Visual Basic bind checkbox check state to application setting at runtime
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I would like to add a checkbox control to a form at runtime. I can accomplish that, but I would also like to bind the "Checked" property to an application setting that is already created.
The code I have so far is below. When I run an exception is raised: "Cannot bind to the property or column Checked on the DataSource"
What am I doing wrong?
Dim CurrentCheckBox As New CheckBox
Dim TableColumn As Integer = 4
Dim TableRow As Integer = 13
CurrentCheckBox.Name = "MyCheckbox"
CurrentCheckBox.Text = ""
CurrentCheckBox.Anchor = AnchorStyles.Bottom Or AnchorStyles.Top
CurrentCheckBox.AutoSize = True
CurrentCheckBox.DataBindings.Add(New System.Windows.Forms.Binding("Checked",
My.Settings.MyCheckboxIsChecked, "Checked"))
MyTableLayoutPanel.Controls.Add(CurrentCheckBox, TableColumn, TableRow)
vb.net
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up vote
0
down vote
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I would like to add a checkbox control to a form at runtime. I can accomplish that, but I would also like to bind the "Checked" property to an application setting that is already created.
The code I have so far is below. When I run an exception is raised: "Cannot bind to the property or column Checked on the DataSource"
What am I doing wrong?
Dim CurrentCheckBox As New CheckBox
Dim TableColumn As Integer = 4
Dim TableRow As Integer = 13
CurrentCheckBox.Name = "MyCheckbox"
CurrentCheckBox.Text = ""
CurrentCheckBox.Anchor = AnchorStyles.Bottom Or AnchorStyles.Top
CurrentCheckBox.AutoSize = True
CurrentCheckBox.DataBindings.Add(New System.Windows.Forms.Binding("Checked",
My.Settings.MyCheckboxIsChecked, "Checked"))
MyTableLayoutPanel.Controls.Add(CurrentCheckBox, TableColumn, TableRow)
vb.net
1
I guess theBindingshould beNew System.Windows.Forms.Binding("Checked", My.Settings, "MyCheckboxIsChecked")...
– sloth
Nov 20 at 14:43
YourBindingconstructor is redundant. TheAddmethod will accept the same arguments directly. In situations like this, the best option is to do the same thing in the designer, i.e. add aCheckBoxand bind it to s setting, then see what code is generated. You can then use the same pattern, cleaning it up if appropriate.
– jmcilhinney
Nov 20 at 21:56
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I would like to add a checkbox control to a form at runtime. I can accomplish that, but I would also like to bind the "Checked" property to an application setting that is already created.
The code I have so far is below. When I run an exception is raised: "Cannot bind to the property or column Checked on the DataSource"
What am I doing wrong?
Dim CurrentCheckBox As New CheckBox
Dim TableColumn As Integer = 4
Dim TableRow As Integer = 13
CurrentCheckBox.Name = "MyCheckbox"
CurrentCheckBox.Text = ""
CurrentCheckBox.Anchor = AnchorStyles.Bottom Or AnchorStyles.Top
CurrentCheckBox.AutoSize = True
CurrentCheckBox.DataBindings.Add(New System.Windows.Forms.Binding("Checked",
My.Settings.MyCheckboxIsChecked, "Checked"))
MyTableLayoutPanel.Controls.Add(CurrentCheckBox, TableColumn, TableRow)
vb.net
I would like to add a checkbox control to a form at runtime. I can accomplish that, but I would also like to bind the "Checked" property to an application setting that is already created.
The code I have so far is below. When I run an exception is raised: "Cannot bind to the property or column Checked on the DataSource"
What am I doing wrong?
Dim CurrentCheckBox As New CheckBox
Dim TableColumn As Integer = 4
Dim TableRow As Integer = 13
CurrentCheckBox.Name = "MyCheckbox"
CurrentCheckBox.Text = ""
CurrentCheckBox.Anchor = AnchorStyles.Bottom Or AnchorStyles.Top
CurrentCheckBox.AutoSize = True
CurrentCheckBox.DataBindings.Add(New System.Windows.Forms.Binding("Checked",
My.Settings.MyCheckboxIsChecked, "Checked"))
MyTableLayoutPanel.Controls.Add(CurrentCheckBox, TableColumn, TableRow)
vb.net
vb.net
asked Nov 20 at 14:29
fooj
13
13
1
I guess theBindingshould beNew System.Windows.Forms.Binding("Checked", My.Settings, "MyCheckboxIsChecked")...
– sloth
Nov 20 at 14:43
YourBindingconstructor is redundant. TheAddmethod will accept the same arguments directly. In situations like this, the best option is to do the same thing in the designer, i.e. add aCheckBoxand bind it to s setting, then see what code is generated. You can then use the same pattern, cleaning it up if appropriate.
– jmcilhinney
Nov 20 at 21:56
add a comment |
1
I guess theBindingshould beNew System.Windows.Forms.Binding("Checked", My.Settings, "MyCheckboxIsChecked")...
– sloth
Nov 20 at 14:43
YourBindingconstructor is redundant. TheAddmethod will accept the same arguments directly. In situations like this, the best option is to do the same thing in the designer, i.e. add aCheckBoxand bind it to s setting, then see what code is generated. You can then use the same pattern, cleaning it up if appropriate.
– jmcilhinney
Nov 20 at 21:56
1
1
I guess the
Binding should be New System.Windows.Forms.Binding("Checked", My.Settings, "MyCheckboxIsChecked")...– sloth
Nov 20 at 14:43
I guess the
Binding should be New System.Windows.Forms.Binding("Checked", My.Settings, "MyCheckboxIsChecked")...– sloth
Nov 20 at 14:43
Your
Binding constructor is redundant. The Add method will accept the same arguments directly. In situations like this, the best option is to do the same thing in the designer, i.e. add a CheckBox and bind it to s setting, then see what code is generated. You can then use the same pattern, cleaning it up if appropriate.– jmcilhinney
Nov 20 at 21:56
Your
Binding constructor is redundant. The Add method will accept the same arguments directly. In situations like this, the best option is to do the same thing in the designer, i.e. add a CheckBox and bind it to s setting, then see what code is generated. You can then use the same pattern, cleaning it up if appropriate.– jmcilhinney
Nov 20 at 21:56
add a comment |
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1
I guess the
Bindingshould beNew System.Windows.Forms.Binding("Checked", My.Settings, "MyCheckboxIsChecked")...– sloth
Nov 20 at 14:43
Your
Bindingconstructor is redundant. TheAddmethod will accept the same arguments directly. In situations like this, the best option is to do the same thing in the designer, i.e. add aCheckBoxand bind it to s setting, then see what code is generated. You can then use the same pattern, cleaning it up if appropriate.– jmcilhinney
Nov 20 at 21:56