How to set the last element of an array as a certain number?
up vote
2
down vote
favorite
Say I have an array that sets values for 5 elements. How do I make the last one to print out as 100?
int n[5];
for(i=0; i<5; i++){
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
c
asked Nov 19 at 21:10
Henry Gibbs
224
add a comment |
up vote
2
down vote
favorite
Say I have an array that sets values for 5 elements. How do I make the last one to print out as 100?
int n[5];
for(i=0; i<5; i++){
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
c
asked Nov 19 at 21:10
Henry Gibbs
224
3
Set your loop condition toi < 4and manually setn[4] = 100;outside of your loop
– Govind Parmar
Nov 19 at 21:11
@GovindParmar under int n[5] I'd write n[4]=100;
– Henry Gibbs
Nov 19 at 21:15
@GovindParmar Anyway you can write that as an answer so I can give your props?
– Henry Gibbs
Nov 19 at 21:20
@danglingpointer Wouldn't that be out of bounds?
– Osiris
Nov 19 at 21:25
@danglingpointer looks like a good way to get yourself shot in the foot.
– SergeyA
Nov 19 at 21:31
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
Say I have an array that sets values for 5 elements. How do I make the last one to print out as 100?
int n[5];
for(i=0; i<5; i++){
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
c
asked Nov 19 at 21:10
Henry Gibbs
224
Say I have an array that sets values for 5 elements. How do I make the last one to print out as 100?
int n[5];
for(i=0; i<5; i++){
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
c
c
asked Nov 19 at 21:10
Henry Gibbs
224
asked Nov 19 at 21:10
Henry Gibbs
224
asked Nov 19 at 21:10
Henry Gibbs
224
asked Nov 19 at 21:10
Henry Gibbs
224
asked Nov 19 at 21:10
Henry Gibbs
224
224
3
Set your loop condition toi < 4and manually setn[4] = 100;outside of your loop
– Govind Parmar
Nov 19 at 21:11
@GovindParmar under int n[5] I'd write n[4]=100;
– Henry Gibbs
Nov 19 at 21:15
@GovindParmar Anyway you can write that as an answer so I can give your props?
– Henry Gibbs
Nov 19 at 21:20
@danglingpointer Wouldn't that be out of bounds?
– Osiris
Nov 19 at 21:25
@danglingpointer looks like a good way to get yourself shot in the foot.
– SergeyA
Nov 19 at 21:31
add a comment |
3
Set your loop condition toi < 4and manually setn[4] = 100;outside of your loop
– Govind Parmar
Nov 19 at 21:11
@GovindParmar under int n[5] I'd write n[4]=100;
– Henry Gibbs
Nov 19 at 21:15
@GovindParmar Anyway you can write that as an answer so I can give your props?
– Henry Gibbs
Nov 19 at 21:20
@danglingpointer Wouldn't that be out of bounds?
– Osiris
Nov 19 at 21:25
@danglingpointer looks like a good way to get yourself shot in the foot.
– SergeyA
Nov 19 at 21:31
3
3
Set your loop condition to
i < 4 and manually set n[4] = 100; outside of your loop– Govind Parmar
Nov 19 at 21:11
Set your loop condition to
i < 4 and manually set n[4] = 100; outside of your loop– Govind Parmar
Nov 19 at 21:11
@GovindParmar under int n[5] I'd write n[4]=100;
– Henry Gibbs
Nov 19 at 21:15
@GovindParmar under int n[5] I'd write n[4]=100;
– Henry Gibbs
Nov 19 at 21:15
@GovindParmar Anyway you can write that as an answer so I can give your props?
– Henry Gibbs
Nov 19 at 21:20
@GovindParmar Anyway you can write that as an answer so I can give your props?
– Henry Gibbs
Nov 19 at 21:20
@danglingpointer Wouldn't that be out of bounds?
– Osiris
Nov 19 at 21:25
@danglingpointer Wouldn't that be out of bounds?
– Osiris
Nov 19 at 21:25
@danglingpointer looks like a good way to get yourself shot in the foot.
– SergeyA
Nov 19 at 21:31
@danglingpointer looks like a good way to get yourself shot in the foot.
– SergeyA
Nov 19 at 21:31
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
You can rewrite your loop to not scan for the final element in your array, and fill that out with the hard-coded value of 100 in your code:
int n[5];
n[4] = 100;
for(i = 0; i < 4; i++)
{
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
Note that since your for loop no longer asks for a value for n[4] from the user, it doesn't matter whether the line n[4] = 100; comes before or after your loop.
answered Nov 19 at 21:22
Govind Parmar
6,69653053
1
Thank you very much.
– Henry Gibbs
Nov 19 at 21:25
add a comment |
up vote
1
down vote
In general, I would solve this problem like this:
#define ARRAY_SIZE 5
void myFunc()
{
int n[ARRAY_SIZE];
int i;
for (i=0; i<ARRAY_SIZE-1; i++)
{
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
// now, i == ARRAY_SIZE-1
n[i] = 100;
}
This will work for any size array.
answered Nov 19 at 21:27
yano
1,424720
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
You can rewrite your loop to not scan for the final element in your array, and fill that out with the hard-coded value of 100 in your code:
int n[5];
n[4] = 100;
for(i = 0; i < 4; i++)
{
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
Note that since your for loop no longer asks for a value for n[4] from the user, it doesn't matter whether the line n[4] = 100; comes before or after your loop.
answered Nov 19 at 21:22
Govind Parmar
6,69653053
1
Thank you very much.
– Henry Gibbs
Nov 19 at 21:25
add a comment |
up vote
1
down vote
accepted
You can rewrite your loop to not scan for the final element in your array, and fill that out with the hard-coded value of 100 in your code:
int n[5];
n[4] = 100;
for(i = 0; i < 4; i++)
{
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
Note that since your for loop no longer asks for a value for n[4] from the user, it doesn't matter whether the line n[4] = 100; comes before or after your loop.
answered Nov 19 at 21:22
Govind Parmar
6,69653053
1
Thank you very much.
– Henry Gibbs
Nov 19 at 21:25
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
You can rewrite your loop to not scan for the final element in your array, and fill that out with the hard-coded value of 100 in your code:
int n[5];
n[4] = 100;
for(i = 0; i < 4; i++)
{
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
Note that since your for loop no longer asks for a value for n[4] from the user, it doesn't matter whether the line n[4] = 100; comes before or after your loop.
answered Nov 19 at 21:22
Govind Parmar
6,69653053
You can rewrite your loop to not scan for the final element in your array, and fill that out with the hard-coded value of 100 in your code:
int n[5];
n[4] = 100;
for(i = 0; i < 4; i++)
{
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
Note that since your for loop no longer asks for a value for n[4] from the user, it doesn't matter whether the line n[4] = 100; comes before or after your loop.
answered Nov 19 at 21:22
Govind Parmar
6,69653053
answered Nov 19 at 21:22
Govind Parmar
6,69653053
answered Nov 19 at 21:22
Govind Parmar
6,69653053
answered Nov 19 at 21:22
Govind Parmar
6,69653053
6,69653053
1
Thank you very much.
– Henry Gibbs
Nov 19 at 21:25
add a comment |
1
Thank you very much.
– Henry Gibbs
Nov 19 at 21:25
1
1
Thank you very much.
– Henry Gibbs
Nov 19 at 21:25
Thank you very much.
– Henry Gibbs
Nov 19 at 21:25
add a comment |
up vote
1
down vote
In general, I would solve this problem like this:
#define ARRAY_SIZE 5
void myFunc()
{
int n[ARRAY_SIZE];
int i;
for (i=0; i<ARRAY_SIZE-1; i++)
{
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
// now, i == ARRAY_SIZE-1
n[i] = 100;
}
This will work for any size array.
answered Nov 19 at 21:27
yano
1,424720
add a comment |
up vote
1
down vote
In general, I would solve this problem like this:
#define ARRAY_SIZE 5
void myFunc()
{
int n[ARRAY_SIZE];
int i;
for (i=0; i<ARRAY_SIZE-1; i++)
{
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
// now, i == ARRAY_SIZE-1
n[i] = 100;
}
This will work for any size array.
answered Nov 19 at 21:27
yano
1,424720
add a comment |
up vote
1
down vote
up vote
1
down vote
In general, I would solve this problem like this:
#define ARRAY_SIZE 5
void myFunc()
{
int n[ARRAY_SIZE];
int i;
for (i=0; i<ARRAY_SIZE-1; i++)
{
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
// now, i == ARRAY_SIZE-1
n[i] = 100;
}
This will work for any size array.
answered Nov 19 at 21:27
yano
1,424720
In general, I would solve this problem like this:
#define ARRAY_SIZE 5
void myFunc()
{
int n[ARRAY_SIZE];
int i;
for (i=0; i<ARRAY_SIZE-1; i++)
{
printf("Please enter value %d: n",i+1);
scanf(" %d", &n[i]);
}
// now, i == ARRAY_SIZE-1
n[i] = 100;
}
This will work for any size array.
answered Nov 19 at 21:27
yano
1,424720
answered Nov 19 at 21:27
yano
1,424720
answered Nov 19 at 21:27
yano
1,424720
answered Nov 19 at 21:27
yano
1,424720
1,424720
add a comment |
add a comment |
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3
Set your loop condition to
i < 4and manually setn[4] = 100;outside of your loop– Govind Parmar
Nov 19 at 21:11
@GovindParmar under int n[5] I'd write n[4]=100;
– Henry Gibbs
Nov 19 at 21:15
@GovindParmar Anyway you can write that as an answer so I can give your props?
– Henry Gibbs
Nov 19 at 21:20
@danglingpointer Wouldn't that be out of bounds?
– Osiris
Nov 19 at 21:25
@danglingpointer looks like a good way to get yourself shot in the foot.
– SergeyA
Nov 19 at 21:31