getting nan on added column
In a dataframe rebinnedDF
, I wanted to add another column that has repeated random row values. I create that value as repeateArray
.
year2014_bin year2015_bin year2016_bin year2017_bin
0 binZ binZ binZ binZ
1 binZ binZ binZ binZ
repeateArray=[x for x in range (0, rebinnedDF.shape[0]/len(rebinnedDF.columns))]
repeateArray =rebinnedDF.join(pd.DataFrame (repeateArray))
when I do repeateArray[0][:2]
which is the added column, I get nan
. Should not that have valued based on the list comprehension above.
year2014_bin year2015_bin year2016_bin year2017_bin 0
0 binZ binZ binZ binZ nan
1 binZ binZ binZ binZ nan
4 binZ binZ binZ binZ nan
5 binZ binZ binZ binZ nan
6 binZ binZ binZ binZ nan
7 binZ binZ binZ binZ nan
8 binZ binZ binZ binZ nan
9 binZ binZ binZ binZ nan
Desired. I want `0` to be randomly repeated based on the length of the dataframe. I have 6 million rows. Number of repetition really does not matter.
year2014_bin year2015_bin year2016_bin year2017_bin 0
0 binZ binZ binZ binZ 1
1 binZ binZ binZ binZ 2
2 binZ binZ binZ binZ 3
3 binZ binZ binZ binZ 4
4 binZ binZ binZ binZ 1
.............
python pandas python-2.7
|
show 1 more comment
In a dataframe rebinnedDF
, I wanted to add another column that has repeated random row values. I create that value as repeateArray
.
year2014_bin year2015_bin year2016_bin year2017_bin
0 binZ binZ binZ binZ
1 binZ binZ binZ binZ
repeateArray=[x for x in range (0, rebinnedDF.shape[0]/len(rebinnedDF.columns))]
repeateArray =rebinnedDF.join(pd.DataFrame (repeateArray))
when I do repeateArray[0][:2]
which is the added column, I get nan
. Should not that have valued based on the list comprehension above.
year2014_bin year2015_bin year2016_bin year2017_bin 0
0 binZ binZ binZ binZ nan
1 binZ binZ binZ binZ nan
4 binZ binZ binZ binZ nan
5 binZ binZ binZ binZ nan
6 binZ binZ binZ binZ nan
7 binZ binZ binZ binZ nan
8 binZ binZ binZ binZ nan
9 binZ binZ binZ binZ nan
Desired. I want `0` to be randomly repeated based on the length of the dataframe. I have 6 million rows. Number of repetition really does not matter.
year2014_bin year2015_bin year2016_bin year2017_bin 0
0 binZ binZ binZ binZ 1
1 binZ binZ binZ binZ 2
2 binZ binZ binZ binZ 3
3 binZ binZ binZ binZ 4
4 binZ binZ binZ binZ 1
.............
python pandas python-2.7
Hi John, Just added to it. Thanks
– lpt
Nov 25 '18 at 0:16
Your code gives'float' object cannot be interpreted as an integer
. Are you really using Python 3? If your code runs, please check that what you've posted here is your actual code and not a broken version of it. Maybe the problem is your example has too few rows? Anyway what you've posted doesn't work at all.
– John Zwinck
Nov 25 '18 at 0:23
Sorry, it was Python 2.7.15. then how would append either of the datatypes in the dataframe which has randomly repeated values based on the length fo the column
– lpt
Nov 25 '18 at 0:28
reformatted with more data. Does this make more sense now?
– lpt
Nov 25 '18 at 0:35
So you're using Python 2.7 but you tagged the question with Python 3? I give up.
– John Zwinck
Nov 25 '18 at 0:40
|
show 1 more comment
In a dataframe rebinnedDF
, I wanted to add another column that has repeated random row values. I create that value as repeateArray
.
year2014_bin year2015_bin year2016_bin year2017_bin
0 binZ binZ binZ binZ
1 binZ binZ binZ binZ
repeateArray=[x for x in range (0, rebinnedDF.shape[0]/len(rebinnedDF.columns))]
repeateArray =rebinnedDF.join(pd.DataFrame (repeateArray))
when I do repeateArray[0][:2]
which is the added column, I get nan
. Should not that have valued based on the list comprehension above.
year2014_bin year2015_bin year2016_bin year2017_bin 0
0 binZ binZ binZ binZ nan
1 binZ binZ binZ binZ nan
4 binZ binZ binZ binZ nan
5 binZ binZ binZ binZ nan
6 binZ binZ binZ binZ nan
7 binZ binZ binZ binZ nan
8 binZ binZ binZ binZ nan
9 binZ binZ binZ binZ nan
Desired. I want `0` to be randomly repeated based on the length of the dataframe. I have 6 million rows. Number of repetition really does not matter.
year2014_bin year2015_bin year2016_bin year2017_bin 0
0 binZ binZ binZ binZ 1
1 binZ binZ binZ binZ 2
2 binZ binZ binZ binZ 3
3 binZ binZ binZ binZ 4
4 binZ binZ binZ binZ 1
.............
python pandas python-2.7
In a dataframe rebinnedDF
, I wanted to add another column that has repeated random row values. I create that value as repeateArray
.
year2014_bin year2015_bin year2016_bin year2017_bin
0 binZ binZ binZ binZ
1 binZ binZ binZ binZ
repeateArray=[x for x in range (0, rebinnedDF.shape[0]/len(rebinnedDF.columns))]
repeateArray =rebinnedDF.join(pd.DataFrame (repeateArray))
when I do repeateArray[0][:2]
which is the added column, I get nan
. Should not that have valued based on the list comprehension above.
year2014_bin year2015_bin year2016_bin year2017_bin 0
0 binZ binZ binZ binZ nan
1 binZ binZ binZ binZ nan
4 binZ binZ binZ binZ nan
5 binZ binZ binZ binZ nan
6 binZ binZ binZ binZ nan
7 binZ binZ binZ binZ nan
8 binZ binZ binZ binZ nan
9 binZ binZ binZ binZ nan
Desired. I want `0` to be randomly repeated based on the length of the dataframe. I have 6 million rows. Number of repetition really does not matter.
year2014_bin year2015_bin year2016_bin year2017_bin 0
0 binZ binZ binZ binZ 1
1 binZ binZ binZ binZ 2
2 binZ binZ binZ binZ 3
3 binZ binZ binZ binZ 4
4 binZ binZ binZ binZ 1
.............
python pandas python-2.7
python pandas python-2.7
edited Nov 27 '18 at 15:53
Ivan Kolesnikov
1,26111032
1,26111032
asked Nov 24 '18 at 23:55
lptlpt
335111
335111
Hi John, Just added to it. Thanks
– lpt
Nov 25 '18 at 0:16
Your code gives'float' object cannot be interpreted as an integer
. Are you really using Python 3? If your code runs, please check that what you've posted here is your actual code and not a broken version of it. Maybe the problem is your example has too few rows? Anyway what you've posted doesn't work at all.
– John Zwinck
Nov 25 '18 at 0:23
Sorry, it was Python 2.7.15. then how would append either of the datatypes in the dataframe which has randomly repeated values based on the length fo the column
– lpt
Nov 25 '18 at 0:28
reformatted with more data. Does this make more sense now?
– lpt
Nov 25 '18 at 0:35
So you're using Python 2.7 but you tagged the question with Python 3? I give up.
– John Zwinck
Nov 25 '18 at 0:40
|
show 1 more comment
Hi John, Just added to it. Thanks
– lpt
Nov 25 '18 at 0:16
Your code gives'float' object cannot be interpreted as an integer
. Are you really using Python 3? If your code runs, please check that what you've posted here is your actual code and not a broken version of it. Maybe the problem is your example has too few rows? Anyway what you've posted doesn't work at all.
– John Zwinck
Nov 25 '18 at 0:23
Sorry, it was Python 2.7.15. then how would append either of the datatypes in the dataframe which has randomly repeated values based on the length fo the column
– lpt
Nov 25 '18 at 0:28
reformatted with more data. Does this make more sense now?
– lpt
Nov 25 '18 at 0:35
So you're using Python 2.7 but you tagged the question with Python 3? I give up.
– John Zwinck
Nov 25 '18 at 0:40
Hi John, Just added to it. Thanks
– lpt
Nov 25 '18 at 0:16
Hi John, Just added to it. Thanks
– lpt
Nov 25 '18 at 0:16
Your code gives
'float' object cannot be interpreted as an integer
. Are you really using Python 3? If your code runs, please check that what you've posted here is your actual code and not a broken version of it. Maybe the problem is your example has too few rows? Anyway what you've posted doesn't work at all.– John Zwinck
Nov 25 '18 at 0:23
Your code gives
'float' object cannot be interpreted as an integer
. Are you really using Python 3? If your code runs, please check that what you've posted here is your actual code and not a broken version of it. Maybe the problem is your example has too few rows? Anyway what you've posted doesn't work at all.– John Zwinck
Nov 25 '18 at 0:23
Sorry, it was Python 2.7.15. then how would append either of the datatypes in the dataframe which has randomly repeated values based on the length fo the column
– lpt
Nov 25 '18 at 0:28
Sorry, it was Python 2.7.15. then how would append either of the datatypes in the dataframe which has randomly repeated values based on the length fo the column
– lpt
Nov 25 '18 at 0:28
reformatted with more data. Does this make more sense now?
– lpt
Nov 25 '18 at 0:35
reformatted with more data. Does this make more sense now?
– lpt
Nov 25 '18 at 0:35
So you're using Python 2.7 but you tagged the question with Python 3? I give up.
– John Zwinck
Nov 25 '18 at 0:40
So you're using Python 2.7 but you tagged the question with Python 3? I give up.
– John Zwinck
Nov 25 '18 at 0:40
|
show 1 more comment
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Hi John, Just added to it. Thanks
– lpt
Nov 25 '18 at 0:16
Your code gives
'float' object cannot be interpreted as an integer
. Are you really using Python 3? If your code runs, please check that what you've posted here is your actual code and not a broken version of it. Maybe the problem is your example has too few rows? Anyway what you've posted doesn't work at all.– John Zwinck
Nov 25 '18 at 0:23
Sorry, it was Python 2.7.15. then how would append either of the datatypes in the dataframe which has randomly repeated values based on the length fo the column
– lpt
Nov 25 '18 at 0:28
reformatted with more data. Does this make more sense now?
– lpt
Nov 25 '18 at 0:35
So you're using Python 2.7 but you tagged the question with Python 3? I give up.
– John Zwinck
Nov 25 '18 at 0:40