How to print input arguments in bash script as is
Could you please help, does exist a command in bash to quote input argument?
script ./test.sh:
#!/bin/bash
echo ${1}
./test.sh "It costs $1"
This prints It costs, but how to print it as is It costs $1.
Of course it is possible to quote the argument directly in the command:
./test.sh "It costs $1"
and it prints It costs $1. But how to quote it in the script?
UPDATED: It is possible with single quotes ./test.sh 'It costs $1'
bash quote
asked Nov 26 '18 at 3:17
WalrusWalrus
7418
add a comment |
Could you please help, does exist a command in bash to quote input argument?
script ./test.sh:
#!/bin/bash
echo ${1}
./test.sh "It costs $1"
This prints It costs, but how to print it as is It costs $1.
Of course it is possible to quote the argument directly in the command:
./test.sh "It costs $1"
and it prints It costs $1. But how to quote it in the script?
UPDATED: It is possible with single quotes ./test.sh 'It costs $1'
bash quote
asked Nov 26 '18 at 3:17
WalrusWalrus
7418
1
Exactly as you just did:echo "It costs ${1}", or with single quotes:echo 'It costs ${1}'.
– Amadan
Nov 26 '18 at 3:19
1
When your script executes, it's already too late. There is nothing your script can do to get the original misquoted$1
– that other guy
Nov 26 '18 at 3:20
Did you mean to print the an argument, or that the cost is a single dollar?$1will do the latter. If you run as-is with just./test.shyou'll get what you're seeing, but try./test.sh "a buck". For real clarity, read this manual, especially here & here.
– Paul Hodges
Nov 26 '18 at 15:25
add a comment |
Could you please help, does exist a command in bash to quote input argument?
script ./test.sh:
#!/bin/bash
echo ${1}
./test.sh "It costs $1"
This prints It costs, but how to print it as is It costs $1.
Of course it is possible to quote the argument directly in the command:
./test.sh "It costs $1"
and it prints It costs $1. But how to quote it in the script?
UPDATED: It is possible with single quotes ./test.sh 'It costs $1'
bash quote
asked Nov 26 '18 at 3:17
WalrusWalrus
7418
Could you please help, does exist a command in bash to quote input argument?
script ./test.sh:
#!/bin/bash
echo ${1}
./test.sh "It costs $1"
This prints It costs, but how to print it as is It costs $1.
Of course it is possible to quote the argument directly in the command:
./test.sh "It costs $1"
and it prints It costs $1. But how to quote it in the script?
UPDATED: It is possible with single quotes ./test.sh 'It costs $1'
bash quote
bash quote
asked Nov 26 '18 at 3:17
WalrusWalrus
7418
asked Nov 26 '18 at 3:17
WalrusWalrus
7418
edited Nov 26 '18 at 3:53
Walrus
asked Nov 26 '18 at 3:17
WalrusWalrus
7418
asked Nov 26 '18 at 3:17
WalrusWalrus
7418
asked Nov 26 '18 at 3:17
WalrusWalrus
7418
7418
1
Exactly as you just did:echo "It costs ${1}", or with single quotes:echo 'It costs ${1}'.
– Amadan
Nov 26 '18 at 3:19
1
When your script executes, it's already too late. There is nothing your script can do to get the original misquoted$1
– that other guy
Nov 26 '18 at 3:20
Did you mean to print the an argument, or that the cost is a single dollar?$1will do the latter. If you run as-is with just./test.shyou'll get what you're seeing, but try./test.sh "a buck". For real clarity, read this manual, especially here & here.
– Paul Hodges
Nov 26 '18 at 15:25
add a comment |
1
Exactly as you just did:echo "It costs ${1}", or with single quotes:echo 'It costs ${1}'.
– Amadan
Nov 26 '18 at 3:19
1
When your script executes, it's already too late. There is nothing your script can do to get the original misquoted$1
– that other guy
Nov 26 '18 at 3:20
Did you mean to print the an argument, or that the cost is a single dollar?$1will do the latter. If you run as-is with just./test.shyou'll get what you're seeing, but try./test.sh "a buck". For real clarity, read this manual, especially here & here.
– Paul Hodges
Nov 26 '18 at 15:25
1
1
Exactly as you just did:
echo "It costs ${1}", or with single quotes: echo 'It costs ${1}'.– Amadan
Nov 26 '18 at 3:19
Exactly as you just did:
echo "It costs ${1}", or with single quotes: echo 'It costs ${1}'.– Amadan
Nov 26 '18 at 3:19
1
1
When your script executes, it's already too late. There is nothing your script can do to get the original misquoted
$1– that other guy
Nov 26 '18 at 3:20
When your script executes, it's already too late. There is nothing your script can do to get the original misquoted
$1– that other guy
Nov 26 '18 at 3:20
Did you mean to print the an argument, or that the cost is a single dollar?
$1 will do the latter. If you run as-is with just ./test.sh you'll get what you're seeing, but try ./test.sh "a buck". For real clarity, read this manual, especially here & here.– Paul Hodges
Nov 26 '18 at 15:25
Did you mean to print the an argument, or that the cost is a single dollar?
$1 will do the latter. If you run as-is with just ./test.sh you'll get what you're seeing, but try ./test.sh "a buck". For real clarity, read this manual, especially here & here.– Paul Hodges
Nov 26 '18 at 15:25
add a comment |
2 Answers
2
active
oldest
votes
You may update your program like below to print/display all arguments.
#!/bin/bash
echo "$@"
This will print all the arguments passed while running test.sh. $1 is a variable which substituted with empty string while calling your program test.sh. Inside test.sh, first argument you passed in command line becomes $1, second becomes $2 and so forth.
$@ prints all arguments.
answered Nov 26 '18 at 3:28
Robert RanjanRobert Ranjan
35339
2
Indeed, it is useful to doman bashand read everything underEXPANSIONheading. There is so much good info there that many people never see.
– Amadan
Nov 26 '18 at 3:57
add a comment |
I often use:
printf "'%s' " "$@"
This is an alternative to echo when you want each argument quoted.
answered Nov 26 '18 at 4:19
CraigCraig
5217
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You may update your program like below to print/display all arguments.
#!/bin/bash
echo "$@"
This will print all the arguments passed while running test.sh. $1 is a variable which substituted with empty string while calling your program test.sh. Inside test.sh, first argument you passed in command line becomes $1, second becomes $2 and so forth.
$@ prints all arguments.
answered Nov 26 '18 at 3:28
Robert RanjanRobert Ranjan
35339
2
Indeed, it is useful to doman bashand read everything underEXPANSIONheading. There is so much good info there that many people never see.
– Amadan
Nov 26 '18 at 3:57
add a comment |
You may update your program like below to print/display all arguments.
#!/bin/bash
echo "$@"
This will print all the arguments passed while running test.sh. $1 is a variable which substituted with empty string while calling your program test.sh. Inside test.sh, first argument you passed in command line becomes $1, second becomes $2 and so forth.
$@ prints all arguments.
answered Nov 26 '18 at 3:28
Robert RanjanRobert Ranjan
35339
2
Indeed, it is useful to doman bashand read everything underEXPANSIONheading. There is so much good info there that many people never see.
– Amadan
Nov 26 '18 at 3:57
add a comment |
You may update your program like below to print/display all arguments.
#!/bin/bash
echo "$@"
This will print all the arguments passed while running test.sh. $1 is a variable which substituted with empty string while calling your program test.sh. Inside test.sh, first argument you passed in command line becomes $1, second becomes $2 and so forth.
$@ prints all arguments.
answered Nov 26 '18 at 3:28
Robert RanjanRobert Ranjan
35339
You may update your program like below to print/display all arguments.
#!/bin/bash
echo "$@"
This will print all the arguments passed while running test.sh. $1 is a variable which substituted with empty string while calling your program test.sh. Inside test.sh, first argument you passed in command line becomes $1, second becomes $2 and so forth.
$@ prints all arguments.
answered Nov 26 '18 at 3:28
Robert RanjanRobert Ranjan
35339
answered Nov 26 '18 at 3:28
Robert RanjanRobert Ranjan
35339
answered Nov 26 '18 at 3:28
Robert RanjanRobert Ranjan
35339
answered Nov 26 '18 at 3:28
Robert RanjanRobert Ranjan
35339
35339
2
Indeed, it is useful to doman bashand read everything underEXPANSIONheading. There is so much good info there that many people never see.
– Amadan
Nov 26 '18 at 3:57
add a comment |
2
Indeed, it is useful to doman bashand read everything underEXPANSIONheading. There is so much good info there that many people never see.
– Amadan
Nov 26 '18 at 3:57
2
2
Indeed, it is useful to do
man bash and read everything under EXPANSION heading. There is so much good info there that many people never see.– Amadan
Nov 26 '18 at 3:57
Indeed, it is useful to do
man bash and read everything under EXPANSION heading. There is so much good info there that many people never see.– Amadan
Nov 26 '18 at 3:57
add a comment |
I often use:
printf "'%s' " "$@"
This is an alternative to echo when you want each argument quoted.
answered Nov 26 '18 at 4:19
CraigCraig
5217
add a comment |
I often use:
printf "'%s' " "$@"
This is an alternative to echo when you want each argument quoted.
answered Nov 26 '18 at 4:19
CraigCraig
5217
add a comment |
I often use:
printf "'%s' " "$@"
This is an alternative to echo when you want each argument quoted.
answered Nov 26 '18 at 4:19
CraigCraig
5217
I often use:
printf "'%s' " "$@"
This is an alternative to echo when you want each argument quoted.
answered Nov 26 '18 at 4:19
CraigCraig
5217
answered Nov 26 '18 at 4:19
CraigCraig
5217
answered Nov 26 '18 at 4:19
CraigCraig
5217
answered Nov 26 '18 at 4:19
CraigCraig
5217
5217
add a comment |
add a comment |
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1
Exactly as you just did:
echo "It costs ${1}", or with single quotes:echo 'It costs ${1}'.– Amadan
Nov 26 '18 at 3:19
1
When your script executes, it's already too late. There is nothing your script can do to get the original misquoted
$1– that other guy
Nov 26 '18 at 3:20
Did you mean to print the an argument, or that the cost is a single dollar?
$1will do the latter. If you run as-is with just./test.shyou'll get what you're seeing, but try./test.sh "a buck". For real clarity, read this manual, especially here & here.– Paul Hodges
Nov 26 '18 at 15:25