Converting a text file to Map<String, List> using lambda
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>>
by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
New contributor
add a comment |
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>>
by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
New contributor
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
add a comment |
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>>
by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
New contributor
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>>
by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
java java-8 java-stream
New contributor
New contributor
edited 3 hours ago
Deadpool
5,1822528
5,1822528
New contributor
asked 3 hours ago
BartDBartD
383
383
New contributor
New contributor
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
add a comment |
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
2
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
add a comment |
4 Answers
4
active
oldest
votes
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collect
documentation
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
add a comment |
Use Collectors.mapping
while groupingBy
, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap
takes a Function
to calculate the key and a separate Function
to calculate the value. The ListMultimap<K, V>
type is equivalent to Map<K, List<V>>
.
Note: I am a committer for Eclipse Collections.
add a comment |
I would rather use apre-compiled Regex Pattern instead of string methods to get the work done. Here's how it looks in practice.
private static final Pattern COMMA_DELIMITER = Pattern.compile("=");
Map<String, List<String>> keyToValuesMap = lines
.map(l -> COMMA_DELIMITER.splitAsStream(l).toArray(String::new))
.collect(Collectors.groupingBy(a -> a[0], Collectors.mapping(a -> a[1],
Collectors.toList())));
Incidentally use specific exceptions instead of generic Exception
. In your case substitute Exception
with the specific IOException
in your catch block. For a larger data set this approach should definitely outperform others that uses string manipulation.
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
BartD is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54383490%2fconverting-a-text-file-to-mapstring-liststring-using-lambda%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collect
documentation
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
add a comment |
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collect
documentation
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
add a comment |
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collect
documentation
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collect
documentation
edited 3 hours ago
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
12.9k967101
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
add a comment |
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
3 hours ago
add a comment |
Use Collectors.mapping
while groupingBy
, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
Use Collectors.mapping
while groupingBy
, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
Use Collectors.mapping
while groupingBy
, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
Use Collectors.mapping
while groupingBy
, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
edited 3 hours ago
answered 3 hours ago
DeadpoolDeadpool
5,1822528
5,1822528
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
1
1
That is exactly what I was looking for!
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
That is exactly what I was looking for!
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap
takes a Function
to calculate the key and a separate Function
to calculate the value. The ListMultimap<K, V>
type is equivalent to Map<K, List<V>>
.
Note: I am a committer for Eclipse Collections.
add a comment |
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap
takes a Function
to calculate the key and a separate Function
to calculate the value. The ListMultimap<K, V>
type is equivalent to Map<K, List<V>>
.
Note: I am a committer for Eclipse Collections.
add a comment |
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap
takes a Function
to calculate the key and a separate Function
to calculate the value. The ListMultimap<K, V>
type is equivalent to Map<K, List<V>>
.
Note: I am a committer for Eclipse Collections.
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap
takes a Function
to calculate the key and a separate Function
to calculate the value. The ListMultimap<K, V>
type is equivalent to Map<K, List<V>>
.
Note: I am a committer for Eclipse Collections.
answered 23 mins ago
Donald RaabDonald Raab
4,26112029
4,26112029
add a comment |
add a comment |
I would rather use apre-compiled Regex Pattern instead of string methods to get the work done. Here's how it looks in practice.
private static final Pattern COMMA_DELIMITER = Pattern.compile("=");
Map<String, List<String>> keyToValuesMap = lines
.map(l -> COMMA_DELIMITER.splitAsStream(l).toArray(String::new))
.collect(Collectors.groupingBy(a -> a[0], Collectors.mapping(a -> a[1],
Collectors.toList())));
Incidentally use specific exceptions instead of generic Exception
. In your case substitute Exception
with the specific IOException
in your catch block. For a larger data set this approach should definitely outperform others that uses string manipulation.
add a comment |
I would rather use apre-compiled Regex Pattern instead of string methods to get the work done. Here's how it looks in practice.
private static final Pattern COMMA_DELIMITER = Pattern.compile("=");
Map<String, List<String>> keyToValuesMap = lines
.map(l -> COMMA_DELIMITER.splitAsStream(l).toArray(String::new))
.collect(Collectors.groupingBy(a -> a[0], Collectors.mapping(a -> a[1],
Collectors.toList())));
Incidentally use specific exceptions instead of generic Exception
. In your case substitute Exception
with the specific IOException
in your catch block. For a larger data set this approach should definitely outperform others that uses string manipulation.
add a comment |
I would rather use apre-compiled Regex Pattern instead of string methods to get the work done. Here's how it looks in practice.
private static final Pattern COMMA_DELIMITER = Pattern.compile("=");
Map<String, List<String>> keyToValuesMap = lines
.map(l -> COMMA_DELIMITER.splitAsStream(l).toArray(String::new))
.collect(Collectors.groupingBy(a -> a[0], Collectors.mapping(a -> a[1],
Collectors.toList())));
Incidentally use specific exceptions instead of generic Exception
. In your case substitute Exception
with the specific IOException
in your catch block. For a larger data set this approach should definitely outperform others that uses string manipulation.
I would rather use apre-compiled Regex Pattern instead of string methods to get the work done. Here's how it looks in practice.
private static final Pattern COMMA_DELIMITER = Pattern.compile("=");
Map<String, List<String>> keyToValuesMap = lines
.map(l -> COMMA_DELIMITER.splitAsStream(l).toArray(String::new))
.collect(Collectors.groupingBy(a -> a[0], Collectors.mapping(a -> a[1],
Collectors.toList())));
Incidentally use specific exceptions instead of generic Exception
. In your case substitute Exception
with the specific IOException
in your catch block. For a larger data set this approach should definitely outperform others that uses string manipulation.
answered 1 min ago
Ravindra RanwalaRavindra Ranwala
9,09531634
9,09531634
add a comment |
add a comment |
BartD is a new contributor. Be nice, and check out our Code of Conduct.
BartD is a new contributor. Be nice, and check out our Code of Conduct.
BartD is a new contributor. Be nice, and check out our Code of Conduct.
BartD is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54383490%2fconverting-a-text-file-to-mapstring-liststring-using-lambda%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago