data type is not recognizable using Threads in Python
I am trying to make a calculation code using threads in Python. My code is the following:
from threading import Thread
from time import sleep
class Fact(Thread):
def __init__(self, start, end):
Thread.__init__(self)
self.start = start
self.end = end
def factorial(self):
p = 1
for i in range(self.start, self.end):
p = p * i
return p
def run(self):
global s
s = s + self.factorial()
sleep(2)
print ("output is ", s)
s = 0
def main():
n = 6
mid = n / 2
obj1 = Fact(1, mid)
obj1.start()
obj2 = Fact(mid + 1, n)
obj2.start()
if __name__ == "__main__":
main()
What I want is to compute, iteratively, the factorial of a number. For example, if I enter 6 as an input it should do the following products:
product(1, 3) + product(4, 6)
The problem is that when I run this code:
obj1.start()
I got the following error:
TypeError: 'int' object is not callable
I cannot find which one could be the mistake.
python
add a comment |
I am trying to make a calculation code using threads in Python. My code is the following:
from threading import Thread
from time import sleep
class Fact(Thread):
def __init__(self, start, end):
Thread.__init__(self)
self.start = start
self.end = end
def factorial(self):
p = 1
for i in range(self.start, self.end):
p = p * i
return p
def run(self):
global s
s = s + self.factorial()
sleep(2)
print ("output is ", s)
s = 0
def main():
n = 6
mid = n / 2
obj1 = Fact(1, mid)
obj1.start()
obj2 = Fact(mid + 1, n)
obj2.start()
if __name__ == "__main__":
main()
What I want is to compute, iteratively, the factorial of a number. For example, if I enter 6 as an input it should do the following products:
product(1, 3) + product(4, 6)
The problem is that when I run this code:
obj1.start()
I got the following error:
TypeError: 'int' object is not callable
I cannot find which one could be the mistake.
python
1
You're trying to usestart
for a method and an instance variable at the same time.
– user2357112
Nov 20 at 18:29
1
There is an instance variable in the same name (start) which is 'int' and 'int' is not callable. When you doobj1.start
, it's actually referring to that instance variable.
– Austin
Nov 20 at 18:30
obj1.start
is not a function - did you meanobj1.run()
instead?
– Robin Zigmond
Nov 20 at 18:31
3
BTW, while using global variables is always a bad idea, in this case it is even worse. You are using multiple threads to modify the same global variable. This can cause you pretty bad errors if one thread modifies the variable while the other one is using it.
– zvone
Nov 20 at 18:35
add a comment |
I am trying to make a calculation code using threads in Python. My code is the following:
from threading import Thread
from time import sleep
class Fact(Thread):
def __init__(self, start, end):
Thread.__init__(self)
self.start = start
self.end = end
def factorial(self):
p = 1
for i in range(self.start, self.end):
p = p * i
return p
def run(self):
global s
s = s + self.factorial()
sleep(2)
print ("output is ", s)
s = 0
def main():
n = 6
mid = n / 2
obj1 = Fact(1, mid)
obj1.start()
obj2 = Fact(mid + 1, n)
obj2.start()
if __name__ == "__main__":
main()
What I want is to compute, iteratively, the factorial of a number. For example, if I enter 6 as an input it should do the following products:
product(1, 3) + product(4, 6)
The problem is that when I run this code:
obj1.start()
I got the following error:
TypeError: 'int' object is not callable
I cannot find which one could be the mistake.
python
I am trying to make a calculation code using threads in Python. My code is the following:
from threading import Thread
from time import sleep
class Fact(Thread):
def __init__(self, start, end):
Thread.__init__(self)
self.start = start
self.end = end
def factorial(self):
p = 1
for i in range(self.start, self.end):
p = p * i
return p
def run(self):
global s
s = s + self.factorial()
sleep(2)
print ("output is ", s)
s = 0
def main():
n = 6
mid = n / 2
obj1 = Fact(1, mid)
obj1.start()
obj2 = Fact(mid + 1, n)
obj2.start()
if __name__ == "__main__":
main()
What I want is to compute, iteratively, the factorial of a number. For example, if I enter 6 as an input it should do the following products:
product(1, 3) + product(4, 6)
The problem is that when I run this code:
obj1.start()
I got the following error:
TypeError: 'int' object is not callable
I cannot find which one could be the mistake.
python
python
edited Nov 20 at 18:57
David the third
1,1681721
1,1681721
asked Nov 20 at 18:26
Little
94052145
94052145
1
You're trying to usestart
for a method and an instance variable at the same time.
– user2357112
Nov 20 at 18:29
1
There is an instance variable in the same name (start) which is 'int' and 'int' is not callable. When you doobj1.start
, it's actually referring to that instance variable.
– Austin
Nov 20 at 18:30
obj1.start
is not a function - did you meanobj1.run()
instead?
– Robin Zigmond
Nov 20 at 18:31
3
BTW, while using global variables is always a bad idea, in this case it is even worse. You are using multiple threads to modify the same global variable. This can cause you pretty bad errors if one thread modifies the variable while the other one is using it.
– zvone
Nov 20 at 18:35
add a comment |
1
You're trying to usestart
for a method and an instance variable at the same time.
– user2357112
Nov 20 at 18:29
1
There is an instance variable in the same name (start) which is 'int' and 'int' is not callable. When you doobj1.start
, it's actually referring to that instance variable.
– Austin
Nov 20 at 18:30
obj1.start
is not a function - did you meanobj1.run()
instead?
– Robin Zigmond
Nov 20 at 18:31
3
BTW, while using global variables is always a bad idea, in this case it is even worse. You are using multiple threads to modify the same global variable. This can cause you pretty bad errors if one thread modifies the variable while the other one is using it.
– zvone
Nov 20 at 18:35
1
1
You're trying to use
start
for a method and an instance variable at the same time.– user2357112
Nov 20 at 18:29
You're trying to use
start
for a method and an instance variable at the same time.– user2357112
Nov 20 at 18:29
1
1
There is an instance variable in the same name (start) which is 'int' and 'int' is not callable. When you do
obj1.start
, it's actually referring to that instance variable.– Austin
Nov 20 at 18:30
There is an instance variable in the same name (start) which is 'int' and 'int' is not callable. When you do
obj1.start
, it's actually referring to that instance variable.– Austin
Nov 20 at 18:30
obj1.start
is not a function - did you mean obj1.run()
instead?– Robin Zigmond
Nov 20 at 18:31
obj1.start
is not a function - did you mean obj1.run()
instead?– Robin Zigmond
Nov 20 at 18:31
3
3
BTW, while using global variables is always a bad idea, in this case it is even worse. You are using multiple threads to modify the same global variable. This can cause you pretty bad errors if one thread modifies the variable while the other one is using it.
– zvone
Nov 20 at 18:35
BTW, while using global variables is always a bad idea, in this case it is even worse. You are using multiple threads to modify the same global variable. This can cause you pretty bad errors if one thread modifies the variable while the other one is using it.
– zvone
Nov 20 at 18:35
add a comment |
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1
You're trying to use
start
for a method and an instance variable at the same time.– user2357112
Nov 20 at 18:29
1
There is an instance variable in the same name (start) which is 'int' and 'int' is not callable. When you do
obj1.start
, it's actually referring to that instance variable.– Austin
Nov 20 at 18:30
obj1.start
is not a function - did you meanobj1.run()
instead?– Robin Zigmond
Nov 20 at 18:31
3
BTW, while using global variables is always a bad idea, in this case it is even worse. You are using multiple threads to modify the same global variable. This can cause you pretty bad errors if one thread modifies the variable while the other one is using it.
– zvone
Nov 20 at 18:35