How to prevent duplicate column rows in the MySQL database while keeping the order down
How can you please help me I have a table in the database with a column called "recioient_id"
The value of its rows is repeated more than once How do I prevent repeating rows while keeping the order descending and displaying the last row
I have tried so much without a find
I did this query and was good at preventing repetition and did not display the last row
Query which was:
SELECT *
FROM `messages`
WHERE `sender_id` = 1
GROUP BY `recioient_id` DESC
HAVING COUNT(*) >= 1
Here is a sample table
I hope to be successful in translation and hope to help
mysql sql
edited Nov 23 '18 at 3:02
Gordon Linoff
768k35300402
asked Nov 23 '18 at 2:56
salem715salem715
146
add a comment |
How can you please help me I have a table in the database with a column called "recioient_id"
The value of its rows is repeated more than once How do I prevent repeating rows while keeping the order descending and displaying the last row
I have tried so much without a find
I did this query and was good at preventing repetition and did not display the last row
Query which was:
SELECT *
FROM `messages`
WHERE `sender_id` = 1
GROUP BY `recioient_id` DESC
HAVING COUNT(*) >= 1
Here is a sample table
I hope to be successful in translation and hope to help
mysql sql
edited Nov 23 '18 at 3:02
Gordon Linoff
768k35300402
asked Nov 23 '18 at 2:56
salem715salem715
146
add a comment |
How can you please help me I have a table in the database with a column called "recioient_id"
The value of its rows is repeated more than once How do I prevent repeating rows while keeping the order descending and displaying the last row
I have tried so much without a find
I did this query and was good at preventing repetition and did not display the last row
Query which was:
SELECT *
FROM `messages`
WHERE `sender_id` = 1
GROUP BY `recioient_id` DESC
HAVING COUNT(*) >= 1
Here is a sample table
I hope to be successful in translation and hope to help
mysql sql
edited Nov 23 '18 at 3:02
Gordon Linoff
768k35300402
asked Nov 23 '18 at 2:56
salem715salem715
146
How can you please help me I have a table in the database with a column called "recioient_id"
The value of its rows is repeated more than once How do I prevent repeating rows while keeping the order descending and displaying the last row
I have tried so much without a find
I did this query and was good at preventing repetition and did not display the last row
Query which was:
SELECT *
FROM `messages`
WHERE `sender_id` = 1
GROUP BY `recioient_id` DESC
HAVING COUNT(*) >= 1
Here is a sample table
I hope to be successful in translation and hope to help
mysql sql
mysql sql
edited Nov 23 '18 at 3:02
Gordon Linoff
768k35300402
asked Nov 23 '18 at 2:56
salem715salem715
146
edited Nov 23 '18 at 3:02
Gordon Linoff
768k35300402
asked Nov 23 '18 at 2:56
salem715salem715
146
edited Nov 23 '18 at 3:02
Gordon Linoff
768k35300402
edited Nov 23 '18 at 3:02
Gordon Linoff
768k35300402
edited Nov 23 '18 at 3:02
Gordon Linoff
768k35300402
768k35300402
asked Nov 23 '18 at 2:56
salem715salem715
146
asked Nov 23 '18 at 2:56
salem715salem715
146
asked Nov 23 '18 at 2:56
salem715salem715
146
146
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
If you want one row per recioient_id, use filtering. I would recommend a correlated subquery:
SELECT m.*
FROM messages m
WHERE m.sender_id = 1 AND
m.messages_id = (SELECT MAX(m2.messages_id)
FROM messages m2
WHERE m2.sender_id = m.sender_id AND
m2.recioient_id = m.recioient_id
)
ORDER BY m.recioient_id;
answered Nov 23 '18 at 3:04
Gordon LinoffGordon Linoff
768k35300402
This is a good thank you but what about the descending order where I can put DESC
– salem715
Nov 23 '18 at 3:16
@salem715 . . . Add anorder byto the outermostselect, if you want the results in a particular order.
– Gordon Linoff
Nov 23 '18 at 3:21
Thank you. You've solved the descending order by your code. I owe you hope I can find a way to express my gratitude to you
– salem715
Nov 23 '18 at 3:25
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you want one row per recioient_id, use filtering. I would recommend a correlated subquery:
SELECT m.*
FROM messages m
WHERE m.sender_id = 1 AND
m.messages_id = (SELECT MAX(m2.messages_id)
FROM messages m2
WHERE m2.sender_id = m.sender_id AND
m2.recioient_id = m.recioient_id
)
ORDER BY m.recioient_id;
answered Nov 23 '18 at 3:04
Gordon LinoffGordon Linoff
768k35300402
This is a good thank you but what about the descending order where I can put DESC
– salem715
Nov 23 '18 at 3:16
@salem715 . . . Add anorder byto the outermostselect, if you want the results in a particular order.
– Gordon Linoff
Nov 23 '18 at 3:21
Thank you. You've solved the descending order by your code. I owe you hope I can find a way to express my gratitude to you
– salem715
Nov 23 '18 at 3:25
add a comment |
If you want one row per recioient_id, use filtering. I would recommend a correlated subquery:
SELECT m.*
FROM messages m
WHERE m.sender_id = 1 AND
m.messages_id = (SELECT MAX(m2.messages_id)
FROM messages m2
WHERE m2.sender_id = m.sender_id AND
m2.recioient_id = m.recioient_id
)
ORDER BY m.recioient_id;
answered Nov 23 '18 at 3:04
Gordon LinoffGordon Linoff
768k35300402
This is a good thank you but what about the descending order where I can put DESC
– salem715
Nov 23 '18 at 3:16
@salem715 . . . Add anorder byto the outermostselect, if you want the results in a particular order.
– Gordon Linoff
Nov 23 '18 at 3:21
Thank you. You've solved the descending order by your code. I owe you hope I can find a way to express my gratitude to you
– salem715
Nov 23 '18 at 3:25
add a comment |
If you want one row per recioient_id, use filtering. I would recommend a correlated subquery:
SELECT m.*
FROM messages m
WHERE m.sender_id = 1 AND
m.messages_id = (SELECT MAX(m2.messages_id)
FROM messages m2
WHERE m2.sender_id = m.sender_id AND
m2.recioient_id = m.recioient_id
)
ORDER BY m.recioient_id;
answered Nov 23 '18 at 3:04
Gordon LinoffGordon Linoff
768k35300402
If you want one row per recioient_id, use filtering. I would recommend a correlated subquery:
SELECT m.*
FROM messages m
WHERE m.sender_id = 1 AND
m.messages_id = (SELECT MAX(m2.messages_id)
FROM messages m2
WHERE m2.sender_id = m.sender_id AND
m2.recioient_id = m.recioient_id
)
ORDER BY m.recioient_id;
answered Nov 23 '18 at 3:04
Gordon LinoffGordon Linoff
768k35300402
edited Nov 23 '18 at 3:21
answered Nov 23 '18 at 3:04
Gordon LinoffGordon Linoff
768k35300402
answered Nov 23 '18 at 3:04
Gordon LinoffGordon Linoff
768k35300402
answered Nov 23 '18 at 3:04
Gordon LinoffGordon Linoff
768k35300402
768k35300402
This is a good thank you but what about the descending order where I can put DESC
– salem715
Nov 23 '18 at 3:16
@salem715 . . . Add anorder byto the outermostselect, if you want the results in a particular order.
– Gordon Linoff
Nov 23 '18 at 3:21
Thank you. You've solved the descending order by your code. I owe you hope I can find a way to express my gratitude to you
– salem715
Nov 23 '18 at 3:25
add a comment |
This is a good thank you but what about the descending order where I can put DESC
– salem715
Nov 23 '18 at 3:16
@salem715 . . . Add anorder byto the outermostselect, if you want the results in a particular order.
– Gordon Linoff
Nov 23 '18 at 3:21
Thank you. You've solved the descending order by your code. I owe you hope I can find a way to express my gratitude to you
– salem715
Nov 23 '18 at 3:25
This is a good thank you but what about the descending order where I can put DESC
– salem715
Nov 23 '18 at 3:16
This is a good thank you but what about the descending order where I can put DESC
– salem715
Nov 23 '18 at 3:16
@salem715 . . . Add an
order by to the outermost select, if you want the results in a particular order.– Gordon Linoff
Nov 23 '18 at 3:21
@salem715 . . . Add an
order by to the outermost select, if you want the results in a particular order.– Gordon Linoff
Nov 23 '18 at 3:21
Thank you. You've solved the descending order by your code. I owe you hope I can find a way to express my gratitude to you
– salem715
Nov 23 '18 at 3:25
Thank you. You've solved the descending order by your code. I owe you hope I can find a way to express my gratitude to you
– salem715
Nov 23 '18 at 3:25
add a comment |
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