Getting the Username of an Active Directory user, not the IdentityReference. From the permissions of a folder












0















I am trying to return the username from the Security tab within a folder's properties. The user-friendly name next to the IdentityReference in brackets.





This is the current script I am using returns the IdentityReference of all attached active directory users of a given path. I was just wondering if there was a way to return that Username rather than the IdentityReference?



%SystemRoot%system32WindowsPowerShellv1.0powershell.exe -Command "& {(get-acl <path>).access | ft IdentityReference -auto}"











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  • 1





    isn't the part after the slash the user [or group] name? [frown] it looks like that is the case on my win7 system ...

    – Lee_Dailey
    Nov 23 '18 at 18:43











  • The system and Admin are the same but the third one isn't, censored it because it has my name, but they are different.

    – r1e2x310
    Nov 23 '18 at 22:12











  • so ... what connection is there between the "your name" item and "your user name"? [grin] without any relationship ... it cannot be derived.

    – Lee_Dailey
    Nov 23 '18 at 23:49
















0















I am trying to return the username from the Security tab within a folder's properties. The user-friendly name next to the IdentityReference in brackets.





This is the current script I am using returns the IdentityReference of all attached active directory users of a given path. I was just wondering if there was a way to return that Username rather than the IdentityReference?



%SystemRoot%system32WindowsPowerShellv1.0powershell.exe -Command "& {(get-acl <path>).access | ft IdentityReference -auto}"











share|improve this question




















  • 1





    isn't the part after the slash the user [or group] name? [frown] it looks like that is the case on my win7 system ...

    – Lee_Dailey
    Nov 23 '18 at 18:43











  • The system and Admin are the same but the third one isn't, censored it because it has my name, but they are different.

    – r1e2x310
    Nov 23 '18 at 22:12











  • so ... what connection is there between the "your name" item and "your user name"? [grin] without any relationship ... it cannot be derived.

    – Lee_Dailey
    Nov 23 '18 at 23:49














0












0








0








I am trying to return the username from the Security tab within a folder's properties. The user-friendly name next to the IdentityReference in brackets.





This is the current script I am using returns the IdentityReference of all attached active directory users of a given path. I was just wondering if there was a way to return that Username rather than the IdentityReference?



%SystemRoot%system32WindowsPowerShellv1.0powershell.exe -Command "& {(get-acl <path>).access | ft IdentityReference -auto}"











share|improve this question
















I am trying to return the username from the Security tab within a folder's properties. The user-friendly name next to the IdentityReference in brackets.





This is the current script I am using returns the IdentityReference of all attached active directory users of a given path. I was just wondering if there was a way to return that Username rather than the IdentityReference?



%SystemRoot%system32WindowsPowerShellv1.0powershell.exe -Command "& {(get-acl <path>).access | ft IdentityReference -auto}"








powershell






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share|improve this question













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edited Nov 23 '18 at 19:34









marc_s

576k12911111258




576k12911111258










asked Nov 23 '18 at 18:18









r1e2x310r1e2x310

1




1








  • 1





    isn't the part after the slash the user [or group] name? [frown] it looks like that is the case on my win7 system ...

    – Lee_Dailey
    Nov 23 '18 at 18:43











  • The system and Admin are the same but the third one isn't, censored it because it has my name, but they are different.

    – r1e2x310
    Nov 23 '18 at 22:12











  • so ... what connection is there between the "your name" item and "your user name"? [grin] without any relationship ... it cannot be derived.

    – Lee_Dailey
    Nov 23 '18 at 23:49














  • 1





    isn't the part after the slash the user [or group] name? [frown] it looks like that is the case on my win7 system ...

    – Lee_Dailey
    Nov 23 '18 at 18:43











  • The system and Admin are the same but the third one isn't, censored it because it has my name, but they are different.

    – r1e2x310
    Nov 23 '18 at 22:12











  • so ... what connection is there between the "your name" item and "your user name"? [grin] without any relationship ... it cannot be derived.

    – Lee_Dailey
    Nov 23 '18 at 23:49








1




1





isn't the part after the slash the user [or group] name? [frown] it looks like that is the case on my win7 system ...

– Lee_Dailey
Nov 23 '18 at 18:43





isn't the part after the slash the user [or group] name? [frown] it looks like that is the case on my win7 system ...

– Lee_Dailey
Nov 23 '18 at 18:43













The system and Admin are the same but the third one isn't, censored it because it has my name, but they are different.

– r1e2x310
Nov 23 '18 at 22:12





The system and Admin are the same but the third one isn't, censored it because it has my name, but they are different.

– r1e2x310
Nov 23 '18 at 22:12













so ... what connection is there between the "your name" item and "your user name"? [grin] without any relationship ... it cannot be derived.

– Lee_Dailey
Nov 23 '18 at 23:49





so ... what connection is there between the "your name" item and "your user name"? [grin] without any relationship ... it cannot be derived.

– Lee_Dailey
Nov 23 '18 at 23:49












1 Answer
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Why not just split on the '' and take the second position



((get-acl 'E:New Folder').access).IdentityReference

IdentityReference
-----------------
LabWS01TestAccount
BUILTINAdministrators
...

(((get-acl 'E:New Folder').access).IdentityReference -split '\')[1]

# Results

TestAccount


The above is on Win10 1809.






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    Why not just split on the '' and take the second position



    ((get-acl 'E:New Folder').access).IdentityReference

    IdentityReference
    -----------------
    LabWS01TestAccount
    BUILTINAdministrators
    ...

    (((get-acl 'E:New Folder').access).IdentityReference -split '\')[1]

    # Results

    TestAccount


    The above is on Win10 1809.






    share|improve this answer




























      0














      Why not just split on the '' and take the second position



      ((get-acl 'E:New Folder').access).IdentityReference

      IdentityReference
      -----------------
      LabWS01TestAccount
      BUILTINAdministrators
      ...

      (((get-acl 'E:New Folder').access).IdentityReference -split '\')[1]

      # Results

      TestAccount


      The above is on Win10 1809.






      share|improve this answer


























        0












        0








        0







        Why not just split on the '' and take the second position



        ((get-acl 'E:New Folder').access).IdentityReference

        IdentityReference
        -----------------
        LabWS01TestAccount
        BUILTINAdministrators
        ...

        (((get-acl 'E:New Folder').access).IdentityReference -split '\')[1]

        # Results

        TestAccount


        The above is on Win10 1809.






        share|improve this answer













        Why not just split on the '' and take the second position



        ((get-acl 'E:New Folder').access).IdentityReference

        IdentityReference
        -----------------
        LabWS01TestAccount
        BUILTINAdministrators
        ...

        (((get-acl 'E:New Folder').access).IdentityReference -split '\')[1]

        # Results

        TestAccount


        The above is on Win10 1809.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 23 '18 at 23:47









        postanotepostanote

        3,5222410




        3,5222410
































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