Python: […] at End of List
I've run into an issue when after I append my list to my dictionary, I get an unwanted [...]
at the end of my list.
Here's my code:
class Account:
accountInfo = {} #ex. ID : 5FE19C (hexadecimal ID's)
def __init__(self):
choice = raw_input("Would you like to login or signup?n")
if choice.lower() == "login":
self.login()
elif choice.lower() == "signup":
print "Great! Fill in the following."
self.signup()
else:
self.__init__()
def signup(self):
accountID = '%010x' % random.randrange(16**10) # 10 digit hexadecimal ID generator
personalInfo =
self.accountInfo[accountID] = personalInfo
firstName = raw_input("First Name: ")
lastName = raw_input("Last Name: ")
email = raw_input("E-Mail: ")
password = raw_input("Password: ")
birthdate = raw_input("DOB (DD/MM/YYYY): ")
alias = raw_input("Username/Alias: ")
personalInfo.append(firstName)
personalInfo.append(lastName)
personalInfo.append(email)
personalInfo.append(password)
personalInfo.append(birthdate)
personalInfo.append(alias)
self.accountInfo[accountID].append(personalInfo)
print self.accountInfo
And here is my output:
>>> {'a92ab2fcea': ['firstName', 'lastName', 'email', 'password', 'birthdate', 'alias', [...]]}
Just wondering why it appears and how to remove it.
Thanks!
python list dictionary
add a comment |
I've run into an issue when after I append my list to my dictionary, I get an unwanted [...]
at the end of my list.
Here's my code:
class Account:
accountInfo = {} #ex. ID : 5FE19C (hexadecimal ID's)
def __init__(self):
choice = raw_input("Would you like to login or signup?n")
if choice.lower() == "login":
self.login()
elif choice.lower() == "signup":
print "Great! Fill in the following."
self.signup()
else:
self.__init__()
def signup(self):
accountID = '%010x' % random.randrange(16**10) # 10 digit hexadecimal ID generator
personalInfo =
self.accountInfo[accountID] = personalInfo
firstName = raw_input("First Name: ")
lastName = raw_input("Last Name: ")
email = raw_input("E-Mail: ")
password = raw_input("Password: ")
birthdate = raw_input("DOB (DD/MM/YYYY): ")
alias = raw_input("Username/Alias: ")
personalInfo.append(firstName)
personalInfo.append(lastName)
personalInfo.append(email)
personalInfo.append(password)
personalInfo.append(birthdate)
personalInfo.append(alias)
self.accountInfo[accountID].append(personalInfo)
print self.accountInfo
And here is my output:
>>> {'a92ab2fcea': ['firstName', 'lastName', 'email', 'password', 'birthdate', 'alias', [...]]}
Just wondering why it appears and how to remove it.
Thanks!
python list dictionary
1
The Ellipses indicates a recursively defined structure. In your cases you have appended the list to itself.
– Klaus D.
Nov 23 '18 at 3:07
add a comment |
I've run into an issue when after I append my list to my dictionary, I get an unwanted [...]
at the end of my list.
Here's my code:
class Account:
accountInfo = {} #ex. ID : 5FE19C (hexadecimal ID's)
def __init__(self):
choice = raw_input("Would you like to login or signup?n")
if choice.lower() == "login":
self.login()
elif choice.lower() == "signup":
print "Great! Fill in the following."
self.signup()
else:
self.__init__()
def signup(self):
accountID = '%010x' % random.randrange(16**10) # 10 digit hexadecimal ID generator
personalInfo =
self.accountInfo[accountID] = personalInfo
firstName = raw_input("First Name: ")
lastName = raw_input("Last Name: ")
email = raw_input("E-Mail: ")
password = raw_input("Password: ")
birthdate = raw_input("DOB (DD/MM/YYYY): ")
alias = raw_input("Username/Alias: ")
personalInfo.append(firstName)
personalInfo.append(lastName)
personalInfo.append(email)
personalInfo.append(password)
personalInfo.append(birthdate)
personalInfo.append(alias)
self.accountInfo[accountID].append(personalInfo)
print self.accountInfo
And here is my output:
>>> {'a92ab2fcea': ['firstName', 'lastName', 'email', 'password', 'birthdate', 'alias', [...]]}
Just wondering why it appears and how to remove it.
Thanks!
python list dictionary
I've run into an issue when after I append my list to my dictionary, I get an unwanted [...]
at the end of my list.
Here's my code:
class Account:
accountInfo = {} #ex. ID : 5FE19C (hexadecimal ID's)
def __init__(self):
choice = raw_input("Would you like to login or signup?n")
if choice.lower() == "login":
self.login()
elif choice.lower() == "signup":
print "Great! Fill in the following."
self.signup()
else:
self.__init__()
def signup(self):
accountID = '%010x' % random.randrange(16**10) # 10 digit hexadecimal ID generator
personalInfo =
self.accountInfo[accountID] = personalInfo
firstName = raw_input("First Name: ")
lastName = raw_input("Last Name: ")
email = raw_input("E-Mail: ")
password = raw_input("Password: ")
birthdate = raw_input("DOB (DD/MM/YYYY): ")
alias = raw_input("Username/Alias: ")
personalInfo.append(firstName)
personalInfo.append(lastName)
personalInfo.append(email)
personalInfo.append(password)
personalInfo.append(birthdate)
personalInfo.append(alias)
self.accountInfo[accountID].append(personalInfo)
print self.accountInfo
And here is my output:
>>> {'a92ab2fcea': ['firstName', 'lastName', 'email', 'password', 'birthdate', 'alias', [...]]}
Just wondering why it appears and how to remove it.
Thanks!
python list dictionary
python list dictionary
asked Nov 23 '18 at 2:57
H4MMYH4MMY
36
36
1
The Ellipses indicates a recursively defined structure. In your cases you have appended the list to itself.
– Klaus D.
Nov 23 '18 at 3:07
add a comment |
1
The Ellipses indicates a recursively defined structure. In your cases you have appended the list to itself.
– Klaus D.
Nov 23 '18 at 3:07
1
1
The Ellipses indicates a recursively defined structure. In your cases you have appended the list to itself.
– Klaus D.
Nov 23 '18 at 3:07
The Ellipses indicates a recursively defined structure. In your cases you have appended the list to itself.
– Klaus D.
Nov 23 '18 at 3:07
add a comment |
2 Answers
2
active
oldest
votes
To understand what exactly happened, you need to know about references.
>>> a =
>>> test['a'] = a
>>> a.append(1)
>>> a.append(2)
>>> test['a']
[1, 2]
When you did the line self.accountInfo[accountID] = personalInfo
What it actually did was pass the reference of personalInfo
to self.accountInfo[accountID]
Meaning modifying personalInfo
will also reflect in self.accountInfo[accountID]
self.accountInfo[accountID] = personalInfo >> {'a92ab2fcea': }
personalInfo.append(firstName) >> {'a92ab2fcea': ['firstName']} # Note: Since personalInfo changed, so self.accountInfo[accountID] also changed.
personalInfo.append(lastName) >> {'a92ab2fcea': ['firstName','lastName']}
personalInfo.append(email) >> {'a92ab2fcea': ['firstName','lastName','email']}
personalInfo.append(password) >> {'a92ab2fcea': ['firstName','lastName','email','password']}
personalInfo.append(birthdate) >> {'a92ab2fcea': ['firstName','lastName','email','password','birthdate']}
personalInfo.append(alias) >> {'a92ab2fcea': ['firstName','lastName','email','password','birthdate','alias']}
self.accountInfo[accountID].append(personalInfo) >> {'a92ab2fcea': ['firstName', 'lastName', 'email', 'password', 'birthdate', 'alias', [...]]} # What you are doing is appending personalInfo to personalInfo
What I think you meant to do is:
- remove
self.accountInfo[accountID] = personalInfo
- replace
self.accountInfo[accountID].append(personalInfo) with self.accountInfo[accountID] = personalInfo
But if you understand the reference concept,
- keep
self.accountInfo[accountID] = personalInfo
- remove
self.accountInfo[accountID].append(personalInfo)
Should also work!
But the latter way is discouraged as it is less readable.
Thank you for your help :) Also, wouldn't either of the instructions you provided do the same thing? I don't mean as far as output because they obviously give the same output, but just overall writing that code would give you the same written reference?
– H4MMY
Nov 23 '18 at 19:56
add a comment |
I think you mean
self.accountInfo[accountID].append(personalInfo)
to be
self.accountInfo[accountID] = personalInfo
you also don't need the latter line earlier in the code.
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
To understand what exactly happened, you need to know about references.
>>> a =
>>> test['a'] = a
>>> a.append(1)
>>> a.append(2)
>>> test['a']
[1, 2]
When you did the line self.accountInfo[accountID] = personalInfo
What it actually did was pass the reference of personalInfo
to self.accountInfo[accountID]
Meaning modifying personalInfo
will also reflect in self.accountInfo[accountID]
self.accountInfo[accountID] = personalInfo >> {'a92ab2fcea': }
personalInfo.append(firstName) >> {'a92ab2fcea': ['firstName']} # Note: Since personalInfo changed, so self.accountInfo[accountID] also changed.
personalInfo.append(lastName) >> {'a92ab2fcea': ['firstName','lastName']}
personalInfo.append(email) >> {'a92ab2fcea': ['firstName','lastName','email']}
personalInfo.append(password) >> {'a92ab2fcea': ['firstName','lastName','email','password']}
personalInfo.append(birthdate) >> {'a92ab2fcea': ['firstName','lastName','email','password','birthdate']}
personalInfo.append(alias) >> {'a92ab2fcea': ['firstName','lastName','email','password','birthdate','alias']}
self.accountInfo[accountID].append(personalInfo) >> {'a92ab2fcea': ['firstName', 'lastName', 'email', 'password', 'birthdate', 'alias', [...]]} # What you are doing is appending personalInfo to personalInfo
What I think you meant to do is:
- remove
self.accountInfo[accountID] = personalInfo
- replace
self.accountInfo[accountID].append(personalInfo) with self.accountInfo[accountID] = personalInfo
But if you understand the reference concept,
- keep
self.accountInfo[accountID] = personalInfo
- remove
self.accountInfo[accountID].append(personalInfo)
Should also work!
But the latter way is discouraged as it is less readable.
Thank you for your help :) Also, wouldn't either of the instructions you provided do the same thing? I don't mean as far as output because they obviously give the same output, but just overall writing that code would give you the same written reference?
– H4MMY
Nov 23 '18 at 19:56
add a comment |
To understand what exactly happened, you need to know about references.
>>> a =
>>> test['a'] = a
>>> a.append(1)
>>> a.append(2)
>>> test['a']
[1, 2]
When you did the line self.accountInfo[accountID] = personalInfo
What it actually did was pass the reference of personalInfo
to self.accountInfo[accountID]
Meaning modifying personalInfo
will also reflect in self.accountInfo[accountID]
self.accountInfo[accountID] = personalInfo >> {'a92ab2fcea': }
personalInfo.append(firstName) >> {'a92ab2fcea': ['firstName']} # Note: Since personalInfo changed, so self.accountInfo[accountID] also changed.
personalInfo.append(lastName) >> {'a92ab2fcea': ['firstName','lastName']}
personalInfo.append(email) >> {'a92ab2fcea': ['firstName','lastName','email']}
personalInfo.append(password) >> {'a92ab2fcea': ['firstName','lastName','email','password']}
personalInfo.append(birthdate) >> {'a92ab2fcea': ['firstName','lastName','email','password','birthdate']}
personalInfo.append(alias) >> {'a92ab2fcea': ['firstName','lastName','email','password','birthdate','alias']}
self.accountInfo[accountID].append(personalInfo) >> {'a92ab2fcea': ['firstName', 'lastName', 'email', 'password', 'birthdate', 'alias', [...]]} # What you are doing is appending personalInfo to personalInfo
What I think you meant to do is:
- remove
self.accountInfo[accountID] = personalInfo
- replace
self.accountInfo[accountID].append(personalInfo) with self.accountInfo[accountID] = personalInfo
But if you understand the reference concept,
- keep
self.accountInfo[accountID] = personalInfo
- remove
self.accountInfo[accountID].append(personalInfo)
Should also work!
But the latter way is discouraged as it is less readable.
Thank you for your help :) Also, wouldn't either of the instructions you provided do the same thing? I don't mean as far as output because they obviously give the same output, but just overall writing that code would give you the same written reference?
– H4MMY
Nov 23 '18 at 19:56
add a comment |
To understand what exactly happened, you need to know about references.
>>> a =
>>> test['a'] = a
>>> a.append(1)
>>> a.append(2)
>>> test['a']
[1, 2]
When you did the line self.accountInfo[accountID] = personalInfo
What it actually did was pass the reference of personalInfo
to self.accountInfo[accountID]
Meaning modifying personalInfo
will also reflect in self.accountInfo[accountID]
self.accountInfo[accountID] = personalInfo >> {'a92ab2fcea': }
personalInfo.append(firstName) >> {'a92ab2fcea': ['firstName']} # Note: Since personalInfo changed, so self.accountInfo[accountID] also changed.
personalInfo.append(lastName) >> {'a92ab2fcea': ['firstName','lastName']}
personalInfo.append(email) >> {'a92ab2fcea': ['firstName','lastName','email']}
personalInfo.append(password) >> {'a92ab2fcea': ['firstName','lastName','email','password']}
personalInfo.append(birthdate) >> {'a92ab2fcea': ['firstName','lastName','email','password','birthdate']}
personalInfo.append(alias) >> {'a92ab2fcea': ['firstName','lastName','email','password','birthdate','alias']}
self.accountInfo[accountID].append(personalInfo) >> {'a92ab2fcea': ['firstName', 'lastName', 'email', 'password', 'birthdate', 'alias', [...]]} # What you are doing is appending personalInfo to personalInfo
What I think you meant to do is:
- remove
self.accountInfo[accountID] = personalInfo
- replace
self.accountInfo[accountID].append(personalInfo) with self.accountInfo[accountID] = personalInfo
But if you understand the reference concept,
- keep
self.accountInfo[accountID] = personalInfo
- remove
self.accountInfo[accountID].append(personalInfo)
Should also work!
But the latter way is discouraged as it is less readable.
To understand what exactly happened, you need to know about references.
>>> a =
>>> test['a'] = a
>>> a.append(1)
>>> a.append(2)
>>> test['a']
[1, 2]
When you did the line self.accountInfo[accountID] = personalInfo
What it actually did was pass the reference of personalInfo
to self.accountInfo[accountID]
Meaning modifying personalInfo
will also reflect in self.accountInfo[accountID]
self.accountInfo[accountID] = personalInfo >> {'a92ab2fcea': }
personalInfo.append(firstName) >> {'a92ab2fcea': ['firstName']} # Note: Since personalInfo changed, so self.accountInfo[accountID] also changed.
personalInfo.append(lastName) >> {'a92ab2fcea': ['firstName','lastName']}
personalInfo.append(email) >> {'a92ab2fcea': ['firstName','lastName','email']}
personalInfo.append(password) >> {'a92ab2fcea': ['firstName','lastName','email','password']}
personalInfo.append(birthdate) >> {'a92ab2fcea': ['firstName','lastName','email','password','birthdate']}
personalInfo.append(alias) >> {'a92ab2fcea': ['firstName','lastName','email','password','birthdate','alias']}
self.accountInfo[accountID].append(personalInfo) >> {'a92ab2fcea': ['firstName', 'lastName', 'email', 'password', 'birthdate', 'alias', [...]]} # What you are doing is appending personalInfo to personalInfo
What I think you meant to do is:
- remove
self.accountInfo[accountID] = personalInfo
- replace
self.accountInfo[accountID].append(personalInfo) with self.accountInfo[accountID] = personalInfo
But if you understand the reference concept,
- keep
self.accountInfo[accountID] = personalInfo
- remove
self.accountInfo[accountID].append(personalInfo)
Should also work!
But the latter way is discouraged as it is less readable.
answered Nov 23 '18 at 3:40
PaltonPalton
16
16
Thank you for your help :) Also, wouldn't either of the instructions you provided do the same thing? I don't mean as far as output because they obviously give the same output, but just overall writing that code would give you the same written reference?
– H4MMY
Nov 23 '18 at 19:56
add a comment |
Thank you for your help :) Also, wouldn't either of the instructions you provided do the same thing? I don't mean as far as output because they obviously give the same output, but just overall writing that code would give you the same written reference?
– H4MMY
Nov 23 '18 at 19:56
Thank you for your help :) Also, wouldn't either of the instructions you provided do the same thing? I don't mean as far as output because they obviously give the same output, but just overall writing that code would give you the same written reference?
– H4MMY
Nov 23 '18 at 19:56
Thank you for your help :) Also, wouldn't either of the instructions you provided do the same thing? I don't mean as far as output because they obviously give the same output, but just overall writing that code would give you the same written reference?
– H4MMY
Nov 23 '18 at 19:56
add a comment |
I think you mean
self.accountInfo[accountID].append(personalInfo)
to be
self.accountInfo[accountID] = personalInfo
you also don't need the latter line earlier in the code.
add a comment |
I think you mean
self.accountInfo[accountID].append(personalInfo)
to be
self.accountInfo[accountID] = personalInfo
you also don't need the latter line earlier in the code.
add a comment |
I think you mean
self.accountInfo[accountID].append(personalInfo)
to be
self.accountInfo[accountID] = personalInfo
you also don't need the latter line earlier in the code.
I think you mean
self.accountInfo[accountID].append(personalInfo)
to be
self.accountInfo[accountID] = personalInfo
you also don't need the latter line earlier in the code.
answered Nov 23 '18 at 3:16
pooh17pooh17
444
444
add a comment |
add a comment |
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1
The Ellipses indicates a recursively defined structure. In your cases you have appended the list to itself.
– Klaus D.
Nov 23 '18 at 3:07