Changing get method to get XML to Post - C#
0
I am using GET to authenticate and generate XML but I want to change this to POST method instead.
Please see my code below:
string url = "https://www.example.com/?username=" + username + "&password=" + password;
XmlDocument xmldoc = new XmlDocument();
ServicePointManager.ServerCertificateValidationCallback += new RemoteCertificateValidationCallback(customXertificateValidation);
ServicePointManager.SecurityProtocol = SecurityProtocolType.Tls12;
xmldoc.Load(url);
XmlNode name = xmldoc.SelectSingleNode("/Node/Name");
This above code is working fine. I just need to change this get request for authentication to post.
I will really appreciate your help.
c# post xmlhttprequest
asked Nov 23 '18 at 18:35
orbnexusorbnexus
399425
add a comment |
0
I am using GET to authenticate and generate XML but I want to change this to POST method instead.
Please see my code below:
string url = "https://www.example.com/?username=" + username + "&password=" + password;
XmlDocument xmldoc = new XmlDocument();
ServicePointManager.ServerCertificateValidationCallback += new RemoteCertificateValidationCallback(customXertificateValidation);
ServicePointManager.SecurityProtocol = SecurityProtocolType.Tls12;
xmldoc.Load(url);
XmlNode name = xmldoc.SelectSingleNode("/Node/Name");
This above code is working fine. I just need to change this get request for authentication to post.
I will really appreciate your help.
c# post xmlhttprequest
asked Nov 23 '18 at 18:35
orbnexusorbnexus
399425
1
I am afraid it is not possible in this way. You shoud use HttpWebRequest or HttpClient for this.
– H.G. Sandhagen
Nov 23 '18 at 19:03
@H.G.Sandhagen Thanks for the comment. I am now writing HttpWebRequest and I am getting an error. Can you please check this post i have just written stackoverflow.com/questions/53453465/…
– orbnexus
Nov 23 '18 at 22:33
add a comment |
0
0
0
I am using GET to authenticate and generate XML but I want to change this to POST method instead.
Please see my code below:
string url = "https://www.example.com/?username=" + username + "&password=" + password;
XmlDocument xmldoc = new XmlDocument();
ServicePointManager.ServerCertificateValidationCallback += new RemoteCertificateValidationCallback(customXertificateValidation);
ServicePointManager.SecurityProtocol = SecurityProtocolType.Tls12;
xmldoc.Load(url);
XmlNode name = xmldoc.SelectSingleNode("/Node/Name");
This above code is working fine. I just need to change this get request for authentication to post.
I will really appreciate your help.
c# post xmlhttprequest
asked Nov 23 '18 at 18:35
orbnexusorbnexus
399425
I am using GET to authenticate and generate XML but I want to change this to POST method instead.
Please see my code below:
string url = "https://www.example.com/?username=" + username + "&password=" + password;
XmlDocument xmldoc = new XmlDocument();
ServicePointManager.ServerCertificateValidationCallback += new RemoteCertificateValidationCallback(customXertificateValidation);
ServicePointManager.SecurityProtocol = SecurityProtocolType.Tls12;
xmldoc.Load(url);
XmlNode name = xmldoc.SelectSingleNode("/Node/Name");
This above code is working fine. I just need to change this get request for authentication to post.
I will really appreciate your help.
c# post xmlhttprequest
c# post xmlhttprequest
asked Nov 23 '18 at 18:35
orbnexusorbnexus
399425
asked Nov 23 '18 at 18:35
orbnexusorbnexus
399425
asked Nov 23 '18 at 18:35
orbnexusorbnexus
399425
asked Nov 23 '18 at 18:35
orbnexusorbnexus
399425
asked Nov 23 '18 at 18:35
orbnexusorbnexus
399425
399425
1
I am afraid it is not possible in this way. You shoud use HttpWebRequest or HttpClient for this.
– H.G. Sandhagen
Nov 23 '18 at 19:03
@H.G.Sandhagen Thanks for the comment. I am now writing HttpWebRequest and I am getting an error. Can you please check this post i have just written stackoverflow.com/questions/53453465/…
– orbnexus
Nov 23 '18 at 22:33
add a comment |
1
I am afraid it is not possible in this way. You shoud use HttpWebRequest or HttpClient for this.
– H.G. Sandhagen
Nov 23 '18 at 19:03
@H.G.Sandhagen Thanks for the comment. I am now writing HttpWebRequest and I am getting an error. Can you please check this post i have just written stackoverflow.com/questions/53453465/…
– orbnexus
Nov 23 '18 at 22:33
1
1
I am afraid it is not possible in this way. You shoud use HttpWebRequest or HttpClient for this.
– H.G. Sandhagen
Nov 23 '18 at 19:03
I am afraid it is not possible in this way. You shoud use HttpWebRequest or HttpClient for this.
– H.G. Sandhagen
Nov 23 '18 at 19:03
@H.G.Sandhagen Thanks for the comment. I am now writing HttpWebRequest and I am getting an error. Can you please check this post i have just written stackoverflow.com/questions/53453465/…
– orbnexus
Nov 23 '18 at 22:33
@H.G.Sandhagen Thanks for the comment. I am now writing HttpWebRequest and I am getting an error. Can you please check this post i have just written stackoverflow.com/questions/53453465/…
– orbnexus
Nov 23 '18 at 22:33
add a comment |
0
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1
I am afraid it is not possible in this way. You shoud use HttpWebRequest or HttpClient for this.
– H.G. Sandhagen
Nov 23 '18 at 19:03
@H.G.Sandhagen Thanks for the comment. I am now writing HttpWebRequest and I am getting an error. Can you please check this post i have just written stackoverflow.com/questions/53453465/…
– orbnexus
Nov 23 '18 at 22:33