My code will append a list but not print out the correct length
I'm using PyCharm and I have to append and then print out the length of the list. But instead of giving me 4 for all the elements it is giving me 2 for each separate list. I'm not sure what the issue is:
my_list = ['ABC, GHI, JKL']
print('My first list', my_list)
my_list.append('MNO')
print('My appended list', my_list)
print('My list size', len(my_list))
python list append string-length
edited Nov 25 '18 at 2:08
Michael Butscher
4,73521421
asked Nov 25 '18 at 2:07
FluffiekittyFluffiekitty
62
add a comment |
I'm using PyCharm and I have to append and then print out the length of the list. But instead of giving me 4 for all the elements it is giving me 2 for each separate list. I'm not sure what the issue is:
my_list = ['ABC, GHI, JKL']
print('My first list', my_list)
my_list.append('MNO')
print('My appended list', my_list)
print('My list size', len(my_list))
python list append string-length
edited Nov 25 '18 at 2:08
Michael Butscher
4,73521421
asked Nov 25 '18 at 2:07
FluffiekittyFluffiekitty
62
3
mylistis initialized as a list with one string element as 'ABC, GHI, JKL'
– John Anderson
Nov 25 '18 at 2:09
'ABC, GHI, JKL'is just one item inside list.
– Austin
Nov 25 '18 at 2:09
Thank you to everyone that answered!!!
– Fluffiekitty
Nov 25 '18 at 18:21
add a comment |
I'm using PyCharm and I have to append and then print out the length of the list. But instead of giving me 4 for all the elements it is giving me 2 for each separate list. I'm not sure what the issue is:
my_list = ['ABC, GHI, JKL']
print('My first list', my_list)
my_list.append('MNO')
print('My appended list', my_list)
print('My list size', len(my_list))
python list append string-length
edited Nov 25 '18 at 2:08
Michael Butscher
4,73521421
asked Nov 25 '18 at 2:07
FluffiekittyFluffiekitty
62
I'm using PyCharm and I have to append and then print out the length of the list. But instead of giving me 4 for all the elements it is giving me 2 for each separate list. I'm not sure what the issue is:
my_list = ['ABC, GHI, JKL']
print('My first list', my_list)
my_list.append('MNO')
print('My appended list', my_list)
print('My list size', len(my_list))
python list append string-length
python list append string-length
edited Nov 25 '18 at 2:08
Michael Butscher
4,73521421
asked Nov 25 '18 at 2:07
FluffiekittyFluffiekitty
62
edited Nov 25 '18 at 2:08
Michael Butscher
4,73521421
asked Nov 25 '18 at 2:07
FluffiekittyFluffiekitty
62
edited Nov 25 '18 at 2:08
Michael Butscher
4,73521421
edited Nov 25 '18 at 2:08
Michael Butscher
4,73521421
edited Nov 25 '18 at 2:08
Michael Butscher
4,73521421
4,73521421
asked Nov 25 '18 at 2:07
FluffiekittyFluffiekitty
62
asked Nov 25 '18 at 2:07
FluffiekittyFluffiekitty
62
asked Nov 25 '18 at 2:07
FluffiekittyFluffiekitty
62
62
3
mylistis initialized as a list with one string element as 'ABC, GHI, JKL'
– John Anderson
Nov 25 '18 at 2:09
'ABC, GHI, JKL'is just one item inside list.
– Austin
Nov 25 '18 at 2:09
Thank you to everyone that answered!!!
– Fluffiekitty
Nov 25 '18 at 18:21
add a comment |
3
mylistis initialized as a list with one string element as 'ABC, GHI, JKL'
– John Anderson
Nov 25 '18 at 2:09
'ABC, GHI, JKL'is just one item inside list.
– Austin
Nov 25 '18 at 2:09
Thank you to everyone that answered!!!
– Fluffiekitty
Nov 25 '18 at 18:21
3
3
mylist is initialized as a list with one string element as 'ABC, GHI, JKL'– John Anderson
Nov 25 '18 at 2:09
mylist is initialized as a list with one string element as 'ABC, GHI, JKL'– John Anderson
Nov 25 '18 at 2:09
'ABC, GHI, JKL' is just one item inside list.– Austin
Nov 25 '18 at 2:09
'ABC, GHI, JKL' is just one item inside list.– Austin
Nov 25 '18 at 2:09
Thank you to everyone that answered!!!
– Fluffiekitty
Nov 25 '18 at 18:21
Thank you to everyone that answered!!!
– Fluffiekitty
Nov 25 '18 at 18:21
add a comment |
3 Answers
3
active
oldest
votes
my_list is a list of one element, because the container is 'ABC, GHI, JKL' which is one string.
So you need a list with three elements at start as ['ABC', 'GHI', 'JKL'].
Then your code will work as expected.
The output of the code would be:
My first list ['ABC', 'GHI', 'JKL']
My appended list ['ABC', 'GHI', 'JKL', 'MNO']
My list size 4
Which is as desired.
answered Nov 25 '18 at 2:12
U9-ForwardU9-Forward
15.6k41540
add a comment |
my_list originally has only one element (notice the start and end of quotes). If there is only one pair of quotes and no other elements as integers or floats, there is only one element in list.
To get a 4 output, you need to split your first element on ', ', like so:
my_list = ['ABC, GHI, JKL']
my_list = my_list[0].split(', ') # <---
print('My first list', my_list)
my_list.append('MNO')
print('My appended list', my_list)
print('My list size', len(my_list))
answered Nov 25 '18 at 2:15
AustinAustin
11k3828
add a comment |
Your code absolutly works correct,
The reason you got 2 as output is that you have given Items as a single string into your list, it means your list has single item of 'ABC, GHI, JKL' and then you append your second list item 'MNO'. Meanwhile should you correct your list at first line, sprating each item using , or using ' within , sperators.
my_list = ['ABC', 'GHI', 'JKL']
len(my_list)
3
my_list.append('MNO')
len(my_list)
4
answered Nov 25 '18 at 2:42
Ashkan KamyabAshkan Kamyab
702
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
my_list is a list of one element, because the container is 'ABC, GHI, JKL' which is one string.
So you need a list with three elements at start as ['ABC', 'GHI', 'JKL'].
Then your code will work as expected.
The output of the code would be:
My first list ['ABC', 'GHI', 'JKL']
My appended list ['ABC', 'GHI', 'JKL', 'MNO']
My list size 4
Which is as desired.
answered Nov 25 '18 at 2:12
U9-ForwardU9-Forward
15.6k41540
add a comment |
my_list is a list of one element, because the container is 'ABC, GHI, JKL' which is one string.
So you need a list with three elements at start as ['ABC', 'GHI', 'JKL'].
Then your code will work as expected.
The output of the code would be:
My first list ['ABC', 'GHI', 'JKL']
My appended list ['ABC', 'GHI', 'JKL', 'MNO']
My list size 4
Which is as desired.
answered Nov 25 '18 at 2:12
U9-ForwardU9-Forward
15.6k41540
add a comment |
my_list is a list of one element, because the container is 'ABC, GHI, JKL' which is one string.
So you need a list with three elements at start as ['ABC', 'GHI', 'JKL'].
Then your code will work as expected.
The output of the code would be:
My first list ['ABC', 'GHI', 'JKL']
My appended list ['ABC', 'GHI', 'JKL', 'MNO']
My list size 4
Which is as desired.
answered Nov 25 '18 at 2:12
U9-ForwardU9-Forward
15.6k41540
my_list is a list of one element, because the container is 'ABC, GHI, JKL' which is one string.
So you need a list with three elements at start as ['ABC', 'GHI', 'JKL'].
Then your code will work as expected.
The output of the code would be:
My first list ['ABC', 'GHI', 'JKL']
My appended list ['ABC', 'GHI', 'JKL', 'MNO']
My list size 4
Which is as desired.
answered Nov 25 '18 at 2:12
U9-ForwardU9-Forward
15.6k41540
answered Nov 25 '18 at 2:12
U9-ForwardU9-Forward
15.6k41540
answered Nov 25 '18 at 2:12
U9-ForwardU9-Forward
15.6k41540
answered Nov 25 '18 at 2:12
U9-ForwardU9-Forward
15.6k41540
15.6k41540
add a comment |
add a comment |
my_list originally has only one element (notice the start and end of quotes). If there is only one pair of quotes and no other elements as integers or floats, there is only one element in list.
To get a 4 output, you need to split your first element on ', ', like so:
my_list = ['ABC, GHI, JKL']
my_list = my_list[0].split(', ') # <---
print('My first list', my_list)
my_list.append('MNO')
print('My appended list', my_list)
print('My list size', len(my_list))
answered Nov 25 '18 at 2:15
AustinAustin
11k3828
add a comment |
my_list originally has only one element (notice the start and end of quotes). If there is only one pair of quotes and no other elements as integers or floats, there is only one element in list.
To get a 4 output, you need to split your first element on ', ', like so:
my_list = ['ABC, GHI, JKL']
my_list = my_list[0].split(', ') # <---
print('My first list', my_list)
my_list.append('MNO')
print('My appended list', my_list)
print('My list size', len(my_list))
answered Nov 25 '18 at 2:15
AustinAustin
11k3828
add a comment |
my_list originally has only one element (notice the start and end of quotes). If there is only one pair of quotes and no other elements as integers or floats, there is only one element in list.
To get a 4 output, you need to split your first element on ', ', like so:
my_list = ['ABC, GHI, JKL']
my_list = my_list[0].split(', ') # <---
print('My first list', my_list)
my_list.append('MNO')
print('My appended list', my_list)
print('My list size', len(my_list))
answered Nov 25 '18 at 2:15
AustinAustin
11k3828
my_list originally has only one element (notice the start and end of quotes). If there is only one pair of quotes and no other elements as integers or floats, there is only one element in list.
To get a 4 output, you need to split your first element on ', ', like so:
my_list = ['ABC, GHI, JKL']
my_list = my_list[0].split(', ') # <---
print('My first list', my_list)
my_list.append('MNO')
print('My appended list', my_list)
print('My list size', len(my_list))
answered Nov 25 '18 at 2:15
AustinAustin
11k3828
answered Nov 25 '18 at 2:15
AustinAustin
11k3828
answered Nov 25 '18 at 2:15
AustinAustin
11k3828
answered Nov 25 '18 at 2:15
AustinAustin
11k3828
11k3828
add a comment |
add a comment |
Your code absolutly works correct,
The reason you got 2 as output is that you have given Items as a single string into your list, it means your list has single item of 'ABC, GHI, JKL' and then you append your second list item 'MNO'. Meanwhile should you correct your list at first line, sprating each item using , or using ' within , sperators.
my_list = ['ABC', 'GHI', 'JKL']
len(my_list)
3
my_list.append('MNO')
len(my_list)
4
answered Nov 25 '18 at 2:42
Ashkan KamyabAshkan Kamyab
702
add a comment |
Your code absolutly works correct,
The reason you got 2 as output is that you have given Items as a single string into your list, it means your list has single item of 'ABC, GHI, JKL' and then you append your second list item 'MNO'. Meanwhile should you correct your list at first line, sprating each item using , or using ' within , sperators.
my_list = ['ABC', 'GHI', 'JKL']
len(my_list)
3
my_list.append('MNO')
len(my_list)
4
answered Nov 25 '18 at 2:42
Ashkan KamyabAshkan Kamyab
702
add a comment |
Your code absolutly works correct,
The reason you got 2 as output is that you have given Items as a single string into your list, it means your list has single item of 'ABC, GHI, JKL' and then you append your second list item 'MNO'. Meanwhile should you correct your list at first line, sprating each item using , or using ' within , sperators.
my_list = ['ABC', 'GHI', 'JKL']
len(my_list)
3
my_list.append('MNO')
len(my_list)
4
answered Nov 25 '18 at 2:42
Ashkan KamyabAshkan Kamyab
702
Your code absolutly works correct,
The reason you got 2 as output is that you have given Items as a single string into your list, it means your list has single item of 'ABC, GHI, JKL' and then you append your second list item 'MNO'. Meanwhile should you correct your list at first line, sprating each item using , or using ' within , sperators.
my_list = ['ABC', 'GHI', 'JKL']
len(my_list)
3
my_list.append('MNO')
len(my_list)
4
answered Nov 25 '18 at 2:42
Ashkan KamyabAshkan Kamyab
702
answered Nov 25 '18 at 2:42
Ashkan KamyabAshkan Kamyab
702
answered Nov 25 '18 at 2:42
Ashkan KamyabAshkan Kamyab
702
answered Nov 25 '18 at 2:42
Ashkan KamyabAshkan Kamyab
702
702
add a comment |
add a comment |
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3
mylistis initialized as a list with one string element as 'ABC, GHI, JKL'– John Anderson
Nov 25 '18 at 2:09
'ABC, GHI, JKL'is just one item inside list.– Austin
Nov 25 '18 at 2:09
Thank you to everyone that answered!!!
– Fluffiekitty
Nov 25 '18 at 18:21