Problem with history.pushState when using AJAX
I'm quite new to javascript and history API in particular.
I'm making an AJAX GET request to load next or previous page on a website.
function ajax_get_update(url)
{
$.ajax({
async: true,
type: "GET",
url: url,
cache: true,
success: function(result){
sessionStorage.setItem("result", result);
update_content(result);
}
});
history.pushState(url, url, url)
}
AJAX part and changing page content works perfectly fine. As you can see I'm using history.pushState(url, url, url)
to add next page to history so I could use back button to get back to that page.
url
looks something like this http://127.0.0.1:8000/?page=2
The problem is if I'd go on page3
from page2
and then to page3
again and so on, history then would contain all these transitions, and when I click on the back button I keep altering back and forth between page2
and page3
few times before I get to the page1
eventually. What I want is page3 -> page2 -> page1
and so on.
How would you solve this problem?
javascript url url-rewriting html5-history
|
show 1 more comment
I'm quite new to javascript and history API in particular.
I'm making an AJAX GET request to load next or previous page on a website.
function ajax_get_update(url)
{
$.ajax({
async: true,
type: "GET",
url: url,
cache: true,
success: function(result){
sessionStorage.setItem("result", result);
update_content(result);
}
});
history.pushState(url, url, url)
}
AJAX part and changing page content works perfectly fine. As you can see I'm using history.pushState(url, url, url)
to add next page to history so I could use back button to get back to that page.
url
looks something like this http://127.0.0.1:8000/?page=2
The problem is if I'd go on page3
from page2
and then to page3
again and so on, history then would contain all these transitions, and when I click on the back button I keep altering back and forth between page2
and page3
few times before I get to the page1
eventually. What I want is page3 -> page2 -> page1
and so on.
How would you solve this problem?
javascript url url-rewriting html5-history
1
That is how history works :) You could try to move yourhistory.pushState()
into the success handler and update the history only on certain cases. I recommend also to update your history only if the ajax request was successful otherwise your application may have an invalid sate.
– gearsdigital
Nov 20 at 20:42
@gearsdigital Good call. Any ideas on how to implement this behaviourpage3 -> page2 -> page1
on a back button? Instead ofpage3->page2->page3->page2...
– bloodwithmilk
Nov 20 at 20:54
Do you have any information about the current page? Other than theurl
?
– gearsdigital
Nov 20 at 20:55
@gearsdigital not realy... content is unique though
– bloodwithmilk
Nov 20 at 20:58
But parameter is always?page
?
– gearsdigital
Nov 20 at 20:58
|
show 1 more comment
I'm quite new to javascript and history API in particular.
I'm making an AJAX GET request to load next or previous page on a website.
function ajax_get_update(url)
{
$.ajax({
async: true,
type: "GET",
url: url,
cache: true,
success: function(result){
sessionStorage.setItem("result", result);
update_content(result);
}
});
history.pushState(url, url, url)
}
AJAX part and changing page content works perfectly fine. As you can see I'm using history.pushState(url, url, url)
to add next page to history so I could use back button to get back to that page.
url
looks something like this http://127.0.0.1:8000/?page=2
The problem is if I'd go on page3
from page2
and then to page3
again and so on, history then would contain all these transitions, and when I click on the back button I keep altering back and forth between page2
and page3
few times before I get to the page1
eventually. What I want is page3 -> page2 -> page1
and so on.
How would you solve this problem?
javascript url url-rewriting html5-history
I'm quite new to javascript and history API in particular.
I'm making an AJAX GET request to load next or previous page on a website.
function ajax_get_update(url)
{
$.ajax({
async: true,
type: "GET",
url: url,
cache: true,
success: function(result){
sessionStorage.setItem("result", result);
update_content(result);
}
});
history.pushState(url, url, url)
}
AJAX part and changing page content works perfectly fine. As you can see I'm using history.pushState(url, url, url)
to add next page to history so I could use back button to get back to that page.
url
looks something like this http://127.0.0.1:8000/?page=2
The problem is if I'd go on page3
from page2
and then to page3
again and so on, history then would contain all these transitions, and when I click on the back button I keep altering back and forth between page2
and page3
few times before I get to the page1
eventually. What I want is page3 -> page2 -> page1
and so on.
How would you solve this problem?
javascript url url-rewriting html5-history
javascript url url-rewriting html5-history
edited Nov 20 at 20:59
asked Nov 20 at 20:35
bloodwithmilk
177112
177112
1
That is how history works :) You could try to move yourhistory.pushState()
into the success handler and update the history only on certain cases. I recommend also to update your history only if the ajax request was successful otherwise your application may have an invalid sate.
– gearsdigital
Nov 20 at 20:42
@gearsdigital Good call. Any ideas on how to implement this behaviourpage3 -> page2 -> page1
on a back button? Instead ofpage3->page2->page3->page2...
– bloodwithmilk
Nov 20 at 20:54
Do you have any information about the current page? Other than theurl
?
– gearsdigital
Nov 20 at 20:55
@gearsdigital not realy... content is unique though
– bloodwithmilk
Nov 20 at 20:58
But parameter is always?page
?
– gearsdigital
Nov 20 at 20:58
|
show 1 more comment
1
That is how history works :) You could try to move yourhistory.pushState()
into the success handler and update the history only on certain cases. I recommend also to update your history only if the ajax request was successful otherwise your application may have an invalid sate.
– gearsdigital
Nov 20 at 20:42
@gearsdigital Good call. Any ideas on how to implement this behaviourpage3 -> page2 -> page1
on a back button? Instead ofpage3->page2->page3->page2...
– bloodwithmilk
Nov 20 at 20:54
Do you have any information about the current page? Other than theurl
?
– gearsdigital
Nov 20 at 20:55
@gearsdigital not realy... content is unique though
– bloodwithmilk
Nov 20 at 20:58
But parameter is always?page
?
– gearsdigital
Nov 20 at 20:58
1
1
That is how history works :) You could try to move your
history.pushState()
into the success handler and update the history only on certain cases. I recommend also to update your history only if the ajax request was successful otherwise your application may have an invalid sate.– gearsdigital
Nov 20 at 20:42
That is how history works :) You could try to move your
history.pushState()
into the success handler and update the history only on certain cases. I recommend also to update your history only if the ajax request was successful otherwise your application may have an invalid sate.– gearsdigital
Nov 20 at 20:42
@gearsdigital Good call. Any ideas on how to implement this behaviour
page3 -> page2 -> page1
on a back button? Instead of page3->page2->page3->page2...
– bloodwithmilk
Nov 20 at 20:54
@gearsdigital Good call. Any ideas on how to implement this behaviour
page3 -> page2 -> page1
on a back button? Instead of page3->page2->page3->page2...
– bloodwithmilk
Nov 20 at 20:54
Do you have any information about the current page? Other than the
url
?– gearsdigital
Nov 20 at 20:55
Do you have any information about the current page? Other than the
url
?– gearsdigital
Nov 20 at 20:55
@gearsdigital not realy... content is unique though
– bloodwithmilk
Nov 20 at 20:58
@gearsdigital not realy... content is unique though
– bloodwithmilk
Nov 20 at 20:58
But parameter is always
?page
?– gearsdigital
Nov 20 at 20:58
But parameter is always
?page
?– gearsdigital
Nov 20 at 20:58
|
show 1 more comment
1 Answer
1
active
oldest
votes
This is untested but should fit your needs. The idea here is to update the window.history
only for newly added urls.
On every successful request we're checking if the current url is present in myState
. If not we can assume a new page and update the history and putting the url to our private cache myState
.
This will keep your urls in order and prevent duplicated history entries.
Please be aware that this code is using ES2015. You can search the web for polyfills :)
// it is probably not a good idea to keep your own history
let myState = ;
function ajax_get_update(url) {
$.ajax({
async: true,
type: "GET",
url: url,
cache: true,
success: function(result) {
sessionStorage.setItem("result", result);
update_content(result);
update_history(url);
}
});
}
function update_history(url) {
// window.history is only updated when the current url is not
// saved in our private history
if (!myState.includes(url)) {
history.pushState(url, url, url);
myState.push(url);
}
}
1
developer.mozilla.org/de/docs/Web/JavaScript/Reference/…
– gearsdigital
Nov 20 at 21:37
1
(!state.includes(url))
must be(!myState.includes(url))
, right?
– bloodwithmilk
Nov 20 at 21:37
Sure! My bad :) But you got the idea, right?
– gearsdigital
Nov 20 at 21:38
Works perfectly fine. Thank you so much for your time and patience.
– bloodwithmilk
Nov 20 at 21:41
Nah, no problem! Glad it worked for you!
– gearsdigital
Nov 20 at 21:43
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53401109%2fproblem-with-history-pushstate-when-using-ajax%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This is untested but should fit your needs. The idea here is to update the window.history
only for newly added urls.
On every successful request we're checking if the current url is present in myState
. If not we can assume a new page and update the history and putting the url to our private cache myState
.
This will keep your urls in order and prevent duplicated history entries.
Please be aware that this code is using ES2015. You can search the web for polyfills :)
// it is probably not a good idea to keep your own history
let myState = ;
function ajax_get_update(url) {
$.ajax({
async: true,
type: "GET",
url: url,
cache: true,
success: function(result) {
sessionStorage.setItem("result", result);
update_content(result);
update_history(url);
}
});
}
function update_history(url) {
// window.history is only updated when the current url is not
// saved in our private history
if (!myState.includes(url)) {
history.pushState(url, url, url);
myState.push(url);
}
}
1
developer.mozilla.org/de/docs/Web/JavaScript/Reference/…
– gearsdigital
Nov 20 at 21:37
1
(!state.includes(url))
must be(!myState.includes(url))
, right?
– bloodwithmilk
Nov 20 at 21:37
Sure! My bad :) But you got the idea, right?
– gearsdigital
Nov 20 at 21:38
Works perfectly fine. Thank you so much for your time and patience.
– bloodwithmilk
Nov 20 at 21:41
Nah, no problem! Glad it worked for you!
– gearsdigital
Nov 20 at 21:43
add a comment |
This is untested but should fit your needs. The idea here is to update the window.history
only for newly added urls.
On every successful request we're checking if the current url is present in myState
. If not we can assume a new page and update the history and putting the url to our private cache myState
.
This will keep your urls in order and prevent duplicated history entries.
Please be aware that this code is using ES2015. You can search the web for polyfills :)
// it is probably not a good idea to keep your own history
let myState = ;
function ajax_get_update(url) {
$.ajax({
async: true,
type: "GET",
url: url,
cache: true,
success: function(result) {
sessionStorage.setItem("result", result);
update_content(result);
update_history(url);
}
});
}
function update_history(url) {
// window.history is only updated when the current url is not
// saved in our private history
if (!myState.includes(url)) {
history.pushState(url, url, url);
myState.push(url);
}
}
1
developer.mozilla.org/de/docs/Web/JavaScript/Reference/…
– gearsdigital
Nov 20 at 21:37
1
(!state.includes(url))
must be(!myState.includes(url))
, right?
– bloodwithmilk
Nov 20 at 21:37
Sure! My bad :) But you got the idea, right?
– gearsdigital
Nov 20 at 21:38
Works perfectly fine. Thank you so much for your time and patience.
– bloodwithmilk
Nov 20 at 21:41
Nah, no problem! Glad it worked for you!
– gearsdigital
Nov 20 at 21:43
add a comment |
This is untested but should fit your needs. The idea here is to update the window.history
only for newly added urls.
On every successful request we're checking if the current url is present in myState
. If not we can assume a new page and update the history and putting the url to our private cache myState
.
This will keep your urls in order and prevent duplicated history entries.
Please be aware that this code is using ES2015. You can search the web for polyfills :)
// it is probably not a good idea to keep your own history
let myState = ;
function ajax_get_update(url) {
$.ajax({
async: true,
type: "GET",
url: url,
cache: true,
success: function(result) {
sessionStorage.setItem("result", result);
update_content(result);
update_history(url);
}
});
}
function update_history(url) {
// window.history is only updated when the current url is not
// saved in our private history
if (!myState.includes(url)) {
history.pushState(url, url, url);
myState.push(url);
}
}
This is untested but should fit your needs. The idea here is to update the window.history
only for newly added urls.
On every successful request we're checking if the current url is present in myState
. If not we can assume a new page and update the history and putting the url to our private cache myState
.
This will keep your urls in order and prevent duplicated history entries.
Please be aware that this code is using ES2015. You can search the web for polyfills :)
// it is probably not a good idea to keep your own history
let myState = ;
function ajax_get_update(url) {
$.ajax({
async: true,
type: "GET",
url: url,
cache: true,
success: function(result) {
sessionStorage.setItem("result", result);
update_content(result);
update_history(url);
}
});
}
function update_history(url) {
// window.history is only updated when the current url is not
// saved in our private history
if (!myState.includes(url)) {
history.pushState(url, url, url);
myState.push(url);
}
}
edited Nov 20 at 21:38
answered Nov 20 at 21:33
gearsdigital
9,27362867
9,27362867
1
developer.mozilla.org/de/docs/Web/JavaScript/Reference/…
– gearsdigital
Nov 20 at 21:37
1
(!state.includes(url))
must be(!myState.includes(url))
, right?
– bloodwithmilk
Nov 20 at 21:37
Sure! My bad :) But you got the idea, right?
– gearsdigital
Nov 20 at 21:38
Works perfectly fine. Thank you so much for your time and patience.
– bloodwithmilk
Nov 20 at 21:41
Nah, no problem! Glad it worked for you!
– gearsdigital
Nov 20 at 21:43
add a comment |
1
developer.mozilla.org/de/docs/Web/JavaScript/Reference/…
– gearsdigital
Nov 20 at 21:37
1
(!state.includes(url))
must be(!myState.includes(url))
, right?
– bloodwithmilk
Nov 20 at 21:37
Sure! My bad :) But you got the idea, right?
– gearsdigital
Nov 20 at 21:38
Works perfectly fine. Thank you so much for your time and patience.
– bloodwithmilk
Nov 20 at 21:41
Nah, no problem! Glad it worked for you!
– gearsdigital
Nov 20 at 21:43
1
1
developer.mozilla.org/de/docs/Web/JavaScript/Reference/…
– gearsdigital
Nov 20 at 21:37
developer.mozilla.org/de/docs/Web/JavaScript/Reference/…
– gearsdigital
Nov 20 at 21:37
1
1
(!state.includes(url))
must be (!myState.includes(url))
, right?– bloodwithmilk
Nov 20 at 21:37
(!state.includes(url))
must be (!myState.includes(url))
, right?– bloodwithmilk
Nov 20 at 21:37
Sure! My bad :) But you got the idea, right?
– gearsdigital
Nov 20 at 21:38
Sure! My bad :) But you got the idea, right?
– gearsdigital
Nov 20 at 21:38
Works perfectly fine. Thank you so much for your time and patience.
– bloodwithmilk
Nov 20 at 21:41
Works perfectly fine. Thank you so much for your time and patience.
– bloodwithmilk
Nov 20 at 21:41
Nah, no problem! Glad it worked for you!
– gearsdigital
Nov 20 at 21:43
Nah, no problem! Glad it worked for you!
– gearsdigital
Nov 20 at 21:43
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53401109%2fproblem-with-history-pushstate-when-using-ajax%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
That is how history works :) You could try to move your
history.pushState()
into the success handler and update the history only on certain cases. I recommend also to update your history only if the ajax request was successful otherwise your application may have an invalid sate.– gearsdigital
Nov 20 at 20:42
@gearsdigital Good call. Any ideas on how to implement this behaviour
page3 -> page2 -> page1
on a back button? Instead ofpage3->page2->page3->page2...
– bloodwithmilk
Nov 20 at 20:54
Do you have any information about the current page? Other than the
url
?– gearsdigital
Nov 20 at 20:55
@gearsdigital not realy... content is unique though
– bloodwithmilk
Nov 20 at 20:58
But parameter is always
?page
?– gearsdigital
Nov 20 at 20:58