Clean object from nulls and undefined












1















I've written the following function which cleans nulls and undefined from an object, but for some reason it also removes key where the value is 0.



For example:



{

  key1: 'value1',

  key2: 0

}


The function will remove key2, even though it should not.



Here is the function:



const cleanJson = function cleanJson (obj) {

    if (Object.prototype.toString.call(obj) !== '[object Object]') return obj;

    return Object.keys(obj).filter(key => obj[key] && obj[key] !== 'delete').reduce((newObj, key) => {

        newObj[key] = Object.prototype.toString.call(obj[key]) !== '[object Object]' ? obj[key] : cleanJson(obj[key]);

        return newObj;

    }, {});

};


Please advise.






javascript node.js







share|improve this question




















  • 1





    Please read the description of the json tag, especially what is in capitals.

    – trincot
    Nov 25 '18 at 20:53






  • 2





    0 is "falsy", so it gets removed. Your function also cleans up things that evaluate to false.

    – Houseman
    Nov 25 '18 at 20:56
















1















I've written the following function which cleans nulls and undefined from an object, but for some reason it also removes key where the value is 0.



For example:



{

  key1: 'value1',

  key2: 0

}


The function will remove key2, even though it should not.



Here is the function:



const cleanJson = function cleanJson (obj) {

    if (Object.prototype.toString.call(obj) !== '[object Object]') return obj;

    return Object.keys(obj).filter(key => obj[key] && obj[key] !== 'delete').reduce((newObj, key) => {

        newObj[key] = Object.prototype.toString.call(obj[key]) !== '[object Object]' ? obj[key] : cleanJson(obj[key]);

        return newObj;

    }, {});

};


Please advise.






javascript node.js







share|improve this question




















  • 1





    Please read the description of the json tag, especially what is in capitals.

    – trincot
    Nov 25 '18 at 20:53






  • 2





    0 is "falsy", so it gets removed. Your function also cleans up things that evaluate to false.

    – Houseman
    Nov 25 '18 at 20:56














1












1








1








I've written the following function which cleans nulls and undefined from an object, but for some reason it also removes key where the value is 0.



For example:



{

  key1: 'value1',

  key2: 0

}


The function will remove key2, even though it should not.



Here is the function:



const cleanJson = function cleanJson (obj) {

    if (Object.prototype.toString.call(obj) !== '[object Object]') return obj;

    return Object.keys(obj).filter(key => obj[key] && obj[key] !== 'delete').reduce((newObj, key) => {

        newObj[key] = Object.prototype.toString.call(obj[key]) !== '[object Object]' ? obj[key] : cleanJson(obj[key]);

        return newObj;

    }, {});

};


Please advise.






javascript node.js







share|improve this question
















I've written the following function which cleans nulls and undefined from an object, but for some reason it also removes key where the value is 0.



For example:



{

  key1: 'value1',

  key2: 0

}


The function will remove key2, even though it should not.



Here is the function:



const cleanJson = function cleanJson (obj) {

    if (Object.prototype.toString.call(obj) !== '[object Object]') return obj;

    return Object.keys(obj).filter(key => obj[key] && obj[key] !== 'delete').reduce((newObj, key) => {

        newObj[key] = Object.prototype.toString.call(obj[key]) !== '[object Object]' ? obj[key] : cleanJson(obj[key]);

        return newObj;

    }, {});

};


Please advise.






javascript node.js




javascript node.js






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 25 '18 at 20:57









trincot

126k1688122




126k1688122










asked Nov 25 '18 at 20:51









David FaizDavid Faiz

92892247




92892247








  • 1





    Please read the description of the json tag, especially what is in capitals.

    – trincot
    Nov 25 '18 at 20:53






  • 2





    0 is "falsy", so it gets removed. Your function also cleans up things that evaluate to false.

    – Houseman
    Nov 25 '18 at 20:56














  • 1





    Please read the description of the json tag, especially what is in capitals.

    – trincot
    Nov 25 '18 at 20:53






  • 2





    0 is "falsy", so it gets removed. Your function also cleans up things that evaluate to false.

    – Houseman
    Nov 25 '18 at 20:56








1




1





Please read the description of the json tag, especially what is in capitals.

– trincot
Nov 25 '18 at 20:53





Please read the description of the json tag, especially what is in capitals.

– trincot
Nov 25 '18 at 20:53




2




2





0 is "falsy", so it gets removed. Your function also cleans up things that evaluate to false.

– Houseman
Nov 25 '18 at 20:56





0 is "falsy", so it gets removed. Your function also cleans up things that evaluate to false.

– Houseman
Nov 25 '18 at 20:56












4 Answers
4






active

oldest

votes


















2














Here is one option using Object.entries:






const myJSON = {key1:'value1', key2:0, key3:null, key4:undefined, key5:""};



const myCleanJSON = Object.entries(myJSON)

  .filter(([key, value]) => (value !== null && typeof value !== 'undefined'))

  .reduce((acc, b) => ((!acc.length) ? {...acc, [b[0]]: b[1] } : { [acc[0]] : acc[1], [b[0]]: b[1] }));

  

console.log(myCleanJSON);








share|improve this answer































    2














    The problem is within 



    obj[key] && obj[key] !== 'delete'


    When obj[key] == 0, would return false.






    share|improve this answer































      1














      Because 0 (as well as the empty string "") evaluates to false when cast to a Boolean, you need to explicitly check for undefined and null:






      let a = {
      
  key1: 'value1',
      
  key2: 0,
      
  key3: null
      
}
      

      
function cleanProps(o) {
      
  if (Object.prototype.toString.call(o) !== '[object Object]') return o
      
  for (key in o) {
      
    if([undefined, null].includes(o[key])) delete o[key]
      
  }
      
  return o
      
}
      

      
console.log(cleanProps(a))








      share|improve this answer































        0














        I think that would solve your issue:



        obj[key] !== null && obj[key] !== undefined && obj[key] !== 'delete'






        share|improve this answer
























        • You can just use != to catch both null and undefined

          – Mark Meyer
          Nov 25 '18 at 21:11











        • And pick one or the other?

          – Kevin Amiranoff
          Nov 25 '18 at 21:14











        • Yes, both undefined != null and null != undefined are false

          – Mark Meyer
          Nov 25 '18 at 21:16











        Your Answer






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        4 Answers
        4






        active

        oldest

        votes








        4 Answers
        4






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2














        Here is one option using Object.entries:






        const myJSON = {key1:'value1', key2:0, key3:null, key4:undefined, key5:""};
        

        
const myCleanJSON = Object.entries(myJSON)
        
  .filter(([key, value]) => (value !== null && typeof value !== 'undefined'))
        
  .reduce((acc, b) => ((!acc.length) ? {...acc, [b[0]]: b[1] } : { [acc[0]] : acc[1], [b[0]]: b[1] }));
        
  
        
console.log(myCleanJSON);








        share|improve this answer




























          2














          Here is one option using Object.entries:






          const myJSON = {key1:'value1', key2:0, key3:null, key4:undefined, key5:""};
          

          
const myCleanJSON = Object.entries(myJSON)
          
  .filter(([key, value]) => (value !== null && typeof value !== 'undefined'))
          
  .reduce((acc, b) => ((!acc.length) ? {...acc, [b[0]]: b[1] } : { [acc[0]] : acc[1], [b[0]]: b[1] }));
          
  
          
console.log(myCleanJSON);








          share|improve this answer


























            2












            2








            2







            Here is one option using Object.entries:






            const myJSON = {key1:'value1', key2:0, key3:null, key4:undefined, key5:""};
            

            
const myCleanJSON = Object.entries(myJSON)
            
  .filter(([key, value]) => (value !== null && typeof value !== 'undefined'))
            
  .reduce((acc, b) => ((!acc.length) ? {...acc, [b[0]]: b[1] } : { [acc[0]] : acc[1], [b[0]]: b[1] }));
            
  
            
console.log(myCleanJSON);








            share|improve this answer













            Here is one option using Object.entries:






            const myJSON = {key1:'value1', key2:0, key3:null, key4:undefined, key5:""};
            

            
const myCleanJSON = Object.entries(myJSON)
            
  .filter(([key, value]) => (value !== null && typeof value !== 'undefined'))
            
  .reduce((acc, b) => ((!acc.length) ? {...acc, [b[0]]: b[1] } : { [acc[0]] : acc[1], [b[0]]: b[1] }));
            
  
            
console.log(myCleanJSON);








            const myJSON = {key1:'value1', key2:0, key3:null, key4:undefined, key5:""};
            

            
const myCleanJSON = Object.entries(myJSON)
            
  .filter(([key, value]) => (value !== null && typeof value !== 'undefined'))
            
  .reduce((acc, b) => ((!acc.length) ? {...acc, [b[0]]: b[1] } : { [acc[0]] : acc[1], [b[0]]: b[1] }));
            
  
            
console.log(myCleanJSON);





            const myJSON = {key1:'value1', key2:0, key3:null, key4:undefined, key5:""};
            

            
const myCleanJSON = Object.entries(myJSON)
            
  .filter(([key, value]) => (value !== null && typeof value !== 'undefined'))
            
  .reduce((acc, b) => ((!acc.length) ? {...acc, [b[0]]: b[1] } : { [acc[0]] : acc[1], [b[0]]: b[1] }));
            
  
            
console.log(myCleanJSON);






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 25 '18 at 21:10









            zvonazvona

            12.6k14059




            12.6k14059

























                2














                The problem is within 



                obj[key] && obj[key] !== 'delete'


                When obj[key] == 0, would return false.






                share|improve this answer




























                  2














                  The problem is within 



                  obj[key] && obj[key] !== 'delete'


                  When obj[key] == 0, would return false.






                  share|improve this answer


























                    2












                    2








                    2







                    The problem is within 



                    obj[key] && obj[key] !== 'delete'


                    When obj[key] == 0, would return false.






                    share|improve this answer













                    The problem is within 



                    obj[key] && obj[key] !== 'delete'


                    When obj[key] == 0, would return false.







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 25 '18 at 20:58









                    Guy YogevGuy Yogev

                    43239




                    43239























                        1














                        Because 0 (as well as the empty string "") evaluates to false when cast to a Boolean, you need to explicitly check for undefined and null:






                        let a = {
                        
  key1: 'value1',
                        
  key2: 0,
                        
  key3: null
                        
}
                        

                        
function cleanProps(o) {
                        
  if (Object.prototype.toString.call(o) !== '[object Object]') return o
                        
  for (key in o) {
                        
    if([undefined, null].includes(o[key])) delete o[key]
                        
  }
                        
  return o
                        
}
                        

                        
console.log(cleanProps(a))








                        share|improve this answer




























                          1














                          Because 0 (as well as the empty string "") evaluates to false when cast to a Boolean, you need to explicitly check for undefined and null:






                          let a = {
                          
  key1: 'value1',
                          
  key2: 0,
                          
  key3: null
                          
}
                          

                          
function cleanProps(o) {
                          
  if (Object.prototype.toString.call(o) !== '[object Object]') return o
                          
  for (key in o) {
                          
    if([undefined, null].includes(o[key])) delete o[key]
                          
  }
                          
  return o
                          
}
                          

                          
console.log(cleanProps(a))








                          share|improve this answer


























                            1












                            1








                            1







                            Because 0 (as well as the empty string "") evaluates to false when cast to a Boolean, you need to explicitly check for undefined and null:






                            let a = {
                            
  key1: 'value1',
                            
  key2: 0,
                            
  key3: null
                            
}
                            

                            
function cleanProps(o) {
                            
  if (Object.prototype.toString.call(o) !== '[object Object]') return o
                            
  for (key in o) {
                            
    if([undefined, null].includes(o[key])) delete o[key]
                            
  }
                            
  return o
                            
}
                            

                            
console.log(cleanProps(a))








                            share|improve this answer













                            Because 0 (as well as the empty string "") evaluates to false when cast to a Boolean, you need to explicitly check for undefined and null:






                            let a = {
                            
  key1: 'value1',
                            
  key2: 0,
                            
  key3: null
                            
}
                            

                            
function cleanProps(o) {
                            
  if (Object.prototype.toString.call(o) !== '[object Object]') return o
                            
  for (key in o) {
                            
    if([undefined, null].includes(o[key])) delete o[key]
                            
  }
                            
  return o
                            
}
                            

                            
console.log(cleanProps(a))








                            let a = {
                            
  key1: 'value1',
                            
  key2: 0,
                            
  key3: null
                            
}
                            

                            
function cleanProps(o) {
                            
  if (Object.prototype.toString.call(o) !== '[object Object]') return o
                            
  for (key in o) {
                            
    if([undefined, null].includes(o[key])) delete o[key]
                            
  }
                            
  return o
                            
}
                            

                            
console.log(cleanProps(a))





                            let a = {
                            
  key1: 'value1',
                            
  key2: 0,
                            
  key3: null
                            
}
                            

                            
function cleanProps(o) {
                            
  if (Object.prototype.toString.call(o) !== '[object Object]') return o
                            
  for (key in o) {
                            
    if([undefined, null].includes(o[key])) delete o[key]
                            
  }
                            
  return o
                            
}
                            

                            
console.log(cleanProps(a))






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Nov 25 '18 at 21:18









                            connexoconnexo

                            22.4k83561




                            22.4k83561























                                0














                                I think that would solve your issue:



                                obj[key] !== null && obj[key] !== undefined && obj[key] !== 'delete'






                                share|improve this answer
























                                • You can just use != to catch both null and undefined

                                  – Mark Meyer
                                  Nov 25 '18 at 21:11











                                • And pick one or the other?

                                  – Kevin Amiranoff
                                  Nov 25 '18 at 21:14











                                • Yes, both undefined != null and null != undefined are false

                                  – Mark Meyer
                                  Nov 25 '18 at 21:16
















                                0














                                I think that would solve your issue:



                                obj[key] !== null && obj[key] !== undefined && obj[key] !== 'delete'






                                share|improve this answer
























                                • You can just use != to catch both null and undefined

                                  – Mark Meyer
                                  Nov 25 '18 at 21:11











                                • And pick one or the other?

                                  – Kevin Amiranoff
                                  Nov 25 '18 at 21:14











                                • Yes, both undefined != null and null != undefined are false

                                  – Mark Meyer
                                  Nov 25 '18 at 21:16














                                0












                                0








                                0







                                I think that would solve your issue:



                                obj[key] !== null && obj[key] !== undefined && obj[key] !== 'delete'






                                share|improve this answer













                                I think that would solve your issue:



                                obj[key] !== null && obj[key] !== undefined && obj[key] !== 'delete'







                                share|improve this answer












                                share|improve this answer



                                share|improve this answer










                                answered Nov 25 '18 at 21:06









                                Kevin AmiranoffKevin Amiranoff

                                2,92651338




                                2,92651338













                                • You can just use != to catch both null and undefined

                                  – Mark Meyer
                                  Nov 25 '18 at 21:11











                                • And pick one or the other?

                                  – Kevin Amiranoff
                                  Nov 25 '18 at 21:14











                                • Yes, both undefined != null and null != undefined are false

                                  – Mark Meyer
                                  Nov 25 '18 at 21:16



















                                • You can just use != to catch both null and undefined

                                  – Mark Meyer
                                  Nov 25 '18 at 21:11











                                • And pick one or the other?

                                  – Kevin Amiranoff
                                  Nov 25 '18 at 21:14











                                • Yes, both undefined != null and null != undefined are false

                                  – Mark Meyer
                                  Nov 25 '18 at 21:16

















                                You can just use != to catch both null and undefined

                                – Mark Meyer
                                Nov 25 '18 at 21:11





                                You can just use != to catch both null and undefined

                                – Mark Meyer
                                Nov 25 '18 at 21:11













                                And pick one or the other?

                                – Kevin Amiranoff
                                Nov 25 '18 at 21:14





                                And pick one or the other?

                                – Kevin Amiranoff
                                Nov 25 '18 at 21:14













                                Yes, both undefined != null and null != undefined are false

                                – Mark Meyer
                                Nov 25 '18 at 21:16





                                Yes, both undefined != null and null != undefined are false

                                – Mark Meyer
                                Nov 25 '18 at 21:16


















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