How to know if today is second or fourth Saturday












0












$begingroup$


This is working. Is it ok?



import calendar
from datetime import datetime


def second_fourth_saturday(year):
holidays = {}
for month in range(1, 13):
holidays[month] =
cal = calendar.monthcalendar(year, month)
if cal[0][calendar.SATURDAY]:
holidays[month] = (
cal[1][calendar.SATURDAY],
cal[3][calendar.SATURDAY]
)
else:
holidays[month] = (
cal[2][calendar.SATURDAY],
cal[4][calendar.SATURDAY]
)
return holidays


if __name__ == "__main__":
today = datetime.today().day
tomonth = datetime.today().month
if today in second_fourth_saturday(2019)[tomonth]:
print("Enjoy")
else:
print("Start Working")









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$endgroup$

















    0












    $begingroup$


    This is working. Is it ok?



    import calendar
    from datetime import datetime


    def second_fourth_saturday(year):
    holidays = {}
    for month in range(1, 13):
    holidays[month] =
    cal = calendar.monthcalendar(year, month)
    if cal[0][calendar.SATURDAY]:
    holidays[month] = (
    cal[1][calendar.SATURDAY],
    cal[3][calendar.SATURDAY]
    )
    else:
    holidays[month] = (
    cal[2][calendar.SATURDAY],
    cal[4][calendar.SATURDAY]
    )
    return holidays


    if __name__ == "__main__":
    today = datetime.today().day
    tomonth = datetime.today().month
    if today in second_fourth_saturday(2019)[tomonth]:
    print("Enjoy")
    else:
    print("Start Working")









    share|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      This is working. Is it ok?



      import calendar
      from datetime import datetime


      def second_fourth_saturday(year):
      holidays = {}
      for month in range(1, 13):
      holidays[month] =
      cal = calendar.monthcalendar(year, month)
      if cal[0][calendar.SATURDAY]:
      holidays[month] = (
      cal[1][calendar.SATURDAY],
      cal[3][calendar.SATURDAY]
      )
      else:
      holidays[month] = (
      cal[2][calendar.SATURDAY],
      cal[4][calendar.SATURDAY]
      )
      return holidays


      if __name__ == "__main__":
      today = datetime.today().day
      tomonth = datetime.today().month
      if today in second_fourth_saturday(2019)[tomonth]:
      print("Enjoy")
      else:
      print("Start Working")









      share|improve this question











      $endgroup$




      This is working. Is it ok?



      import calendar
      from datetime import datetime


      def second_fourth_saturday(year):
      holidays = {}
      for month in range(1, 13):
      holidays[month] =
      cal = calendar.monthcalendar(year, month)
      if cal[0][calendar.SATURDAY]:
      holidays[month] = (
      cal[1][calendar.SATURDAY],
      cal[3][calendar.SATURDAY]
      )
      else:
      holidays[month] = (
      cal[2][calendar.SATURDAY],
      cal[4][calendar.SATURDAY]
      )
      return holidays


      if __name__ == "__main__":
      today = datetime.today().day
      tomonth = datetime.today().month
      if today in second_fourth_saturday(2019)[tomonth]:
      print("Enjoy")
      else:
      print("Start Working")






      python python-3.x






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 1 min ago







      Rahul Patel

















      asked 29 mins ago









      Rahul PatelRahul Patel

      220413




      220413






















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