Convert to Suzhou numerals
up vote
4
down vote
favorite
Suzhou numerals (蘇州碼子; also 花碼) are Chinese decimal numerals:
0 〇
1 〡 一
2 〢 二
3 〣 三
4 〤
5 〥
6 〦
7 〧
8 〨
9 〩
They pretty much work like Arabic numerals, except that when there are consecutive digits belonging to the set {1, 2, 3}, the digits alternate between vertical stroke notation {〡,〢,〣} and horizontal stroke notation {一,二,三} to avoid ambiguity. The first digit of such a consecutive group is always written with vertical stroke notation.
The task is to convert a positive integer into Suzhou numerals.
Test cases
1 〡
11 〡一
25 〢〥
50 〥〇
99 〩〩
111 〡一〡
511 〥〡一
2018 〢〇〡〨
123321 〡二〣三〢一
1234321 〡二〣〤〣二〡
9876543210 〩〨〧〦〥〤〣二〡〇
Shortest code in bytes wins.
code-golf number
asked 3 hours ago
lastresort
795311
add a comment |
up vote
4
down vote
favorite
Suzhou numerals (蘇州碼子; also 花碼) are Chinese decimal numerals:
0 〇
1 〡 一
2 〢 二
3 〣 三
4 〤
5 〥
6 〦
7 〧
8 〨
9 〩
They pretty much work like Arabic numerals, except that when there are consecutive digits belonging to the set {1, 2, 3}, the digits alternate between vertical stroke notation {〡,〢,〣} and horizontal stroke notation {一,二,三} to avoid ambiguity. The first digit of such a consecutive group is always written with vertical stroke notation.
The task is to convert a positive integer into Suzhou numerals.
Test cases
1 〡
11 〡一
25 〢〥
50 〥〇
99 〩〩
111 〡一〡
511 〥〡一
2018 〢〇〡〨
123321 〡二〣三〢一
1234321 〡二〣〤〣二〡
9876543210 〩〨〧〦〥〤〣二〡〇
Shortest code in bytes wins.
code-golf number
asked 3 hours ago
lastresort
795311
add a comment |
up vote
4
down vote
favorite
up vote
4
down vote
favorite
Suzhou numerals (蘇州碼子; also 花碼) are Chinese decimal numerals:
0 〇
1 〡 一
2 〢 二
3 〣 三
4 〤
5 〥
6 〦
7 〧
8 〨
9 〩
They pretty much work like Arabic numerals, except that when there are consecutive digits belonging to the set {1, 2, 3}, the digits alternate between vertical stroke notation {〡,〢,〣} and horizontal stroke notation {一,二,三} to avoid ambiguity. The first digit of such a consecutive group is always written with vertical stroke notation.
The task is to convert a positive integer into Suzhou numerals.
Test cases
1 〡
11 〡一
25 〢〥
50 〥〇
99 〩〩
111 〡一〡
511 〥〡一
2018 〢〇〡〨
123321 〡二〣三〢一
1234321 〡二〣〤〣二〡
9876543210 〩〨〧〦〥〤〣二〡〇
Shortest code in bytes wins.
code-golf number
asked 3 hours ago
lastresort
795311
Suzhou numerals (蘇州碼子; also 花碼) are Chinese decimal numerals:
0 〇
1 〡 一
2 〢 二
3 〣 三
4 〤
5 〥
6 〦
7 〧
8 〨
9 〩
They pretty much work like Arabic numerals, except that when there are consecutive digits belonging to the set {1, 2, 3}, the digits alternate between vertical stroke notation {〡,〢,〣} and horizontal stroke notation {一,二,三} to avoid ambiguity. The first digit of such a consecutive group is always written with vertical stroke notation.
The task is to convert a positive integer into Suzhou numerals.
Test cases
1 〡
11 〡一
25 〢〥
50 〥〇
99 〩〩
111 〡一〡
511 〥〡一
2018 〢〇〡〨
123321 〡二〣三〢一
1234321 〡二〣〤〣二〡
9876543210 〩〨〧〦〥〤〣二〡〇
Shortest code in bytes wins.
code-golf number
code-golf number
asked 3 hours ago
lastresort
795311
asked 3 hours ago
lastresort
795311
asked 3 hours ago
lastresort
795311
asked 3 hours ago
lastresort
795311
asked 3 hours ago
lastresort
795311
795311
add a comment |
add a comment |
5 Answers
5
active
oldest
votes
up vote
3
down vote
Retina, 46 bytes
/[1-3]{2}|./_T`d`〇〡-〩`^.
T`123`一二三
Try it online! Link includes test cases. Explanation:
/[1-3]{2}|./
Match either two digits 1-3 or any other digit.
_T`d`〇〡-〩`^.
Replace the first character of each match with its Suzhou.
T`123`一二三
Replace any remaining digits with horizontal Suzhou.
51 bytes in Retina 0.8.2:
M!`[1-3]{2}|.
mT`d`〇〡-〩`^.
T`¶123`_一二三
Try it online! Link includes test cases. Explanation:
M!`[1-3]{2}|.
Split the input into individual digits or pairs of digits if they are both 1-3.
mT`d`〇〡-〩`^.
Replace the first character of each line with its Suzhou.
T`¶123`_一二三
Join the lines back together and replace any remaining digits with horizontal Suzhou.
answered 2 hours ago
Neil
78.8k744175
add a comment |
up vote
2
down vote
Perl 5 -p -Mutf8, 53 bytes
s/[123]K[123]/chr$&+57/ge;y/0-</〇〡-〩一二三/
Try it online!
answered 2 hours ago
nwellnhof
6,4331125
add a comment |
up vote
2
down vote
Perl 6 -p, 85 61 bytes
-13 bytes thanks to Jo King
s:g[(1|2|3)<((1|2|3)]=chr $/+57;tr/0..</〇〡..〩一二三/
Try it online!
answered 2 hours ago
nwellnhof
6,4331125
add a comment |
up vote
2
down vote
JavaScript (ES6), 95 89 bytes
Saved 6 bytes thanks to @ShieruAsakoto
Takes input as a string.
s=>s.replace(i=/./g,c=>'三二一〇〡〢〣〤〥〦〧〨〩'[i=c<4&i>3&i<7?3-c:+c+3])
Try it online!
answered 2 hours ago
Arnauld
71.3k688298
89 bytes
– Shieru Asakoto
1 hour ago
@ShieruAsakoto That's much better! Thanks a lot!
– Arnauld
47 mins ago
add a comment |
up vote
0
down vote
Clean, 181 165 bytes
All octal escapes can be replaced by the equivalent single-byte characters (and are counted as one byte each), but used for readability and because otherwise it breaks TIO and SE with invalid UTF-8.
import StdEnv
u=mapc={'343','200',c}
?s=((!!)["〇":s++u['244245246247250']])o digitToInt
$=
$[h:t]=[?(u['241242243'])h:if(h-'1'<'03')f$t]
f=
f[h:t]=[?["一","二","三"]h: $t]
Try it online!
An encoding-unaware compiler is both a blessing and a curse.
answered 36 mins ago
Οurous
6,18311032
add a comment |
Your Answer
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
Retina, 46 bytes
/[1-3]{2}|./_T`d`〇〡-〩`^.
T`123`一二三
Try it online! Link includes test cases. Explanation:
/[1-3]{2}|./
Match either two digits 1-3 or any other digit.
_T`d`〇〡-〩`^.
Replace the first character of each match with its Suzhou.
T`123`一二三
Replace any remaining digits with horizontal Suzhou.
51 bytes in Retina 0.8.2:
M!`[1-3]{2}|.
mT`d`〇〡-〩`^.
T`¶123`_一二三
Try it online! Link includes test cases. Explanation:
M!`[1-3]{2}|.
Split the input into individual digits or pairs of digits if they are both 1-3.
mT`d`〇〡-〩`^.
Replace the first character of each line with its Suzhou.
T`¶123`_一二三
Join the lines back together and replace any remaining digits with horizontal Suzhou.
answered 2 hours ago
Neil
78.8k744175
add a comment |
up vote
3
down vote
Retina, 46 bytes
/[1-3]{2}|./_T`d`〇〡-〩`^.
T`123`一二三
Try it online! Link includes test cases. Explanation:
/[1-3]{2}|./
Match either two digits 1-3 or any other digit.
_T`d`〇〡-〩`^.
Replace the first character of each match with its Suzhou.
T`123`一二三
Replace any remaining digits with horizontal Suzhou.
51 bytes in Retina 0.8.2:
M!`[1-3]{2}|.
mT`d`〇〡-〩`^.
T`¶123`_一二三
Try it online! Link includes test cases. Explanation:
M!`[1-3]{2}|.
Split the input into individual digits or pairs of digits if they are both 1-3.
mT`d`〇〡-〩`^.
Replace the first character of each line with its Suzhou.
T`¶123`_一二三
Join the lines back together and replace any remaining digits with horizontal Suzhou.
answered 2 hours ago
Neil
78.8k744175
add a comment |
up vote
3
down vote
up vote
3
down vote
Retina, 46 bytes
/[1-3]{2}|./_T`d`〇〡-〩`^.
T`123`一二三
Try it online! Link includes test cases. Explanation:
/[1-3]{2}|./
Match either two digits 1-3 or any other digit.
_T`d`〇〡-〩`^.
Replace the first character of each match with its Suzhou.
T`123`一二三
Replace any remaining digits with horizontal Suzhou.
51 bytes in Retina 0.8.2:
M!`[1-3]{2}|.
mT`d`〇〡-〩`^.
T`¶123`_一二三
Try it online! Link includes test cases. Explanation:
M!`[1-3]{2}|.
Split the input into individual digits or pairs of digits if they are both 1-3.
mT`d`〇〡-〩`^.
Replace the first character of each line with its Suzhou.
T`¶123`_一二三
Join the lines back together and replace any remaining digits with horizontal Suzhou.
answered 2 hours ago
Neil
78.8k744175
Retina, 46 bytes
/[1-3]{2}|./_T`d`〇〡-〩`^.
T`123`一二三
Try it online! Link includes test cases. Explanation:
/[1-3]{2}|./
Match either two digits 1-3 or any other digit.
_T`d`〇〡-〩`^.
Replace the first character of each match with its Suzhou.
T`123`一二三
Replace any remaining digits with horizontal Suzhou.
51 bytes in Retina 0.8.2:
M!`[1-3]{2}|.
mT`d`〇〡-〩`^.
T`¶123`_一二三
Try it online! Link includes test cases. Explanation:
M!`[1-3]{2}|.
Split the input into individual digits or pairs of digits if they are both 1-3.
mT`d`〇〡-〩`^.
Replace the first character of each line with its Suzhou.
T`¶123`_一二三
Join the lines back together and replace any remaining digits with horizontal Suzhou.
answered 2 hours ago
Neil
78.8k744175
answered 2 hours ago
Neil
78.8k744175
answered 2 hours ago
Neil
78.8k744175
answered 2 hours ago
Neil
78.8k744175
78.8k744175
add a comment |
add a comment |
up vote
2
down vote
Perl 5 -p -Mutf8, 53 bytes
s/[123]K[123]/chr$&+57/ge;y/0-</〇〡-〩一二三/
Try it online!
answered 2 hours ago
nwellnhof
6,4331125
add a comment |
up vote
2
down vote
Perl 5 -p -Mutf8, 53 bytes
s/[123]K[123]/chr$&+57/ge;y/0-</〇〡-〩一二三/
Try it online!
answered 2 hours ago
nwellnhof
6,4331125
add a comment |
up vote
2
down vote
up vote
2
down vote
Perl 5 -p -Mutf8, 53 bytes
s/[123]K[123]/chr$&+57/ge;y/0-</〇〡-〩一二三/
Try it online!
answered 2 hours ago
nwellnhof
6,4331125
Perl 5 -p -Mutf8, 53 bytes
s/[123]K[123]/chr$&+57/ge;y/0-</〇〡-〩一二三/
Try it online!
answered 2 hours ago
nwellnhof
6,4331125
answered 2 hours ago
nwellnhof
6,4331125
answered 2 hours ago
nwellnhof
6,4331125
answered 2 hours ago
nwellnhof
6,4331125
6,4331125
add a comment |
add a comment |
up vote
2
down vote
Perl 6 -p, 85 61 bytes
-13 bytes thanks to Jo King
s:g[(1|2|3)<((1|2|3)]=chr $/+57;tr/0..</〇〡..〩一二三/
Try it online!
answered 2 hours ago
nwellnhof
6,4331125
add a comment |
up vote
2
down vote
Perl 6 -p, 85 61 bytes
-13 bytes thanks to Jo King
s:g[(1|2|3)<((1|2|3)]=chr $/+57;tr/0..</〇〡..〩一二三/
Try it online!
answered 2 hours ago
nwellnhof
6,4331125
add a comment |
up vote
2
down vote
up vote
2
down vote
Perl 6 -p, 85 61 bytes
-13 bytes thanks to Jo King
s:g[(1|2|3)<((1|2|3)]=chr $/+57;tr/0..</〇〡..〩一二三/
Try it online!
answered 2 hours ago
nwellnhof
6,4331125
Perl 6 -p, 85 61 bytes
-13 bytes thanks to Jo King
s:g[(1|2|3)<((1|2|3)]=chr $/+57;tr/0..</〇〡..〩一二三/
Try it online!
answered 2 hours ago
nwellnhof
6,4331125
edited 2 hours ago
answered 2 hours ago
nwellnhof
6,4331125
answered 2 hours ago
nwellnhof
6,4331125
answered 2 hours ago
nwellnhof
6,4331125
6,4331125
add a comment |
add a comment |
up vote
2
down vote
JavaScript (ES6), 95 89 bytes
Saved 6 bytes thanks to @ShieruAsakoto
Takes input as a string.
s=>s.replace(i=/./g,c=>'三二一〇〡〢〣〤〥〦〧〨〩'[i=c<4&i>3&i<7?3-c:+c+3])
Try it online!
answered 2 hours ago
Arnauld
71.3k688298
89 bytes
– Shieru Asakoto
1 hour ago
@ShieruAsakoto That's much better! Thanks a lot!
– Arnauld
47 mins ago
add a comment |
up vote
2
down vote
JavaScript (ES6), 95 89 bytes
Saved 6 bytes thanks to @ShieruAsakoto
Takes input as a string.
s=>s.replace(i=/./g,c=>'三二一〇〡〢〣〤〥〦〧〨〩'[i=c<4&i>3&i<7?3-c:+c+3])
Try it online!
answered 2 hours ago
Arnauld
71.3k688298
89 bytes
– Shieru Asakoto
1 hour ago
@ShieruAsakoto That's much better! Thanks a lot!
– Arnauld
47 mins ago
add a comment |
up vote
2
down vote
up vote
2
down vote
JavaScript (ES6), 95 89 bytes
Saved 6 bytes thanks to @ShieruAsakoto
Takes input as a string.
s=>s.replace(i=/./g,c=>'三二一〇〡〢〣〤〥〦〧〨〩'[i=c<4&i>3&i<7?3-c:+c+3])
Try it online!
answered 2 hours ago
Arnauld
71.3k688298
JavaScript (ES6), 95 89 bytes
Saved 6 bytes thanks to @ShieruAsakoto
Takes input as a string.
s=>s.replace(i=/./g,c=>'三二一〇〡〢〣〤〥〦〧〨〩'[i=c<4&i>3&i<7?3-c:+c+3])
Try it online!
answered 2 hours ago
Arnauld
71.3k688298
edited 47 mins ago
answered 2 hours ago
Arnauld
71.3k688298
answered 2 hours ago
Arnauld
71.3k688298
answered 2 hours ago
Arnauld
71.3k688298
71.3k688298
89 bytes
– Shieru Asakoto
1 hour ago
@ShieruAsakoto That's much better! Thanks a lot!
– Arnauld
47 mins ago
add a comment |
89 bytes
– Shieru Asakoto
1 hour ago
@ShieruAsakoto That's much better! Thanks a lot!
– Arnauld
47 mins ago
89 bytes
– Shieru Asakoto
1 hour ago
89 bytes
– Shieru Asakoto
1 hour ago
@ShieruAsakoto That's much better! Thanks a lot!
– Arnauld
47 mins ago
@ShieruAsakoto That's much better! Thanks a lot!
– Arnauld
47 mins ago
add a comment |
up vote
0
down vote
Clean, 181 165 bytes
All octal escapes can be replaced by the equivalent single-byte characters (and are counted as one byte each), but used for readability and because otherwise it breaks TIO and SE with invalid UTF-8.
import StdEnv
u=mapc={'343','200',c}
?s=((!!)["〇":s++u['244245246247250']])o digitToInt
$=
$[h:t]=[?(u['241242243'])h:if(h-'1'<'03')f$t]
f=
f[h:t]=[?["一","二","三"]h: $t]
Try it online!
An encoding-unaware compiler is both a blessing and a curse.
answered 36 mins ago
Οurous
6,18311032
add a comment |
up vote
0
down vote
Clean, 181 165 bytes
All octal escapes can be replaced by the equivalent single-byte characters (and are counted as one byte each), but used for readability and because otherwise it breaks TIO and SE with invalid UTF-8.
import StdEnv
u=mapc={'343','200',c}
?s=((!!)["〇":s++u['244245246247250']])o digitToInt
$=
$[h:t]=[?(u['241242243'])h:if(h-'1'<'03')f$t]
f=
f[h:t]=[?["一","二","三"]h: $t]
Try it online!
An encoding-unaware compiler is both a blessing and a curse.
answered 36 mins ago
Οurous
6,18311032
add a comment |
up vote
0
down vote
up vote
0
down vote
Clean, 181 165 bytes
All octal escapes can be replaced by the equivalent single-byte characters (and are counted as one byte each), but used for readability and because otherwise it breaks TIO and SE with invalid UTF-8.
import StdEnv
u=mapc={'343','200',c}
?s=((!!)["〇":s++u['244245246247250']])o digitToInt
$=
$[h:t]=[?(u['241242243'])h:if(h-'1'<'03')f$t]
f=
f[h:t]=[?["一","二","三"]h: $t]
Try it online!
An encoding-unaware compiler is both a blessing and a curse.
answered 36 mins ago
Οurous
6,18311032
Clean, 181 165 bytes
All octal escapes can be replaced by the equivalent single-byte characters (and are counted as one byte each), but used for readability and because otherwise it breaks TIO and SE with invalid UTF-8.
import StdEnv
u=mapc={'343','200',c}
?s=((!!)["〇":s++u['244245246247250']])o digitToInt
$=
$[h:t]=[?(u['241242243'])h:if(h-'1'<'03')f$t]
f=
f[h:t]=[?["一","二","三"]h: $t]
Try it online!
An encoding-unaware compiler is both a blessing and a curse.
answered 36 mins ago
Οurous
6,18311032
edited 22 mins ago
answered 36 mins ago
Οurous
6,18311032
answered 36 mins ago
Οurous
6,18311032
answered 36 mins ago
Οurous
6,18311032
6,18311032
add a comment |
add a comment |
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