How to do a two different array results manipulation in angular6
Here is a product Service response.
productServiceResponse = [
{productOrderId:108898,productStatus:"C",productId:'4'},
{productOrderId:108899,productStatus:"P",productId:'2'},
];
by using const value currentProductStatus = "C";
In product Service response ,i need to find the current product and taken the product by using above constant value and taken the product id.
So here i did that .Here i have did the index of the current product instead of that need it in dynamicllay find out from the collection .
this.productServiceResponse[0].productStatus
// check the current product
const ProductCode =
this.productServiceResponse[0].productStatus ===
this.currentProductStatus
? this.productServiceResponse[0].productId.toString()
: null;
once get the current productId.
i have check it in another collection.
productTypes =[
{id: "1", name: "Laptop"},
{id: "2", name: "Mobile"},
{id: "3", name: "headphone"},
{id: "4", name: "Cameras"}
];
from the product types collection , i have match the product id from the above result.
this.currentProduct = this.productTypes.find(product=>product.id ===ProductCode).name;
final o/p becomes cameras.
I have got the o/p :but i need this query in single line filteration instead of two variables.
can any one refactor this.
Demo:filter
angular typescript rxjs angular6 rxjs6
add a comment |
Here is a product Service response.
productServiceResponse = [
{productOrderId:108898,productStatus:"C",productId:'4'},
{productOrderId:108899,productStatus:"P",productId:'2'},
];
by using const value currentProductStatus = "C";
In product Service response ,i need to find the current product and taken the product by using above constant value and taken the product id.
So here i did that .Here i have did the index of the current product instead of that need it in dynamicllay find out from the collection .
this.productServiceResponse[0].productStatus
// check the current product
const ProductCode =
this.productServiceResponse[0].productStatus ===
this.currentProductStatus
? this.productServiceResponse[0].productId.toString()
: null;
once get the current productId.
i have check it in another collection.
productTypes =[
{id: "1", name: "Laptop"},
{id: "2", name: "Mobile"},
{id: "3", name: "headphone"},
{id: "4", name: "Cameras"}
];
from the product types collection , i have match the product id from the above result.
this.currentProduct = this.productTypes.find(product=>product.id ===ProductCode).name;
final o/p becomes cameras.
I have got the o/p :but i need this query in single line filteration instead of two variables.
can any one refactor this.
Demo:filter
angular typescript rxjs angular6 rxjs6
stackblitz.com/edit/angular-ss14hb?file=src/app/…
– dee zg
Nov 24 '18 at 15:04
The result is wrong o/p should be camera and not both , because productStatus is C for product Id{productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:17
i gave you flexible solution where everything is mapped correctly. now you just pick up your index you need ;)
– dee zg
Nov 24 '18 at 15:20
add a comment |
Here is a product Service response.
productServiceResponse = [
{productOrderId:108898,productStatus:"C",productId:'4'},
{productOrderId:108899,productStatus:"P",productId:'2'},
];
by using const value currentProductStatus = "C";
In product Service response ,i need to find the current product and taken the product by using above constant value and taken the product id.
So here i did that .Here i have did the index of the current product instead of that need it in dynamicllay find out from the collection .
this.productServiceResponse[0].productStatus
// check the current product
const ProductCode =
this.productServiceResponse[0].productStatus ===
this.currentProductStatus
? this.productServiceResponse[0].productId.toString()
: null;
once get the current productId.
i have check it in another collection.
productTypes =[
{id: "1", name: "Laptop"},
{id: "2", name: "Mobile"},
{id: "3", name: "headphone"},
{id: "4", name: "Cameras"}
];
from the product types collection , i have match the product id from the above result.
this.currentProduct = this.productTypes.find(product=>product.id ===ProductCode).name;
final o/p becomes cameras.
I have got the o/p :but i need this query in single line filteration instead of two variables.
can any one refactor this.
Demo:filter
angular typescript rxjs angular6 rxjs6
Here is a product Service response.
productServiceResponse = [
{productOrderId:108898,productStatus:"C",productId:'4'},
{productOrderId:108899,productStatus:"P",productId:'2'},
];
by using const value currentProductStatus = "C";
In product Service response ,i need to find the current product and taken the product by using above constant value and taken the product id.
So here i did that .Here i have did the index of the current product instead of that need it in dynamicllay find out from the collection .
this.productServiceResponse[0].productStatus
// check the current product
const ProductCode =
this.productServiceResponse[0].productStatus ===
this.currentProductStatus
? this.productServiceResponse[0].productId.toString()
: null;
once get the current productId.
i have check it in another collection.
productTypes =[
{id: "1", name: "Laptop"},
{id: "2", name: "Mobile"},
{id: "3", name: "headphone"},
{id: "4", name: "Cameras"}
];
from the product types collection , i have match the product id from the above result.
this.currentProduct = this.productTypes.find(product=>product.id ===ProductCode).name;
final o/p becomes cameras.
I have got the o/p :but i need this query in single line filteration instead of two variables.
can any one refactor this.
Demo:filter
angular typescript rxjs angular6 rxjs6
angular typescript rxjs angular6 rxjs6
edited Nov 24 '18 at 14:53
Mohamed Sahir
asked Nov 24 '18 at 14:45
Mohamed SahirMohamed Sahir
60941430
60941430
stackblitz.com/edit/angular-ss14hb?file=src/app/…
– dee zg
Nov 24 '18 at 15:04
The result is wrong o/p should be camera and not both , because productStatus is C for product Id{productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:17
i gave you flexible solution where everything is mapped correctly. now you just pick up your index you need ;)
– dee zg
Nov 24 '18 at 15:20
add a comment |
stackblitz.com/edit/angular-ss14hb?file=src/app/…
– dee zg
Nov 24 '18 at 15:04
The result is wrong o/p should be camera and not both , because productStatus is C for product Id{productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:17
i gave you flexible solution where everything is mapped correctly. now you just pick up your index you need ;)
– dee zg
Nov 24 '18 at 15:20
stackblitz.com/edit/angular-ss14hb?file=src/app/…
– dee zg
Nov 24 '18 at 15:04
stackblitz.com/edit/angular-ss14hb?file=src/app/…
– dee zg
Nov 24 '18 at 15:04
The result is wrong o/p should be camera and not both , because productStatus is C for product Id
{productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:17
The result is wrong o/p should be camera and not both , because productStatus is C for product Id
{productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:17
i gave you flexible solution where everything is mapped correctly. now you just pick up your index you need ;)
– dee zg
Nov 24 '18 at 15:20
i gave you flexible solution where everything is mapped correctly. now you just pick up your index you need ;)
– dee zg
Nov 24 '18 at 15:20
add a comment |
1 Answer
1
active
oldest
votes
Try this way
this.productTypes.find(product=>
product.id === productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).productID
).name
Be advised I typed this in my cell phone 🤓
i have changed that tothis.productTypes.find(product => { product.id === this.productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).map(x=>x.productID) }).map(x=>x.name);
getting below error _this.productServiceResponse.find(...).map is not a function
– Mohamed Sahir
Nov 24 '18 at 15:03
sure, sincemap
is being ran on anobject
and notarray
sincefind
returns (first)object
satisfying criteria given to it.
– dee zg
Nov 24 '18 at 15:09
Just take the .map out of the code and leave it like .productId and .name I edited my answer like so
– Gabriel Lopez
Nov 24 '18 at 15:16
@deezig o/p is wrong in your code there is no check for currentProductStatus The result is wrong o/p should be camera and not both , because productStatus is C for product Id {productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:18
@Gabriel Lopez thanks man i have nested manipulation from your solution.keep support in stackoverflow
– Mohamed Sahir
Nov 24 '18 at 15:26
|
show 1 more comment
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try this way
this.productTypes.find(product=>
product.id === productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).productID
).name
Be advised I typed this in my cell phone 🤓
i have changed that tothis.productTypes.find(product => { product.id === this.productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).map(x=>x.productID) }).map(x=>x.name);
getting below error _this.productServiceResponse.find(...).map is not a function
– Mohamed Sahir
Nov 24 '18 at 15:03
sure, sincemap
is being ran on anobject
and notarray
sincefind
returns (first)object
satisfying criteria given to it.
– dee zg
Nov 24 '18 at 15:09
Just take the .map out of the code and leave it like .productId and .name I edited my answer like so
– Gabriel Lopez
Nov 24 '18 at 15:16
@deezig o/p is wrong in your code there is no check for currentProductStatus The result is wrong o/p should be camera and not both , because productStatus is C for product Id {productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:18
@Gabriel Lopez thanks man i have nested manipulation from your solution.keep support in stackoverflow
– Mohamed Sahir
Nov 24 '18 at 15:26
|
show 1 more comment
Try this way
this.productTypes.find(product=>
product.id === productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).productID
).name
Be advised I typed this in my cell phone 🤓
i have changed that tothis.productTypes.find(product => { product.id === this.productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).map(x=>x.productID) }).map(x=>x.name);
getting below error _this.productServiceResponse.find(...).map is not a function
– Mohamed Sahir
Nov 24 '18 at 15:03
sure, sincemap
is being ran on anobject
and notarray
sincefind
returns (first)object
satisfying criteria given to it.
– dee zg
Nov 24 '18 at 15:09
Just take the .map out of the code and leave it like .productId and .name I edited my answer like so
– Gabriel Lopez
Nov 24 '18 at 15:16
@deezig o/p is wrong in your code there is no check for currentProductStatus The result is wrong o/p should be camera and not both , because productStatus is C for product Id {productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:18
@Gabriel Lopez thanks man i have nested manipulation from your solution.keep support in stackoverflow
– Mohamed Sahir
Nov 24 '18 at 15:26
|
show 1 more comment
Try this way
this.productTypes.find(product=>
product.id === productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).productID
).name
Be advised I typed this in my cell phone 🤓
Try this way
this.productTypes.find(product=>
product.id === productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).productID
).name
Be advised I typed this in my cell phone 🤓
edited Nov 24 '18 at 15:20
answered Nov 24 '18 at 14:59
Gabriel LopezGabriel Lopez
28217
28217
i have changed that tothis.productTypes.find(product => { product.id === this.productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).map(x=>x.productID) }).map(x=>x.name);
getting below error _this.productServiceResponse.find(...).map is not a function
– Mohamed Sahir
Nov 24 '18 at 15:03
sure, sincemap
is being ran on anobject
and notarray
sincefind
returns (first)object
satisfying criteria given to it.
– dee zg
Nov 24 '18 at 15:09
Just take the .map out of the code and leave it like .productId and .name I edited my answer like so
– Gabriel Lopez
Nov 24 '18 at 15:16
@deezig o/p is wrong in your code there is no check for currentProductStatus The result is wrong o/p should be camera and not both , because productStatus is C for product Id {productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:18
@Gabriel Lopez thanks man i have nested manipulation from your solution.keep support in stackoverflow
– Mohamed Sahir
Nov 24 '18 at 15:26
|
show 1 more comment
i have changed that tothis.productTypes.find(product => { product.id === this.productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).map(x=>x.productID) }).map(x=>x.name);
getting below error _this.productServiceResponse.find(...).map is not a function
– Mohamed Sahir
Nov 24 '18 at 15:03
sure, sincemap
is being ran on anobject
and notarray
sincefind
returns (first)object
satisfying criteria given to it.
– dee zg
Nov 24 '18 at 15:09
Just take the .map out of the code and leave it like .productId and .name I edited my answer like so
– Gabriel Lopez
Nov 24 '18 at 15:16
@deezig o/p is wrong in your code there is no check for currentProductStatus The result is wrong o/p should be camera and not both , because productStatus is C for product Id {productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:18
@Gabriel Lopez thanks man i have nested manipulation from your solution.keep support in stackoverflow
– Mohamed Sahir
Nov 24 '18 at 15:26
i have changed that to
this.productTypes.find(product => { product.id === this.productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).map(x=>x.productID) }).map(x=>x.name);
getting below error _this.productServiceResponse.find(...).map is not a function– Mohamed Sahir
Nov 24 '18 at 15:03
i have changed that to
this.productTypes.find(product => { product.id === this.productServiceResponse.find(psr=>psr.productStatus === this.currentProductStatus).map(x=>x.productID) }).map(x=>x.name);
getting below error _this.productServiceResponse.find(...).map is not a function– Mohamed Sahir
Nov 24 '18 at 15:03
sure, since
map
is being ran on an object
and not array
since find
returns (first) object
satisfying criteria given to it.– dee zg
Nov 24 '18 at 15:09
sure, since
map
is being ran on an object
and not array
since find
returns (first) object
satisfying criteria given to it.– dee zg
Nov 24 '18 at 15:09
Just take the .map out of the code and leave it like .productId and .name I edited my answer like so
– Gabriel Lopez
Nov 24 '18 at 15:16
Just take the .map out of the code and leave it like .productId and .name I edited my answer like so
– Gabriel Lopez
Nov 24 '18 at 15:16
@deezig o/p is wrong in your code there is no check for currentProductStatus The result is wrong o/p should be camera and not both , because productStatus is C for product Id {productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:18
@deezig o/p is wrong in your code there is no check for currentProductStatus The result is wrong o/p should be camera and not both , because productStatus is C for product Id {productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:18
@Gabriel Lopez thanks man i have nested manipulation from your solution.keep support in stackoverflow
– Mohamed Sahir
Nov 24 '18 at 15:26
@Gabriel Lopez thanks man i have nested manipulation from your solution.keep support in stackoverflow
– Mohamed Sahir
Nov 24 '18 at 15:26
|
show 1 more comment
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stackblitz.com/edit/angular-ss14hb?file=src/app/…
– dee zg
Nov 24 '18 at 15:04
The result is wrong o/p should be camera and not both , because productStatus is C for product Id
{productOrderId:108898,productStatus:"C",productId:'4'}
– Mohamed Sahir
Nov 24 '18 at 15:17
i gave you flexible solution where everything is mapped correctly. now you just pick up your index you need ;)
– dee zg
Nov 24 '18 at 15:20