Position of element in a list within a Pandas DataFrame
2
newbie here
I've got a Pandas DataFrame that contains that contains the column crewjob as below. It looks like each row is a list.
crewjob
[Director, Screenplay, Screenplay, Screenplay,...
[Executive Producer, Screenplay, Original Musi...
[Director, Characters, Writer, Sound Recordist]
[Director, Screenplay, Producer, Producer, Pro...
[Original Music Composer, Director of Photogra...
[Director, Screenplay, Producer, Producer, Ori...
[Director, Screenplay, Producer, Original Musi...
[Screenplay, Screenplay, Director, Novel]
[Director, Screenplay, Screenplay, Producer, P...
I'd like to extract for each row the position of director within the list.
I've tried the enumerate method and it chucks out a blank list.
indices = [i for i, x in enumerate(creditsdf['crewjob']) if x == "Director"]
I've also tried the .index method
creditsdf['test'] = creditsdf['crewjob'].index("Director")
Which gives the following error;
TypeError: 'RangeIndex' object is not callable
python pandas
edited Nov 25 '18 at 14:32
Abhi
2,505320
asked Nov 25 '18 at 14:24
BilzRBilzR
294
add a comment |
2
newbie here
I've got a Pandas DataFrame that contains that contains the column crewjob as below. It looks like each row is a list.
crewjob
[Director, Screenplay, Screenplay, Screenplay,...
[Executive Producer, Screenplay, Original Musi...
[Director, Characters, Writer, Sound Recordist]
[Director, Screenplay, Producer, Producer, Pro...
[Original Music Composer, Director of Photogra...
[Director, Screenplay, Producer, Producer, Ori...
[Director, Screenplay, Producer, Original Musi...
[Screenplay, Screenplay, Director, Novel]
[Director, Screenplay, Screenplay, Producer, P...
I'd like to extract for each row the position of director within the list.
I've tried the enumerate method and it chucks out a blank list.
indices = [i for i, x in enumerate(creditsdf['crewjob']) if x == "Director"]
I've also tried the .index method
creditsdf['test'] = creditsdf['crewjob'].index("Director")
Which gives the following error;
TypeError: 'RangeIndex' object is not callable
python pandas
edited Nov 25 '18 at 14:32
Abhi
2,505320
asked Nov 25 '18 at 14:24
BilzRBilzR
294
add a comment |
2
2
2
newbie here
I've got a Pandas DataFrame that contains that contains the column crewjob as below. It looks like each row is a list.
crewjob
[Director, Screenplay, Screenplay, Screenplay,...
[Executive Producer, Screenplay, Original Musi...
[Director, Characters, Writer, Sound Recordist]
[Director, Screenplay, Producer, Producer, Pro...
[Original Music Composer, Director of Photogra...
[Director, Screenplay, Producer, Producer, Ori...
[Director, Screenplay, Producer, Original Musi...
[Screenplay, Screenplay, Director, Novel]
[Director, Screenplay, Screenplay, Producer, P...
I'd like to extract for each row the position of director within the list.
I've tried the enumerate method and it chucks out a blank list.
indices = [i for i, x in enumerate(creditsdf['crewjob']) if x == "Director"]
I've also tried the .index method
creditsdf['test'] = creditsdf['crewjob'].index("Director")
Which gives the following error;
TypeError: 'RangeIndex' object is not callable
python pandas
edited Nov 25 '18 at 14:32
Abhi
2,505320
asked Nov 25 '18 at 14:24
BilzRBilzR
294
newbie here
I've got a Pandas DataFrame that contains that contains the column crewjob as below. It looks like each row is a list.
crewjob
[Director, Screenplay, Screenplay, Screenplay,...
[Executive Producer, Screenplay, Original Musi...
[Director, Characters, Writer, Sound Recordist]
[Director, Screenplay, Producer, Producer, Pro...
[Original Music Composer, Director of Photogra...
[Director, Screenplay, Producer, Producer, Ori...
[Director, Screenplay, Producer, Original Musi...
[Screenplay, Screenplay, Director, Novel]
[Director, Screenplay, Screenplay, Producer, P...
I'd like to extract for each row the position of director within the list.
I've tried the enumerate method and it chucks out a blank list.
indices = [i for i, x in enumerate(creditsdf['crewjob']) if x == "Director"]
I've also tried the .index method
creditsdf['test'] = creditsdf['crewjob'].index("Director")
Which gives the following error;
TypeError: 'RangeIndex' object is not callable
python pandas
python pandas
edited Nov 25 '18 at 14:32
Abhi
2,505320
asked Nov 25 '18 at 14:24
BilzRBilzR
294
edited Nov 25 '18 at 14:32
Abhi
2,505320
asked Nov 25 '18 at 14:24
BilzRBilzR
294
edited Nov 25 '18 at 14:32
Abhi
2,505320
edited Nov 25 '18 at 14:32
Abhi
2,505320
edited Nov 25 '18 at 14:32
Abhi
2,505320
2,505320
asked Nov 25 '18 at 14:24
BilzRBilzR
294
asked Nov 25 '18 at 14:24
BilzRBilzR
294
asked Nov 25 '18 at 14:24
BilzRBilzR
294
294
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
0
Use nested list comprehension:
indices = [[i for i, x in enumerate(y) if x == "Director"] for y in increditsdf['crewjob']]
print (indices)
[[0], , [0], [0], , [0], [0], [2], [0]]
answered Nov 25 '18 at 14:26
jezraeljezrael
342k25297369
Thanks jezrael, the above solution works. Out of curiousity is it possible to do this with the .index method?
– BilzR
Nov 25 '18 at 14:41
@BilzR - Yes, but is necessary useindices = [find_element_in_list("Director", y) for y in increditsdf['crewjob']]from here for avoid error if not exist value in list.
– jezrael
Nov 25 '18 at 14:44
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Use nested list comprehension:
indices = [[i for i, x in enumerate(y) if x == "Director"] for y in increditsdf['crewjob']]
print (indices)
[[0], , [0], [0], , [0], [0], [2], [0]]
answered Nov 25 '18 at 14:26
jezraeljezrael
342k25297369
Thanks jezrael, the above solution works. Out of curiousity is it possible to do this with the .index method?
– BilzR
Nov 25 '18 at 14:41
@BilzR - Yes, but is necessary useindices = [find_element_in_list("Director", y) for y in increditsdf['crewjob']]from here for avoid error if not exist value in list.
– jezrael
Nov 25 '18 at 14:44
add a comment |
0
Use nested list comprehension:
indices = [[i for i, x in enumerate(y) if x == "Director"] for y in increditsdf['crewjob']]
print (indices)
[[0], , [0], [0], , [0], [0], [2], [0]]
answered Nov 25 '18 at 14:26
jezraeljezrael
342k25297369
Thanks jezrael, the above solution works. Out of curiousity is it possible to do this with the .index method?
– BilzR
Nov 25 '18 at 14:41
@BilzR - Yes, but is necessary useindices = [find_element_in_list("Director", y) for y in increditsdf['crewjob']]from here for avoid error if not exist value in list.
– jezrael
Nov 25 '18 at 14:44
add a comment |
0
0
0
Use nested list comprehension:
indices = [[i for i, x in enumerate(y) if x == "Director"] for y in increditsdf['crewjob']]
print (indices)
[[0], , [0], [0], , [0], [0], [2], [0]]
answered Nov 25 '18 at 14:26
jezraeljezrael
342k25297369
Use nested list comprehension:
indices = [[i for i, x in enumerate(y) if x == "Director"] for y in increditsdf['crewjob']]
print (indices)
[[0], , [0], [0], , [0], [0], [2], [0]]
answered Nov 25 '18 at 14:26
jezraeljezrael
342k25297369
answered Nov 25 '18 at 14:26
jezraeljezrael
342k25297369
answered Nov 25 '18 at 14:26
jezraeljezrael
342k25297369
answered Nov 25 '18 at 14:26
jezraeljezrael
342k25297369
342k25297369
Thanks jezrael, the above solution works. Out of curiousity is it possible to do this with the .index method?
– BilzR
Nov 25 '18 at 14:41
@BilzR - Yes, but is necessary useindices = [find_element_in_list("Director", y) for y in increditsdf['crewjob']]from here for avoid error if not exist value in list.
– jezrael
Nov 25 '18 at 14:44
add a comment |
Thanks jezrael, the above solution works. Out of curiousity is it possible to do this with the .index method?
– BilzR
Nov 25 '18 at 14:41
@BilzR - Yes, but is necessary useindices = [find_element_in_list("Director", y) for y in increditsdf['crewjob']]from here for avoid error if not exist value in list.
– jezrael
Nov 25 '18 at 14:44
Thanks jezrael, the above solution works. Out of curiousity is it possible to do this with the .index method?
– BilzR
Nov 25 '18 at 14:41
Thanks jezrael, the above solution works. Out of curiousity is it possible to do this with the .index method?
– BilzR
Nov 25 '18 at 14:41
@BilzR - Yes, but is necessary use
indices = [find_element_in_list("Director", y) for y in increditsdf['crewjob']] from here for avoid error if not exist value in list.– jezrael
Nov 25 '18 at 14:44
@BilzR - Yes, but is necessary use
indices = [find_element_in_list("Director", y) for y in increditsdf['crewjob']] from here for avoid error if not exist value in list.– jezrael
Nov 25 '18 at 14:44
add a comment |
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