How to count all RecyclerView items in UiAutomator for not different items
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I have to swipe to the end of the list and to count the elements, but these elements are not all different. How can I count them?
uiautomator android-uiautomator
asked Nov 19 at 21:09
Ani Daniel
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up vote
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favorite
I have to swipe to the end of the list and to count the elements, but these elements are not all different. How can I count them?
uiautomator android-uiautomator
asked Nov 19 at 21:09
Ani Daniel
11
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have to swipe to the end of the list and to count the elements, but these elements are not all different. How can I count them?
uiautomator android-uiautomator
asked Nov 19 at 21:09
Ani Daniel
11
I have to swipe to the end of the list and to count the elements, but these elements are not all different. How can I count them?
uiautomator android-uiautomator
uiautomator android-uiautomator
asked Nov 19 at 21:09
Ani Daniel
11
asked Nov 19 at 21:09
Ani Daniel
11
asked Nov 19 at 21:09
Ani Daniel
11
asked Nov 19 at 21:09
Ani Daniel
11
asked Nov 19 at 21:09
Ani Daniel
11
11
add a comment |
add a comment |
1 Answer
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up vote
0
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You can add those elements in a list and scroll down after adding them.
You can add all those list elements in HashSet which will ensure that no elements are counted twice.
You can swipe down the recycler view using UiDevice object.
I can give more detail and code about this once I get to know about your scenario in more detail.
answered Nov 28 at 8:27
Sushant Somani
4171218
The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action
– Ani Daniel
Nov 29 at 16:55
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
You can add those elements in a list and scroll down after adding them.
You can add all those list elements in HashSet which will ensure that no elements are counted twice.
You can swipe down the recycler view using UiDevice object.
I can give more detail and code about this once I get to know about your scenario in more detail.
answered Nov 28 at 8:27
Sushant Somani
4171218
The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action
– Ani Daniel
Nov 29 at 16:55
add a comment |
up vote
0
down vote
You can add those elements in a list and scroll down after adding them.
You can add all those list elements in HashSet which will ensure that no elements are counted twice.
You can swipe down the recycler view using UiDevice object.
I can give more detail and code about this once I get to know about your scenario in more detail.
answered Nov 28 at 8:27
Sushant Somani
4171218
The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action
– Ani Daniel
Nov 29 at 16:55
add a comment |
up vote
0
down vote
up vote
0
down vote
You can add those elements in a list and scroll down after adding them.
You can add all those list elements in HashSet which will ensure that no elements are counted twice.
You can swipe down the recycler view using UiDevice object.
I can give more detail and code about this once I get to know about your scenario in more detail.
answered Nov 28 at 8:27
Sushant Somani
4171218
You can add those elements in a list and scroll down after adding them.
You can add all those list elements in HashSet which will ensure that no elements are counted twice.
You can swipe down the recycler view using UiDevice object.
I can give more detail and code about this once I get to know about your scenario in more detail.
answered Nov 28 at 8:27
Sushant Somani
4171218
answered Nov 28 at 8:27
Sushant Somani
4171218
answered Nov 28 at 8:27
Sushant Somani
4171218
answered Nov 28 at 8:27
Sushant Somani
4171218
4171218
The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action
– Ani Daniel
Nov 29 at 16:55
add a comment |
The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action
– Ani Daniel
Nov 29 at 16:55
The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action
– Ani Daniel
Nov 29 at 16:55
The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action
– Ani Daniel
Nov 29 at 16:55
add a comment |
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