How to mock an interface default method Java8/Mockito2












1















I cannot mock a method defined as default in an interface. Can anyone help me here?



The interface has default method providing a logger.



import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

public interface Loggable {

default Logger logger() {
return LoggerFactory.getLogger(this.getClass());
}
}


It is used this way:



public class AppShowOff implements Loggable{

public void doMagic() {
logger().debug("It works");
System.out.println("Works");
}
}


now I would like to write a test proving that debug method has been called.



import static org.mockito.ArgumentMatchers.any;
import static org.mockito.Mockito.mock;
import static org.mockito.Mockito.times;
import static org.mockito.Mockito.verify;
import static org.mockito.Mockito.when;

import org.junit.Test;
import org.mockito.Mockito;
import org.slf4j.Logger;

public class AppShowOffTest {

@Test
public void doMagic() {
Logger loggerMock = mock(Logger.class);
Loggable loggableMock = mock(Loggable.class); // <- not needed, but I also tried this way

// mocks done

AppShowOff app = new AppShowOff();
AppShowOff appSpy = Mockito.spy(new AppShowOff());

when(loggableMock.logger()).thenReturn(loggerMock);
when(appSpy.logger()).thenReturn(loggerMock);

app.doMagic();
verify(loggerMock, times(1)).debug(any());
}
}


as you can see I have tried to mock the default method in two ways:



when(loggableMock.logger()).thenReturn(loggerMock);
when(appSpy.logger()).thenReturn(loggerMock);


but it does not work. The result is:




Wanted but not invoked: logger.debug();
-> at so.AppShowOffTest.doMagic(AppShowOffTest.java:29) Actually, there were zero interactions with this mock.











share|improve this question


















  • 1





    You're mocking on appSpy but calling doMagic on app...

    – daniu
    Nov 23 '18 at 12:48
















1















I cannot mock a method defined as default in an interface. Can anyone help me here?



The interface has default method providing a logger.



import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

public interface Loggable {

default Logger logger() {
return LoggerFactory.getLogger(this.getClass());
}
}


It is used this way:



public class AppShowOff implements Loggable{

public void doMagic() {
logger().debug("It works");
System.out.println("Works");
}
}


now I would like to write a test proving that debug method has been called.



import static org.mockito.ArgumentMatchers.any;
import static org.mockito.Mockito.mock;
import static org.mockito.Mockito.times;
import static org.mockito.Mockito.verify;
import static org.mockito.Mockito.when;

import org.junit.Test;
import org.mockito.Mockito;
import org.slf4j.Logger;

public class AppShowOffTest {

@Test
public void doMagic() {
Logger loggerMock = mock(Logger.class);
Loggable loggableMock = mock(Loggable.class); // <- not needed, but I also tried this way

// mocks done

AppShowOff app = new AppShowOff();
AppShowOff appSpy = Mockito.spy(new AppShowOff());

when(loggableMock.logger()).thenReturn(loggerMock);
when(appSpy.logger()).thenReturn(loggerMock);

app.doMagic();
verify(loggerMock, times(1)).debug(any());
}
}


as you can see I have tried to mock the default method in two ways:



when(loggableMock.logger()).thenReturn(loggerMock);
when(appSpy.logger()).thenReturn(loggerMock);


but it does not work. The result is:




Wanted but not invoked: logger.debug();
-> at so.AppShowOffTest.doMagic(AppShowOffTest.java:29) Actually, there were zero interactions with this mock.











share|improve this question


















  • 1





    You're mocking on appSpy but calling doMagic on app...

    – daniu
    Nov 23 '18 at 12:48














1












1








1








I cannot mock a method defined as default in an interface. Can anyone help me here?



The interface has default method providing a logger.



import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

public interface Loggable {

default Logger logger() {
return LoggerFactory.getLogger(this.getClass());
}
}


It is used this way:



public class AppShowOff implements Loggable{

public void doMagic() {
logger().debug("It works");
System.out.println("Works");
}
}


now I would like to write a test proving that debug method has been called.



import static org.mockito.ArgumentMatchers.any;
import static org.mockito.Mockito.mock;
import static org.mockito.Mockito.times;
import static org.mockito.Mockito.verify;
import static org.mockito.Mockito.when;

import org.junit.Test;
import org.mockito.Mockito;
import org.slf4j.Logger;

public class AppShowOffTest {

@Test
public void doMagic() {
Logger loggerMock = mock(Logger.class);
Loggable loggableMock = mock(Loggable.class); // <- not needed, but I also tried this way

// mocks done

AppShowOff app = new AppShowOff();
AppShowOff appSpy = Mockito.spy(new AppShowOff());

when(loggableMock.logger()).thenReturn(loggerMock);
when(appSpy.logger()).thenReturn(loggerMock);

app.doMagic();
verify(loggerMock, times(1)).debug(any());
}
}


as you can see I have tried to mock the default method in two ways:



when(loggableMock.logger()).thenReturn(loggerMock);
when(appSpy.logger()).thenReturn(loggerMock);


but it does not work. The result is:




Wanted but not invoked: logger.debug();
-> at so.AppShowOffTest.doMagic(AppShowOffTest.java:29) Actually, there were zero interactions with this mock.











share|improve this question














I cannot mock a method defined as default in an interface. Can anyone help me here?



The interface has default method providing a logger.



import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

public interface Loggable {

default Logger logger() {
return LoggerFactory.getLogger(this.getClass());
}
}


It is used this way:



public class AppShowOff implements Loggable{

public void doMagic() {
logger().debug("It works");
System.out.println("Works");
}
}


now I would like to write a test proving that debug method has been called.



import static org.mockito.ArgumentMatchers.any;
import static org.mockito.Mockito.mock;
import static org.mockito.Mockito.times;
import static org.mockito.Mockito.verify;
import static org.mockito.Mockito.when;

import org.junit.Test;
import org.mockito.Mockito;
import org.slf4j.Logger;

public class AppShowOffTest {

@Test
public void doMagic() {
Logger loggerMock = mock(Logger.class);
Loggable loggableMock = mock(Loggable.class); // <- not needed, but I also tried this way

// mocks done

AppShowOff app = new AppShowOff();
AppShowOff appSpy = Mockito.spy(new AppShowOff());

when(loggableMock.logger()).thenReturn(loggerMock);
when(appSpy.logger()).thenReturn(loggerMock);

app.doMagic();
verify(loggerMock, times(1)).debug(any());
}
}


as you can see I have tried to mock the default method in two ways:



when(loggableMock.logger()).thenReturn(loggerMock);
when(appSpy.logger()).thenReturn(loggerMock);


but it does not work. The result is:




Wanted but not invoked: logger.debug();
-> at so.AppShowOffTest.doMagic(AppShowOffTest.java:29) Actually, there were zero interactions with this mock.








java unit-testing mockito






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 23 '18 at 12:45









Panicking DeveloperPanicking Developer

82




82








  • 1





    You're mocking on appSpy but calling doMagic on app...

    – daniu
    Nov 23 '18 at 12:48














  • 1





    You're mocking on appSpy but calling doMagic on app...

    – daniu
    Nov 23 '18 at 12:48








1




1





You're mocking on appSpy but calling doMagic on app...

– daniu
Nov 23 '18 at 12:48





You're mocking on appSpy but calling doMagic on app...

– daniu
Nov 23 '18 at 12:48












1 Answer
1






active

oldest

votes


















0














Here:



AppShowOff app = new AppShowOff();
AppShowOff appSpy = Mockito.spy(new AppShowOff());


That first app ... is never used, besides to call your method under test doMagic().



The simple answer: drop app completely, and invoke appSpy.doMagic().






share|improve this answer























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53446979%2fhow-to-mock-an-interface-default-method-java8-mockito2%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    Here:



    AppShowOff app = new AppShowOff();
    AppShowOff appSpy = Mockito.spy(new AppShowOff());


    That first app ... is never used, besides to call your method under test doMagic().



    The simple answer: drop app completely, and invoke appSpy.doMagic().






    share|improve this answer




























      0














      Here:



      AppShowOff app = new AppShowOff();
      AppShowOff appSpy = Mockito.spy(new AppShowOff());


      That first app ... is never used, besides to call your method under test doMagic().



      The simple answer: drop app completely, and invoke appSpy.doMagic().






      share|improve this answer


























        0












        0








        0







        Here:



        AppShowOff app = new AppShowOff();
        AppShowOff appSpy = Mockito.spy(new AppShowOff());


        That first app ... is never used, besides to call your method under test doMagic().



        The simple answer: drop app completely, and invoke appSpy.doMagic().






        share|improve this answer













        Here:



        AppShowOff app = new AppShowOff();
        AppShowOff appSpy = Mockito.spy(new AppShowOff());


        That first app ... is never used, besides to call your method under test doMagic().



        The simple answer: drop app completely, and invoke appSpy.doMagic().







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 23 '18 at 13:15









        GhostCatGhostCat

        90.4k1688146




        90.4k1688146






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53446979%2fhow-to-mock-an-interface-default-method-java8-mockito2%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            404 Error Contact Form 7 ajax form submitting

            How to know if a Active Directory user can login interactively

            TypeError: fit_transform() missing 1 required positional argument: 'X'