Generating a specific dataset in R
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I would like to generate at dataset that looks something like this
1 US US1001
2 GB GB3400
3 DE 4DE497
4 CE EAPO68
Where the first column follows a certain pattern, in this case two letters. The next column the entries start with the same two letters. There are also some that don't obey the rule, such as entry 3 and 4. I am not sure how to do this. Any help greatly appreciated
r
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up vote
-1
down vote
favorite
I would like to generate at dataset that looks something like this
1 US US1001
2 GB GB3400
3 DE 4DE497
4 CE EAPO68
Where the first column follows a certain pattern, in this case two letters. The next column the entries start with the same two letters. There are also some that don't obey the rule, such as entry 3 and 4. I am not sure how to do this. Any help greatly appreciated
r
1
You'll need to show what you've tried and what is not working. People will help you solve a problem, but they will not design a solution. The part about some not obeying the rule is also vague.
– manotheshark
Nov 20 at 17:57
Try samplingLETTERS
and integers from 1000 to 9999, and then concatenating them usingpaste
. Also consider usingapply
instead ofx$newcol <- sample(LETTERS, 2)
to avoid populating the columns with identical values
– 12b345b6b78
Nov 20 at 18:02
Do you mean you need to create a dataset with random values/factor/value-factor?
– s_t
Nov 21 at 8:22
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I would like to generate at dataset that looks something like this
1 US US1001
2 GB GB3400
3 DE 4DE497
4 CE EAPO68
Where the first column follows a certain pattern, in this case two letters. The next column the entries start with the same two letters. There are also some that don't obey the rule, such as entry 3 and 4. I am not sure how to do this. Any help greatly appreciated
r
I would like to generate at dataset that looks something like this
1 US US1001
2 GB GB3400
3 DE 4DE497
4 CE EAPO68
Where the first column follows a certain pattern, in this case two letters. The next column the entries start with the same two letters. There are also some that don't obey the rule, such as entry 3 and 4. I am not sure how to do this. Any help greatly appreciated
r
r
asked Nov 20 at 17:53
Sarah
94
94
1
You'll need to show what you've tried and what is not working. People will help you solve a problem, but they will not design a solution. The part about some not obeying the rule is also vague.
– manotheshark
Nov 20 at 17:57
Try samplingLETTERS
and integers from 1000 to 9999, and then concatenating them usingpaste
. Also consider usingapply
instead ofx$newcol <- sample(LETTERS, 2)
to avoid populating the columns with identical values
– 12b345b6b78
Nov 20 at 18:02
Do you mean you need to create a dataset with random values/factor/value-factor?
– s_t
Nov 21 at 8:22
add a comment |
1
You'll need to show what you've tried and what is not working. People will help you solve a problem, but they will not design a solution. The part about some not obeying the rule is also vague.
– manotheshark
Nov 20 at 17:57
Try samplingLETTERS
and integers from 1000 to 9999, and then concatenating them usingpaste
. Also consider usingapply
instead ofx$newcol <- sample(LETTERS, 2)
to avoid populating the columns with identical values
– 12b345b6b78
Nov 20 at 18:02
Do you mean you need to create a dataset with random values/factor/value-factor?
– s_t
Nov 21 at 8:22
1
1
You'll need to show what you've tried and what is not working. People will help you solve a problem, but they will not design a solution. The part about some not obeying the rule is also vague.
– manotheshark
Nov 20 at 17:57
You'll need to show what you've tried and what is not working. People will help you solve a problem, but they will not design a solution. The part about some not obeying the rule is also vague.
– manotheshark
Nov 20 at 17:57
Try sampling
LETTERS
and integers from 1000 to 9999, and then concatenating them using paste
. Also consider using apply
instead of x$newcol <- sample(LETTERS, 2)
to avoid populating the columns with identical values– 12b345b6b78
Nov 20 at 18:02
Try sampling
LETTERS
and integers from 1000 to 9999, and then concatenating them using paste
. Also consider using apply
instead of x$newcol <- sample(LETTERS, 2)
to avoid populating the columns with identical values– 12b345b6b78
Nov 20 at 18:02
Do you mean you need to create a dataset with random values/factor/value-factor?
– s_t
Nov 21 at 8:22
Do you mean you need to create a dataset with random values/factor/value-factor?
– s_t
Nov 21 at 8:22
add a comment |
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1
You'll need to show what you've tried and what is not working. People will help you solve a problem, but they will not design a solution. The part about some not obeying the rule is also vague.
– manotheshark
Nov 20 at 17:57
Try sampling
LETTERS
and integers from 1000 to 9999, and then concatenating them usingpaste
. Also consider usingapply
instead ofx$newcol <- sample(LETTERS, 2)
to avoid populating the columns with identical values– 12b345b6b78
Nov 20 at 18:02
Do you mean you need to create a dataset with random values/factor/value-factor?
– s_t
Nov 21 at 8:22