How can I detach an event listener from cloned collection?
up vote
0
down vote
favorite
I am working around search models inside collection.
For prevent fetching collection at all queries I made collection.clone()
var filteredContacts = contactsCollection.clone();
filteredContacts.reset(filteredContacts.filter(function(contact) {
if(contact.get("login"))
return contact.get("login").search(new RegExp(Value, "i")) >= 0;
else
return false;
}));
filteredContacts.each(function(contact) {
new ContactView( { model: contact } );
});
also there is listenTo in contactsCollection
initialize: function() {
this.listenTo(Backbone, "contacts:open", this.getContacts);
},
which make an fetch contacts from server.
So when I try to trigger this event both of those collections catch this event.
How can I call enything like collection.destory?
javascript backbone.js
edited Nov 21 at 9:37
Anki
23918
asked Nov 20 at 17:53
Павел Зорин
419
add a comment |
up vote
0
down vote
favorite
I am working around search models inside collection.
For prevent fetching collection at all queries I made collection.clone()
var filteredContacts = contactsCollection.clone();
filteredContacts.reset(filteredContacts.filter(function(contact) {
if(contact.get("login"))
return contact.get("login").search(new RegExp(Value, "i")) >= 0;
else
return false;
}));
filteredContacts.each(function(contact) {
new ContactView( { model: contact } );
});
also there is listenTo in contactsCollection
initialize: function() {
this.listenTo(Backbone, "contacts:open", this.getContacts);
},
which make an fetch contacts from server.
So when I try to trigger this event both of those collections catch this event.
How can I call enything like collection.destory?
javascript backbone.js
edited Nov 21 at 9:37
Anki
23918
asked Nov 20 at 17:53
Павел Зорин
419
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am working around search models inside collection.
For prevent fetching collection at all queries I made collection.clone()
var filteredContacts = contactsCollection.clone();
filteredContacts.reset(filteredContacts.filter(function(contact) {
if(contact.get("login"))
return contact.get("login").search(new RegExp(Value, "i")) >= 0;
else
return false;
}));
filteredContacts.each(function(contact) {
new ContactView( { model: contact } );
});
also there is listenTo in contactsCollection
initialize: function() {
this.listenTo(Backbone, "contacts:open", this.getContacts);
},
which make an fetch contacts from server.
So when I try to trigger this event both of those collections catch this event.
How can I call enything like collection.destory?
javascript backbone.js
edited Nov 21 at 9:37
Anki
23918
asked Nov 20 at 17:53
Павел Зорин
419
I am working around search models inside collection.
For prevent fetching collection at all queries I made collection.clone()
var filteredContacts = contactsCollection.clone();
filteredContacts.reset(filteredContacts.filter(function(contact) {
if(contact.get("login"))
return contact.get("login").search(new RegExp(Value, "i")) >= 0;
else
return false;
}));
filteredContacts.each(function(contact) {
new ContactView( { model: contact } );
});
also there is listenTo in contactsCollection
initialize: function() {
this.listenTo(Backbone, "contacts:open", this.getContacts);
},
which make an fetch contacts from server.
So when I try to trigger this event both of those collections catch this event.
How can I call enything like collection.destory?
javascript backbone.js
javascript backbone.js
edited Nov 21 at 9:37
Anki
23918
asked Nov 20 at 17:53
Павел Зорин
419
edited Nov 21 at 9:37
Anki
23918
asked Nov 20 at 17:53
Павел Зорин
419
edited Nov 21 at 9:37
Anki
23918
edited Nov 21 at 9:37
Anki
23918
edited Nov 21 at 9:37
Anki
23918
23918
asked Nov 20 at 17:53
Павел Зорин
419
asked Nov 20 at 17:53
Павел Зорин
419
asked Nov 20 at 17:53
Павел Зорин
419
419
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
Backbone provides us a function stopListening(). This method actually tells an object to stop listening to events.
In your case we can proceed like this
var filteredContacts = contactsCollection.clone();
filteredContacts.reset(filteredContacts.filter(function(contact) {
if(contact.get("login"))
return contact.get("login").search(new RegExp(Value, "i")) >= 0;
else
return false;
}));
filteredContacts.stopListening("contacts:open");
filteredContacts.each(function(contact) {
new ContactView( { model: contact } );
});Even there is listenTo in contactsCollection like below
initialize: function() {
this.listenTo(Backbone, "contacts:open", this.getContacts);
},answered Nov 21 at 9:38
Anki
23918
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53398781%2fhow-can-i-detach-an-event-listener-from-cloned-collection%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Backbone provides us a function stopListening(). This method actually tells an object to stop listening to events.
In your case we can proceed like this
var filteredContacts = contactsCollection.clone();
filteredContacts.reset(filteredContacts.filter(function(contact) {
if(contact.get("login"))
return contact.get("login").search(new RegExp(Value, "i")) >= 0;
else
return false;
}));
filteredContacts.stopListening("contacts:open");
filteredContacts.each(function(contact) {
new ContactView( { model: contact } );
});Even there is listenTo in contactsCollection like below
initialize: function() {
this.listenTo(Backbone, "contacts:open", this.getContacts);
},answered Nov 21 at 9:38
Anki
23918
add a comment |
up vote
0
down vote
accepted
Backbone provides us a function stopListening(). This method actually tells an object to stop listening to events.
In your case we can proceed like this
var filteredContacts = contactsCollection.clone();
filteredContacts.reset(filteredContacts.filter(function(contact) {
if(contact.get("login"))
return contact.get("login").search(new RegExp(Value, "i")) >= 0;
else
return false;
}));
filteredContacts.stopListening("contacts:open");
filteredContacts.each(function(contact) {
new ContactView( { model: contact } );
});Even there is listenTo in contactsCollection like below
initialize: function() {
this.listenTo(Backbone, "contacts:open", this.getContacts);
},answered Nov 21 at 9:38
Anki
23918
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Backbone provides us a function stopListening(). This method actually tells an object to stop listening to events.
In your case we can proceed like this
var filteredContacts = contactsCollection.clone();
filteredContacts.reset(filteredContacts.filter(function(contact) {
if(contact.get("login"))
return contact.get("login").search(new RegExp(Value, "i")) >= 0;
else
return false;
}));
filteredContacts.stopListening("contacts:open");
filteredContacts.each(function(contact) {
new ContactView( { model: contact } );
});Even there is listenTo in contactsCollection like below
initialize: function() {
this.listenTo(Backbone, "contacts:open", this.getContacts);
},answered Nov 21 at 9:38
Anki
23918
Backbone provides us a function stopListening(). This method actually tells an object to stop listening to events.
In your case we can proceed like this
var filteredContacts = contactsCollection.clone();
filteredContacts.reset(filteredContacts.filter(function(contact) {
if(contact.get("login"))
return contact.get("login").search(new RegExp(Value, "i")) >= 0;
else
return false;
}));
filteredContacts.stopListening("contacts:open");
filteredContacts.each(function(contact) {
new ContactView( { model: contact } );
});Even there is listenTo in contactsCollection like below
initialize: function() {
this.listenTo(Backbone, "contacts:open", this.getContacts);
},var filteredContacts = contactsCollection.clone();
filteredContacts.reset(filteredContacts.filter(function(contact) {
if(contact.get("login"))
return contact.get("login").search(new RegExp(Value, "i")) >= 0;
else
return false;
}));
filteredContacts.stopListening("contacts:open");
filteredContacts.each(function(contact) {
new ContactView( { model: contact } );
});var filteredContacts = contactsCollection.clone();
filteredContacts.reset(filteredContacts.filter(function(contact) {
if(contact.get("login"))
return contact.get("login").search(new RegExp(Value, "i")) >= 0;
else
return false;
}));
filteredContacts.stopListening("contacts:open");
filteredContacts.each(function(contact) {
new ContactView( { model: contact } );
});initialize: function() {
this.listenTo(Backbone, "contacts:open", this.getContacts);
},initialize: function() {
this.listenTo(Backbone, "contacts:open", this.getContacts);
},answered Nov 21 at 9:38
Anki
23918
answered Nov 21 at 9:38
Anki
23918
answered Nov 21 at 9:38
Anki
23918
answered Nov 21 at 9:38
Anki
23918
23918
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53398781%2fhow-can-i-detach-an-event-listener-from-cloned-collection%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
