Check if multiple elements in an array contain the same value

For instance I have an array that gets filled with random numbers and am going to call this one dice.

Random rnd = new Random()

int dice=new int [5]

for (int i=0;i<dice.length;i++)

{

dice[i]= rnd.next(1,7)

}

Now for the sake of simplicity I wanna ask how can I find out if got a three of a kind of instance.

edited Dec 12 '18 at 20:04

asked Nov 25 '18 at 20:54

Abdul SH

int dice=new dice [5] not sure if this compiles

– Hanjun Chen
Nov 25 '18 at 22:17

@HanjunChen Well in my original code I have dice as a class therefore my array was like so (public Dice dices = new Dice[5];) and that's why I made this VERY MINOR mistake writing the questions. Yet the ONLY thing you've seen in the questions is this! So helpful really

– Abdul SH
Nov 26 '18 at 21:57

add a comment |

For instance I have an array that gets filled with random numbers and am going to call this one dice.

Random rnd = new Random()

int dice=new int [5]

for (int i=0;i<dice.length;i++)

{

dice[i]= rnd.next(1,7)

}

Now for the sake of simplicity I wanna ask how can I find out if got a three of a kind of instance.

edited Dec 12 '18 at 20:04

asked Nov 25 '18 at 20:54

Abdul SH

int dice=new dice [5] not sure if this compiles

– Hanjun Chen
Nov 25 '18 at 22:17

@HanjunChen Well in my original code I have dice as a class therefore my array was like so (public Dice dices = new Dice[5];) and that's why I made this VERY MINOR mistake writing the questions. Yet the ONLY thing you've seen in the questions is this! So helpful really

– Abdul SH
Nov 26 '18 at 21:57

add a comment |

For instance I have an array that gets filled with random numbers and am going to call this one dice.

Random rnd = new Random()

int dice=new int [5]

for (int i=0;i<dice.length;i++)

{

dice[i]= rnd.next(1,7)

}

Now for the sake of simplicity I wanna ask how can I find out if got a three of a kind of instance.

edited Dec 12 '18 at 20:04

asked Nov 25 '18 at 20:54

Abdul SH

For instance I have an array that gets filled with random numbers and am going to call this one dice.

Random rnd = new Random()

int dice=new int [5]

for (int i=0;i<dice.length;i++)

{

dice[i]= rnd.next(1,7)

}

Now for the sake of simplicity I wanna ask how can I find out if got a three of a kind of instance.

c# arrays algorithm random

edited Dec 12 '18 at 20:04

asked Nov 25 '18 at 20:54

Abdul SH

edited Dec 12 '18 at 20:04

asked Nov 25 '18 at 20:54

Abdul SH

edited Dec 12 '18 at 20:04

asked Nov 25 '18 at 20:54

Abdul SH

asked Nov 25 '18 at 20:54

Abdul SH

asked Nov 25 '18 at 20:54

Abdul SH

int dice=new dice [5] not sure if this compiles

– Hanjun Chen
Nov 25 '18 at 22:17

@HanjunChen Well in my original code I have dice as a class therefore my array was like so (public Dice dices = new Dice[5];) and that's why I made this VERY MINOR mistake writing the questions. Yet the ONLY thing you've seen in the questions is this! So helpful really

– Abdul SH
Nov 26 '18 at 21:57

add a comment |

int dice=new dice [5] not sure if this compiles

– Hanjun Chen
Nov 25 '18 at 22:17

@HanjunChen Well in my original code I have dice as a class therefore my array was like so (public Dice dices = new Dice[5];) and that's why I made this VERY MINOR mistake writing the questions. Yet the ONLY thing you've seen in the questions is this! So helpful really

– Abdul SH
Nov 26 '18 at 21:57

int dice=new dice [5] not sure if this compiles

– Hanjun Chen
Nov 25 '18 at 22:17

@HanjunChen Well in my original code I have dice as a class therefore my array was like so (public Dice dices = new Dice[5];) and that's why I made this VERY MINOR mistake writing the questions. Yet the ONLY thing you've seen in the questions is this! So helpful really

– Abdul SH
Nov 26 '18 at 21:57

add a comment |

3 Answers
3

active

oldest

votes

use a IDictionary<int,int>

var dict = new Dictionary<int,int>();

foreach (int i in dice)

    if(!dict.ContainsKey(i))

        dict.Add(i,1);

    else dict[i]++;

(optional) you can use Linq to get the numbers that appear multiple times

var duplicates = dict.Where( x=>x.Value > 1 )

  .Select(x=>x.Key)

  .ToList();

edited Nov 25 '18 at 22:28

answered Nov 25 '18 at 22:21

Hanjun Chen

34128

add a comment |

    // preparation (basically your code)

    var rnd = new Random();

    var dice = new int[5];



    for (int i=0; i < dice.Length; i++)

    {

        dice[i]= rnd.Next(1,7);

    }



    // select dices, grouped by with their count

    var groupedByCount = dice.GroupBy(d => d, d => 1 /* each hit counts as 1 */);



    // show all dices with their count

    foreach (var g in groupedByCount)

        Console.WriteLine(g.Key + ": " + g.Count());



    // show the dices with 3 or more 

    foreach (var g in groupedByCount.Where(g => g.Count() >= 3))

        Console.WriteLine("3 times or more: " + g.Key);

answered Nov 25 '18 at 21:06

Waescher

2,85431730

add a comment |

To give a completely different approach, instead of:

Random rnd = new Random();

int dice=new int[5];

for (int i=0;i<dice.length;i++)

{

    dice[i]= rnd.next(1,7);

}

Try this:

Random rnd = new Random();

int valueCount = new int[6];

for (int i=0; i<5; i++)

{

    valueCount[rnd.next(0,6)]++;

}



//you have kept track of each value.

if (valueCount.Any(c => c == 3))

    //3 of a kind

Of course you can combine both....

Do note that this works for a really specific rule engine, optimized for counting events.

If you really want a card/dice game, you'll need to rethink the rule engine to coupe with rules like "is it: 1,2,3,4,5,6, and in that order?".

For that, try: How to implement a rule engine?

edited Nov 26 '18 at 14:12

answered Nov 25 '18 at 21:00

Stefan

8,52873761

But you never update the valueCount array.

– Jim Mischel
Nov 26 '18 at 14:10

@JimMischel: .... oops, my bad... copy/past issue

– Stefan
Nov 26 '18 at 14:12

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

use a IDictionary<int,int>

var dict = new Dictionary<int,int>();

foreach (int i in dice)

    if(!dict.ContainsKey(i))

        dict.Add(i,1);

    else dict[i]++;

(optional) you can use Linq to get the numbers that appear multiple times

var duplicates = dict.Where( x=>x.Value > 1 )

  .Select(x=>x.Key)

  .ToList();

edited Nov 25 '18 at 22:28

answered Nov 25 '18 at 22:21

Hanjun Chen

34128

add a comment |

use a IDictionary<int,int>

var dict = new Dictionary<int,int>();

foreach (int i in dice)

    if(!dict.ContainsKey(i))

        dict.Add(i,1);

    else dict[i]++;

(optional) you can use Linq to get the numbers that appear multiple times

var duplicates = dict.Where( x=>x.Value > 1 )

  .Select(x=>x.Key)

  .ToList();

edited Nov 25 '18 at 22:28

answered Nov 25 '18 at 22:21

Hanjun Chen

34128

add a comment |

use a IDictionary<int,int>

var dict = new Dictionary<int,int>();

foreach (int i in dice)

    if(!dict.ContainsKey(i))

        dict.Add(i,1);

    else dict[i]++;

(optional) you can use Linq to get the numbers that appear multiple times

var duplicates = dict.Where( x=>x.Value > 1 )

  .Select(x=>x.Key)

  .ToList();

edited Nov 25 '18 at 22:28

answered Nov 25 '18 at 22:21

Hanjun Chen

34128

use a IDictionary<int,int>

var dict = new Dictionary<int,int>();

foreach (int i in dice)

    if(!dict.ContainsKey(i))

        dict.Add(i,1);

    else dict[i]++;

(optional) you can use Linq to get the numbers that appear multiple times

var duplicates = dict.Where( x=>x.Value > 1 )

  .Select(x=>x.Key)

  .ToList();

edited Nov 25 '18 at 22:28

answered Nov 25 '18 at 22:21

Hanjun Chen

34128

edited Nov 25 '18 at 22:28

answered Nov 25 '18 at 22:21

Hanjun Chen

34128

answered Nov 25 '18 at 22:21

Hanjun Chen

34128

answered Nov 25 '18 at 22:21

Hanjun Chen

34128

add a comment |

    // preparation (basically your code)

    var rnd = new Random();

    var dice = new int[5];



    for (int i=0; i < dice.Length; i++)

    {

        dice[i]= rnd.Next(1,7);

    }



    // select dices, grouped by with their count

    var groupedByCount = dice.GroupBy(d => d, d => 1 /* each hit counts as 1 */);



    // show all dices with their count

    foreach (var g in groupedByCount)

        Console.WriteLine(g.Key + ": " + g.Count());



    // show the dices with 3 or more 

    foreach (var g in groupedByCount.Where(g => g.Count() >= 3))

        Console.WriteLine("3 times or more: " + g.Key);

answered Nov 25 '18 at 21:06

Waescher

2,85431730

add a comment |

    // preparation (basically your code)

    var rnd = new Random();

    var dice = new int[5];



    for (int i=0; i < dice.Length; i++)

    {

        dice[i]= rnd.Next(1,7);

    }



    // select dices, grouped by with their count

    var groupedByCount = dice.GroupBy(d => d, d => 1 /* each hit counts as 1 */);



    // show all dices with their count

    foreach (var g in groupedByCount)

        Console.WriteLine(g.Key + ": " + g.Count());



    // show the dices with 3 or more 

    foreach (var g in groupedByCount.Where(g => g.Count() >= 3))

        Console.WriteLine("3 times or more: " + g.Key);

answered Nov 25 '18 at 21:06

Waescher

2,85431730

add a comment |

    // preparation (basically your code)

    var rnd = new Random();

    var dice = new int[5];



    for (int i=0; i < dice.Length; i++)

    {

        dice[i]= rnd.Next(1,7);

    }



    // select dices, grouped by with their count

    var groupedByCount = dice.GroupBy(d => d, d => 1 /* each hit counts as 1 */);



    // show all dices with their count

    foreach (var g in groupedByCount)

        Console.WriteLine(g.Key + ": " + g.Count());



    // show the dices with 3 or more 

    foreach (var g in groupedByCount.Where(g => g.Count() >= 3))

        Console.WriteLine("3 times or more: " + g.Key);

answered Nov 25 '18 at 21:06

Waescher

2,85431730

    // preparation (basically your code)

    var rnd = new Random();

    var dice = new int[5];



    for (int i=0; i < dice.Length; i++)

    {

        dice[i]= rnd.Next(1,7);

    }



    // select dices, grouped by with their count

    var groupedByCount = dice.GroupBy(d => d, d => 1 /* each hit counts as 1 */);



    // show all dices with their count

    foreach (var g in groupedByCount)

        Console.WriteLine(g.Key + ": " + g.Count());



    // show the dices with 3 or more 

    foreach (var g in groupedByCount.Where(g => g.Count() >= 3))

        Console.WriteLine("3 times or more: " + g.Key);

answered Nov 25 '18 at 21:06

Waescher

2,85431730

answered Nov 25 '18 at 21:06

Waescher

2,85431730

answered Nov 25 '18 at 21:06

Waescher

2,85431730

answered Nov 25 '18 at 21:06

Waescher

2,85431730

add a comment |

To give a completely different approach, instead of:

Random rnd = new Random();

int dice=new int[5];

for (int i=0;i<dice.length;i++)

{

    dice[i]= rnd.next(1,7);

}

Try this:

Random rnd = new Random();

int valueCount = new int[6];

for (int i=0; i<5; i++)

{

    valueCount[rnd.next(0,6)]++;

}



//you have kept track of each value.

if (valueCount.Any(c => c == 3))

    //3 of a kind

Of course you can combine both....

Do note that this works for a really specific rule engine, optimized for counting events.

If you really want a card/dice game, you'll need to rethink the rule engine to coupe with rules like "is it: 1,2,3,4,5,6, and in that order?".

For that, try: How to implement a rule engine?

edited Nov 26 '18 at 14:12

answered Nov 25 '18 at 21:00

Stefan

8,52873761

But you never update the valueCount array.

– Jim Mischel
Nov 26 '18 at 14:10

@JimMischel: .... oops, my bad... copy/past issue

– Stefan
Nov 26 '18 at 14:12

add a comment |

To give a completely different approach, instead of:

Random rnd = new Random();

int dice=new int[5];

for (int i=0;i<dice.length;i++)

{

    dice[i]= rnd.next(1,7);

}

Try this:

Random rnd = new Random();

int valueCount = new int[6];

for (int i=0; i<5; i++)

{

    valueCount[rnd.next(0,6)]++;

}



//you have kept track of each value.

if (valueCount.Any(c => c == 3))

    //3 of a kind

Of course you can combine both....

Do note that this works for a really specific rule engine, optimized for counting events.

If you really want a card/dice game, you'll need to rethink the rule engine to coupe with rules like "is it: 1,2,3,4,5,6, and in that order?".

For that, try: How to implement a rule engine?

edited Nov 26 '18 at 14:12

answered Nov 25 '18 at 21:00

Stefan

8,52873761

But you never update the valueCount array.

– Jim Mischel
Nov 26 '18 at 14:10

@JimMischel: .... oops, my bad... copy/past issue

– Stefan
Nov 26 '18 at 14:12

add a comment |

To give a completely different approach, instead of:

Random rnd = new Random();

int dice=new int[5];

for (int i=0;i<dice.length;i++)

{

    dice[i]= rnd.next(1,7);

}

Try this:

Random rnd = new Random();

int valueCount = new int[6];

for (int i=0; i<5; i++)

{

    valueCount[rnd.next(0,6)]++;

}



//you have kept track of each value.

if (valueCount.Any(c => c == 3))

    //3 of a kind

Of course you can combine both....

Do note that this works for a really specific rule engine, optimized for counting events.

If you really want a card/dice game, you'll need to rethink the rule engine to coupe with rules like "is it: 1,2,3,4,5,6, and in that order?".

For that, try: How to implement a rule engine?

edited Nov 26 '18 at 14:12

answered Nov 25 '18 at 21:00

Stefan

8,52873761

To give a completely different approach, instead of:

Random rnd = new Random();

int dice=new int[5];

for (int i=0;i<dice.length;i++)

{

    dice[i]= rnd.next(1,7);

}

Try this:

Random rnd = new Random();

int valueCount = new int[6];

for (int i=0; i<5; i++)

{

    valueCount[rnd.next(0,6)]++;

}



//you have kept track of each value.

if (valueCount.Any(c => c == 3))

    //3 of a kind

Of course you can combine both....

Do note that this works for a really specific rule engine, optimized for counting events.

If you really want a card/dice game, you'll need to rethink the rule engine to coupe with rules like "is it: 1,2,3,4,5,6, and in that order?".

For that, try: How to implement a rule engine?

edited Nov 26 '18 at 14:12

answered Nov 25 '18 at 21:00

Stefan

8,52873761

edited Nov 26 '18 at 14:12

answered Nov 25 '18 at 21:00

Stefan

8,52873761

answered Nov 25 '18 at 21:00

Stefan

8,52873761

answered Nov 25 '18 at 21:00

Stefan

8,52873761

But you never update the valueCount array.

– Jim Mischel
Nov 26 '18 at 14:10

@JimMischel: .... oops, my bad... copy/past issue

– Stefan
Nov 26 '18 at 14:12

add a comment |

But you never update the valueCount array.

– Jim Mischel
Nov 26 '18 at 14:10

@JimMischel: .... oops, my bad... copy/past issue

– Stefan
Nov 26 '18 at 14:12

But you never update the valueCount array.

– Jim Mischel
Nov 26 '18 at 14:10

@JimMischel: .... oops, my bad... copy/past issue

– Stefan
Nov 26 '18 at 14:12

add a comment |

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