(Codewars) Linked Lists-Sorted Insert
$begingroup$
Kata: https://www.codewars.com/kata/linked-lists-sorted-insert
Description
Write a SortedInsert() function which inserts a node into the correct location of a pre-sorted linked list which is sorted in ascending order. SortedInsert takes the head of a linked list and data used to create a node as arguments. SortedInsert() should also return the head of the list.
sortedInsert(1 -> 2 -> 3 -> null, 4) === 1 -> 2 -> 3 -> 4 -> null)
sortedInsert(1 -> 7 -> 8 -> null, 5) === 1 -> 5 -> 7 -> 8 -> null)
sortedInsert(3 -> 5 -> 9 -> null, 7) === 3 -> 5 -> 7 -> 9 -> null)
My Solution
def sorted_insert(head, data):
prev = None
node_j = head
node_i = Node(data)
while node_j:
if node_j.data > data:
node_i.next = node_j
break
prev = node_j
node_j = node_j.next
else:
node_i.next = None
if prev:
prev.next = node_i
return head if prev else node_i
python beginner linked-list
asked 8 mins ago
Tobi AlafinTobi Alafin
48719
$endgroup$
add a comment |
$begingroup$
Kata: https://www.codewars.com/kata/linked-lists-sorted-insert
Description
Write a SortedInsert() function which inserts a node into the correct location of a pre-sorted linked list which is sorted in ascending order. SortedInsert takes the head of a linked list and data used to create a node as arguments. SortedInsert() should also return the head of the list.
sortedInsert(1 -> 2 -> 3 -> null, 4) === 1 -> 2 -> 3 -> 4 -> null)
sortedInsert(1 -> 7 -> 8 -> null, 5) === 1 -> 5 -> 7 -> 8 -> null)
sortedInsert(3 -> 5 -> 9 -> null, 7) === 3 -> 5 -> 7 -> 9 -> null)
My Solution
def sorted_insert(head, data):
prev = None
node_j = head
node_i = Node(data)
while node_j:
if node_j.data > data:
node_i.next = node_j
break
prev = node_j
node_j = node_j.next
else:
node_i.next = None
if prev:
prev.next = node_i
return head if prev else node_i
python beginner linked-list
asked 8 mins ago
Tobi AlafinTobi Alafin
48719
$endgroup$
add a comment |
$begingroup$
Kata: https://www.codewars.com/kata/linked-lists-sorted-insert
Description
Write a SortedInsert() function which inserts a node into the correct location of a pre-sorted linked list which is sorted in ascending order. SortedInsert takes the head of a linked list and data used to create a node as arguments. SortedInsert() should also return the head of the list.
sortedInsert(1 -> 2 -> 3 -> null, 4) === 1 -> 2 -> 3 -> 4 -> null)
sortedInsert(1 -> 7 -> 8 -> null, 5) === 1 -> 5 -> 7 -> 8 -> null)
sortedInsert(3 -> 5 -> 9 -> null, 7) === 3 -> 5 -> 7 -> 9 -> null)
My Solution
def sorted_insert(head, data):
prev = None
node_j = head
node_i = Node(data)
while node_j:
if node_j.data > data:
node_i.next = node_j
break
prev = node_j
node_j = node_j.next
else:
node_i.next = None
if prev:
prev.next = node_i
return head if prev else node_i
python beginner linked-list
asked 8 mins ago
Tobi AlafinTobi Alafin
48719
$endgroup$
Kata: https://www.codewars.com/kata/linked-lists-sorted-insert
Description
Write a SortedInsert() function which inserts a node into the correct location of a pre-sorted linked list which is sorted in ascending order. SortedInsert takes the head of a linked list and data used to create a node as arguments. SortedInsert() should also return the head of the list.
sortedInsert(1 -> 2 -> 3 -> null, 4) === 1 -> 2 -> 3 -> 4 -> null)
sortedInsert(1 -> 7 -> 8 -> null, 5) === 1 -> 5 -> 7 -> 8 -> null)
sortedInsert(3 -> 5 -> 9 -> null, 7) === 3 -> 5 -> 7 -> 9 -> null)
My Solution
def sorted_insert(head, data):
prev = None
node_j = head
node_i = Node(data)
while node_j:
if node_j.data > data:
node_i.next = node_j
break
prev = node_j
node_j = node_j.next
else:
node_i.next = None
if prev:
prev.next = node_i
return head if prev else node_i
python beginner linked-list
python beginner linked-list
asked 8 mins ago
Tobi AlafinTobi Alafin
48719
asked 8 mins ago
Tobi AlafinTobi Alafin
48719
asked 8 mins ago
Tobi AlafinTobi Alafin
48719
asked 8 mins ago
Tobi AlafinTobi Alafin
48719
asked 8 mins ago
Tobi AlafinTobi Alafin
48719
48719
add a comment |
add a comment |
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