Remove Element from an Array
I am trying to solve this problem:
Given an array nums and a value val, remove all instances of that value in-place and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
and this is my implementation:
public int removeElement(int numbers, int value) {
int index = 0;
for(; index < numbers.length; index++) {
if(numbers[index] == value) {
boolean otherNumberPresent = false;
int j = index + 1;
for(; j < numbers.length; j++ ){
if(numbers[j] != value) {
otherNumberPresent = true;
break;
}
}
if(otherNumberPresent) {
int temp = numbers[j];
numbers[j] = numbers[index];
numbers[index] = temp;
} else {
return index;
}
}
}
return index;
}
How can I improve its execution time and also, if there is any better way of doing it?
java performance programming-challenge
add a comment |
I am trying to solve this problem:
Given an array nums and a value val, remove all instances of that value in-place and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
and this is my implementation:
public int removeElement(int numbers, int value) {
int index = 0;
for(; index < numbers.length; index++) {
if(numbers[index] == value) {
boolean otherNumberPresent = false;
int j = index + 1;
for(; j < numbers.length; j++ ){
if(numbers[j] != value) {
otherNumberPresent = true;
break;
}
}
if(otherNumberPresent) {
int temp = numbers[j];
numbers[j] = numbers[index];
numbers[index] = temp;
} else {
return index;
}
}
}
return index;
}
How can I improve its execution time and also, if there is any better way of doing it?
java performance programming-challenge
add a comment |
I am trying to solve this problem:
Given an array nums and a value val, remove all instances of that value in-place and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
and this is my implementation:
public int removeElement(int numbers, int value) {
int index = 0;
for(; index < numbers.length; index++) {
if(numbers[index] == value) {
boolean otherNumberPresent = false;
int j = index + 1;
for(; j < numbers.length; j++ ){
if(numbers[j] != value) {
otherNumberPresent = true;
break;
}
}
if(otherNumberPresent) {
int temp = numbers[j];
numbers[j] = numbers[index];
numbers[index] = temp;
} else {
return index;
}
}
}
return index;
}
How can I improve its execution time and also, if there is any better way of doing it?
java performance programming-challenge
I am trying to solve this problem:
Given an array nums and a value val, remove all instances of that value in-place and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
and this is my implementation:
public int removeElement(int numbers, int value) {
int index = 0;
for(; index < numbers.length; index++) {
if(numbers[index] == value) {
boolean otherNumberPresent = false;
int j = index + 1;
for(; j < numbers.length; j++ ){
if(numbers[j] != value) {
otherNumberPresent = true;
break;
}
}
if(otherNumberPresent) {
int temp = numbers[j];
numbers[j] = numbers[index];
numbers[index] = temp;
} else {
return index;
}
}
}
return index;
}
How can I improve its execution time and also, if there is any better way of doing it?
java performance programming-challenge
java performance programming-challenge
asked 4 mins ago
Karan Khanna
1385
1385
add a comment |
add a comment |
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