Printing integers with spaces between the digits
-1
$begingroup$
Problem: Given an integer between 1 and 32767 print the individual digits with 2 spaces between them.
I am using C How To Program but this is not homework. The book has not gotten to arrays or anything more complicated than looping structures and function. I try to avoid using those structures and concepts that have not been introduced yet. I get the digits to separate and output. I was wondering if there is a better way to do this using the tools I have.
My Code:
//-----------------------------------------------------------------------------
// Program: EX5_22.c - Separating Digits
// Programmer: Joseph Cunningham
// Class: CsC_20 - c
// Date: 2/16/19
//
// This program will prompt the user for a number from 1 - 32767. It will then
// output that number separated into its constituent digits with 2 spaces
// between each digit
//-----------------------------------------------------------------------------
#include<stdio.h>
#include<math.h>
int getNumLength(int number);
void separate(int number, int power); // Fucntion prototype
int main (void)
{
// Variable declaration
int number; // User entered number to digitize
int power; // Power to generate divisor
// Prompt user for number
printf("Please input a number (1-32767): ");
scanf("%d", &number);
// Get the power for the divisor
power = getNumLength(number);
// Output digits
separate(number, power);
return 0;
}
//-----------------------------------------------------------------------------
// Function: getPower(number) - counts the number of digits in the number to
// generate a power
// Input: int number - the user entered number
// Output: none
// Return value - length of thr number
//-----------------------------------------------------------------------------
int getNumLength(int number)
{
int length; // the length of number
while (number != 0)
{
number = number / 10;
length++;
}
return length;
}
//-----------------------------------------------------------------------------
// Function: separate(number) - separates and displays an integer between 1
// -32767 into its digits
// Input: int number - intger betwenn 1 - 32767, int power - power for divisor
// Output: numbers digits separated by 2 spaces
// Return value: none
//-----------------------------------------------------------------------------
void separate(int number, int power)
{
int divisor; // the divisor from power
int i; // loop counter
for(i = power - 1; i >=0; i--)
{
divisor = (int)pow(10, i);
printf("%d ", number / divisor);
number = number % divisor;
}
}
beginner c formatting
edited 17 mins ago
200_success
129k15153415
asked 3 hours ago
JayJay
63
New contributor
Jay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
-1
$begingroup$
Problem: Given an integer between 1 and 32767 print the individual digits with 2 spaces between them.
I am using C How To Program but this is not homework. The book has not gotten to arrays or anything more complicated than looping structures and function. I try to avoid using those structures and concepts that have not been introduced yet. I get the digits to separate and output. I was wondering if there is a better way to do this using the tools I have.
My Code:
//-----------------------------------------------------------------------------
// Program: EX5_22.c - Separating Digits
// Programmer: Joseph Cunningham
// Class: CsC_20 - c
// Date: 2/16/19
//
// This program will prompt the user for a number from 1 - 32767. It will then
// output that number separated into its constituent digits with 2 spaces
// between each digit
//-----------------------------------------------------------------------------
#include<stdio.h>
#include<math.h>
int getNumLength(int number);
void separate(int number, int power); // Fucntion prototype
int main (void)
{
// Variable declaration
int number; // User entered number to digitize
int power; // Power to generate divisor
// Prompt user for number
printf("Please input a number (1-32767): ");
scanf("%d", &number);
// Get the power for the divisor
power = getNumLength(number);
// Output digits
separate(number, power);
return 0;
}
//-----------------------------------------------------------------------------
// Function: getPower(number) - counts the number of digits in the number to
// generate a power
// Input: int number - the user entered number
// Output: none
// Return value - length of thr number
//-----------------------------------------------------------------------------
int getNumLength(int number)
{
int length; // the length of number
while (number != 0)
{
number = number / 10;
length++;
}
return length;
}
//-----------------------------------------------------------------------------
// Function: separate(number) - separates and displays an integer between 1
// -32767 into its digits
// Input: int number - intger betwenn 1 - 32767, int power - power for divisor
// Output: numbers digits separated by 2 spaces
// Return value: none
//-----------------------------------------------------------------------------
void separate(int number, int power)
{
int divisor; // the divisor from power
int i; // loop counter
for(i = power - 1; i >=0; i--)
{
divisor = (int)pow(10, i);
printf("%d ", number / divisor);
number = number % divisor;
}
}
beginner c formatting
edited 17 mins ago
200_success
129k15153415
asked 3 hours ago
JayJay
63
New contributor
Jay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Looks interesting (Iscasemore complicated than looping?). But, as the code is known not to work as intended, it is off topic here.
$endgroup$
– greybeard
2 hours ago
$begingroup$
I'll change the code above to one that works as intended but may need optimizing?
$endgroup$
– Jay
2 hours ago
$begingroup$
Sounds promising: Welcome to Code Review! Even if your post gets closed before you're done, it will be bound to be re-opened once fixed. (Closing would be for the better: it is an indication that the question is not in a state to be answered.) Note that you should not alter your code a considerable time after posting, and are forbidden to so in a way that invalidates answers.
$endgroup$
– greybeard
2 hours ago
2
$begingroup$
Can I take it down and try again later?
$endgroup$
– Jay
2 hours ago
$begingroup$
Yes, of course. Removing content that is useful for others is frowned upon, but possible, too.
$endgroup$
– greybeard
2 hours ago
add a comment |
-1
-1
-1
$begingroup$
Problem: Given an integer between 1 and 32767 print the individual digits with 2 spaces between them.
I am using C How To Program but this is not homework. The book has not gotten to arrays or anything more complicated than looping structures and function. I try to avoid using those structures and concepts that have not been introduced yet. I get the digits to separate and output. I was wondering if there is a better way to do this using the tools I have.
My Code:
//-----------------------------------------------------------------------------
// Program: EX5_22.c - Separating Digits
// Programmer: Joseph Cunningham
// Class: CsC_20 - c
// Date: 2/16/19
//
// This program will prompt the user for a number from 1 - 32767. It will then
// output that number separated into its constituent digits with 2 spaces
// between each digit
//-----------------------------------------------------------------------------
#include<stdio.h>
#include<math.h>
int getNumLength(int number);
void separate(int number, int power); // Fucntion prototype
int main (void)
{
// Variable declaration
int number; // User entered number to digitize
int power; // Power to generate divisor
// Prompt user for number
printf("Please input a number (1-32767): ");
scanf("%d", &number);
// Get the power for the divisor
power = getNumLength(number);
// Output digits
separate(number, power);
return 0;
}
//-----------------------------------------------------------------------------
// Function: getPower(number) - counts the number of digits in the number to
// generate a power
// Input: int number - the user entered number
// Output: none
// Return value - length of thr number
//-----------------------------------------------------------------------------
int getNumLength(int number)
{
int length; // the length of number
while (number != 0)
{
number = number / 10;
length++;
}
return length;
}
//-----------------------------------------------------------------------------
// Function: separate(number) - separates and displays an integer between 1
// -32767 into its digits
// Input: int number - intger betwenn 1 - 32767, int power - power for divisor
// Output: numbers digits separated by 2 spaces
// Return value: none
//-----------------------------------------------------------------------------
void separate(int number, int power)
{
int divisor; // the divisor from power
int i; // loop counter
for(i = power - 1; i >=0; i--)
{
divisor = (int)pow(10, i);
printf("%d ", number / divisor);
number = number % divisor;
}
}
beginner c formatting
edited 17 mins ago
200_success
129k15153415
asked 3 hours ago
JayJay
63
New contributor
Jay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Problem: Given an integer between 1 and 32767 print the individual digits with 2 spaces between them.
I am using C How To Program but this is not homework. The book has not gotten to arrays or anything more complicated than looping structures and function. I try to avoid using those structures and concepts that have not been introduced yet. I get the digits to separate and output. I was wondering if there is a better way to do this using the tools I have.
My Code:
//-----------------------------------------------------------------------------
// Program: EX5_22.c - Separating Digits
// Programmer: Joseph Cunningham
// Class: CsC_20 - c
// Date: 2/16/19
//
// This program will prompt the user for a number from 1 - 32767. It will then
// output that number separated into its constituent digits with 2 spaces
// between each digit
//-----------------------------------------------------------------------------
#include<stdio.h>
#include<math.h>
int getNumLength(int number);
void separate(int number, int power); // Fucntion prototype
int main (void)
{
// Variable declaration
int number; // User entered number to digitize
int power; // Power to generate divisor
// Prompt user for number
printf("Please input a number (1-32767): ");
scanf("%d", &number);
// Get the power for the divisor
power = getNumLength(number);
// Output digits
separate(number, power);
return 0;
}
//-----------------------------------------------------------------------------
// Function: getPower(number) - counts the number of digits in the number to
// generate a power
// Input: int number - the user entered number
// Output: none
// Return value - length of thr number
//-----------------------------------------------------------------------------
int getNumLength(int number)
{
int length; // the length of number
while (number != 0)
{
number = number / 10;
length++;
}
return length;
}
//-----------------------------------------------------------------------------
// Function: separate(number) - separates and displays an integer between 1
// -32767 into its digits
// Input: int number - intger betwenn 1 - 32767, int power - power for divisor
// Output: numbers digits separated by 2 spaces
// Return value: none
//-----------------------------------------------------------------------------
void separate(int number, int power)
{
int divisor; // the divisor from power
int i; // loop counter
for(i = power - 1; i >=0; i--)
{
divisor = (int)pow(10, i);
printf("%d ", number / divisor);
number = number % divisor;
}
}
beginner c formatting
beginner c formatting
edited 17 mins ago
200_success
129k15153415
asked 3 hours ago
JayJay
63
New contributor
Jay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 17 mins ago
200_success
129k15153415
asked 3 hours ago
JayJay
63
New contributor
Jay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 17 mins ago
200_success
129k15153415
edited 17 mins ago
200_success
129k15153415
edited 17 mins ago
200_success
129k15153415
129k15153415
asked 3 hours ago
JayJay
63
New contributor
Jay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
JayJay
63
asked 3 hours ago
JayJay
63
63
New contributor
Jay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Jay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Jay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
Looks interesting (Iscasemore complicated than looping?). But, as the code is known not to work as intended, it is off topic here.
$endgroup$
– greybeard
2 hours ago
$begingroup$
I'll change the code above to one that works as intended but may need optimizing?
$endgroup$
– Jay
2 hours ago
$begingroup$
Sounds promising: Welcome to Code Review! Even if your post gets closed before you're done, it will be bound to be re-opened once fixed. (Closing would be for the better: it is an indication that the question is not in a state to be answered.) Note that you should not alter your code a considerable time after posting, and are forbidden to so in a way that invalidates answers.
$endgroup$
– greybeard
2 hours ago
2
$begingroup$
Can I take it down and try again later?
$endgroup$
– Jay
2 hours ago
$begingroup$
Yes, of course. Removing content that is useful for others is frowned upon, but possible, too.
$endgroup$
– greybeard
2 hours ago
add a comment |
$begingroup$
Looks interesting (Iscasemore complicated than looping?). But, as the code is known not to work as intended, it is off topic here.
$endgroup$
– greybeard
2 hours ago
$begingroup$
I'll change the code above to one that works as intended but may need optimizing?
$endgroup$
– Jay
2 hours ago
$begingroup$
Sounds promising: Welcome to Code Review! Even if your post gets closed before you're done, it will be bound to be re-opened once fixed. (Closing would be for the better: it is an indication that the question is not in a state to be answered.) Note that you should not alter your code a considerable time after posting, and are forbidden to so in a way that invalidates answers.
$endgroup$
– greybeard
2 hours ago
2
$begingroup$
Can I take it down and try again later?
$endgroup$
– Jay
2 hours ago
$begingroup$
Yes, of course. Removing content that is useful for others is frowned upon, but possible, too.
$endgroup$
– greybeard
2 hours ago
$begingroup$
Looks interesting (Is
case more complicated than looping?). But, as the code is known not to work as intended, it is off topic here.$endgroup$
– greybeard
2 hours ago
$begingroup$
Looks interesting (Is
case more complicated than looping?). But, as the code is known not to work as intended, it is off topic here.$endgroup$
– greybeard
2 hours ago
$begingroup$
I'll change the code above to one that works as intended but may need optimizing?
$endgroup$
– Jay
2 hours ago
$begingroup$
I'll change the code above to one that works as intended but may need optimizing?
$endgroup$
– Jay
2 hours ago
$begingroup$
Sounds promising: Welcome to Code Review! Even if your post gets closed before you're done, it will be bound to be re-opened once fixed. (Closing would be for the better: it is an indication that the question is not in a state to be answered.) Note that you should not alter your code a considerable time after posting, and are forbidden to so in a way that invalidates answers.
$endgroup$
– greybeard
2 hours ago
$begingroup$
Sounds promising: Welcome to Code Review! Even if your post gets closed before you're done, it will be bound to be re-opened once fixed. (Closing would be for the better: it is an indication that the question is not in a state to be answered.) Note that you should not alter your code a considerable time after posting, and are forbidden to so in a way that invalidates answers.
$endgroup$
– greybeard
2 hours ago
2
2
$begingroup$
Can I take it down and try again later?
$endgroup$
– Jay
2 hours ago
$begingroup$
Can I take it down and try again later?
$endgroup$
– Jay
2 hours ago
$begingroup$
Yes, of course. Removing content that is useful for others is frowned upon, but possible, too.
$endgroup$
– greybeard
2 hours ago
$begingroup$
Yes, of course. Removing content that is useful for others is frowned upon, but possible, too.
$endgroup$
– greybeard
2 hours ago
add a comment |
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$begingroup$
Looks interesting (Is
casemore complicated than looping?). But, as the code is known not to work as intended, it is off topic here.$endgroup$
– greybeard
2 hours ago
$begingroup$
I'll change the code above to one that works as intended but may need optimizing?
$endgroup$
– Jay
2 hours ago
$begingroup$
Sounds promising: Welcome to Code Review! Even if your post gets closed before you're done, it will be bound to be re-opened once fixed. (Closing would be for the better: it is an indication that the question is not in a state to be answered.) Note that you should not alter your code a considerable time after posting, and are forbidden to so in a way that invalidates answers.
$endgroup$
– greybeard
2 hours ago
2
$begingroup$
Can I take it down and try again later?
$endgroup$
– Jay
2 hours ago
$begingroup$
Yes, of course. Removing content that is useful for others is frowned upon, but possible, too.
$endgroup$
– greybeard
2 hours ago