Tukukkk

I'm using python 3.6. I am trying to read a lot of (.txt) files in multiple directories. Some files have a comma in the file name, e.g. 'Proposal for Anne, Barry and Carol.txt'.

The following code:

for filepath in glob.iglob(params.input_dir + r'****.*', recursive=True):

    # [not shown here: code that filters on .txt filetype]



    with open(filepath) as f:

        for line in f:

            for word in re.findall(r'w+', line):

                # do stuff

Gives me an error on reading that file:

Traceback (most recent call last):

  File "dir_scraper.py", line 50, in <module>

    results_new = scraper.scrape_file(filepath)

  File "C:Projectsscraper.py", line 33, in scrape_file

    return func(filepath)

  File "C:Projectsscraper.py", line 15, in txt

   with open(filepath) as f:

FileNotFoundError: [Errno 2] No such file or directory: 'Z:\groups\Proposal for Anne, Barry and Carol.txt'

I do not want to edit the names of the files.

How can I properly read the files with comma's in the filenames?

Edit:

• I'm sure the path exists.




• Other files from the same directory are parsed without issues.




• Trying to open the file directly from the commandline also gives: The system cannot find the path specified.




• Also, I seem to be unable to rename the file, if I try to change the name through Windows File Explorer to remove the comma (or change something else), it is reset to the original filename.




• Could it have something to do with file permissions?



• Or maybe is the filename too long? The full path from Z:[..] to [..].txt is 270 characters long.

This works fine on Python 3, Windows 10

import glob, re

for filepath in glob.iglob('C:/Users/test-ABC/Desktop/test/' + r'****.*', recursive=True):

    with open(filepath) as f:

        print(f)

        for line in f:

            print(line)

            for word in re.findall(r'w+', line):

                pass



<_io.TextIOWrapper

name='C:/Users/test-ABC/Desktop/test\loooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooong

name\another

looooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooong

name\test, file, name.txt' mode='r' encoding='cp1251'>



line1 

line2

line3

May be the problem in the long path. Try to check questions like this:
Long paths in Python on Windows

First, you only work on files, not directories, and second, you can use os.path.join to convert on Windows:

>>>os.path.join("d:ss")

'd:\ss'

Try this:

    from pathlib import Path

    import os

    import re

    pathName='./'# r'd:/xx' on windows

    fnLst=list(filter(lambda x:not x.is_dir(),Path(pathName).glob('**/*.txt')))

    print(fnLst)

    for fn in fnLst:

        with open(fn) as f:

            print()

            print(fn)

            for line in f:

                for word in re.findall(r'w+', line):

                    print(word,end="|")

Output:

[PosixPath('2.txt'), PosixPath('1.txt')]





2.txt

This|tutorial|introduces|the|reader|informally|to|the|basic|concepts|and|features|of|the|Python|language|and|system|It|helps|to|have|a|Python|interpreter|handy|for|hands|on|experience|but|all|examples|are|self|contained|so|the|tutorial|can|be|read|off|line|as|well|

1.txt

Python|is|an|easy|to|learn|powerful|programming|language|It|has|efficient|high|level|data|structures|and|a|simple|but|effective|approach|to|object|oriented|programming|Python|s|elegant|syntax|and|dynamic|typing|together|with|its|interpreted|nature|make|it|an|ideal|language|for|scripting|and|rapid|application|development|in|many|areas|on|most|platforms|