jar file built with maven can't find configuration file











up vote
-1
down vote

favorite












I built a jar file with maven. I am using the following code in the only class in the jar file to try to access the config file.



 InputStream is = Myclass.class.getClassLoader().getResourceAsStream("/config.properties");


The config.properties file is in the jar file located at Path /



I don't see any error messages. But when I try to access the values in the Properties object, the values are null.



 Properties prop = new Properties();
prop.load(is);
serverUrl=prop.getProperty("serverUrl");


serverUrl is null.



Any suggestions on how to get the values in the config file in the jar file?










share|improve this question
























  • you should add the error that you are getting
    – Nawnit Sen
    Nov 16 at 7:43










  • Try Myclass.class.getClassLoader().getResourceAsStream("config.properties") or put your config in same package as MyClass.
    – talex
    Nov 16 at 7:51










  • no error message that I can see, but when I try to access the values, there is a null value or a null pointer exception
    – user840930
    Nov 16 at 8:37















up vote
-1
down vote

favorite












I built a jar file with maven. I am using the following code in the only class in the jar file to try to access the config file.



 InputStream is = Myclass.class.getClassLoader().getResourceAsStream("/config.properties");


The config.properties file is in the jar file located at Path /



I don't see any error messages. But when I try to access the values in the Properties object, the values are null.



 Properties prop = new Properties();
prop.load(is);
serverUrl=prop.getProperty("serverUrl");


serverUrl is null.



Any suggestions on how to get the values in the config file in the jar file?










share|improve this question
























  • you should add the error that you are getting
    – Nawnit Sen
    Nov 16 at 7:43










  • Try Myclass.class.getClassLoader().getResourceAsStream("config.properties") or put your config in same package as MyClass.
    – talex
    Nov 16 at 7:51










  • no error message that I can see, but when I try to access the values, there is a null value or a null pointer exception
    – user840930
    Nov 16 at 8:37













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I built a jar file with maven. I am using the following code in the only class in the jar file to try to access the config file.



 InputStream is = Myclass.class.getClassLoader().getResourceAsStream("/config.properties");


The config.properties file is in the jar file located at Path /



I don't see any error messages. But when I try to access the values in the Properties object, the values are null.



 Properties prop = new Properties();
prop.load(is);
serverUrl=prop.getProperty("serverUrl");


serverUrl is null.



Any suggestions on how to get the values in the config file in the jar file?










share|improve this question















I built a jar file with maven. I am using the following code in the only class in the jar file to try to access the config file.



 InputStream is = Myclass.class.getClassLoader().getResourceAsStream("/config.properties");


The config.properties file is in the jar file located at Path /



I don't see any error messages. But when I try to access the values in the Properties object, the values are null.



 Properties prop = new Properties();
prop.load(is);
serverUrl=prop.getProperty("serverUrl");


serverUrl is null.



Any suggestions on how to get the values in the config file in the jar file?







java maven jar






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 at 9:33

























asked Nov 16 at 7:39









user840930

1,336144163




1,336144163












  • you should add the error that you are getting
    – Nawnit Sen
    Nov 16 at 7:43










  • Try Myclass.class.getClassLoader().getResourceAsStream("config.properties") or put your config in same package as MyClass.
    – talex
    Nov 16 at 7:51










  • no error message that I can see, but when I try to access the values, there is a null value or a null pointer exception
    – user840930
    Nov 16 at 8:37


















  • you should add the error that you are getting
    – Nawnit Sen
    Nov 16 at 7:43










  • Try Myclass.class.getClassLoader().getResourceAsStream("config.properties") or put your config in same package as MyClass.
    – talex
    Nov 16 at 7:51










  • no error message that I can see, but when I try to access the values, there is a null value or a null pointer exception
    – user840930
    Nov 16 at 8:37
















you should add the error that you are getting
– Nawnit Sen
Nov 16 at 7:43




you should add the error that you are getting
– Nawnit Sen
Nov 16 at 7:43












Try Myclass.class.getClassLoader().getResourceAsStream("config.properties") or put your config in same package as MyClass.
– talex
Nov 16 at 7:51




Try Myclass.class.getClassLoader().getResourceAsStream("config.properties") or put your config in same package as MyClass.
– talex
Nov 16 at 7:51












no error message that I can see, but when I try to access the values, there is a null value or a null pointer exception
– user840930
Nov 16 at 8:37




no error message that I can see, but when I try to access the values, there is a null value or a null pointer exception
– user840930
Nov 16 at 8:37












3 Answers
3






active

oldest

votes

















up vote
0
down vote













Typically in maven, you locate resources under src/main/resources.



Then you can access these resources by using the classloader:



try (InputStream in = Myclass.class.getClassLoader().getResourceAsStream("config.properties") {
//doSomething
}





share|improve this answer








New contributor




Tobias Bertram-Köhler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.


















  • Thank you for your comment! I updated my question and code to reflect the change. So my code appears to access the file but the values are null.
    – user840930
    Nov 16 at 9:09










  • Or at least I should say InputStream is no longer null
    – user840930
    Nov 16 at 11:59


















up vote
0
down vote













I was facing same issue before I realized that the following way is only good for loading files in your classpath.



InputStream is = Myclass.class.getClassLoader().getResourceAsStream("/config.properties");


For picking files regardless of whether they are in classpath or not, I use Apache FileUtils. For e.g I used following and it worked like a charm.



String str = FileUtils.readFileToString(new File(path_to_your_file), "UTF-8");
IOUtils.toInputStream(str, "UTF-8"); // if you need InputStream object


You can have a look at other APIs provided by FileUtils too other than readFileToString






share|improve this answer




























    up vote
    0
    down vote













    getResourceAsStream("config.properties") - this method will only work if your properties file is in the classpath. I think you have added the properties file outside the classpath. This method is basically used for accessing a file present in the classpath.



    Please check it again.



    Thanks :)



    Working Code :



    public class MyClass {

    public static void main(String args) throws Exception {
    Properties prop = new Properties();
    InputStream input = null;

    try {

    String filename = "config.properties";
    input = MyClass.class.getClassLoader().getResourceAsStream(filename);
    if (input == null) {
    System.out.println("Sorry, unable to find " + filename);
    return;
    }

    // load a properties file from class path, inside static method
    prop.load(input);

    // get the property value and print it out
    System.out.println(prop.getProperty("serverUrl"));

    } catch (IOException ex) {
    ex.printStackTrace();
    } finally {
    if (input != null) {
    try {
    input.close();
    } catch (IOException e) {
    e.printStackTrace();
    }
    }
    }

    }

    }





    share|improve this answer























    • how do I add the file to the classpath?
      – user840930
      Nov 16 at 8:29






    • 1




      I'm pretty sure the file is being found now. I changed the code to getResourceAsStream("/config.properties");
      – user840930
      Nov 16 at 10:00












    • keep the properties file in the resources folder of your project.. Then if you are using eclipse. Then right click on the project -> Properties ->Java Build Path -> click on source tab -> Click on Add folder and add the resources folder -> Click on Apply -> Click on Apply and close. Make a little modification to getResourceAsStream("resources/config.properties")
      – Anish B.
      Nov 16 at 10:04












    • tried "resources/config.properties. That did not work. Can't access the file. NullPointerException. The correct way looks like "/config.properties"
      – user840930
      Nov 16 at 11:06










    • then its fine :)
      – Anish B.
      Nov 16 at 12:39











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    3 Answers
    3






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    3 Answers
    3






    active

    oldest

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    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    Typically in maven, you locate resources under src/main/resources.



    Then you can access these resources by using the classloader:



    try (InputStream in = Myclass.class.getClassLoader().getResourceAsStream("config.properties") {
    //doSomething
    }





    share|improve this answer








    New contributor




    Tobias Bertram-Köhler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.


















    • Thank you for your comment! I updated my question and code to reflect the change. So my code appears to access the file but the values are null.
      – user840930
      Nov 16 at 9:09










    • Or at least I should say InputStream is no longer null
      – user840930
      Nov 16 at 11:59















    up vote
    0
    down vote













    Typically in maven, you locate resources under src/main/resources.



    Then you can access these resources by using the classloader:



    try (InputStream in = Myclass.class.getClassLoader().getResourceAsStream("config.properties") {
    //doSomething
    }





    share|improve this answer








    New contributor




    Tobias Bertram-Köhler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.


















    • Thank you for your comment! I updated my question and code to reflect the change. So my code appears to access the file but the values are null.
      – user840930
      Nov 16 at 9:09










    • Or at least I should say InputStream is no longer null
      – user840930
      Nov 16 at 11:59













    up vote
    0
    down vote










    up vote
    0
    down vote









    Typically in maven, you locate resources under src/main/resources.



    Then you can access these resources by using the classloader:



    try (InputStream in = Myclass.class.getClassLoader().getResourceAsStream("config.properties") {
    //doSomething
    }





    share|improve this answer








    New contributor




    Tobias Bertram-Köhler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.









    Typically in maven, you locate resources under src/main/resources.



    Then you can access these resources by using the classloader:



    try (InputStream in = Myclass.class.getClassLoader().getResourceAsStream("config.properties") {
    //doSomething
    }






    share|improve this answer








    New contributor




    Tobias Bertram-Köhler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.









    share|improve this answer



    share|improve this answer






    New contributor




    Tobias Bertram-Köhler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.









    answered Nov 16 at 7:57









    Tobias Bertram-Köhler

    32




    32




    New contributor




    Tobias Bertram-Köhler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





    New contributor





    Tobias Bertram-Köhler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    Tobias Bertram-Köhler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.












    • Thank you for your comment! I updated my question and code to reflect the change. So my code appears to access the file but the values are null.
      – user840930
      Nov 16 at 9:09










    • Or at least I should say InputStream is no longer null
      – user840930
      Nov 16 at 11:59


















    • Thank you for your comment! I updated my question and code to reflect the change. So my code appears to access the file but the values are null.
      – user840930
      Nov 16 at 9:09










    • Or at least I should say InputStream is no longer null
      – user840930
      Nov 16 at 11:59
















    Thank you for your comment! I updated my question and code to reflect the change. So my code appears to access the file but the values are null.
    – user840930
    Nov 16 at 9:09




    Thank you for your comment! I updated my question and code to reflect the change. So my code appears to access the file but the values are null.
    – user840930
    Nov 16 at 9:09












    Or at least I should say InputStream is no longer null
    – user840930
    Nov 16 at 11:59




    Or at least I should say InputStream is no longer null
    – user840930
    Nov 16 at 11:59












    up vote
    0
    down vote













    I was facing same issue before I realized that the following way is only good for loading files in your classpath.



    InputStream is = Myclass.class.getClassLoader().getResourceAsStream("/config.properties");


    For picking files regardless of whether they are in classpath or not, I use Apache FileUtils. For e.g I used following and it worked like a charm.



    String str = FileUtils.readFileToString(new File(path_to_your_file), "UTF-8");
    IOUtils.toInputStream(str, "UTF-8"); // if you need InputStream object


    You can have a look at other APIs provided by FileUtils too other than readFileToString






    share|improve this answer

























      up vote
      0
      down vote













      I was facing same issue before I realized that the following way is only good for loading files in your classpath.



      InputStream is = Myclass.class.getClassLoader().getResourceAsStream("/config.properties");


      For picking files regardless of whether they are in classpath or not, I use Apache FileUtils. For e.g I used following and it worked like a charm.



      String str = FileUtils.readFileToString(new File(path_to_your_file), "UTF-8");
      IOUtils.toInputStream(str, "UTF-8"); // if you need InputStream object


      You can have a look at other APIs provided by FileUtils too other than readFileToString






      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        I was facing same issue before I realized that the following way is only good for loading files in your classpath.



        InputStream is = Myclass.class.getClassLoader().getResourceAsStream("/config.properties");


        For picking files regardless of whether they are in classpath or not, I use Apache FileUtils. For e.g I used following and it worked like a charm.



        String str = FileUtils.readFileToString(new File(path_to_your_file), "UTF-8");
        IOUtils.toInputStream(str, "UTF-8"); // if you need InputStream object


        You can have a look at other APIs provided by FileUtils too other than readFileToString






        share|improve this answer












        I was facing same issue before I realized that the following way is only good for loading files in your classpath.



        InputStream is = Myclass.class.getClassLoader().getResourceAsStream("/config.properties");


        For picking files regardless of whether they are in classpath or not, I use Apache FileUtils. For e.g I used following and it worked like a charm.



        String str = FileUtils.readFileToString(new File(path_to_your_file), "UTF-8");
        IOUtils.toInputStream(str, "UTF-8"); // if you need InputStream object


        You can have a look at other APIs provided by FileUtils too other than readFileToString







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered yesterday









        tryingToLearn

        2,33922546




        2,33922546






















            up vote
            0
            down vote













            getResourceAsStream("config.properties") - this method will only work if your properties file is in the classpath. I think you have added the properties file outside the classpath. This method is basically used for accessing a file present in the classpath.



            Please check it again.



            Thanks :)



            Working Code :



            public class MyClass {

            public static void main(String args) throws Exception {
            Properties prop = new Properties();
            InputStream input = null;

            try {

            String filename = "config.properties";
            input = MyClass.class.getClassLoader().getResourceAsStream(filename);
            if (input == null) {
            System.out.println("Sorry, unable to find " + filename);
            return;
            }

            // load a properties file from class path, inside static method
            prop.load(input);

            // get the property value and print it out
            System.out.println(prop.getProperty("serverUrl"));

            } catch (IOException ex) {
            ex.printStackTrace();
            } finally {
            if (input != null) {
            try {
            input.close();
            } catch (IOException e) {
            e.printStackTrace();
            }
            }
            }

            }

            }





            share|improve this answer























            • how do I add the file to the classpath?
              – user840930
              Nov 16 at 8:29






            • 1




              I'm pretty sure the file is being found now. I changed the code to getResourceAsStream("/config.properties");
              – user840930
              Nov 16 at 10:00












            • keep the properties file in the resources folder of your project.. Then if you are using eclipse. Then right click on the project -> Properties ->Java Build Path -> click on source tab -> Click on Add folder and add the resources folder -> Click on Apply -> Click on Apply and close. Make a little modification to getResourceAsStream("resources/config.properties")
              – Anish B.
              Nov 16 at 10:04












            • tried "resources/config.properties. That did not work. Can't access the file. NullPointerException. The correct way looks like "/config.properties"
              – user840930
              Nov 16 at 11:06










            • then its fine :)
              – Anish B.
              Nov 16 at 12:39















            up vote
            0
            down vote













            getResourceAsStream("config.properties") - this method will only work if your properties file is in the classpath. I think you have added the properties file outside the classpath. This method is basically used for accessing a file present in the classpath.



            Please check it again.



            Thanks :)



            Working Code :



            public class MyClass {

            public static void main(String args) throws Exception {
            Properties prop = new Properties();
            InputStream input = null;

            try {

            String filename = "config.properties";
            input = MyClass.class.getClassLoader().getResourceAsStream(filename);
            if (input == null) {
            System.out.println("Sorry, unable to find " + filename);
            return;
            }

            // load a properties file from class path, inside static method
            prop.load(input);

            // get the property value and print it out
            System.out.println(prop.getProperty("serverUrl"));

            } catch (IOException ex) {
            ex.printStackTrace();
            } finally {
            if (input != null) {
            try {
            input.close();
            } catch (IOException e) {
            e.printStackTrace();
            }
            }
            }

            }

            }





            share|improve this answer























            • how do I add the file to the classpath?
              – user840930
              Nov 16 at 8:29






            • 1




              I'm pretty sure the file is being found now. I changed the code to getResourceAsStream("/config.properties");
              – user840930
              Nov 16 at 10:00












            • keep the properties file in the resources folder of your project.. Then if you are using eclipse. Then right click on the project -> Properties ->Java Build Path -> click on source tab -> Click on Add folder and add the resources folder -> Click on Apply -> Click on Apply and close. Make a little modification to getResourceAsStream("resources/config.properties")
              – Anish B.
              Nov 16 at 10:04












            • tried "resources/config.properties. That did not work. Can't access the file. NullPointerException. The correct way looks like "/config.properties"
              – user840930
              Nov 16 at 11:06










            • then its fine :)
              – Anish B.
              Nov 16 at 12:39













            up vote
            0
            down vote










            up vote
            0
            down vote









            getResourceAsStream("config.properties") - this method will only work if your properties file is in the classpath. I think you have added the properties file outside the classpath. This method is basically used for accessing a file present in the classpath.



            Please check it again.



            Thanks :)



            Working Code :



            public class MyClass {

            public static void main(String args) throws Exception {
            Properties prop = new Properties();
            InputStream input = null;

            try {

            String filename = "config.properties";
            input = MyClass.class.getClassLoader().getResourceAsStream(filename);
            if (input == null) {
            System.out.println("Sorry, unable to find " + filename);
            return;
            }

            // load a properties file from class path, inside static method
            prop.load(input);

            // get the property value and print it out
            System.out.println(prop.getProperty("serverUrl"));

            } catch (IOException ex) {
            ex.printStackTrace();
            } finally {
            if (input != null) {
            try {
            input.close();
            } catch (IOException e) {
            e.printStackTrace();
            }
            }
            }

            }

            }





            share|improve this answer














            getResourceAsStream("config.properties") - this method will only work if your properties file is in the classpath. I think you have added the properties file outside the classpath. This method is basically used for accessing a file present in the classpath.



            Please check it again.



            Thanks :)



            Working Code :



            public class MyClass {

            public static void main(String args) throws Exception {
            Properties prop = new Properties();
            InputStream input = null;

            try {

            String filename = "config.properties";
            input = MyClass.class.getClassLoader().getResourceAsStream(filename);
            if (input == null) {
            System.out.println("Sorry, unable to find " + filename);
            return;
            }

            // load a properties file from class path, inside static method
            prop.load(input);

            // get the property value and print it out
            System.out.println(prop.getProperty("serverUrl"));

            } catch (IOException ex) {
            ex.printStackTrace();
            } finally {
            if (input != null) {
            try {
            input.close();
            } catch (IOException e) {
            e.printStackTrace();
            }
            }
            }

            }

            }






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited yesterday

























            answered Nov 16 at 7:56









            Anish B.

            168




            168












            • how do I add the file to the classpath?
              – user840930
              Nov 16 at 8:29






            • 1




              I'm pretty sure the file is being found now. I changed the code to getResourceAsStream("/config.properties");
              – user840930
              Nov 16 at 10:00












            • keep the properties file in the resources folder of your project.. Then if you are using eclipse. Then right click on the project -> Properties ->Java Build Path -> click on source tab -> Click on Add folder and add the resources folder -> Click on Apply -> Click on Apply and close. Make a little modification to getResourceAsStream("resources/config.properties")
              – Anish B.
              Nov 16 at 10:04












            • tried "resources/config.properties. That did not work. Can't access the file. NullPointerException. The correct way looks like "/config.properties"
              – user840930
              Nov 16 at 11:06










            • then its fine :)
              – Anish B.
              Nov 16 at 12:39


















            • how do I add the file to the classpath?
              – user840930
              Nov 16 at 8:29






            • 1




              I'm pretty sure the file is being found now. I changed the code to getResourceAsStream("/config.properties");
              – user840930
              Nov 16 at 10:00












            • keep the properties file in the resources folder of your project.. Then if you are using eclipse. Then right click on the project -> Properties ->Java Build Path -> click on source tab -> Click on Add folder and add the resources folder -> Click on Apply -> Click on Apply and close. Make a little modification to getResourceAsStream("resources/config.properties")
              – Anish B.
              Nov 16 at 10:04












            • tried "resources/config.properties. That did not work. Can't access the file. NullPointerException. The correct way looks like "/config.properties"
              – user840930
              Nov 16 at 11:06










            • then its fine :)
              – Anish B.
              Nov 16 at 12:39
















            how do I add the file to the classpath?
            – user840930
            Nov 16 at 8:29




            how do I add the file to the classpath?
            – user840930
            Nov 16 at 8:29




            1




            1




            I'm pretty sure the file is being found now. I changed the code to getResourceAsStream("/config.properties");
            – user840930
            Nov 16 at 10:00






            I'm pretty sure the file is being found now. I changed the code to getResourceAsStream("/config.properties");
            – user840930
            Nov 16 at 10:00














            keep the properties file in the resources folder of your project.. Then if you are using eclipse. Then right click on the project -> Properties ->Java Build Path -> click on source tab -> Click on Add folder and add the resources folder -> Click on Apply -> Click on Apply and close. Make a little modification to getResourceAsStream("resources/config.properties")
            – Anish B.
            Nov 16 at 10:04






            keep the properties file in the resources folder of your project.. Then if you are using eclipse. Then right click on the project -> Properties ->Java Build Path -> click on source tab -> Click on Add folder and add the resources folder -> Click on Apply -> Click on Apply and close. Make a little modification to getResourceAsStream("resources/config.properties")
            – Anish B.
            Nov 16 at 10:04














            tried "resources/config.properties. That did not work. Can't access the file. NullPointerException. The correct way looks like "/config.properties"
            – user840930
            Nov 16 at 11:06




            tried "resources/config.properties. That did not work. Can't access the file. NullPointerException. The correct way looks like "/config.properties"
            – user840930
            Nov 16 at 11:06












            then its fine :)
            – Anish B.
            Nov 16 at 12:39




            then its fine :)
            – Anish B.
            Nov 16 at 12:39


















             

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