Converting a text file to Map<String, List> using lambda












7















I am trying to convert the following text input file:



A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2


into Map<String, List<String>> by splitting each line on "="



So far I manged to get this sort of output:



KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2


using such code:



File reqFile = new File("test.config");

try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}


How to tweak the above lambda to get something like this:



KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2









share|improve this question









New contributor




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  • 2





    much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.

    – Jarrod Roberson
    3 hours ago
















7















I am trying to convert the following text input file:



A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2


into Map<String, List<String>> by splitting each line on "="



So far I manged to get this sort of output:



KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2


using such code:



File reqFile = new File("test.config");

try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}


How to tweak the above lambda to get something like this:



KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2









share|improve this question









New contributor




BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 2





    much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.

    – Jarrod Roberson
    3 hours ago














7












7








7


1






I am trying to convert the following text input file:



A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2


into Map<String, List<String>> by splitting each line on "="



So far I manged to get this sort of output:



KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2


using such code:



File reqFile = new File("test.config");

try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}


How to tweak the above lambda to get something like this:



KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2









share|improve this question









New contributor




BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I am trying to convert the following text input file:



A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2


into Map<String, List<String>> by splitting each line on "="



So far I manged to get this sort of output:



KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2


using such code:



File reqFile = new File("test.config");

try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}


How to tweak the above lambda to get something like this:



KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2






java java-8 java-stream






share|improve this question









New contributor




BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









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Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 3 hours ago









Deadpool

5,1822528




5,1822528






New contributor




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Check out our Code of Conduct.









asked 3 hours ago









BartDBartD

383




383




New contributor




BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 2





    much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.

    – Jarrod Roberson
    3 hours ago














  • 2





    much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.

    – Jarrod Roberson
    3 hours ago








2




2





much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.

– Jarrod Roberson
3 hours ago





much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.

– Jarrod Roberson
3 hours ago












4 Answers
4






active

oldest

votes


















3














Map and collect:



Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);


Or map and group by:



Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));




  1. Stream.collect documentation






share|improve this answer


























  • This one also works nicely! Thank you @Michał Ziober

    – BartD
    3 hours ago











  • No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.

    – Michał Ziober
    3 hours ago



















2














Use Collectors.mapping while groupingBy, for more information look at this doc-with-example



Map<String, List<String>> conf = stream.    
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));

System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}





share|improve this answer





















  • 1





    That is exactly what I was looking for! Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList()))); and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2

    – BartD
    3 hours ago





















0














If you are open to using a third-party library, the following will work using Eclipse Collections.



ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));


Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.



Note: I am a committer for Eclipse Collections.






share|improve this answer































    0














    I would rather use apre-compiled Regex Pattern instead of string methods to get the work done. Here's how it looks in practice.



    private static final Pattern COMMA_DELIMITER = Pattern.compile("=");

    Map<String, List<String>> keyToValuesMap = lines
    .map(l -> COMMA_DELIMITER.splitAsStream(l).toArray(String::new))
    .collect(Collectors.groupingBy(a -> a[0], Collectors.mapping(a -> a[1],
    Collectors.toList())));


    Incidentally use specific exceptions instead of generic Exception. In your case substitute Exception with the specific IOException in your catch block. For a larger data set this approach should definitely outperform others that uses string manipulation.





    share























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      4 Answers
      4






      active

      oldest

      votes








      4 Answers
      4






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3














      Map and collect:



      Map<String, List<String>> res = lines.stream()
      .map(s -> Arrays.asList(s.split("=")))
      .collect(HashMap::new,
      (map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
      HashMap::putAll);


      Or map and group by:



      Map<String, List<String>> res = lines.stream()
      .map(s -> Arrays.asList(s.split("=")))
      .collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));




      1. Stream.collect documentation






      share|improve this answer


























      • This one also works nicely! Thank you @Michał Ziober

        – BartD
        3 hours ago











      • No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.

        – Michał Ziober
        3 hours ago
















      3














      Map and collect:



      Map<String, List<String>> res = lines.stream()
      .map(s -> Arrays.asList(s.split("=")))
      .collect(HashMap::new,
      (map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
      HashMap::putAll);


      Or map and group by:



      Map<String, List<String>> res = lines.stream()
      .map(s -> Arrays.asList(s.split("=")))
      .collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));




      1. Stream.collect documentation






      share|improve this answer


























      • This one also works nicely! Thank you @Michał Ziober

        – BartD
        3 hours ago











      • No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.

        – Michał Ziober
        3 hours ago














      3












      3








      3







      Map and collect:



      Map<String, List<String>> res = lines.stream()
      .map(s -> Arrays.asList(s.split("=")))
      .collect(HashMap::new,
      (map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
      HashMap::putAll);


      Or map and group by:



      Map<String, List<String>> res = lines.stream()
      .map(s -> Arrays.asList(s.split("=")))
      .collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));




      1. Stream.collect documentation






      share|improve this answer















      Map and collect:



      Map<String, List<String>> res = lines.stream()
      .map(s -> Arrays.asList(s.split("=")))
      .collect(HashMap::new,
      (map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
      HashMap::putAll);


      Or map and group by:



      Map<String, List<String>> res = lines.stream()
      .map(s -> Arrays.asList(s.split("=")))
      .collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));




      1. Stream.collect documentation







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited 3 hours ago

























      answered 3 hours ago









      Michał ZioberMichał Ziober

      12.9k967101




      12.9k967101













      • This one also works nicely! Thank you @Michał Ziober

        – BartD
        3 hours ago











      • No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.

        – Michał Ziober
        3 hours ago



















      • This one also works nicely! Thank you @Michał Ziober

        – BartD
        3 hours ago











      • No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.

        – Michał Ziober
        3 hours ago

















      This one also works nicely! Thank you @Michał Ziober

      – BartD
      3 hours ago





      This one also works nicely! Thank you @Michał Ziober

      – BartD
      3 hours ago













      No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.

      – Michał Ziober
      3 hours ago





      No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.

      – Michał Ziober
      3 hours ago













      2














      Use Collectors.mapping while groupingBy, for more information look at this doc-with-example



      Map<String, List<String>> conf = stream.    
      collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));

      System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}





      share|improve this answer





















      • 1





        That is exactly what I was looking for! Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList()))); and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2

        – BartD
        3 hours ago


















      2














      Use Collectors.mapping while groupingBy, for more information look at this doc-with-example



      Map<String, List<String>> conf = stream.    
      collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));

      System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}





      share|improve this answer





















      • 1





        That is exactly what I was looking for! Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList()))); and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2

        – BartD
        3 hours ago
















      2












      2








      2







      Use Collectors.mapping while groupingBy, for more information look at this doc-with-example



      Map<String, List<String>> conf = stream.    
      collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));

      System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}





      share|improve this answer















      Use Collectors.mapping while groupingBy, for more information look at this doc-with-example



      Map<String, List<String>> conf = stream.    
      collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));

      System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited 3 hours ago

























      answered 3 hours ago









      DeadpoolDeadpool

      5,1822528




      5,1822528








      • 1





        That is exactly what I was looking for! Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList()))); and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2

        – BartD
        3 hours ago
















      • 1





        That is exactly what I was looking for! Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList()))); and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2

        – BartD
        3 hours ago










      1




      1





      That is exactly what I was looking for! Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList()))); and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2

      – BartD
      3 hours ago







      That is exactly what I was looking for! Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList()))); and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2

      – BartD
      3 hours ago













      0














      If you are open to using a third-party library, the following will work using Eclipse Collections.



      ListMultimap<String, String> strings = stream
      .map(s -> s.split("="))
      .collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));


      Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.



      Note: I am a committer for Eclipse Collections.






      share|improve this answer




























        0














        If you are open to using a third-party library, the following will work using Eclipse Collections.



        ListMultimap<String, String> strings = stream
        .map(s -> s.split("="))
        .collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));


        Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.



        Note: I am a committer for Eclipse Collections.






        share|improve this answer


























          0












          0








          0







          If you are open to using a third-party library, the following will work using Eclipse Collections.



          ListMultimap<String, String> strings = stream
          .map(s -> s.split("="))
          .collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));


          Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.



          Note: I am a committer for Eclipse Collections.






          share|improve this answer













          If you are open to using a third-party library, the following will work using Eclipse Collections.



          ListMultimap<String, String> strings = stream
          .map(s -> s.split("="))
          .collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));


          Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.



          Note: I am a committer for Eclipse Collections.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 23 mins ago









          Donald RaabDonald Raab

          4,26112029




          4,26112029























              0














              I would rather use apre-compiled Regex Pattern instead of string methods to get the work done. Here's how it looks in practice.



              private static final Pattern COMMA_DELIMITER = Pattern.compile("=");

              Map<String, List<String>> keyToValuesMap = lines
              .map(l -> COMMA_DELIMITER.splitAsStream(l).toArray(String::new))
              .collect(Collectors.groupingBy(a -> a[0], Collectors.mapping(a -> a[1],
              Collectors.toList())));


              Incidentally use specific exceptions instead of generic Exception. In your case substitute Exception with the specific IOException in your catch block. For a larger data set this approach should definitely outperform others that uses string manipulation.





              share




























                0














                I would rather use apre-compiled Regex Pattern instead of string methods to get the work done. Here's how it looks in practice.



                private static final Pattern COMMA_DELIMITER = Pattern.compile("=");

                Map<String, List<String>> keyToValuesMap = lines
                .map(l -> COMMA_DELIMITER.splitAsStream(l).toArray(String::new))
                .collect(Collectors.groupingBy(a -> a[0], Collectors.mapping(a -> a[1],
                Collectors.toList())));


                Incidentally use specific exceptions instead of generic Exception. In your case substitute Exception with the specific IOException in your catch block. For a larger data set this approach should definitely outperform others that uses string manipulation.





                share


























                  0












                  0








                  0







                  I would rather use apre-compiled Regex Pattern instead of string methods to get the work done. Here's how it looks in practice.



                  private static final Pattern COMMA_DELIMITER = Pattern.compile("=");

                  Map<String, List<String>> keyToValuesMap = lines
                  .map(l -> COMMA_DELIMITER.splitAsStream(l).toArray(String::new))
                  .collect(Collectors.groupingBy(a -> a[0], Collectors.mapping(a -> a[1],
                  Collectors.toList())));


                  Incidentally use specific exceptions instead of generic Exception. In your case substitute Exception with the specific IOException in your catch block. For a larger data set this approach should definitely outperform others that uses string manipulation.





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                  I would rather use apre-compiled Regex Pattern instead of string methods to get the work done. Here's how it looks in practice.



                  private static final Pattern COMMA_DELIMITER = Pattern.compile("=");

                  Map<String, List<String>> keyToValuesMap = lines
                  .map(l -> COMMA_DELIMITER.splitAsStream(l).toArray(String::new))
                  .collect(Collectors.groupingBy(a -> a[0], Collectors.mapping(a -> a[1],
                  Collectors.toList())));


                  Incidentally use specific exceptions instead of generic Exception. In your case substitute Exception with the specific IOException in your catch block. For a larger data set this approach should definitely outperform others that uses string manipulation.






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                  answered 1 min ago









                  Ravindra RanwalaRavindra Ranwala

                  9,09531634




                  9,09531634






















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