Rotating an Image using own algorithm in python











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For an uni assignment I have been giving the task of making my own rotating algorithm in python. This is my code so far.



import cv2
import math
import numpy as np

class rotator:

angle = 20.0
x = 330
y = 330

radians = float(angle*(math.pi/180))
img = cv2.imread('FNAF.png',0)
width,height = img.shape


def showImg(name, self):
cv2.imshow(name, self.img)
self.img = np.pad(self.img, (self.height) ,'constant', constant_values=0)
self.width,self.height = self.img.shape

def printWH(self):
print(self.width)
print(self.height)

def rotate(self):
emptyF = np.zeros((self.width,self.height),dtype="uint8")
emptyB = np.zeros((self.width,self.height),dtype="uint8")
emptyBB = np.zeros((self.width,self.height),dtype="uint8")


for i in range(self.width):
for j in range(self.height):
temp = self.img[i,j]
#forward mapping
xf = (i-self.x)*math.cos(self.radians)-(j-self.y)*math.sin(self.radians)+self.x
yf = (i-self.x)*math.sin(self.radians)+(j-self.y)*math.cos(self.radians)+self.x
#backward mapping should change the forward mapping to the original image
xbb = (i-self.x)*math.cos(self.radians)+(j-self.y)*math.sin(self.radians)+self.x
ybb = -(i-self.x)*math.sin(self.radians)+(j-self.y)*math.cos(self.radians)+self.x
xbb = int(xbb)
ybb = int(ybb)
if xf < 660 and yf < 660 and xf>0 and yf > 0:
emptyF[int(xf),int(yf)] = temp
else:
pass
if xbb < 660 and ybb < 660 and xbb>0 and ybb > 0:
emptyBB[(xbb),(ybb)] = temp
else:
pass
cv2.imshow('Forward', emptyF)
cv2.imshow('Backward', emptyBB)
def main():
rotator.showImg('normal', rotator)
rotator.printWH(rotator)
rotator.rotate(rotator)
cv2.waitKey(0)
cv2.destroyAllWindows

if __name__ == '__main__':
main()


Is there any way to improve this code or my algorithm? Any advise would be awesome.



NB. I also hav a problem with my backwards mapping. The output image has a lot of small black dots. Any suggestions to what that might be?



Please let me know.










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  • 1




    I suspect that the black dots might be due to integer rounding of trigonometric results.
    – 200_success
    6 hours ago















up vote
4
down vote

favorite
1












For an uni assignment I have been giving the task of making my own rotating algorithm in python. This is my code so far.



import cv2
import math
import numpy as np

class rotator:

angle = 20.0
x = 330
y = 330

radians = float(angle*(math.pi/180))
img = cv2.imread('FNAF.png',0)
width,height = img.shape


def showImg(name, self):
cv2.imshow(name, self.img)
self.img = np.pad(self.img, (self.height) ,'constant', constant_values=0)
self.width,self.height = self.img.shape

def printWH(self):
print(self.width)
print(self.height)

def rotate(self):
emptyF = np.zeros((self.width,self.height),dtype="uint8")
emptyB = np.zeros((self.width,self.height),dtype="uint8")
emptyBB = np.zeros((self.width,self.height),dtype="uint8")


for i in range(self.width):
for j in range(self.height):
temp = self.img[i,j]
#forward mapping
xf = (i-self.x)*math.cos(self.radians)-(j-self.y)*math.sin(self.radians)+self.x
yf = (i-self.x)*math.sin(self.radians)+(j-self.y)*math.cos(self.radians)+self.x
#backward mapping should change the forward mapping to the original image
xbb = (i-self.x)*math.cos(self.radians)+(j-self.y)*math.sin(self.radians)+self.x
ybb = -(i-self.x)*math.sin(self.radians)+(j-self.y)*math.cos(self.radians)+self.x
xbb = int(xbb)
ybb = int(ybb)
if xf < 660 and yf < 660 and xf>0 and yf > 0:
emptyF[int(xf),int(yf)] = temp
else:
pass
if xbb < 660 and ybb < 660 and xbb>0 and ybb > 0:
emptyBB[(xbb),(ybb)] = temp
else:
pass
cv2.imshow('Forward', emptyF)
cv2.imshow('Backward', emptyBB)
def main():
rotator.showImg('normal', rotator)
rotator.printWH(rotator)
rotator.rotate(rotator)
cv2.waitKey(0)
cv2.destroyAllWindows

if __name__ == '__main__':
main()


Is there any way to improve this code or my algorithm? Any advise would be awesome.



NB. I also hav a problem with my backwards mapping. The output image has a lot of small black dots. Any suggestions to what that might be?



Please let me know.










share|improve this question







New contributor




Zorn01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 1




    I suspect that the black dots might be due to integer rounding of trigonometric results.
    – 200_success
    6 hours ago













up vote
4
down vote

favorite
1









up vote
4
down vote

favorite
1






1





For an uni assignment I have been giving the task of making my own rotating algorithm in python. This is my code so far.



import cv2
import math
import numpy as np

class rotator:

angle = 20.0
x = 330
y = 330

radians = float(angle*(math.pi/180))
img = cv2.imread('FNAF.png',0)
width,height = img.shape


def showImg(name, self):
cv2.imshow(name, self.img)
self.img = np.pad(self.img, (self.height) ,'constant', constant_values=0)
self.width,self.height = self.img.shape

def printWH(self):
print(self.width)
print(self.height)

def rotate(self):
emptyF = np.zeros((self.width,self.height),dtype="uint8")
emptyB = np.zeros((self.width,self.height),dtype="uint8")
emptyBB = np.zeros((self.width,self.height),dtype="uint8")


for i in range(self.width):
for j in range(self.height):
temp = self.img[i,j]
#forward mapping
xf = (i-self.x)*math.cos(self.radians)-(j-self.y)*math.sin(self.radians)+self.x
yf = (i-self.x)*math.sin(self.radians)+(j-self.y)*math.cos(self.radians)+self.x
#backward mapping should change the forward mapping to the original image
xbb = (i-self.x)*math.cos(self.radians)+(j-self.y)*math.sin(self.radians)+self.x
ybb = -(i-self.x)*math.sin(self.radians)+(j-self.y)*math.cos(self.radians)+self.x
xbb = int(xbb)
ybb = int(ybb)
if xf < 660 and yf < 660 and xf>0 and yf > 0:
emptyF[int(xf),int(yf)] = temp
else:
pass
if xbb < 660 and ybb < 660 and xbb>0 and ybb > 0:
emptyBB[(xbb),(ybb)] = temp
else:
pass
cv2.imshow('Forward', emptyF)
cv2.imshow('Backward', emptyBB)
def main():
rotator.showImg('normal', rotator)
rotator.printWH(rotator)
rotator.rotate(rotator)
cv2.waitKey(0)
cv2.destroyAllWindows

if __name__ == '__main__':
main()


Is there any way to improve this code or my algorithm? Any advise would be awesome.



NB. I also hav a problem with my backwards mapping. The output image has a lot of small black dots. Any suggestions to what that might be?



Please let me know.










share|improve this question







New contributor




Zorn01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











For an uni assignment I have been giving the task of making my own rotating algorithm in python. This is my code so far.



import cv2
import math
import numpy as np

class rotator:

angle = 20.0
x = 330
y = 330

radians = float(angle*(math.pi/180))
img = cv2.imread('FNAF.png',0)
width,height = img.shape


def showImg(name, self):
cv2.imshow(name, self.img)
self.img = np.pad(self.img, (self.height) ,'constant', constant_values=0)
self.width,self.height = self.img.shape

def printWH(self):
print(self.width)
print(self.height)

def rotate(self):
emptyF = np.zeros((self.width,self.height),dtype="uint8")
emptyB = np.zeros((self.width,self.height),dtype="uint8")
emptyBB = np.zeros((self.width,self.height),dtype="uint8")


for i in range(self.width):
for j in range(self.height):
temp = self.img[i,j]
#forward mapping
xf = (i-self.x)*math.cos(self.radians)-(j-self.y)*math.sin(self.radians)+self.x
yf = (i-self.x)*math.sin(self.radians)+(j-self.y)*math.cos(self.radians)+self.x
#backward mapping should change the forward mapping to the original image
xbb = (i-self.x)*math.cos(self.radians)+(j-self.y)*math.sin(self.radians)+self.x
ybb = -(i-self.x)*math.sin(self.radians)+(j-self.y)*math.cos(self.radians)+self.x
xbb = int(xbb)
ybb = int(ybb)
if xf < 660 and yf < 660 and xf>0 and yf > 0:
emptyF[int(xf),int(yf)] = temp
else:
pass
if xbb < 660 and ybb < 660 and xbb>0 and ybb > 0:
emptyBB[(xbb),(ybb)] = temp
else:
pass
cv2.imshow('Forward', emptyF)
cv2.imshow('Backward', emptyBB)
def main():
rotator.showImg('normal', rotator)
rotator.printWH(rotator)
rotator.rotate(rotator)
cv2.waitKey(0)
cv2.destroyAllWindows

if __name__ == '__main__':
main()


Is there any way to improve this code or my algorithm? Any advise would be awesome.



NB. I also hav a problem with my backwards mapping. The output image has a lot of small black dots. Any suggestions to what that might be?



Please let me know.







python algorithm image numpy opencv






share|improve this question







New contributor




Zorn01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




Zorn01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




Zorn01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 6 hours ago









Zorn01

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211




New contributor




Zorn01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Zorn01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Zorn01 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 1




    I suspect that the black dots might be due to integer rounding of trigonometric results.
    – 200_success
    6 hours ago














  • 1




    I suspect that the black dots might be due to integer rounding of trigonometric results.
    – 200_success
    6 hours ago








1




1




I suspect that the black dots might be due to integer rounding of trigonometric results.
– 200_success
6 hours ago




I suspect that the black dots might be due to integer rounding of trigonometric results.
– 200_success
6 hours ago










1 Answer
1






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0
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The most common method for getting rid of the black dots is to paint over each pixel of the entire destination image with pixels copied from computed positions in the source image, instead of painting the source image pixels into computed positions in the destination image.



for i in range(660):
for j in range(660):
xb = int(...)
yb = int(...)
if xb in range(self.width) and yb in range(self.height):
emptyF[i, j] = self.img[xb, yb]


Computing destination pixels positions from the source pixel positions may result in tiny areas unpainted in the destination due to numeric errors/limits.



Computing source pixels positions from the destination pixel position may result in a pixel value being copied to two adjacent locations, and other pixels never being copied from, but this is usually/often unnoticeable.






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    The most common method for getting rid of the black dots is to paint over each pixel of the entire destination image with pixels copied from computed positions in the source image, instead of painting the source image pixels into computed positions in the destination image.



    for i in range(660):
    for j in range(660):
    xb = int(...)
    yb = int(...)
    if xb in range(self.width) and yb in range(self.height):
    emptyF[i, j] = self.img[xb, yb]


    Computing destination pixels positions from the source pixel positions may result in tiny areas unpainted in the destination due to numeric errors/limits.



    Computing source pixels positions from the destination pixel position may result in a pixel value being copied to two adjacent locations, and other pixels never being copied from, but this is usually/often unnoticeable.






    share|improve this answer

























      up vote
      0
      down vote













      The most common method for getting rid of the black dots is to paint over each pixel of the entire destination image with pixels copied from computed positions in the source image, instead of painting the source image pixels into computed positions in the destination image.



      for i in range(660):
      for j in range(660):
      xb = int(...)
      yb = int(...)
      if xb in range(self.width) and yb in range(self.height):
      emptyF[i, j] = self.img[xb, yb]


      Computing destination pixels positions from the source pixel positions may result in tiny areas unpainted in the destination due to numeric errors/limits.



      Computing source pixels positions from the destination pixel position may result in a pixel value being copied to two adjacent locations, and other pixels never being copied from, but this is usually/often unnoticeable.






      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        The most common method for getting rid of the black dots is to paint over each pixel of the entire destination image with pixels copied from computed positions in the source image, instead of painting the source image pixels into computed positions in the destination image.



        for i in range(660):
        for j in range(660):
        xb = int(...)
        yb = int(...)
        if xb in range(self.width) and yb in range(self.height):
        emptyF[i, j] = self.img[xb, yb]


        Computing destination pixels positions from the source pixel positions may result in tiny areas unpainted in the destination due to numeric errors/limits.



        Computing source pixels positions from the destination pixel position may result in a pixel value being copied to two adjacent locations, and other pixels never being copied from, but this is usually/often unnoticeable.






        share|improve this answer












        The most common method for getting rid of the black dots is to paint over each pixel of the entire destination image with pixels copied from computed positions in the source image, instead of painting the source image pixels into computed positions in the destination image.



        for i in range(660):
        for j in range(660):
        xb = int(...)
        yb = int(...)
        if xb in range(self.width) and yb in range(self.height):
        emptyF[i, j] = self.img[xb, yb]


        Computing destination pixels positions from the source pixel positions may result in tiny areas unpainted in the destination due to numeric errors/limits.



        Computing source pixels positions from the destination pixel position may result in a pixel value being copied to two adjacent locations, and other pixels never being copied from, but this is usually/often unnoticeable.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 2 hours ago









        AJNeufeld

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