X11 programming, some questions












0














I would like to make a simple visualisation using X11. I don't want a fancy guy with buttons and stuff, I simply want to display an ordinary line chart in a window and that's it.



Since I have not that much experience in programming X11, I used this example code:



https://rosettacode.org/wiki/Window_creation/X11#Xlib



It compiles fine and works, but when the window it creates is closed, the error



XIO:  fatal IO error 11 (Resource temporarily unavailable) on X server ":0.0"
after 11 requests (9 known processed) with 0 events remaining.


appears in the terminal. So I wonder what the reason for this could be and how it could be fixed?










share|improve this question






















  • We're a knowledge base, not a help forum -- each question should be exactly one question, posed as a Minimal, Complete, and Verifiable example with everything necessary for someone to reproduce the problem themselves and test proposed answers.
    – Charles Duffy
    Nov 21 '18 at 18:56
















0














I would like to make a simple visualisation using X11. I don't want a fancy guy with buttons and stuff, I simply want to display an ordinary line chart in a window and that's it.



Since I have not that much experience in programming X11, I used this example code:



https://rosettacode.org/wiki/Window_creation/X11#Xlib



It compiles fine and works, but when the window it creates is closed, the error



XIO:  fatal IO error 11 (Resource temporarily unavailable) on X server ":0.0"
after 11 requests (9 known processed) with 0 events remaining.


appears in the terminal. So I wonder what the reason for this could be and how it could be fixed?










share|improve this question






















  • We're a knowledge base, not a help forum -- each question should be exactly one question, posed as a Minimal, Complete, and Verifiable example with everything necessary for someone to reproduce the problem themselves and test proposed answers.
    – Charles Duffy
    Nov 21 '18 at 18:56














0












0








0







I would like to make a simple visualisation using X11. I don't want a fancy guy with buttons and stuff, I simply want to display an ordinary line chart in a window and that's it.



Since I have not that much experience in programming X11, I used this example code:



https://rosettacode.org/wiki/Window_creation/X11#Xlib



It compiles fine and works, but when the window it creates is closed, the error



XIO:  fatal IO error 11 (Resource temporarily unavailable) on X server ":0.0"
after 11 requests (9 known processed) with 0 events remaining.


appears in the terminal. So I wonder what the reason for this could be and how it could be fixed?










share|improve this question













I would like to make a simple visualisation using X11. I don't want a fancy guy with buttons and stuff, I simply want to display an ordinary line chart in a window and that's it.



Since I have not that much experience in programming X11, I used this example code:



https://rosettacode.org/wiki/Window_creation/X11#Xlib



It compiles fine and works, but when the window it creates is closed, the error



XIO:  fatal IO error 11 (Resource temporarily unavailable) on X server ":0.0"
after 11 requests (9 known processed) with 0 events remaining.


appears in the terminal. So I wonder what the reason for this could be and how it could be fixed?







x11






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share|improve this question











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asked Nov 21 '18 at 18:47









T. PluessT. Pluess

1288




1288












  • We're a knowledge base, not a help forum -- each question should be exactly one question, posed as a Minimal, Complete, and Verifiable example with everything necessary for someone to reproduce the problem themselves and test proposed answers.
    – Charles Duffy
    Nov 21 '18 at 18:56


















  • We're a knowledge base, not a help forum -- each question should be exactly one question, posed as a Minimal, Complete, and Verifiable example with everything necessary for someone to reproduce the problem themselves and test proposed answers.
    – Charles Duffy
    Nov 21 '18 at 18:56
















We're a knowledge base, not a help forum -- each question should be exactly one question, posed as a Minimal, Complete, and Verifiable example with everything necessary for someone to reproduce the problem themselves and test proposed answers.
– Charles Duffy
Nov 21 '18 at 18:56




We're a knowledge base, not a help forum -- each question should be exactly one question, posed as a Minimal, Complete, and Verifiable example with everything necessary for someone to reproduce the problem themselves and test proposed answers.
– Charles Duffy
Nov 21 '18 at 18:56












1 Answer
1






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oldest

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Use The Source, Luke.



while (1) {
XNextEvent(d, &e);
if (e.type == Expose) {
XFillRectangle(d, w, DefaultGC(d, s), 20, 20, 10, 10);
XDrawString(d, w, DefaultGC(d, s), 10, 50, msg, strlen(msg));
}
if (e.type == KeyPress)
break;
}

XCloseDisplay(d);


If you exit the loop by pressing a key, you call XCloseDisplay(). If you kill the window "from the outside" (say, with your mouse) that function is never called. The process goes away abruptly, and X warns you about it.



On my system at least, kill(1) doesn't produce the warning, either. I suspect there's some interaction with your window manager, something you'll deal with later in your xlib education. :-)






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    1 Answer
    1






    active

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    1 Answer
    1






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    active

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    0














    Use The Source, Luke.



    while (1) {
    XNextEvent(d, &e);
    if (e.type == Expose) {
    XFillRectangle(d, w, DefaultGC(d, s), 20, 20, 10, 10);
    XDrawString(d, w, DefaultGC(d, s), 10, 50, msg, strlen(msg));
    }
    if (e.type == KeyPress)
    break;
    }

    XCloseDisplay(d);


    If you exit the loop by pressing a key, you call XCloseDisplay(). If you kill the window "from the outside" (say, with your mouse) that function is never called. The process goes away abruptly, and X warns you about it.



    On my system at least, kill(1) doesn't produce the warning, either. I suspect there's some interaction with your window manager, something you'll deal with later in your xlib education. :-)






    share|improve this answer


























      0














      Use The Source, Luke.



      while (1) {
      XNextEvent(d, &e);
      if (e.type == Expose) {
      XFillRectangle(d, w, DefaultGC(d, s), 20, 20, 10, 10);
      XDrawString(d, w, DefaultGC(d, s), 10, 50, msg, strlen(msg));
      }
      if (e.type == KeyPress)
      break;
      }

      XCloseDisplay(d);


      If you exit the loop by pressing a key, you call XCloseDisplay(). If you kill the window "from the outside" (say, with your mouse) that function is never called. The process goes away abruptly, and X warns you about it.



      On my system at least, kill(1) doesn't produce the warning, either. I suspect there's some interaction with your window manager, something you'll deal with later in your xlib education. :-)






      share|improve this answer
























        0












        0








        0






        Use The Source, Luke.



        while (1) {
        XNextEvent(d, &e);
        if (e.type == Expose) {
        XFillRectangle(d, w, DefaultGC(d, s), 20, 20, 10, 10);
        XDrawString(d, w, DefaultGC(d, s), 10, 50, msg, strlen(msg));
        }
        if (e.type == KeyPress)
        break;
        }

        XCloseDisplay(d);


        If you exit the loop by pressing a key, you call XCloseDisplay(). If you kill the window "from the outside" (say, with your mouse) that function is never called. The process goes away abruptly, and X warns you about it.



        On my system at least, kill(1) doesn't produce the warning, either. I suspect there's some interaction with your window manager, something you'll deal with later in your xlib education. :-)






        share|improve this answer












        Use The Source, Luke.



        while (1) {
        XNextEvent(d, &e);
        if (e.type == Expose) {
        XFillRectangle(d, w, DefaultGC(d, s), 20, 20, 10, 10);
        XDrawString(d, w, DefaultGC(d, s), 10, 50, msg, strlen(msg));
        }
        if (e.type == KeyPress)
        break;
        }

        XCloseDisplay(d);


        If you exit the loop by pressing a key, you call XCloseDisplay(). If you kill the window "from the outside" (say, with your mouse) that function is never called. The process goes away abruptly, and X warns you about it.



        On my system at least, kill(1) doesn't produce the warning, either. I suspect there's some interaction with your window manager, something you'll deal with later in your xlib education. :-)







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 21 '18 at 20:19









        James K. LowdenJames K. Lowden

        5,28211025




        5,28211025






























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