, cd = d1;
while (ch !== h2 || cd !== d2) {
res.push([ch, cd]);
[ch, cd] = next([ch, cd]);
}
res.push([ch, cd]);
return res;
}
console.log(range([13, 2], [2, 3]));
console.log(range([13, 7], [10, 2]));answered Nov 25 '18 at 21:03
sliderslider
8,46311231
add a comment |
It is probably easier to use two Date objects.
Something like:
var date1 = new Date(2018, 11, 20, 13);
var date2 = new Date(2018, 11, 21, 3);
var result = ;
while(date1.getTime() <= date2.getTime()) {
result.push(new Date(date1.getTime()))
date1.setHours(date1.getHours() + 1);
}
console.log(result)answered Nov 25 '18 at 21:25
TitusTitus
14.4k11423
add a comment |
You can do something like this:
const getDate = (h, d) => {
let date = new Date()
date.setHours(h)
date.setDate(date.getDate() - date.getDay() + d);
return date
}
const generateRange = (s, e) => {
let [startHour, startDay] = s, [endHour, endDay] = e, result =
startDate = getDate(startHour, startDay), endDate = getDate(endHour, endDay)
while (startDate < endDate) {
startDate.setHours(startDate.getHours() + 1)
result.push([startDate.getHours(), startDate.getDay()])
}
return result
}
console.log(generateRange([13, 2], [2, 3]))
console.log(generateRange([11, 1], [3, 2]))The idea is to create the 2 dates and then in the while loop just keep adding the hours until your start date is no longer less than the end date.
answered Nov 25 '18 at 22:27
AkrionAkrion
9,52011224
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can define a next date function that relies on % to select the next hour and day, and then you can generate all dates within a range with a simple while loop:
function next([hour, day]) {
let nextHour = (hour + 1) % 24;
let nextDay = nextHour === 0 ? (day % 7) + 1 : day;
return [nextHour, nextDay];
}
function range([h1, d1], [h2, d2]) {
let res = , ch = h1, cd = d1;
while (ch !== h2 || cd !== d2) {
res.push([ch, cd]);
[ch, cd] = next([ch, cd]);
}
res.push([ch, cd]);
return res;
}
console.log(range([13, 2], [2, 3]));
console.log(range([13, 7], [10, 2]));answered Nov 25 '18 at 21:03
sliderslider
8,46311231
add a comment |
You can define a next date function that relies on % to select the next hour and day, and then you can generate all dates within a range with a simple while loop:
function next([hour, day]) {
let nextHour = (hour + 1) % 24;
let nextDay = nextHour === 0 ? (day % 7) + 1 : day;
return [nextHour, nextDay];
}
function range([h1, d1], [h2, d2]) {
let res = , ch = h1, cd = d1;
while (ch !== h2 || cd !== d2) {
res.push([ch, cd]);
[ch, cd] = next([ch, cd]);
}
res.push([ch, cd]);
return res;
}
console.log(range([13, 2], [2, 3]));
console.log(range([13, 7], [10, 2]));answered Nov 25 '18 at 21:03
sliderslider
8,46311231
add a comment |
You can define a next date function that relies on % to select the next hour and day, and then you can generate all dates within a range with a simple while loop:
function next([hour, day]) {
let nextHour = (hour + 1) % 24;
let nextDay = nextHour === 0 ? (day % 7) + 1 : day;
return [nextHour, nextDay];
}
function range([h1, d1], [h2, d2]) {
let res = , ch = h1, cd = d1;
while (ch !== h2 || cd !== d2) {
res.push([ch, cd]);
[ch, cd] = next([ch, cd]);
}
res.push([ch, cd]);
return res;
}
console.log(range([13, 2], [2, 3]));
console.log(range([13, 7], [10, 2]));answered Nov 25 '18 at 21:03
sliderslider
8,46311231
You can define a next date function that relies on % to select the next hour and day, and then you can generate all dates within a range with a simple while loop:
function next([hour, day]) {
let nextHour = (hour + 1) % 24;
let nextDay = nextHour === 0 ? (day % 7) + 1 : day;
return [nextHour, nextDay];
}
function range([h1, d1], [h2, d2]) {
let res = , ch = h1, cd = d1;
while (ch !== h2 || cd !== d2) {
res.push([ch, cd]);
[ch, cd] = next([ch, cd]);
}
res.push([ch, cd]);
return res;
}
console.log(range([13, 2], [2, 3]));
console.log(range([13, 7], [10, 2]));function next([hour, day]) {
let nextHour = (hour + 1) % 24;
let nextDay = nextHour === 0 ? (day % 7) + 1 : day;
return [nextHour, nextDay];
}
function range([h1, d1], [h2, d2]) {
let res = , ch = h1, cd = d1;
while (ch !== h2 || cd !== d2) {
res.push([ch, cd]);
[ch, cd] = next([ch, cd]);
}
res.push([ch, cd]);
return res;
}
console.log(range([13, 2], [2, 3]));
console.log(range([13, 7], [10, 2]));function next([hour, day]) {
let nextHour = (hour + 1) % 24;
let nextDay = nextHour === 0 ? (day % 7) + 1 : day;
return [nextHour, nextDay];
}
function range([h1, d1], [h2, d2]) {
let res = , ch = h1, cd = d1;
while (ch !== h2 || cd !== d2) {
res.push([ch, cd]);
[ch, cd] = next([ch, cd]);
}
res.push([ch, cd]);
return res;
}
console.log(range([13, 2], [2, 3]));
console.log(range([13, 7], [10, 2]));answered Nov 25 '18 at 21:03
sliderslider
8,46311231
edited Nov 25 '18 at 21:12
answered Nov 25 '18 at 21:03
sliderslider
8,46311231
answered Nov 25 '18 at 21:03
sliderslider
8,46311231
answered Nov 25 '18 at 21:03
sliderslider
8,46311231
8,46311231
add a comment |
add a comment |
It is probably easier to use two Date objects.
Something like:
var date1 = new Date(2018, 11, 20, 13);
var date2 = new Date(2018, 11, 21, 3);
var result = ;
while(date1.getTime() <= date2.getTime()) {
result.push(new Date(date1.getTime()))
date1.setHours(date1.getHours() + 1);
}
console.log(result)answered Nov 25 '18 at 21:25
TitusTitus
14.4k11423
add a comment |
It is probably easier to use two Date objects.
Something like:
var date1 = new Date(2018, 11, 20, 13);
var date2 = new Date(2018, 11, 21, 3);
var result = ;
while(date1.getTime() <= date2.getTime()) {
result.push(new Date(date1.getTime()))
date1.setHours(date1.getHours() + 1);
}
console.log(result)answered Nov 25 '18 at 21:25
TitusTitus
14.4k11423
add a comment |
It is probably easier to use two Date objects.
Something like:
var date1 = new Date(2018, 11, 20, 13);
var date2 = new Date(2018, 11, 21, 3);
var result = ;
while(date1.getTime() <= date2.getTime()) {
result.push(new Date(date1.getTime()))
date1.setHours(date1.getHours() + 1);
}
console.log(result)answered Nov 25 '18 at 21:25
TitusTitus
14.4k11423
It is probably easier to use two Date objects.
Something like:
var date1 = new Date(2018, 11, 20, 13);
var date2 = new Date(2018, 11, 21, 3);
var result = ;
while(date1.getTime() <= date2.getTime()) {
result.push(new Date(date1.getTime()))
date1.setHours(date1.getHours() + 1);
}
console.log(result)var date1 = new Date(2018, 11, 20, 13);
var date2 = new Date(2018, 11, 21, 3);
var result = ;
while(date1.getTime() <= date2.getTime()) {
result.push(new Date(date1.getTime()))
date1.setHours(date1.getHours() + 1);
}
console.log(result)var date1 = new Date(2018, 11, 20, 13);
var date2 = new Date(2018, 11, 21, 3);
var result = ;
while(date1.getTime() <= date2.getTime()) {
result.push(new Date(date1.getTime()))
date1.setHours(date1.getHours() + 1);
}
console.log(result)answered Nov 25 '18 at 21:25
TitusTitus
14.4k11423
answered Nov 25 '18 at 21:25
TitusTitus
14.4k11423
answered Nov 25 '18 at 21:25
TitusTitus
14.4k11423
answered Nov 25 '18 at 21:25
TitusTitus
14.4k11423
14.4k11423
add a comment |
add a comment |
You can do something like this:
const getDate = (h, d) => {
let date = new Date()
date.setHours(h)
date.setDate(date.getDate() - date.getDay() + d);
return date
}
const generateRange = (s, e) => {
let [startHour, startDay] = s, [endHour, endDay] = e, result =
startDate = getDate(startHour, startDay), endDate = getDate(endHour, endDay)
while (startDate < endDate) {
startDate.setHours(startDate.getHours() + 1)
result.push([startDate.getHours(), startDate.getDay()])
}
return result
}
console.log(generateRange([13, 2], [2, 3]))
console.log(generateRange([11, 1], [3, 2]))The idea is to create the 2 dates and then in the while loop just keep adding the hours until your start date is no longer less than the end date.
answered Nov 25 '18 at 22:27
AkrionAkrion
9,52011224
add a comment |
You can do something like this:
const getDate = (h, d) => {
let date = new Date()
date.setHours(h)
date.setDate(date.getDate() - date.getDay() + d);
return date
}
const generateRange = (s, e) => {
let [startHour, startDay] = s, [endHour, endDay] = e, result =
startDate = getDate(startHour, startDay), endDate = getDate(endHour, endDay)
while (startDate < endDate) {
startDate.setHours(startDate.getHours() + 1)
result.push([startDate.getHours(), startDate.getDay()])
}
return result
}
console.log(generateRange([13, 2], [2, 3]))
console.log(generateRange([11, 1], [3, 2]))The idea is to create the 2 dates and then in the while loop just keep adding the hours until your start date is no longer less than the end date.
answered Nov 25 '18 at 22:27
AkrionAkrion
9,52011224
add a comment |
You can do something like this:
const getDate = (h, d) => {
let date = new Date()
date.setHours(h)
date.setDate(date.getDate() - date.getDay() + d);
return date
}
const generateRange = (s, e) => {
let [startHour, startDay] = s, [endHour, endDay] = e, result =
startDate = getDate(startHour, startDay), endDate = getDate(endHour, endDay)
while (startDate < endDate) {
startDate.setHours(startDate.getHours() + 1)
result.push([startDate.getHours(), startDate.getDay()])
}
return result
}
console.log(generateRange([13, 2], [2, 3]))
console.log(generateRange([11, 1], [3, 2]))The idea is to create the 2 dates and then in the while loop just keep adding the hours until your start date is no longer less than the end date.
answered Nov 25 '18 at 22:27
AkrionAkrion
9,52011224
You can do something like this:
const getDate = (h, d) => {
let date = new Date()
date.setHours(h)
date.setDate(date.getDate() - date.getDay() + d);
return date
}
const generateRange = (s, e) => {
let [startHour, startDay] = s, [endHour, endDay] = e, result =
startDate = getDate(startHour, startDay), endDate = getDate(endHour, endDay)
while (startDate < endDate) {
startDate.setHours(startDate.getHours() + 1)
result.push([startDate.getHours(), startDate.getDay()])
}
return result
}
console.log(generateRange([13, 2], [2, 3]))
console.log(generateRange([11, 1], [3, 2]))The idea is to create the 2 dates and then in the while loop just keep adding the hours until your start date is no longer less than the end date.
const getDate = (h, d) => {
let date = new Date()
date.setHours(h)
date.setDate(date.getDate() - date.getDay() + d);
return date
}
const generateRange = (s, e) => {
let [startHour, startDay] = s, [endHour, endDay] = e, result =
startDate = getDate(startHour, startDay), endDate = getDate(endHour, endDay)
while (startDate < endDate) {
startDate.setHours(startDate.getHours() + 1)
result.push([startDate.getHours(), startDate.getDay()])
}
return result
}
console.log(generateRange([13, 2], [2, 3]))
console.log(generateRange([11, 1], [3, 2]))const getDate = (h, d) => {
let date = new Date()
date.setHours(h)
date.setDate(date.getDate() - date.getDay() + d);
return date
}
const generateRange = (s, e) => {
let [startHour, startDay] = s, [endHour, endDay] = e, result =
startDate = getDate(startHour, startDay), endDate = getDate(endHour, endDay)
while (startDate < endDate) {
startDate.setHours(startDate.getHours() + 1)
result.push([startDate.getHours(), startDate.getDay()])
}
return result
}
console.log(generateRange([13, 2], [2, 3]))
console.log(generateRange([11, 1], [3, 2]))answered Nov 25 '18 at 22:27
AkrionAkrion
9,52011224
edited Nov 25 '18 at 22:54
answered Nov 25 '18 at 22:27
AkrionAkrion
9,52011224
answered Nov 25 '18 at 22:27
AkrionAkrion
9,52011224
answered Nov 25 '18 at 22:27
AkrionAkrion
9,52011224
9,52011224
add a comment |
add a comment |
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