Finding inverse matrix in R
I have a variance covariance matrix S:
> S
[,1] [,2]
[1,] 4 -3
[2,] -3 9
I am trying to find an inverse of it.
The code I have is:
>invS <- (1/((S[1,1]*S[2,2])-(S[1,2]*S[2,1])))*S
[,1] [,2]
[1,] 0.1481481 -0.1111111
[2,] -0.1111111 0.3333333
However, if I use solve(), I get this:
>invSalt <- solve(S)
[,1] [,2]
[1,] 0.3333333 0.1111111
[2,] 0.1111111 0.1481481
Why is invS incorrect? What should I change to correct it?
r covariance variance covariance-matrix
add a comment |
I have a variance covariance matrix S:
> S
[,1] [,2]
[1,] 4 -3
[2,] -3 9
I am trying to find an inverse of it.
The code I have is:
>invS <- (1/((S[1,1]*S[2,2])-(S[1,2]*S[2,1])))*S
[,1] [,2]
[1,] 0.1481481 -0.1111111
[2,] -0.1111111 0.3333333
However, if I use solve(), I get this:
>invSalt <- solve(S)
[,1] [,2]
[1,] 0.3333333 0.1111111
[2,] 0.1111111 0.1481481
Why is invS incorrect? What should I change to correct it?
r covariance variance covariance-matrix
add a comment |
I have a variance covariance matrix S:
> S
[,1] [,2]
[1,] 4 -3
[2,] -3 9
I am trying to find an inverse of it.
The code I have is:
>invS <- (1/((S[1,1]*S[2,2])-(S[1,2]*S[2,1])))*S
[,1] [,2]
[1,] 0.1481481 -0.1111111
[2,] -0.1111111 0.3333333
However, if I use solve(), I get this:
>invSalt <- solve(S)
[,1] [,2]
[1,] 0.3333333 0.1111111
[2,] 0.1111111 0.1481481
Why is invS incorrect? What should I change to correct it?
r covariance variance covariance-matrix
I have a variance covariance matrix S:
> S
[,1] [,2]
[1,] 4 -3
[2,] -3 9
I am trying to find an inverse of it.
The code I have is:
>invS <- (1/((S[1,1]*S[2,2])-(S[1,2]*S[2,1])))*S
[,1] [,2]
[1,] 0.1481481 -0.1111111
[2,] -0.1111111 0.3333333
However, if I use solve(), I get this:
>invSalt <- solve(S)
[,1] [,2]
[1,] 0.3333333 0.1111111
[2,] 0.1111111 0.1481481
Why is invS incorrect? What should I change to correct it?
r covariance variance covariance-matrix
r covariance variance covariance-matrix
asked Nov 23 '18 at 18:08
Feyzi BagirovFeyzi Bagirov
4001723
4001723
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You correctly found the determinant in the denominator, but the rest is wrong.
Off-diagonal elements should be with the opposite sign, while the diagonal elements should be switched. Both of those things are clearly visible when comparing the two matrices.
That's not the most convenient thing to do by hand, so solve
is really better. If you insist on doing it manually, then you could use
matrix(rev(S), 2, 2) / (prod(diag(S)) - S[1, 2] * S[2, 1]) * (2 * diag(1, 2) - 1)
# [,1] [,2]
# [1,] 0.3333333 0.1111111
# [2,] 0.1111111 0.1481481
add a comment |
The correct formula is
(1/((S[1,1]*S[2,2])-(S[1,2]*S[2,1])))* matrix(c(S[2,2], -S[2,1], -S[1,2], S[1,1]),2)
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53451259%2ffinding-inverse-matrix-in-r%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You correctly found the determinant in the denominator, but the rest is wrong.
Off-diagonal elements should be with the opposite sign, while the diagonal elements should be switched. Both of those things are clearly visible when comparing the two matrices.
That's not the most convenient thing to do by hand, so solve
is really better. If you insist on doing it manually, then you could use
matrix(rev(S), 2, 2) / (prod(diag(S)) - S[1, 2] * S[2, 1]) * (2 * diag(1, 2) - 1)
# [,1] [,2]
# [1,] 0.3333333 0.1111111
# [2,] 0.1111111 0.1481481
add a comment |
You correctly found the determinant in the denominator, but the rest is wrong.
Off-diagonal elements should be with the opposite sign, while the diagonal elements should be switched. Both of those things are clearly visible when comparing the two matrices.
That's not the most convenient thing to do by hand, so solve
is really better. If you insist on doing it manually, then you could use
matrix(rev(S), 2, 2) / (prod(diag(S)) - S[1, 2] * S[2, 1]) * (2 * diag(1, 2) - 1)
# [,1] [,2]
# [1,] 0.3333333 0.1111111
# [2,] 0.1111111 0.1481481
add a comment |
You correctly found the determinant in the denominator, but the rest is wrong.
Off-diagonal elements should be with the opposite sign, while the diagonal elements should be switched. Both of those things are clearly visible when comparing the two matrices.
That's not the most convenient thing to do by hand, so solve
is really better. If you insist on doing it manually, then you could use
matrix(rev(S), 2, 2) / (prod(diag(S)) - S[1, 2] * S[2, 1]) * (2 * diag(1, 2) - 1)
# [,1] [,2]
# [1,] 0.3333333 0.1111111
# [2,] 0.1111111 0.1481481
You correctly found the determinant in the denominator, but the rest is wrong.
Off-diagonal elements should be with the opposite sign, while the diagonal elements should be switched. Both of those things are clearly visible when comparing the two matrices.
That's not the most convenient thing to do by hand, so solve
is really better. If you insist on doing it manually, then you could use
matrix(rev(S), 2, 2) / (prod(diag(S)) - S[1, 2] * S[2, 1]) * (2 * diag(1, 2) - 1)
# [,1] [,2]
# [1,] 0.3333333 0.1111111
# [2,] 0.1111111 0.1481481
edited Nov 23 '18 at 18:21
answered Nov 23 '18 at 18:14
Julius VainoraJulius Vainora
36.9k76481
36.9k76481
add a comment |
add a comment |
The correct formula is
(1/((S[1,1]*S[2,2])-(S[1,2]*S[2,1])))* matrix(c(S[2,2], -S[2,1], -S[1,2], S[1,1]),2)
add a comment |
The correct formula is
(1/((S[1,1]*S[2,2])-(S[1,2]*S[2,1])))* matrix(c(S[2,2], -S[2,1], -S[1,2], S[1,1]),2)
add a comment |
The correct formula is
(1/((S[1,1]*S[2,2])-(S[1,2]*S[2,1])))* matrix(c(S[2,2], -S[2,1], -S[1,2], S[1,1]),2)
The correct formula is
(1/((S[1,1]*S[2,2])-(S[1,2]*S[2,1])))* matrix(c(S[2,2], -S[2,1], -S[1,2], S[1,1]),2)
answered Nov 23 '18 at 18:18
dwwdww
15k22656
15k22656
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53451259%2ffinding-inverse-matrix-in-r%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown