Split an array with commas, except the last item with “and” e.g. (['one', 'two', 'three', 'four'] ->...
6
I want to convert the array ['one', 'two', 'three', 'four'] into one, two, three and four
Note that the first items have a comma, and but there is the word and between the second-last one and the last one.
The best solution I've come up with:
a.reduce( (res, v, i) => i === a.length - 2 ? res + v + ' and ' : res + v + ( i == a.length -1? '' : ', '), '' )
It's based on adding the commas at the end -- with the exception of the second-last one (a.length - 2) and with a way to avoid the last comma (a.length - 2).
SURELY there must be a better, neater, more intelligent way to do this?
It's a difficult topic to search on search engines because it contains the word "and"...
javascript arrays string
asked 1 hour ago
Merc
6,76294785
add a comment |
6
I want to convert the array ['one', 'two', 'three', 'four'] into one, two, three and four
Note that the first items have a comma, and but there is the word and between the second-last one and the last one.
The best solution I've come up with:
a.reduce( (res, v, i) => i === a.length - 2 ? res + v + ' and ' : res + v + ( i == a.length -1? '' : ', '), '' )
It's based on adding the commas at the end -- with the exception of the second-last one (a.length - 2) and with a way to avoid the last comma (a.length - 2).
SURELY there must be a better, neater, more intelligent way to do this?
It's a difficult topic to search on search engines because it contains the word "and"...
javascript arrays string
asked 1 hour ago
Merc
6,76294785
SURELY you value the serial/Oxford comma?!?
– Argalatyr
12 mins ago
You mean I should returnone, two, three, and four?
– Merc
just now
add a comment |
6
6
6
I want to convert the array ['one', 'two', 'three', 'four'] into one, two, three and four
Note that the first items have a comma, and but there is the word and between the second-last one and the last one.
The best solution I've come up with:
a.reduce( (res, v, i) => i === a.length - 2 ? res + v + ' and ' : res + v + ( i == a.length -1? '' : ', '), '' )
It's based on adding the commas at the end -- with the exception of the second-last one (a.length - 2) and with a way to avoid the last comma (a.length - 2).
SURELY there must be a better, neater, more intelligent way to do this?
It's a difficult topic to search on search engines because it contains the word "and"...
javascript arrays string
asked 1 hour ago
Merc
6,76294785
I want to convert the array ['one', 'two', 'three', 'four'] into one, two, three and four
Note that the first items have a comma, and but there is the word and between the second-last one and the last one.
The best solution I've come up with:
a.reduce( (res, v, i) => i === a.length - 2 ? res + v + ' and ' : res + v + ( i == a.length -1? '' : ', '), '' )
It's based on adding the commas at the end -- with the exception of the second-last one (a.length - 2) and with a way to avoid the last comma (a.length - 2).
SURELY there must be a better, neater, more intelligent way to do this?
It's a difficult topic to search on search engines because it contains the word "and"...
javascript arrays string
javascript arrays string
asked 1 hour ago
Merc
6,76294785
asked 1 hour ago
Merc
6,76294785
asked 1 hour ago
Merc
6,76294785
asked 1 hour ago
Merc
6,76294785
asked 1 hour ago
Merc
6,76294785
6,76294785
SURELY you value the serial/Oxford comma?!?
– Argalatyr
12 mins ago
You mean I should returnone, two, three, and four?
– Merc
just now
add a comment |
SURELY you value the serial/Oxford comma?!?
– Argalatyr
12 mins ago
You mean I should returnone, two, three, and four?
– Merc
just now
SURELY you value the serial/Oxford comma?!?
– Argalatyr
12 mins ago
SURELY you value the serial/Oxford comma?!?
– Argalatyr
12 mins ago
You mean I should return
one, two, three, and four?– Merc
just now
You mean I should return
one, two, three, and four?– Merc
just now
add a comment |
4 Answers
4
active
oldest
votes
8
One option would be to pop the last item, then join all the rest by commas, and concatenate with and plus the last item:
const input = ['one', 'two', 'three', 'four'];
const last = input.pop();
const result = input.join(', ') + ' and ' + last;
console.log(result);answered 1 hour ago
CertainPerformance
73.4k143454
Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
– user2864740
1 hour ago
1
I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
– Merc
1 hour ago
I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
– Merc
1 hour ago
2
Very nice, thought the lack of the Oxford comma is killing me.
– Mark Meyer
1 hour ago
As an echo to an other answer, you may want to pushlastback ininput(you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
– Kaiido
54 mins ago
add a comment |
2
Another approach could be using the splice method to remove the last two elements of the array and then join they using and. After this, you could push this result again on the array and finally join using the , separator.
let input = ['one', 'two', 'three', 'four'];
let removed = input.splice(-2, 2);
input.push(removed.join(" and "));
console.log(input.join(", "));answered 58 mins ago
Shidersz
3,3011425
add a comment |
1
You can use Array.prototype.slice()
Code:
const input = ['one', 'two', 'three', 'four'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);And works with more complex data input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
Code:
const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);answered 1 hour ago
Yosvel Quintero
10.9k42229
Easy to introduce subtle issues that'll be found later (outside of a restricted set of input):['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
– user2864740
1 hour ago
@user2864740 Good comment, thanks
– Yosvel Quintero
1 hour ago
1
@user2864740 I have updated my answer for that type ofinputdata..
– Yosvel Quintero
1 hour ago
add a comment |
1
I like Mark Meyer's approach (and would upvote if I had the rep) as it doesn't alter the input. Here's my spin:
function makeCommaSeparatedString(arr, useOxfordComma) {
const listStart = arr.slice(0, -1).join(', ');
const listEnd = arr.slice(-1);
const conjunction = arr.length <= 1 ? '' :
useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
return [listStart, listEnd].join(conjunction);
}
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
// one, two, three and four
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
// one, two, three, and four
console.log(makeCommaSeparatedString(['one', 'two'], true));
// one and two
console.log(makeCommaSeparatedString(['one']));
// one
console.log(makeCommaSeparatedString());
// answered 29 mins ago
Jug
261
New contributor
Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
8
One option would be to pop the last item, then join all the rest by commas, and concatenate with and plus the last item:
const input = ['one', 'two', 'three', 'four'];
const last = input.pop();
const result = input.join(', ') + ' and ' + last;
console.log(result);answered 1 hour ago
CertainPerformance
73.4k143454
Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
– user2864740
1 hour ago
1
I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
– Merc
1 hour ago
I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
– Merc
1 hour ago
2
Very nice, thought the lack of the Oxford comma is killing me.
– Mark Meyer
1 hour ago
As an echo to an other answer, you may want to pushlastback ininput(you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
– Kaiido
54 mins ago
add a comment |
8
One option would be to pop the last item, then join all the rest by commas, and concatenate with and plus the last item:
const input = ['one', 'two', 'three', 'four'];
const last = input.pop();
const result = input.join(', ') + ' and ' + last;
console.log(result);answered 1 hour ago
CertainPerformance
73.4k143454
Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
– user2864740
1 hour ago
1
I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
– Merc
1 hour ago
I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
– Merc
1 hour ago
2
Very nice, thought the lack of the Oxford comma is killing me.
– Mark Meyer
1 hour ago
As an echo to an other answer, you may want to pushlastback ininput(you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
– Kaiido
54 mins ago
add a comment |
8
8
8
One option would be to pop the last item, then join all the rest by commas, and concatenate with and plus the last item:
const input = ['one', 'two', 'three', 'four'];
const last = input.pop();
const result = input.join(', ') + ' and ' + last;
console.log(result);answered 1 hour ago
CertainPerformance
73.4k143454
One option would be to pop the last item, then join all the rest by commas, and concatenate with and plus the last item:
const input = ['one', 'two', 'three', 'four'];
const last = input.pop();
const result = input.join(', ') + ' and ' + last;
console.log(result);const input = ['one', 'two', 'three', 'four'];
const last = input.pop();
const result = input.join(', ') + ' and ' + last;
console.log(result);const input = ['one', 'two', 'three', 'four'];
const last = input.pop();
const result = input.join(', ') + ' and ' + last;
console.log(result);answered 1 hour ago
CertainPerformance
73.4k143454
answered 1 hour ago
CertainPerformance
73.4k143454
answered 1 hour ago
CertainPerformance
73.4k143454
answered 1 hour ago
CertainPerformance
73.4k143454
73.4k143454
Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
– user2864740
1 hour ago
1
I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
– Merc
1 hour ago
I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
– Merc
1 hour ago
2
Very nice, thought the lack of the Oxford comma is killing me.
– Mark Meyer
1 hour ago
As an echo to an other answer, you may want to pushlastback ininput(you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
– Kaiido
54 mins ago
add a comment |
Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
– user2864740
1 hour ago
1
I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
– Merc
1 hour ago
I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
– Merc
1 hour ago
2
Very nice, thought the lack of the Oxford comma is killing me.
– Mark Meyer
1 hour ago
As an echo to an other answer, you may want to pushlastback ininput(you know, "modifying the inputs when it's not the output is bad" and stuff like that...)
– Kaiido
54 mins ago
Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
– user2864740
1 hour ago
Might have to be some guards on lengths, and it's the same-same approach I'd probably recommend.
– user2864740
1 hour ago
1
1
I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
– Merc
1 hour ago
I love this, and it's just so simple -- especially simple to read (I am a great fan of code maintenance)
– Merc
1 hour ago
I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
– Merc
1 hour ago
I think this is hard to beat, but I am waiting a little before accepting in case it attracts even better answers. But, I love it
– Merc
1 hour ago
2
2
Very nice, thought the lack of the Oxford comma is killing me.
– Mark Meyer
1 hour ago
Very nice, thought the lack of the Oxford comma is killing me.
– Mark Meyer
1 hour ago
As an echo to an other answer, you may want to push
last back in input (you know, "modifying the inputs when it's not the output is bad" and stuff like that...)– Kaiido
54 mins ago
As an echo to an other answer, you may want to push
last back in input (you know, "modifying the inputs when it's not the output is bad" and stuff like that...)– Kaiido
54 mins ago
add a comment |
2
Another approach could be using the splice method to remove the last two elements of the array and then join they using and. After this, you could push this result again on the array and finally join using the , separator.
let input = ['one', 'two', 'three', 'four'];
let removed = input.splice(-2, 2);
input.push(removed.join(" and "));
console.log(input.join(", "));answered 58 mins ago
Shidersz
3,3011425
add a comment |
2
Another approach could be using the splice method to remove the last two elements of the array and then join they using and. After this, you could push this result again on the array and finally join using the , separator.
let input = ['one', 'two', 'three', 'four'];
let removed = input.splice(-2, 2);
input.push(removed.join(" and "));
console.log(input.join(", "));answered 58 mins ago
Shidersz
3,3011425
add a comment |
2
2
2
Another approach could be using the splice method to remove the last two elements of the array and then join they using and. After this, you could push this result again on the array and finally join using the , separator.
let input = ['one', 'two', 'three', 'four'];
let removed = input.splice(-2, 2);
input.push(removed.join(" and "));
console.log(input.join(", "));answered 58 mins ago
Shidersz
3,3011425
Another approach could be using the splice method to remove the last two elements of the array and then join they using and. After this, you could push this result again on the array and finally join using the , separator.
let input = ['one', 'two', 'three', 'four'];
let removed = input.splice(-2, 2);
input.push(removed.join(" and "));
console.log(input.join(", "));let input = ['one', 'two', 'three', 'four'];
let removed = input.splice(-2, 2);
input.push(removed.join(" and "));
console.log(input.join(", "));let input = ['one', 'two', 'three', 'four'];
let removed = input.splice(-2, 2);
input.push(removed.join(" and "));
console.log(input.join(", "));answered 58 mins ago
Shidersz
3,3011425
edited 21 mins ago
answered 58 mins ago
Shidersz
3,3011425
answered 58 mins ago
Shidersz
3,3011425
answered 58 mins ago
Shidersz
3,3011425
3,3011425
add a comment |
add a comment |
1
You can use Array.prototype.slice()
Code:
const input = ['one', 'two', 'three', 'four'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);And works with more complex data input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
Code:
const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);answered 1 hour ago
Yosvel Quintero
10.9k42229
Easy to introduce subtle issues that'll be found later (outside of a restricted set of input):['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
– user2864740
1 hour ago
@user2864740 Good comment, thanks
– Yosvel Quintero
1 hour ago
1
@user2864740 I have updated my answer for that type ofinputdata..
– Yosvel Quintero
1 hour ago
add a comment |
1
You can use Array.prototype.slice()
Code:
const input = ['one', 'two', 'three', 'four'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);And works with more complex data input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
Code:
const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);answered 1 hour ago
Yosvel Quintero
10.9k42229
Easy to introduce subtle issues that'll be found later (outside of a restricted set of input):['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
– user2864740
1 hour ago
@user2864740 Good comment, thanks
– Yosvel Quintero
1 hour ago
1
@user2864740 I have updated my answer for that type ofinputdata..
– Yosvel Quintero
1 hour ago
add a comment |
1
1
1
You can use Array.prototype.slice()
Code:
const input = ['one', 'two', 'three', 'four'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);And works with more complex data input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
Code:
const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);answered 1 hour ago
Yosvel Quintero
10.9k42229
You can use Array.prototype.slice()
Code:
const input = ['one', 'two', 'three', 'four'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);And works with more complex data input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
Code:
const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);const input = ['one', 'two', 'three', 'four'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);const input = ['one', 'two', 'three', 'four'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);const input = ['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish'];
const result = `${input.slice(0, -1).join(', ')} and ${input.slice(-1)}`;
console.log(result);answered 1 hour ago
Yosvel Quintero
10.9k42229
edited 57 mins ago
answered 1 hour ago
Yosvel Quintero
10.9k42229
answered 1 hour ago
Yosvel Quintero
10.9k42229
answered 1 hour ago
Yosvel Quintero
10.9k42229
10.9k42229
Easy to introduce subtle issues that'll be found later (outside of a restricted set of input):['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
– user2864740
1 hour ago
@user2864740 Good comment, thanks
– Yosvel Quintero
1 hour ago
1
@user2864740 I have updated my answer for that type ofinputdata..
– Yosvel Quintero
1 hour ago
add a comment |
Easy to introduce subtle issues that'll be found later (outside of a restricted set of input):['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']
– user2864740
1 hour ago
@user2864740 Good comment, thanks
– Yosvel Quintero
1 hour ago
1
@user2864740 I have updated my answer for that type ofinputdata..
– Yosvel Quintero
1 hour ago
Easy to introduce subtle issues that'll be found later (outside of a restricted set of input):
['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']– user2864740
1 hour ago
Easy to introduce subtle issues that'll be found later (outside of a restricted set of input):
['A Tale of Two Cities', 'Harry Potter and the smth', 'One Fish, Two Fish, Red Fish, Blue Fish']– user2864740
1 hour ago
@user2864740 Good comment, thanks
– Yosvel Quintero
1 hour ago
@user2864740 Good comment, thanks
– Yosvel Quintero
1 hour ago
1
1
@user2864740 I have updated my answer for that type of
input data..– Yosvel Quintero
1 hour ago
@user2864740 I have updated my answer for that type of
input data..– Yosvel Quintero
1 hour ago
add a comment |
1
I like Mark Meyer's approach (and would upvote if I had the rep) as it doesn't alter the input. Here's my spin:
function makeCommaSeparatedString(arr, useOxfordComma) {
const listStart = arr.slice(0, -1).join(', ');
const listEnd = arr.slice(-1);
const conjunction = arr.length <= 1 ? '' :
useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
return [listStart, listEnd].join(conjunction);
}
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
// one, two, three and four
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
// one, two, three, and four
console.log(makeCommaSeparatedString(['one', 'two'], true));
// one and two
console.log(makeCommaSeparatedString(['one']));
// one
console.log(makeCommaSeparatedString());
// answered 29 mins ago
Jug
261
New contributor
Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
1
I like Mark Meyer's approach (and would upvote if I had the rep) as it doesn't alter the input. Here's my spin:
function makeCommaSeparatedString(arr, useOxfordComma) {
const listStart = arr.slice(0, -1).join(', ');
const listEnd = arr.slice(-1);
const conjunction = arr.length <= 1 ? '' :
useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
return [listStart, listEnd].join(conjunction);
}
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
// one, two, three and four
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
// one, two, three, and four
console.log(makeCommaSeparatedString(['one', 'two'], true));
// one and two
console.log(makeCommaSeparatedString(['one']));
// one
console.log(makeCommaSeparatedString());
// answered 29 mins ago
Jug
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I like Mark Meyer's approach (and would upvote if I had the rep) as it doesn't alter the input. Here's my spin:
function makeCommaSeparatedString(arr, useOxfordComma) {
const listStart = arr.slice(0, -1).join(', ');
const listEnd = arr.slice(-1);
const conjunction = arr.length <= 1 ? '' :
useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
return [listStart, listEnd].join(conjunction);
}
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
// one, two, three and four
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
// one, two, three, and four
console.log(makeCommaSeparatedString(['one', 'two'], true));
// one and two
console.log(makeCommaSeparatedString(['one']));
// one
console.log(makeCommaSeparatedString());
// answered 29 mins ago
Jug
261
New contributor
Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I like Mark Meyer's approach (and would upvote if I had the rep) as it doesn't alter the input. Here's my spin:
function makeCommaSeparatedString(arr, useOxfordComma) {
const listStart = arr.slice(0, -1).join(', ');
const listEnd = arr.slice(-1);
const conjunction = arr.length <= 1 ? '' :
useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
return [listStart, listEnd].join(conjunction);
}
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
// one, two, three and four
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
// one, two, three, and four
console.log(makeCommaSeparatedString(['one', 'two'], true));
// one and two
console.log(makeCommaSeparatedString(['one']));
// one
console.log(makeCommaSeparatedString());
// function makeCommaSeparatedString(arr, useOxfordComma) {
const listStart = arr.slice(0, -1).join(', ');
const listEnd = arr.slice(-1);
const conjunction = arr.length <= 1 ? '' :
useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
return [listStart, listEnd].join(conjunction);
}
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
// one, two, three and four
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
// one, two, three, and four
console.log(makeCommaSeparatedString(['one', 'two'], true));
// one and two
console.log(makeCommaSeparatedString(['one']));
// one
console.log(makeCommaSeparatedString());
// function makeCommaSeparatedString(arr, useOxfordComma) {
const listStart = arr.slice(0, -1).join(', ');
const listEnd = arr.slice(-1);
const conjunction = arr.length <= 1 ? '' :
useOxfordComma && arr.length > 2 ? ', and ' : ' and ';
return [listStart, listEnd].join(conjunction);
}
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four']));
// one, two, three and four
console.log(makeCommaSeparatedString(['one', 'two', 'three', 'four'], true));
// one, two, three, and four
console.log(makeCommaSeparatedString(['one', 'two'], true));
// one and two
console.log(makeCommaSeparatedString(['one']));
// one
console.log(makeCommaSeparatedString());
// answered 29 mins ago
Jug
261
New contributor
Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 29 mins ago
Jug
261
New contributor
Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 29 mins ago
Jug
261
answered 29 mins ago
Jug
261
261
New contributor
Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Jug is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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SURELY you value the serial/Oxford comma?!?
– Argalatyr
12 mins ago
You mean I should return
one, two, three, and four?– Merc
just now