Using `gsub` inside (double quoted) heredoc does not work
It appears that using gsub
inside a (double quoted) heredoc does not evaluate the result of gsub
, as follows:
class Test
def self.define_phone
class_eval <<-EOS
def _phone=(val)
puts val
puts val.gsub(/D/,'')
end
EOS
end
end
Test.define_phone
test = Test.new
test._phone = '123-456-7890'
# >> 123-456-7890
# >> 123-456-7890
The second puts
should have printed 1234567890
, just as it would in this case:
'123-456-7890'.gsub(/D/,'')
# => "1234567890"
What is going on inside the heredoc?
ruby literals heredoc
add a comment |
It appears that using gsub
inside a (double quoted) heredoc does not evaluate the result of gsub
, as follows:
class Test
def self.define_phone
class_eval <<-EOS
def _phone=(val)
puts val
puts val.gsub(/D/,'')
end
EOS
end
end
Test.define_phone
test = Test.new
test._phone = '123-456-7890'
# >> 123-456-7890
# >> 123-456-7890
The second puts
should have printed 1234567890
, just as it would in this case:
'123-456-7890'.gsub(/D/,'')
# => "1234567890"
What is going on inside the heredoc?
ruby literals heredoc
Note that you can accomplish this without class eval (and thus no worrying about string escaping). Just replace theclass_eval
anddef _phone
withdefine_method :_phone do |val|
– Max
Nov 26 '18 at 14:46
add a comment |
It appears that using gsub
inside a (double quoted) heredoc does not evaluate the result of gsub
, as follows:
class Test
def self.define_phone
class_eval <<-EOS
def _phone=(val)
puts val
puts val.gsub(/D/,'')
end
EOS
end
end
Test.define_phone
test = Test.new
test._phone = '123-456-7890'
# >> 123-456-7890
# >> 123-456-7890
The second puts
should have printed 1234567890
, just as it would in this case:
'123-456-7890'.gsub(/D/,'')
# => "1234567890"
What is going on inside the heredoc?
ruby literals heredoc
It appears that using gsub
inside a (double quoted) heredoc does not evaluate the result of gsub
, as follows:
class Test
def self.define_phone
class_eval <<-EOS
def _phone=(val)
puts val
puts val.gsub(/D/,'')
end
EOS
end
end
Test.define_phone
test = Test.new
test._phone = '123-456-7890'
# >> 123-456-7890
# >> 123-456-7890
The second puts
should have printed 1234567890
, just as it would in this case:
'123-456-7890'.gsub(/D/,'')
# => "1234567890"
What is going on inside the heredoc?
ruby literals heredoc
ruby literals heredoc
edited Nov 26 '18 at 5:05
sawa
132k29205304
132k29205304
asked Nov 26 '18 at 3:18
DonatoDonato
2,11431434
2,11431434
Note that you can accomplish this without class eval (and thus no worrying about string escaping). Just replace theclass_eval
anddef _phone
withdefine_method :_phone do |val|
– Max
Nov 26 '18 at 14:46
add a comment |
Note that you can accomplish this without class eval (and thus no worrying about string escaping). Just replace theclass_eval
anddef _phone
withdefine_method :_phone do |val|
– Max
Nov 26 '18 at 14:46
Note that you can accomplish this without class eval (and thus no worrying about string escaping). Just replace the
class_eval
and def _phone
with define_method :_phone do |val|
– Max
Nov 26 '18 at 14:46
Note that you can accomplish this without class eval (and thus no worrying about string escaping). Just replace the
class_eval
and def _phone
with define_method :_phone do |val|
– Max
Nov 26 '18 at 14:46
add a comment |
1 Answer
1
active
oldest
votes
The problem is with the D
in the regex. It will be evaluated when the heredoc is evaluated as a string, which results in D
:
"D" # => "D"
eval("/D/") #=> /D/
On the other hand, D
inside a single quote will not be evaluated as D
:
'D' # => "\D"
eval('/D/') # => /D/
So wrap the heredoc terminator EOS
in a single quote to achieve what you want:
class Test
def self.define_phone
class_eval <<-'EOS'
def _phone=(val)
puts val
puts val.gsub(/D/,'')
end
EOS
end
end
Test.define_phone
test = Test.new
test._phone = '123-456-7890'
# >> 123-456-7890
# >> 1234567890
Reference
If you run the above code without the wrapped EOS
, gsub
will try to replace "D" (literally) in the val
. See this:
test._phone = '123-D456-D7890DD'
# >> 123-D456-D7890DD
# >> 123-456-7890
3
Or, another way is to replaceD
with\D
.
– sawa
Nov 26 '18 at 4:54
Official reference: Literals - Here Documents
– Stefan
Nov 26 '18 at 9:12
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The problem is with the D
in the regex. It will be evaluated when the heredoc is evaluated as a string, which results in D
:
"D" # => "D"
eval("/D/") #=> /D/
On the other hand, D
inside a single quote will not be evaluated as D
:
'D' # => "\D"
eval('/D/') # => /D/
So wrap the heredoc terminator EOS
in a single quote to achieve what you want:
class Test
def self.define_phone
class_eval <<-'EOS'
def _phone=(val)
puts val
puts val.gsub(/D/,'')
end
EOS
end
end
Test.define_phone
test = Test.new
test._phone = '123-456-7890'
# >> 123-456-7890
# >> 1234567890
Reference
If you run the above code without the wrapped EOS
, gsub
will try to replace "D" (literally) in the val
. See this:
test._phone = '123-D456-D7890DD'
# >> 123-D456-D7890DD
# >> 123-456-7890
3
Or, another way is to replaceD
with\D
.
– sawa
Nov 26 '18 at 4:54
Official reference: Literals - Here Documents
– Stefan
Nov 26 '18 at 9:12
add a comment |
The problem is with the D
in the regex. It will be evaluated when the heredoc is evaluated as a string, which results in D
:
"D" # => "D"
eval("/D/") #=> /D/
On the other hand, D
inside a single quote will not be evaluated as D
:
'D' # => "\D"
eval('/D/') # => /D/
So wrap the heredoc terminator EOS
in a single quote to achieve what you want:
class Test
def self.define_phone
class_eval <<-'EOS'
def _phone=(val)
puts val
puts val.gsub(/D/,'')
end
EOS
end
end
Test.define_phone
test = Test.new
test._phone = '123-456-7890'
# >> 123-456-7890
# >> 1234567890
Reference
If you run the above code without the wrapped EOS
, gsub
will try to replace "D" (literally) in the val
. See this:
test._phone = '123-D456-D7890DD'
# >> 123-D456-D7890DD
# >> 123-456-7890
3
Or, another way is to replaceD
with\D
.
– sawa
Nov 26 '18 at 4:54
Official reference: Literals - Here Documents
– Stefan
Nov 26 '18 at 9:12
add a comment |
The problem is with the D
in the regex. It will be evaluated when the heredoc is evaluated as a string, which results in D
:
"D" # => "D"
eval("/D/") #=> /D/
On the other hand, D
inside a single quote will not be evaluated as D
:
'D' # => "\D"
eval('/D/') # => /D/
So wrap the heredoc terminator EOS
in a single quote to achieve what you want:
class Test
def self.define_phone
class_eval <<-'EOS'
def _phone=(val)
puts val
puts val.gsub(/D/,'')
end
EOS
end
end
Test.define_phone
test = Test.new
test._phone = '123-456-7890'
# >> 123-456-7890
# >> 1234567890
Reference
If you run the above code without the wrapped EOS
, gsub
will try to replace "D" (literally) in the val
. See this:
test._phone = '123-D456-D7890DD'
# >> 123-D456-D7890DD
# >> 123-456-7890
The problem is with the D
in the regex. It will be evaluated when the heredoc is evaluated as a string, which results in D
:
"D" # => "D"
eval("/D/") #=> /D/
On the other hand, D
inside a single quote will not be evaluated as D
:
'D' # => "\D"
eval('/D/') # => /D/
So wrap the heredoc terminator EOS
in a single quote to achieve what you want:
class Test
def self.define_phone
class_eval <<-'EOS'
def _phone=(val)
puts val
puts val.gsub(/D/,'')
end
EOS
end
end
Test.define_phone
test = Test.new
test._phone = '123-456-7890'
# >> 123-456-7890
# >> 1234567890
Reference
If you run the above code without the wrapped EOS
, gsub
will try to replace "D" (literally) in the val
. See this:
test._phone = '123-D456-D7890DD'
# >> 123-D456-D7890DD
# >> 123-456-7890
edited Nov 26 '18 at 5:03
sawa
132k29205304
132k29205304
answered Nov 26 '18 at 4:51
Lenin Raj RajasekaranLenin Raj Rajasekaran
16k1171114
16k1171114
3
Or, another way is to replaceD
with\D
.
– sawa
Nov 26 '18 at 4:54
Official reference: Literals - Here Documents
– Stefan
Nov 26 '18 at 9:12
add a comment |
3
Or, another way is to replaceD
with\D
.
– sawa
Nov 26 '18 at 4:54
Official reference: Literals - Here Documents
– Stefan
Nov 26 '18 at 9:12
3
3
Or, another way is to replace
D
with \D
.– sawa
Nov 26 '18 at 4:54
Or, another way is to replace
D
with \D
.– sawa
Nov 26 '18 at 4:54
Official reference: Literals - Here Documents
– Stefan
Nov 26 '18 at 9:12
Official reference: Literals - Here Documents
– Stefan
Nov 26 '18 at 9:12
add a comment |
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Note that you can accomplish this without class eval (and thus no worrying about string escaping). Just replace the
class_eval
anddef _phone
withdefine_method :_phone do |val|
– Max
Nov 26 '18 at 14:46