I am having trouble with return value of char * function in C [duplicate]
up vote
0
down vote
favorite
This question already has an answer here:
Returning Local Variable Pointers - C [duplicate]
1 answer
Char array corrupted after its pointer is passed between functions [duplicate]
2 answers
Capitalize string and return local variable
3 answers
This function should read the first line from the text file and return it.
char *meno(FILE *fin) {
char meno1[50];
fscanf(fin," %[^n]",meno1 );
return meno1;
}
If there is a text file in the directory the main function opens it and executes the function above and should print it's return value(in my case four names) but it doesn't work and prints "ÚJ8" 4 times.
int main() {
FILE *fin;
char s[10], *x=NULL;
int i = 1;
while (1) {
sprintf(s, "text%d.txt", i);
i++;
fin = fopen(s, "r");
if (fin == NULL) {
break;
}
*meno(fin);
printf("%s n", meno ); // this doesn't work
}
}
I am a beginner.
c
asked Nov 20 at 18:03
Jakub
1
marked as duplicate by Paul R c
Users with the c badge can single-handedly close c questions as duplicates and reopen them as needed.
StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;
$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');
$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 20 at 18:08
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
up vote
0
down vote
favorite
This question already has an answer here:
Returning Local Variable Pointers - C [duplicate]
1 answer
Char array corrupted after its pointer is passed between functions [duplicate]
2 answers
Capitalize string and return local variable
3 answers
This function should read the first line from the text file and return it.
char *meno(FILE *fin) {
char meno1[50];
fscanf(fin," %[^n]",meno1 );
return meno1;
}
If there is a text file in the directory the main function opens it and executes the function above and should print it's return value(in my case four names) but it doesn't work and prints "ÚJ8" 4 times.
int main() {
FILE *fin;
char s[10], *x=NULL;
int i = 1;
while (1) {
sprintf(s, "text%d.txt", i);
i++;
fin = fopen(s, "r");
if (fin == NULL) {
break;
}
*meno(fin);
printf("%s n", meno ); // this doesn't work
}
}
I am a beginner.
c
asked Nov 20 at 18:03
Jakub
1
marked as duplicate by Paul R c
Users with the c badge can single-handedly close c questions as duplicates and reopen them as needed.
StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;
$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');
$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 20 at 18:08
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
2
You're trying to return a pointer to something that no longer exists when the function returns. You need to pick up an introductory book on C, learn some basics, and you'll understand why.
– Carey Gregory
Nov 20 at 18:08
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
This question already has an answer here:
Returning Local Variable Pointers - C [duplicate]
1 answer
Char array corrupted after its pointer is passed between functions [duplicate]
2 answers
Capitalize string and return local variable
3 answers
This function should read the first line from the text file and return it.
char *meno(FILE *fin) {
char meno1[50];
fscanf(fin," %[^n]",meno1 );
return meno1;
}
If there is a text file in the directory the main function opens it and executes the function above and should print it's return value(in my case four names) but it doesn't work and prints "ÚJ8" 4 times.
int main() {
FILE *fin;
char s[10], *x=NULL;
int i = 1;
while (1) {
sprintf(s, "text%d.txt", i);
i++;
fin = fopen(s, "r");
if (fin == NULL) {
break;
}
*meno(fin);
printf("%s n", meno ); // this doesn't work
}
}
I am a beginner.
c
asked Nov 20 at 18:03
Jakub
1
This question already has an answer here:
Returning Local Variable Pointers - C [duplicate]
1 answer
Char array corrupted after its pointer is passed between functions [duplicate]
2 answers
Capitalize string and return local variable
3 answers
This function should read the first line from the text file and return it.
char *meno(FILE *fin) {
char meno1[50];
fscanf(fin," %[^n]",meno1 );
return meno1;
}
If there is a text file in the directory the main function opens it and executes the function above and should print it's return value(in my case four names) but it doesn't work and prints "ÚJ8" 4 times.
int main() {
FILE *fin;
char s[10], *x=NULL;
int i = 1;
while (1) {
sprintf(s, "text%d.txt", i);
i++;
fin = fopen(s, "r");
if (fin == NULL) {
break;
}
*meno(fin);
printf("%s n", meno ); // this doesn't work
}
}
I am a beginner.
This question already has an answer here:
Returning Local Variable Pointers - C [duplicate]
1 answer
Char array corrupted after its pointer is passed between functions [duplicate]
2 answers
Capitalize string and return local variable
3 answers
c
c
asked Nov 20 at 18:03
Jakub
1
asked Nov 20 at 18:03
Jakub
1
asked Nov 20 at 18:03
Jakub
1
asked Nov 20 at 18:03
Jakub
1
asked Nov 20 at 18:03
Jakub
1
1
marked as duplicate by Paul R c
Users with the c badge can single-handedly close c questions as duplicates and reopen them as needed.
StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;
$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');
$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 20 at 18:08
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Paul R c
Users with the c badge can single-handedly close c questions as duplicates and reopen them as needed.
StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;
$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');
$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 20 at 18:08
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
2
You're trying to return a pointer to something that no longer exists when the function returns. You need to pick up an introductory book on C, learn some basics, and you'll understand why.
– Carey Gregory
Nov 20 at 18:08
add a comment |
2
You're trying to return a pointer to something that no longer exists when the function returns. You need to pick up an introductory book on C, learn some basics, and you'll understand why.
– Carey Gregory
Nov 20 at 18:08
2
2
You're trying to return a pointer to something that no longer exists when the function returns. You need to pick up an introductory book on C, learn some basics, and you'll understand why.
– Carey Gregory
Nov 20 at 18:08
You're trying to return a pointer to something that no longer exists when the function returns. You need to pick up an introductory book on C, learn some basics, and you'll understand why.
– Carey Gregory
Nov 20 at 18:08
add a comment |
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You're trying to return a pointer to something that no longer exists when the function returns. You need to pick up an introductory book on C, learn some basics, and you'll understand why.
– Carey Gregory
Nov 20 at 18:08