Understanding %%i and %%k in a Windows batch file
I am trying to understand a Windows batch file with the following statements:
:GetVSCommonToolsDirHelper32
@for /F "tokens=1,2*" %%i in ('reg query "%1SOFTWAREMicrosoftVisualStudioSxSVS7" /v "10.0"') DO (
@if "%%i"=="10.0" (
@SET "VS100COMNTOOLS=%%k"
)
)
I understand the %1 parameters, but what does %%i and %%k specify?
FYI, the statement is called using a label with this statement:
call :GetVSCommonToolsDirHelper32 HKCU > nul 2>&1
Any additional information about this code would be very useful too
visual-studio batch-file cmd
edited Nov 25 '18 at 1:44
phuclv
15.1k852223
asked Jan 6 '12 at 11:07
RichardRichard
9021614
add a comment |
I am trying to understand a Windows batch file with the following statements:
:GetVSCommonToolsDirHelper32
@for /F "tokens=1,2*" %%i in ('reg query "%1SOFTWAREMicrosoftVisualStudioSxSVS7" /v "10.0"') DO (
@if "%%i"=="10.0" (
@SET "VS100COMNTOOLS=%%k"
)
)
I understand the %1 parameters, but what does %%i and %%k specify?
FYI, the statement is called using a label with this statement:
call :GetVSCommonToolsDirHelper32 HKCU > nul 2>&1
Any additional information about this code would be very useful too
visual-studio batch-file cmd
edited Nov 25 '18 at 1:44
phuclv
15.1k852223
asked Jan 6 '12 at 11:07
RichardRichard
9021614
add a comment |
I am trying to understand a Windows batch file with the following statements:
:GetVSCommonToolsDirHelper32
@for /F "tokens=1,2*" %%i in ('reg query "%1SOFTWAREMicrosoftVisualStudioSxSVS7" /v "10.0"') DO (
@if "%%i"=="10.0" (
@SET "VS100COMNTOOLS=%%k"
)
)
I understand the %1 parameters, but what does %%i and %%k specify?
FYI, the statement is called using a label with this statement:
call :GetVSCommonToolsDirHelper32 HKCU > nul 2>&1
Any additional information about this code would be very useful too
visual-studio batch-file cmd
edited Nov 25 '18 at 1:44
phuclv
15.1k852223
asked Jan 6 '12 at 11:07
RichardRichard
9021614
I am trying to understand a Windows batch file with the following statements:
:GetVSCommonToolsDirHelper32
@for /F "tokens=1,2*" %%i in ('reg query "%1SOFTWAREMicrosoftVisualStudioSxSVS7" /v "10.0"') DO (
@if "%%i"=="10.0" (
@SET "VS100COMNTOOLS=%%k"
)
)
I understand the %1 parameters, but what does %%i and %%k specify?
FYI, the statement is called using a label with this statement:
call :GetVSCommonToolsDirHelper32 HKCU > nul 2>&1
Any additional information about this code would be very useful too
visual-studio batch-file cmd
visual-studio batch-file cmd
edited Nov 25 '18 at 1:44
phuclv
15.1k852223
asked Jan 6 '12 at 11:07
RichardRichard
9021614
edited Nov 25 '18 at 1:44
phuclv
15.1k852223
asked Jan 6 '12 at 11:07
RichardRichard
9021614
edited Nov 25 '18 at 1:44
phuclv
15.1k852223
edited Nov 25 '18 at 1:44
phuclv
15.1k852223
edited Nov 25 '18 at 1:44
phuclv
15.1k852223
15.1k852223
asked Jan 6 '12 at 11:07
RichardRichard
9021614
asked Jan 6 '12 at 11:07
RichardRichard
9021614
asked Jan 6 '12 at 11:07
RichardRichard
9021614
9021614
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Looks like its just the way you format modifiable variables in the FOR see http://www.computerhope.com/forhlp.htm
From that page, it seems the %%k is taken from the tokens part.
answered Jan 6 '12 at 11:25
TruanTruan
369210
Perfect! Thanks. I read the article, then ran the "reg query" statement from my dos prompt. That returns a line with 3 tokens separated by spaces which gets parsed and each token put into the variable declared by %i, then %j and %k respectively. So %%k refers to the value of the 3rd token, which is what is returned.
– Richard
Jan 6 '12 at 11:39
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Looks like its just the way you format modifiable variables in the FOR see http://www.computerhope.com/forhlp.htm
From that page, it seems the %%k is taken from the tokens part.
answered Jan 6 '12 at 11:25
TruanTruan
369210
Perfect! Thanks. I read the article, then ran the "reg query" statement from my dos prompt. That returns a line with 3 tokens separated by spaces which gets parsed and each token put into the variable declared by %i, then %j and %k respectively. So %%k refers to the value of the 3rd token, which is what is returned.
– Richard
Jan 6 '12 at 11:39
add a comment |
Looks like its just the way you format modifiable variables in the FOR see http://www.computerhope.com/forhlp.htm
From that page, it seems the %%k is taken from the tokens part.
answered Jan 6 '12 at 11:25
TruanTruan
369210
Perfect! Thanks. I read the article, then ran the "reg query" statement from my dos prompt. That returns a line with 3 tokens separated by spaces which gets parsed and each token put into the variable declared by %i, then %j and %k respectively. So %%k refers to the value of the 3rd token, which is what is returned.
– Richard
Jan 6 '12 at 11:39
add a comment |
Looks like its just the way you format modifiable variables in the FOR see http://www.computerhope.com/forhlp.htm
From that page, it seems the %%k is taken from the tokens part.
answered Jan 6 '12 at 11:25
TruanTruan
369210
Looks like its just the way you format modifiable variables in the FOR see http://www.computerhope.com/forhlp.htm
From that page, it seems the %%k is taken from the tokens part.
answered Jan 6 '12 at 11:25
TruanTruan
369210
answered Jan 6 '12 at 11:25
TruanTruan
369210
answered Jan 6 '12 at 11:25
TruanTruan
369210
answered Jan 6 '12 at 11:25
TruanTruan
369210
369210
Perfect! Thanks. I read the article, then ran the "reg query" statement from my dos prompt. That returns a line with 3 tokens separated by spaces which gets parsed and each token put into the variable declared by %i, then %j and %k respectively. So %%k refers to the value of the 3rd token, which is what is returned.
– Richard
Jan 6 '12 at 11:39
add a comment |
Perfect! Thanks. I read the article, then ran the "reg query" statement from my dos prompt. That returns a line with 3 tokens separated by spaces which gets parsed and each token put into the variable declared by %i, then %j and %k respectively. So %%k refers to the value of the 3rd token, which is what is returned.
– Richard
Jan 6 '12 at 11:39
Perfect! Thanks. I read the article, then ran the "reg query" statement from my dos prompt. That returns a line with 3 tokens separated by spaces which gets parsed and each token put into the variable declared by %i, then %j and %k respectively. So %%k refers to the value of the 3rd token, which is what is returned.
– Richard
Jan 6 '12 at 11:39
Perfect! Thanks. I read the article, then ran the "reg query" statement from my dos prompt. That returns a line with 3 tokens separated by spaces which gets parsed and each token put into the variable declared by %i, then %j and %k respectively. So %%k refers to the value of the 3rd token, which is what is returned.
– Richard
Jan 6 '12 at 11:39
add a comment |
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