Counting Occurences of a String within elements of a list?
I'm trying to count the amount of times "a class" occurs within each "h2 class", so I split the parsed texted by "h2 class" but am having struggles with the second part, this is where I'm at
#splitting parsed text by header
parsed.split("h2 class")
#creating the list for the a value count to be stored
aValCount =
#counting amount of items per header
for i in range (len(parsed)):
aValCount = aValCount + ((parsed[i]).count("a class"))
the error I'm getting is
TypeError: can only concatenate list (not "int") to list
, but I can't figure out how to this without getting some sort of error
Edited: Thought I should add, I want it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
python for-loop
edited Nov 21 at 6:42
Aqueous Carlos
289213
asked Nov 21 at 1:31
SoloTriesToLearn
466
add a comment |
I'm trying to count the amount of times "a class" occurs within each "h2 class", so I split the parsed texted by "h2 class" but am having struggles with the second part, this is where I'm at
#splitting parsed text by header
parsed.split("h2 class")
#creating the list for the a value count to be stored
aValCount =
#counting amount of items per header
for i in range (len(parsed)):
aValCount = aValCount + ((parsed[i]).count("a class"))
the error I'm getting is
TypeError: can only concatenate list (not "int") to list
, but I can't figure out how to this without getting some sort of error
Edited: Thought I should add, I want it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
python for-loop
edited Nov 21 at 6:42
Aqueous Carlos
289213
asked Nov 21 at 1:31
SoloTriesToLearn
466
1
InitializeaValCount=0
– Julian Peller
Nov 21 at 1:32
Thought I should add, I want it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:34
1
I see, you need to useappend()as the actual answer suggests then!
– Julian Peller
Nov 21 at 1:38
add a comment |
I'm trying to count the amount of times "a class" occurs within each "h2 class", so I split the parsed texted by "h2 class" but am having struggles with the second part, this is where I'm at
#splitting parsed text by header
parsed.split("h2 class")
#creating the list for the a value count to be stored
aValCount =
#counting amount of items per header
for i in range (len(parsed)):
aValCount = aValCount + ((parsed[i]).count("a class"))
the error I'm getting is
TypeError: can only concatenate list (not "int") to list
, but I can't figure out how to this without getting some sort of error
Edited: Thought I should add, I want it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
python for-loop
edited Nov 21 at 6:42
Aqueous Carlos
289213
asked Nov 21 at 1:31
SoloTriesToLearn
466
I'm trying to count the amount of times "a class" occurs within each "h2 class", so I split the parsed texted by "h2 class" but am having struggles with the second part, this is where I'm at
#splitting parsed text by header
parsed.split("h2 class")
#creating the list for the a value count to be stored
aValCount =
#counting amount of items per header
for i in range (len(parsed)):
aValCount = aValCount + ((parsed[i]).count("a class"))
the error I'm getting is
TypeError: can only concatenate list (not "int") to list
, but I can't figure out how to this without getting some sort of error
Edited: Thought I should add, I want it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
python for-loop
python for-loop
edited Nov 21 at 6:42
Aqueous Carlos
289213
asked Nov 21 at 1:31
SoloTriesToLearn
466
edited Nov 21 at 6:42
Aqueous Carlos
289213
asked Nov 21 at 1:31
SoloTriesToLearn
466
edited Nov 21 at 6:42
Aqueous Carlos
289213
edited Nov 21 at 6:42
Aqueous Carlos
289213
edited Nov 21 at 6:42
Aqueous Carlos
289213
289213
asked Nov 21 at 1:31
SoloTriesToLearn
466
asked Nov 21 at 1:31
SoloTriesToLearn
466
asked Nov 21 at 1:31
SoloTriesToLearn
466
466
1
InitializeaValCount=0
– Julian Peller
Nov 21 at 1:32
Thought I should add, I want it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:34
1
I see, you need to useappend()as the actual answer suggests then!
– Julian Peller
Nov 21 at 1:38
add a comment |
1
InitializeaValCount=0
– Julian Peller
Nov 21 at 1:32
Thought I should add, I want it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:34
1
I see, you need to useappend()as the actual answer suggests then!
– Julian Peller
Nov 21 at 1:38
1
1
Initialize
aValCount=0– Julian Peller
Nov 21 at 1:32
Initialize
aValCount=0– Julian Peller
Nov 21 at 1:32
Thought I should add, I want it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:34
Thought I should add, I want it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:34
1
1
I see, you need to use
append() as the actual answer suggests then!– Julian Peller
Nov 21 at 1:38
I see, you need to use
append() as the actual answer suggests then!– Julian Peller
Nov 21 at 1:38
add a comment |
1 Answer
1
active
oldest
votes
The issue is that aValCount is an array and ((parsed[i]).count("a class")) is an int.
What you want is to add the count to aValCount so you need to pass another array.
aValCount = aValCount + [((parsed[i]).count("a class"))]
If you add [...] that should do it.
Or you can also do
aValCount.append(((parsed[i]).count("a class"))])
Hope that help.
results = parsed.split("h2 class")
aValCountList =
for i in range (len(results)):
aValCountList.append((results[i]).count("a class"))
answered Nov 21 at 1:37
Antoine
793624
When I try to print this, I get a significant amount of zeros, would that be a zero for every occurrence? I'm trying to have it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:40
You need to assign the value of the split to another variable.
– Antoine
Nov 21 at 1:42
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The issue is that aValCount is an array and ((parsed[i]).count("a class")) is an int.
What you want is to add the count to aValCount so you need to pass another array.
aValCount = aValCount + [((parsed[i]).count("a class"))]
If you add [...] that should do it.
Or you can also do
aValCount.append(((parsed[i]).count("a class"))])
Hope that help.
results = parsed.split("h2 class")
aValCountList =
for i in range (len(results)):
aValCountList.append((results[i]).count("a class"))
answered Nov 21 at 1:37
Antoine
793624
When I try to print this, I get a significant amount of zeros, would that be a zero for every occurrence? I'm trying to have it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:40
You need to assign the value of the split to another variable.
– Antoine
Nov 21 at 1:42
add a comment |
The issue is that aValCount is an array and ((parsed[i]).count("a class")) is an int.
What you want is to add the count to aValCount so you need to pass another array.
aValCount = aValCount + [((parsed[i]).count("a class"))]
If you add [...] that should do it.
Or you can also do
aValCount.append(((parsed[i]).count("a class"))])
Hope that help.
results = parsed.split("h2 class")
aValCountList =
for i in range (len(results)):
aValCountList.append((results[i]).count("a class"))
answered Nov 21 at 1:37
Antoine
793624
When I try to print this, I get a significant amount of zeros, would that be a zero for every occurrence? I'm trying to have it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:40
You need to assign the value of the split to another variable.
– Antoine
Nov 21 at 1:42
add a comment |
The issue is that aValCount is an array and ((parsed[i]).count("a class")) is an int.
What you want is to add the count to aValCount so you need to pass another array.
aValCount = aValCount + [((parsed[i]).count("a class"))]
If you add [...] that should do it.
Or you can also do
aValCount.append(((parsed[i]).count("a class"))])
Hope that help.
results = parsed.split("h2 class")
aValCountList =
for i in range (len(results)):
aValCountList.append((results[i]).count("a class"))
answered Nov 21 at 1:37
Antoine
793624
The issue is that aValCount is an array and ((parsed[i]).count("a class")) is an int.
What you want is to add the count to aValCount so you need to pass another array.
aValCount = aValCount + [((parsed[i]).count("a class"))]
If you add [...] that should do it.
Or you can also do
aValCount.append(((parsed[i]).count("a class"))])
Hope that help.
results = parsed.split("h2 class")
aValCountList =
for i in range (len(results)):
aValCountList.append((results[i]).count("a class"))
answered Nov 21 at 1:37
Antoine
793624
edited Nov 21 at 1:44
answered Nov 21 at 1:37
Antoine
793624
answered Nov 21 at 1:37
Antoine
793624
answered Nov 21 at 1:37
Antoine
793624
793624
When I try to print this, I get a significant amount of zeros, would that be a zero for every occurrence? I'm trying to have it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:40
You need to assign the value of the split to another variable.
– Antoine
Nov 21 at 1:42
add a comment |
When I try to print this, I get a significant amount of zeros, would that be a zero for every occurrence? I'm trying to have it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:40
You need to assign the value of the split to another variable.
– Antoine
Nov 21 at 1:42
When I try to print this, I get a significant amount of zeros, would that be a zero for every occurrence? I'm trying to have it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:40
When I try to print this, I get a significant amount of zeros, would that be a zero for every occurrence? I'm trying to have it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:40
You need to assign the value of the split to another variable.
– Antoine
Nov 21 at 1:42
You need to assign the value of the split to another variable.
– Antoine
Nov 21 at 1:42
add a comment |
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1
Initialize
aValCount=0– Julian Peller
Nov 21 at 1:32
Thought I should add, I want it to be a list of the counts from the strings, so the count from element one in parsed, should be element 1 in aValCount
– SoloTriesToLearn
Nov 21 at 1:34
1
I see, you need to use
append()as the actual answer suggests then!– Julian Peller
Nov 21 at 1:38