Drawing a bordered square with least time complexity in JS

-2

I just wrote a code that draws a bordered square.

Given the square size of 5 for example, the code should print the following multi-line string:

#####

#   #

#   #

#   #

#####

and I was wondering if there's anyway of simplifying this more and reduce time complexity.

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";



function DrawSquare() {



  for (i = 0; i < BoxSize; i++) {

    var r = BoxSize - 1;



    if (i == 0 || i == r) {

      Row = BoxFiller.repeat(BoxSize);

    } else {

      Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;

    }



    console.log(Row);



  }

}



DrawSquare();

edited Nov 23 '18 at 1:52

Ele

22.8k42045

asked Nov 23 '18 at 1:49

CoreDo

98831018

2

I think this question would be more suitable posted on Code Review Stack Exchange

– NewToJS
Nov 23 '18 at 1:55

1

There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.

– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57

add a comment |

-2

I just wrote a code that draws a bordered square.

Given the square size of 5 for example, the code should print the following multi-line string:

#####

#   #

#   #

#   #

#####

and I was wondering if there's anyway of simplifying this more and reduce time complexity.

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";



function DrawSquare() {



  for (i = 0; i < BoxSize; i++) {

    var r = BoxSize - 1;



    if (i == 0 || i == r) {

      Row = BoxFiller.repeat(BoxSize);

    } else {

      Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;

    }



    console.log(Row);



  }

}



DrawSquare();

edited Nov 23 '18 at 1:52

Ele

22.8k42045

asked Nov 23 '18 at 1:49

CoreDo

98831018

2

I think this question would be more suitable posted on Code Review Stack Exchange

– NewToJS
Nov 23 '18 at 1:55

1

There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.

– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57

add a comment |

-2

I just wrote a code that draws a bordered square.

Given the square size of 5 for example, the code should print the following multi-line string:

#####

#   #

#   #

#   #

#####

and I was wondering if there's anyway of simplifying this more and reduce time complexity.

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";



function DrawSquare() {



  for (i = 0; i < BoxSize; i++) {

    var r = BoxSize - 1;



    if (i == 0 || i == r) {

      Row = BoxFiller.repeat(BoxSize);

    } else {

      Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;

    }



    console.log(Row);



  }

}



DrawSquare();

edited Nov 23 '18 at 1:52

Ele

22.8k42045

asked Nov 23 '18 at 1:49

CoreDo

98831018

I just wrote a code that draws a bordered square.

Given the square size of 5 for example, the code should print the following multi-line string:

#####

#   #

#   #

#   #

#####

and I was wondering if there's anyway of simplifying this more and reduce time complexity.

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";



function DrawSquare() {



  for (i = 0; i < BoxSize; i++) {

    var r = BoxSize - 1;



    if (i == 0 || i == r) {

      Row = BoxFiller.repeat(BoxSize);

    } else {

      Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;

    }



    console.log(Row);



  }

}



DrawSquare();

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";



function DrawSquare() {



  for (i = 0; i < BoxSize; i++) {

    var r = BoxSize - 1;



    if (i == 0 || i == r) {

      Row = BoxFiller.repeat(BoxSize);

    } else {

      Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;

    }



    console.log(Row);



  }

}



DrawSquare();

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";



function DrawSquare() {



  for (i = 0; i < BoxSize; i++) {

    var r = BoxSize - 1;



    if (i == 0 || i == r) {

      Row = BoxFiller.repeat(BoxSize);

    } else {

      Row = BoxFiller + " ".repeat(BoxSize - 2) + BoxFiller;

    }



    console.log(Row);



  }

}



DrawSquare();

javascript time-complexity

edited Nov 23 '18 at 1:52

Ele

22.8k42045

asked Nov 23 '18 at 1:49

CoreDo

98831018

edited Nov 23 '18 at 1:52

Ele

22.8k42045

asked Nov 23 '18 at 1:49

CoreDo

98831018

edited Nov 23 '18 at 1:52

Ele

22.8k42045

edited Nov 23 '18 at 1:52

Ele

22.8k42045

edited Nov 23 '18 at 1:52

Ele

22.8k42045

asked Nov 23 '18 at 1:49

CoreDo

98831018

asked Nov 23 '18 at 1:49

CoreDo

98831018

asked Nov 23 '18 at 1:49

CoreDo

98831018

2

I think this question would be more suitable posted on Code Review Stack Exchange

– NewToJS
Nov 23 '18 at 1:55

1

There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.

– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57

add a comment |

2

I think this question would be more suitable posted on Code Review Stack Exchange

– NewToJS
Nov 23 '18 at 1:55

1

There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.

– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57

I think this question would be more suitable posted on Code Review Stack Exchange

– NewToJS
Nov 23 '18 at 1:55

There is, and this is not the place to ask. Follow @NewToJS's advice. This is a request for help improving already working code.

– Mike 'Pomax' Kamermans
Nov 23 '18 at 1:57

add a comment |

3 Answers
3

active

oldest

votes

This is an alternative which reduces Space and Time complexity.

Time complexity: O(n)

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";

var spaces = " ".repeat(BoxSize - 2);

var hashtags = BoxFiller.repeat(BoxSize);



function DrawSquare() {  

  console.log(hashtags);

  

  for (var i = 1; i < BoxSize - 1; i++) {

    console.log(BoxFiller + spaces + BoxFiller);

  }

  

  console.log(hashtags);

}



DrawSquare();

.as-console-wrapper { max-height: 100% !important; top: 0; }

edited Nov 23 '18 at 15:59

answered Nov 23 '18 at 2:04

Ele

22.8k42045

add a comment |

Can use recursion

let BoxFiller = "#";

let Row = "";

var spaces, hashtags;



function DrawRow(BoxSize, CurrPos) { 

	if(CurrPos >= BoxSize - 2)

		return;

		

	console.log(BoxFiller + spaces + BoxFiller);

	DrawRow(BoxSize, CurrPos + 1);

}



function DrawSquare(BoxSize) { 

	spaces = " ".repeat(BoxSize - 2);

	hashtags = BoxFiller.repeat(BoxSize);

	console.log(hashtags);

	DrawRow(BoxSize, 0);

	console.log(hashtags);

}



DrawSquare(8);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Nov 23 '18 at 2:58

Miller Cy Chan

22929

add a comment |

Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.

function DrawSquare(size, filler) { 

  const line = filler.repeat(size);

  const mid = filler+' '.repeat(size-2)+filler;

  let lines = [line];

  

  for (var i = 1; i < size - 1; i++) {

    lines.push(mid);

  }

  

  lines.push(line);

  

  console.log(lines.join('n'));

}



DrawSquare(8, '*');

If I was going to redraw the same thing several times I would change it to look like this:

const cache = {};



function DrawSquare(size, filler) {

  if (!cache[size]) {

    const line = filler.repeat(size);

    const mid = filler+' '.repeat(size-2)+filler;

    let lines = [line];



    for (var i = 1; i < size - 1; i++) {

      lines.push(mid);

    }



    lines.push(line);



    cache[size] = lines.join('n');

  }

  

  console.log(cache[size]);

}





console.time('first');

DrawSquare(12, '*');

console.timeEnd('first');



console.time('second');

DrawSquare(12, '*');

console.timeEnd('second');

answered Nov 23 '18 at 3:17

Intervalia

4,25611033

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

This is an alternative which reduces Space and Time complexity.

Time complexity: O(n)

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";

var spaces = " ".repeat(BoxSize - 2);

var hashtags = BoxFiller.repeat(BoxSize);



function DrawSquare() {  

  console.log(hashtags);

  

  for (var i = 1; i < BoxSize - 1; i++) {

    console.log(BoxFiller + spaces + BoxFiller);

  }

  

  console.log(hashtags);

}



DrawSquare();

.as-console-wrapper { max-height: 100% !important; top: 0; }

edited Nov 23 '18 at 15:59

answered Nov 23 '18 at 2:04

Ele

22.8k42045

add a comment |

This is an alternative which reduces Space and Time complexity.

Time complexity: O(n)

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";

var spaces = " ".repeat(BoxSize - 2);

var hashtags = BoxFiller.repeat(BoxSize);



function DrawSquare() {  

  console.log(hashtags);

  

  for (var i = 1; i < BoxSize - 1; i++) {

    console.log(BoxFiller + spaces + BoxFiller);

  }

  

  console.log(hashtags);

}



DrawSquare();

.as-console-wrapper { max-height: 100% !important; top: 0; }

edited Nov 23 '18 at 15:59

answered Nov 23 '18 at 2:04

Ele

22.8k42045

add a comment |

This is an alternative which reduces Space and Time complexity.

Time complexity: O(n)

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";

var spaces = " ".repeat(BoxSize - 2);

var hashtags = BoxFiller.repeat(BoxSize);



function DrawSquare() {  

  console.log(hashtags);

  

  for (var i = 1; i < BoxSize - 1; i++) {

    console.log(BoxFiller + spaces + BoxFiller);

  }

  

  console.log(hashtags);

}



DrawSquare();

.as-console-wrapper { max-height: 100% !important; top: 0; }

edited Nov 23 '18 at 15:59

answered Nov 23 '18 at 2:04

Ele

22.8k42045

This is an alternative which reduces Space and Time complexity.

Time complexity: O(n)

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";

var spaces = " ".repeat(BoxSize - 2);

var hashtags = BoxFiller.repeat(BoxSize);



function DrawSquare() {  

  console.log(hashtags);

  

  for (var i = 1; i < BoxSize - 1; i++) {

    console.log(BoxFiller + spaces + BoxFiller);

  }

  

  console.log(hashtags);

}



DrawSquare();

.as-console-wrapper { max-height: 100% !important; top: 0; }

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";

var spaces = " ".repeat(BoxSize - 2);

var hashtags = BoxFiller.repeat(BoxSize);



function DrawSquare() {  

  console.log(hashtags);

  

  for (var i = 1; i < BoxSize - 1; i++) {

    console.log(BoxFiller + spaces + BoxFiller);

  }

  

  console.log(hashtags);

}



DrawSquare();

.as-console-wrapper { max-height: 100% !important; top: 0; }

var BoxFiller = "#";

var BoxSize = 8;

var Row = "";

var spaces = " ".repeat(BoxSize - 2);

var hashtags = BoxFiller.repeat(BoxSize);



function DrawSquare() {  

  console.log(hashtags);

  

  for (var i = 1; i < BoxSize - 1; i++) {

    console.log(BoxFiller + spaces + BoxFiller);

  }

  

  console.log(hashtags);

}



DrawSquare();

.as-console-wrapper { max-height: 100% !important; top: 0; }

edited Nov 23 '18 at 15:59

answered Nov 23 '18 at 2:04

Ele

22.8k42045

edited Nov 23 '18 at 15:59

answered Nov 23 '18 at 2:04

Ele

22.8k42045

answered Nov 23 '18 at 2:04

Ele

22.8k42045

answered Nov 23 '18 at 2:04

Ele

22.8k42045

add a comment |

Can use recursion

let BoxFiller = "#";

let Row = "";

var spaces, hashtags;



function DrawRow(BoxSize, CurrPos) { 

	if(CurrPos >= BoxSize - 2)

		return;

		

	console.log(BoxFiller + spaces + BoxFiller);

	DrawRow(BoxSize, CurrPos + 1);

}



function DrawSquare(BoxSize) { 

	spaces = " ".repeat(BoxSize - 2);

	hashtags = BoxFiller.repeat(BoxSize);

	console.log(hashtags);

	DrawRow(BoxSize, 0);

	console.log(hashtags);

}



DrawSquare(8);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Nov 23 '18 at 2:58

Miller Cy Chan

22929

add a comment |

Can use recursion

let BoxFiller = "#";

let Row = "";

var spaces, hashtags;



function DrawRow(BoxSize, CurrPos) { 

	if(CurrPos >= BoxSize - 2)

		return;

		

	console.log(BoxFiller + spaces + BoxFiller);

	DrawRow(BoxSize, CurrPos + 1);

}



function DrawSquare(BoxSize) { 

	spaces = " ".repeat(BoxSize - 2);

	hashtags = BoxFiller.repeat(BoxSize);

	console.log(hashtags);

	DrawRow(BoxSize, 0);

	console.log(hashtags);

}



DrawSquare(8);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Nov 23 '18 at 2:58

Miller Cy Chan

22929

add a comment |

Can use recursion

let BoxFiller = "#";

let Row = "";

var spaces, hashtags;



function DrawRow(BoxSize, CurrPos) { 

	if(CurrPos >= BoxSize - 2)

		return;

		

	console.log(BoxFiller + spaces + BoxFiller);

	DrawRow(BoxSize, CurrPos + 1);

}



function DrawSquare(BoxSize) { 

	spaces = " ".repeat(BoxSize - 2);

	hashtags = BoxFiller.repeat(BoxSize);

	console.log(hashtags);

	DrawRow(BoxSize, 0);

	console.log(hashtags);

}



DrawSquare(8);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Nov 23 '18 at 2:58

Miller Cy Chan

22929

Can use recursion

let BoxFiller = "#";

let Row = "";

var spaces, hashtags;



function DrawRow(BoxSize, CurrPos) { 

	if(CurrPos >= BoxSize - 2)

		return;

		

	console.log(BoxFiller + spaces + BoxFiller);

	DrawRow(BoxSize, CurrPos + 1);

}



function DrawSquare(BoxSize) { 

	spaces = " ".repeat(BoxSize - 2);

	hashtags = BoxFiller.repeat(BoxSize);

	console.log(hashtags);

	DrawRow(BoxSize, 0);

	console.log(hashtags);

}



DrawSquare(8);

.as-console-wrapper { max-height: 100% !important; top: 0; }

let BoxFiller = "#";

let Row = "";

var spaces, hashtags;



function DrawRow(BoxSize, CurrPos) { 

	if(CurrPos >= BoxSize - 2)

		return;

		

	console.log(BoxFiller + spaces + BoxFiller);

	DrawRow(BoxSize, CurrPos + 1);

}



function DrawSquare(BoxSize) { 

	spaces = " ".repeat(BoxSize - 2);

	hashtags = BoxFiller.repeat(BoxSize);

	console.log(hashtags);

	DrawRow(BoxSize, 0);

	console.log(hashtags);

}



DrawSquare(8);

.as-console-wrapper { max-height: 100% !important; top: 0; }

let BoxFiller = "#";

let Row = "";

var spaces, hashtags;



function DrawRow(BoxSize, CurrPos) { 

	if(CurrPos >= BoxSize - 2)

		return;

		

	console.log(BoxFiller + spaces + BoxFiller);

	DrawRow(BoxSize, CurrPos + 1);

}



function DrawSquare(BoxSize) { 

	spaces = " ".repeat(BoxSize - 2);

	hashtags = BoxFiller.repeat(BoxSize);

	console.log(hashtags);

	DrawRow(BoxSize, 0);

	console.log(hashtags);

}



DrawSquare(8);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Nov 23 '18 at 2:58

Miller Cy Chan

22929

answered Nov 23 '18 at 2:58

Miller Cy Chan

22929

answered Nov 23 '18 at 2:58

Miller Cy Chan

22929

answered Nov 23 '18 at 2:58

Miller Cy Chan

22929

add a comment |

Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.

function DrawSquare(size, filler) { 

  const line = filler.repeat(size);

  const mid = filler+' '.repeat(size-2)+filler;

  let lines = [line];

  

  for (var i = 1; i < size - 1; i++) {

    lines.push(mid);

  }

  

  lines.push(line);

  

  console.log(lines.join('n'));

}



DrawSquare(8, '*');

If I was going to redraw the same thing several times I would change it to look like this:

const cache = {};



function DrawSquare(size, filler) {

  if (!cache[size]) {

    const line = filler.repeat(size);

    const mid = filler+' '.repeat(size-2)+filler;

    let lines = [line];



    for (var i = 1; i < size - 1; i++) {

      lines.push(mid);

    }



    lines.push(line);



    cache[size] = lines.join('n');

  }

  

  console.log(cache[size]);

}





console.time('first');

DrawSquare(12, '*');

console.timeEnd('first');



console.time('second');

DrawSquare(12, '*');

console.timeEnd('second');

answered Nov 23 '18 at 3:17

Intervalia

4,25611033

add a comment |

Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.

function DrawSquare(size, filler) { 

  const line = filler.repeat(size);

  const mid = filler+' '.repeat(size-2)+filler;

  let lines = [line];

  

  for (var i = 1; i < size - 1; i++) {

    lines.push(mid);

  }

  

  lines.push(line);

  

  console.log(lines.join('n'));

}



DrawSquare(8, '*');

If I was going to redraw the same thing several times I would change it to look like this:

const cache = {};



function DrawSquare(size, filler) {

  if (!cache[size]) {

    const line = filler.repeat(size);

    const mid = filler+' '.repeat(size-2)+filler;

    let lines = [line];



    for (var i = 1; i < size - 1; i++) {

      lines.push(mid);

    }



    lines.push(line);



    cache[size] = lines.join('n');

  }

  

  console.log(cache[size]);

}





console.time('first');

DrawSquare(12, '*');

console.timeEnd('first');



console.time('second');

DrawSquare(12, '*');

console.timeEnd('second');

answered Nov 23 '18 at 3:17

Intervalia

4,25611033

add a comment |

Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.

function DrawSquare(size, filler) { 

  const line = filler.repeat(size);

  const mid = filler+' '.repeat(size-2)+filler;

  let lines = [line];

  

  for (var i = 1; i < size - 1; i++) {

    lines.push(mid);

  }

  

  lines.push(line);

  

  console.log(lines.join('n'));

}



DrawSquare(8, '*');

If I was going to redraw the same thing several times I would change it to look like this:

const cache = {};



function DrawSquare(size, filler) {

  if (!cache[size]) {

    const line = filler.repeat(size);

    const mid = filler+' '.repeat(size-2)+filler;

    let lines = [line];



    for (var i = 1; i < size - 1; i++) {

      lines.push(mid);

    }



    lines.push(line);



    cache[size] = lines.join('n');

  }

  

  console.log(cache[size]);

}





console.time('first');

DrawSquare(12, '*');

console.timeEnd('first');



console.time('second');

DrawSquare(12, '*');

console.timeEnd('second');

answered Nov 23 '18 at 3:17

Intervalia

4,25611033

Slight alteration to @Ele's version that allows for both a size and a filler to be passed in.

function DrawSquare(size, filler) { 

  const line = filler.repeat(size);

  const mid = filler+' '.repeat(size-2)+filler;

  let lines = [line];

  

  for (var i = 1; i < size - 1; i++) {

    lines.push(mid);

  }

  

  lines.push(line);

  

  console.log(lines.join('n'));

}



DrawSquare(8, '*');

If I was going to redraw the same thing several times I would change it to look like this:

const cache = {};



function DrawSquare(size, filler) {

  if (!cache[size]) {

    const line = filler.repeat(size);

    const mid = filler+' '.repeat(size-2)+filler;

    let lines = [line];



    for (var i = 1; i < size - 1; i++) {

      lines.push(mid);

    }



    lines.push(line);



    cache[size] = lines.join('n');

  }

  

  console.log(cache[size]);

}





console.time('first');

DrawSquare(12, '*');

console.timeEnd('first');



console.time('second');

DrawSquare(12, '*');

console.timeEnd('second');

function DrawSquare(size, filler) { 

  const line = filler.repeat(size);

  const mid = filler+' '.repeat(size-2)+filler;

  let lines = [line];

  

  for (var i = 1; i < size - 1; i++) {

    lines.push(mid);

  }

  

  lines.push(line);

  

  console.log(lines.join('n'));

}



DrawSquare(8, '*');

function DrawSquare(size, filler) { 

  const line = filler.repeat(size);

  const mid = filler+' '.repeat(size-2)+filler;

  let lines = [line];

  

  for (var i = 1; i < size - 1; i++) {

    lines.push(mid);

  }

  

  lines.push(line);

  

  console.log(lines.join('n'));

}



DrawSquare(8, '*');

const cache = {};



function DrawSquare(size, filler) {

  if (!cache[size]) {

    const line = filler.repeat(size);

    const mid = filler+' '.repeat(size-2)+filler;

    let lines = [line];



    for (var i = 1; i < size - 1; i++) {

      lines.push(mid);

    }



    lines.push(line);



    cache[size] = lines.join('n');

  }

  

  console.log(cache[size]);

}





console.time('first');

DrawSquare(12, '*');

console.timeEnd('first');



console.time('second');

DrawSquare(12, '*');

console.timeEnd('second');

const cache = {};



function DrawSquare(size, filler) {

  if (!cache[size]) {

    const line = filler.repeat(size);

    const mid = filler+' '.repeat(size-2)+filler;

    let lines = [line];



    for (var i = 1; i < size - 1; i++) {

      lines.push(mid);

    }



    lines.push(line);



    cache[size] = lines.join('n');

  }

  

  console.log(cache[size]);

}





console.time('first');

DrawSquare(12, '*');

console.timeEnd('first');



console.time('second');

DrawSquare(12, '*');

console.timeEnd('second');

answered Nov 23 '18 at 3:17

Intervalia

4,25611033

answered Nov 23 '18 at 3:17

Intervalia

4,25611033

answered Nov 23 '18 at 3:17

Intervalia

4,25611033

answered Nov 23 '18 at 3:17

Intervalia

4,25611033

add a comment |

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