How can I rewrite this to give me a list of answers?
I am new to python and programming, any help would be much appreciated! I am having trouble with a piece of coding I am writing in Python. My task is to write a function to calculate the number of times a particular letter appears divided by the total number of letters in that sequence.
My function is supposed to return a list with the fraction of letters for each sequence.
def calculate_let(sequences, letter):
calculate_letNew =
for seq in sequences:
len(seq)
calculate_letNew = seq.count(letter)/len(seq)
return calculate_letNew
This is my code so far. The output gives me a fraction for only one sequence even tough the list sequenceA
has four sequences.
Letter_A = calculate_let(sequenceA, 'A')
print(Letter_A)
output: 0.10273972602739725
I have been trying my hardest to try and solve this problem, but quite honestly don't know where to start.
python
add a comment |
I am new to python and programming, any help would be much appreciated! I am having trouble with a piece of coding I am writing in Python. My task is to write a function to calculate the number of times a particular letter appears divided by the total number of letters in that sequence.
My function is supposed to return a list with the fraction of letters for each sequence.
def calculate_let(sequences, letter):
calculate_letNew =
for seq in sequences:
len(seq)
calculate_letNew = seq.count(letter)/len(seq)
return calculate_letNew
This is my code so far. The output gives me a fraction for only one sequence even tough the list sequenceA
has four sequences.
Letter_A = calculate_let(sequenceA, 'A')
print(Letter_A)
output: 0.10273972602739725
I have been trying my hardest to try and solve this problem, but quite honestly don't know where to start.
python
4
Please fix your indentation. Badly indented Python is not a Minimal, Complete, and Verifiable example.
– khelwood
Nov 20 at 23:03
add a comment |
I am new to python and programming, any help would be much appreciated! I am having trouble with a piece of coding I am writing in Python. My task is to write a function to calculate the number of times a particular letter appears divided by the total number of letters in that sequence.
My function is supposed to return a list with the fraction of letters for each sequence.
def calculate_let(sequences, letter):
calculate_letNew =
for seq in sequences:
len(seq)
calculate_letNew = seq.count(letter)/len(seq)
return calculate_letNew
This is my code so far. The output gives me a fraction for only one sequence even tough the list sequenceA
has four sequences.
Letter_A = calculate_let(sequenceA, 'A')
print(Letter_A)
output: 0.10273972602739725
I have been trying my hardest to try and solve this problem, but quite honestly don't know where to start.
python
I am new to python and programming, any help would be much appreciated! I am having trouble with a piece of coding I am writing in Python. My task is to write a function to calculate the number of times a particular letter appears divided by the total number of letters in that sequence.
My function is supposed to return a list with the fraction of letters for each sequence.
def calculate_let(sequences, letter):
calculate_letNew =
for seq in sequences:
len(seq)
calculate_letNew = seq.count(letter)/len(seq)
return calculate_letNew
This is my code so far. The output gives me a fraction for only one sequence even tough the list sequenceA
has four sequences.
Letter_A = calculate_let(sequenceA, 'A')
print(Letter_A)
output: 0.10273972602739725
I have been trying my hardest to try and solve this problem, but quite honestly don't know where to start.
python
python
edited Nov 21 at 4:59
asked Nov 20 at 23:01
user10682340
4
Please fix your indentation. Badly indented Python is not a Minimal, Complete, and Verifiable example.
– khelwood
Nov 20 at 23:03
add a comment |
4
Please fix your indentation. Badly indented Python is not a Minimal, Complete, and Verifiable example.
– khelwood
Nov 20 at 23:03
4
4
Please fix your indentation. Badly indented Python is not a Minimal, Complete, and Verifiable example.
– khelwood
Nov 20 at 23:03
Please fix your indentation. Badly indented Python is not a Minimal, Complete, and Verifiable example.
– khelwood
Nov 20 at 23:03
add a comment |
2 Answers
2
active
oldest
votes
I think you meant to make a list of them like this:
Notice the list.append
method will add an element to the list.
def count_lett(sequences, AminoAcid):
count_lettNew =
for seq in sequences:
count_lettNew.append(seq.count(AminoAcid)/len(seq))
return count_lettNew
As random advice:
Python only uses the TitleCase for class names, so I would choose to write the code like this (keeping the forloop
for simplicity):
def count_lett(sequences, amino_acid):
counts = # Although, you may consider something like fracs
# for "fractions" since these aren't actually counts
for seq in sequences:
counts.append(seq.count(amino_acid)/len(seq))
return counts
add a comment |
You could do it in a very readable and concise way using a list comprehension:
def calc_freqs(sequences, letter):
return [seq.count(letter)/len(seq) for seq in sequences]
sequenceA = 'ALABAMA', 'MISSISSIPPI', 'UTAH', 'IDAHO'
letterA = calc_freqs(sequenceA, 'A')
print(letterA) # -> [0.5714285714285714, 0.0, 0.25, 0.2]
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think you meant to make a list of them like this:
Notice the list.append
method will add an element to the list.
def count_lett(sequences, AminoAcid):
count_lettNew =
for seq in sequences:
count_lettNew.append(seq.count(AminoAcid)/len(seq))
return count_lettNew
As random advice:
Python only uses the TitleCase for class names, so I would choose to write the code like this (keeping the forloop
for simplicity):
def count_lett(sequences, amino_acid):
counts = # Although, you may consider something like fracs
# for "fractions" since these aren't actually counts
for seq in sequences:
counts.append(seq.count(amino_acid)/len(seq))
return counts
add a comment |
I think you meant to make a list of them like this:
Notice the list.append
method will add an element to the list.
def count_lett(sequences, AminoAcid):
count_lettNew =
for seq in sequences:
count_lettNew.append(seq.count(AminoAcid)/len(seq))
return count_lettNew
As random advice:
Python only uses the TitleCase for class names, so I would choose to write the code like this (keeping the forloop
for simplicity):
def count_lett(sequences, amino_acid):
counts = # Although, you may consider something like fracs
# for "fractions" since these aren't actually counts
for seq in sequences:
counts.append(seq.count(amino_acid)/len(seq))
return counts
add a comment |
I think you meant to make a list of them like this:
Notice the list.append
method will add an element to the list.
def count_lett(sequences, AminoAcid):
count_lettNew =
for seq in sequences:
count_lettNew.append(seq.count(AminoAcid)/len(seq))
return count_lettNew
As random advice:
Python only uses the TitleCase for class names, so I would choose to write the code like this (keeping the forloop
for simplicity):
def count_lett(sequences, amino_acid):
counts = # Although, you may consider something like fracs
# for "fractions" since these aren't actually counts
for seq in sequences:
counts.append(seq.count(amino_acid)/len(seq))
return counts
I think you meant to make a list of them like this:
Notice the list.append
method will add an element to the list.
def count_lett(sequences, AminoAcid):
count_lettNew =
for seq in sequences:
count_lettNew.append(seq.count(AminoAcid)/len(seq))
return count_lettNew
As random advice:
Python only uses the TitleCase for class names, so I would choose to write the code like this (keeping the forloop
for simplicity):
def count_lett(sequences, amino_acid):
counts = # Although, you may consider something like fracs
# for "fractions" since these aren't actually counts
for seq in sequences:
counts.append(seq.count(amino_acid)/len(seq))
return counts
edited Nov 20 at 23:15
answered Nov 20 at 23:09
Stephen Cowley
1,099417
1,099417
add a comment |
add a comment |
You could do it in a very readable and concise way using a list comprehension:
def calc_freqs(sequences, letter):
return [seq.count(letter)/len(seq) for seq in sequences]
sequenceA = 'ALABAMA', 'MISSISSIPPI', 'UTAH', 'IDAHO'
letterA = calc_freqs(sequenceA, 'A')
print(letterA) # -> [0.5714285714285714, 0.0, 0.25, 0.2]
add a comment |
You could do it in a very readable and concise way using a list comprehension:
def calc_freqs(sequences, letter):
return [seq.count(letter)/len(seq) for seq in sequences]
sequenceA = 'ALABAMA', 'MISSISSIPPI', 'UTAH', 'IDAHO'
letterA = calc_freqs(sequenceA, 'A')
print(letterA) # -> [0.5714285714285714, 0.0, 0.25, 0.2]
add a comment |
You could do it in a very readable and concise way using a list comprehension:
def calc_freqs(sequences, letter):
return [seq.count(letter)/len(seq) for seq in sequences]
sequenceA = 'ALABAMA', 'MISSISSIPPI', 'UTAH', 'IDAHO'
letterA = calc_freqs(sequenceA, 'A')
print(letterA) # -> [0.5714285714285714, 0.0, 0.25, 0.2]
You could do it in a very readable and concise way using a list comprehension:
def calc_freqs(sequences, letter):
return [seq.count(letter)/len(seq) for seq in sequences]
sequenceA = 'ALABAMA', 'MISSISSIPPI', 'UTAH', 'IDAHO'
letterA = calc_freqs(sequenceA, 'A')
print(letterA) # -> [0.5714285714285714, 0.0, 0.25, 0.2]
edited Nov 21 at 6:56
answered Nov 21 at 1:04
martineau
65.6k988177
65.6k988177
add a comment |
add a comment |
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4
Please fix your indentation. Badly indented Python is not a Minimal, Complete, and Verifiable example.
– khelwood
Nov 20 at 23:03