How can I get images under a blog for a user












0














What I actually want is, for a specific user, I'm trying to show every image under a single blog. What I'm getting is a single blog post images for every blog.



Controller



$user_id = Session::get('id');
$user = Users::find($user_id);
$blogs = Blog::where('user_id', $user_id)->paginate(10);
$blogImage = BlogImage::where('blog_id', $blogs->pluck('id'))->get();


return view('Users.userlayout', compact('user', 'blogCat', 'blogs', 'username', 'blogImage'));




View Page



@foreach($blogs as $blog)
<div class="post">

@foreach($blogImage as $img)
<img src="{{asset('storage/blog_img/'.$img->blog_img)}}" alt="Image"
class="img-responsive">
@endforeach

<p>
<?php $str = $blog->blog_desc; ?>
{{str_limit($str, 250, "...")}}
</p>
<a href="{{URL::to('/blog-details/'.$blog->id)}}" target="_blank" class="btn_1">
Read more
</a>
</div>
<hr>
@endforeach









share|improve this question
























  • Can you the code you in your models?
    – Peter Sowah
    Nov 21 '18 at 19:07










  • In those modes, I just added the tables name, nothing else. Cause I'm not that good to use models function like hasMany, belongsTo.
    – Eyakub
    Nov 21 '18 at 21:32
















0














What I actually want is, for a specific user, I'm trying to show every image under a single blog. What I'm getting is a single blog post images for every blog.



Controller



$user_id = Session::get('id');
$user = Users::find($user_id);
$blogs = Blog::where('user_id', $user_id)->paginate(10);
$blogImage = BlogImage::where('blog_id', $blogs->pluck('id'))->get();


return view('Users.userlayout', compact('user', 'blogCat', 'blogs', 'username', 'blogImage'));




View Page



@foreach($blogs as $blog)
<div class="post">

@foreach($blogImage as $img)
<img src="{{asset('storage/blog_img/'.$img->blog_img)}}" alt="Image"
class="img-responsive">
@endforeach

<p>
<?php $str = $blog->blog_desc; ?>
{{str_limit($str, 250, "...")}}
</p>
<a href="{{URL::to('/blog-details/'.$blog->id)}}" target="_blank" class="btn_1">
Read more
</a>
</div>
<hr>
@endforeach









share|improve this question
























  • Can you the code you in your models?
    – Peter Sowah
    Nov 21 '18 at 19:07










  • In those modes, I just added the tables name, nothing else. Cause I'm not that good to use models function like hasMany, belongsTo.
    – Eyakub
    Nov 21 '18 at 21:32














0












0








0







What I actually want is, for a specific user, I'm trying to show every image under a single blog. What I'm getting is a single blog post images for every blog.



Controller



$user_id = Session::get('id');
$user = Users::find($user_id);
$blogs = Blog::where('user_id', $user_id)->paginate(10);
$blogImage = BlogImage::where('blog_id', $blogs->pluck('id'))->get();


return view('Users.userlayout', compact('user', 'blogCat', 'blogs', 'username', 'blogImage'));




View Page



@foreach($blogs as $blog)
<div class="post">

@foreach($blogImage as $img)
<img src="{{asset('storage/blog_img/'.$img->blog_img)}}" alt="Image"
class="img-responsive">
@endforeach

<p>
<?php $str = $blog->blog_desc; ?>
{{str_limit($str, 250, "...")}}
</p>
<a href="{{URL::to('/blog-details/'.$blog->id)}}" target="_blank" class="btn_1">
Read more
</a>
</div>
<hr>
@endforeach









share|improve this question















What I actually want is, for a specific user, I'm trying to show every image under a single blog. What I'm getting is a single blog post images for every blog.



Controller



$user_id = Session::get('id');
$user = Users::find($user_id);
$blogs = Blog::where('user_id', $user_id)->paginate(10);
$blogImage = BlogImage::where('blog_id', $blogs->pluck('id'))->get();


return view('Users.userlayout', compact('user', 'blogCat', 'blogs', 'username', 'blogImage'));




View Page



@foreach($blogs as $blog)
<div class="post">

@foreach($blogImage as $img)
<img src="{{asset('storage/blog_img/'.$img->blog_img)}}" alt="Image"
class="img-responsive">
@endforeach

<p>
<?php $str = $blog->blog_desc; ?>
{{str_limit($str, 250, "...")}}
</p>
<a href="{{URL::to('/blog-details/'.$blog->id)}}" target="_blank" class="btn_1">
Read more
</a>
</div>
<hr>
@endforeach






laravel image blogs laravel-5.6






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 20:16









Ross Wilson

15.7k22539




15.7k22539










asked Nov 21 '18 at 18:33









EyakubEyakub

53




53












  • Can you the code you in your models?
    – Peter Sowah
    Nov 21 '18 at 19:07










  • In those modes, I just added the tables name, nothing else. Cause I'm not that good to use models function like hasMany, belongsTo.
    – Eyakub
    Nov 21 '18 at 21:32


















  • Can you the code you in your models?
    – Peter Sowah
    Nov 21 '18 at 19:07










  • In those modes, I just added the tables name, nothing else. Cause I'm not that good to use models function like hasMany, belongsTo.
    – Eyakub
    Nov 21 '18 at 21:32
















Can you the code you in your models?
– Peter Sowah
Nov 21 '18 at 19:07




Can you the code you in your models?
– Peter Sowah
Nov 21 '18 at 19:07












In those modes, I just added the tables name, nothing else. Cause I'm not that good to use models function like hasMany, belongsTo.
– Eyakub
Nov 21 '18 at 21:32




In those modes, I just added the tables name, nothing else. Cause I'm not that good to use models function like hasMany, belongsTo.
– Eyakub
Nov 21 '18 at 21:32












1 Answer
1






active

oldest

votes


















1














This is because you're using where instead of whereIn.



If you try and pass an array or a collection to where it will only use the first value.



$blogImage = BlogImage::whereIn('blog_id', $blogs->pluck('id'))->get();


Since this will return all of the BlogImage's associated with the Blog's the in the paginated list I would imagine you'll need to do a check to make sure you're only displaying the images that are associated with the specific Blog. One way you can do this is by using `@continue():



@foreach($blogImage as $img)

@continue($blogImage->blog_id !== $blog->id)

<img src="{{asset('storage/blog_img/'.$img->blog_img)}}" alt="Image" class="img-responsive">

@endforeach




All of that being said I would recommend using a one-to-many relationship between Blog and BlogImage:



Blog



public function images()
{
return $this->hasMany(BlogImage::class);
}


BlogImage



public function blog()
{
return $this->belongTo(Blog::class);
}


Then in your controller you can Eager load the images and have something like:



$blogs = Blog::with('images')->where('user_id', $user_id)->paginate(10);


And your blade file would have:



@foreach($blog->images as $image)

<img src="{{asset('storage/blog_img/'.$image->blog_img)}}" alt="Image" class="img-responsive">

@endforeach


You could then apply the same one-to-many relationship logic between User and Blog as well.






share|improve this answer























  • sorry for a silly question, do I have to use this @foreach($blog->images as $image) under @foreach($blogs as $blog)?
    – Eyakub
    Nov 21 '18 at 21:13












  • btw, Thanks, I guess I solved it with your help, thanks for your valuable time. btw in Blog::with('images') is that the function that i declared? or just passing the variable?
    – Eyakub
    Nov 21 '18 at 21:34










  • @Eyakub Yes, you would need to put @foreach($blog->images as $image) under @foreach($blogs as $blog). The with() method allows you to eager load your relationships so the with('images') will load the relationship defined in the images() method in your Blog class.
    – Ross Wilson
    Nov 21 '18 at 23:40











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














This is because you're using where instead of whereIn.



If you try and pass an array or a collection to where it will only use the first value.



$blogImage = BlogImage::whereIn('blog_id', $blogs->pluck('id'))->get();


Since this will return all of the BlogImage's associated with the Blog's the in the paginated list I would imagine you'll need to do a check to make sure you're only displaying the images that are associated with the specific Blog. One way you can do this is by using `@continue():



@foreach($blogImage as $img)

@continue($blogImage->blog_id !== $blog->id)

<img src="{{asset('storage/blog_img/'.$img->blog_img)}}" alt="Image" class="img-responsive">

@endforeach




All of that being said I would recommend using a one-to-many relationship between Blog and BlogImage:



Blog



public function images()
{
return $this->hasMany(BlogImage::class);
}


BlogImage



public function blog()
{
return $this->belongTo(Blog::class);
}


Then in your controller you can Eager load the images and have something like:



$blogs = Blog::with('images')->where('user_id', $user_id)->paginate(10);


And your blade file would have:



@foreach($blog->images as $image)

<img src="{{asset('storage/blog_img/'.$image->blog_img)}}" alt="Image" class="img-responsive">

@endforeach


You could then apply the same one-to-many relationship logic between User and Blog as well.






share|improve this answer























  • sorry for a silly question, do I have to use this @foreach($blog->images as $image) under @foreach($blogs as $blog)?
    – Eyakub
    Nov 21 '18 at 21:13












  • btw, Thanks, I guess I solved it with your help, thanks for your valuable time. btw in Blog::with('images') is that the function that i declared? or just passing the variable?
    – Eyakub
    Nov 21 '18 at 21:34










  • @Eyakub Yes, you would need to put @foreach($blog->images as $image) under @foreach($blogs as $blog). The with() method allows you to eager load your relationships so the with('images') will load the relationship defined in the images() method in your Blog class.
    – Ross Wilson
    Nov 21 '18 at 23:40
















1














This is because you're using where instead of whereIn.



If you try and pass an array or a collection to where it will only use the first value.



$blogImage = BlogImage::whereIn('blog_id', $blogs->pluck('id'))->get();


Since this will return all of the BlogImage's associated with the Blog's the in the paginated list I would imagine you'll need to do a check to make sure you're only displaying the images that are associated with the specific Blog. One way you can do this is by using `@continue():



@foreach($blogImage as $img)

@continue($blogImage->blog_id !== $blog->id)

<img src="{{asset('storage/blog_img/'.$img->blog_img)}}" alt="Image" class="img-responsive">

@endforeach




All of that being said I would recommend using a one-to-many relationship between Blog and BlogImage:



Blog



public function images()
{
return $this->hasMany(BlogImage::class);
}


BlogImage



public function blog()
{
return $this->belongTo(Blog::class);
}


Then in your controller you can Eager load the images and have something like:



$blogs = Blog::with('images')->where('user_id', $user_id)->paginate(10);


And your blade file would have:



@foreach($blog->images as $image)

<img src="{{asset('storage/blog_img/'.$image->blog_img)}}" alt="Image" class="img-responsive">

@endforeach


You could then apply the same one-to-many relationship logic between User and Blog as well.






share|improve this answer























  • sorry for a silly question, do I have to use this @foreach($blog->images as $image) under @foreach($blogs as $blog)?
    – Eyakub
    Nov 21 '18 at 21:13












  • btw, Thanks, I guess I solved it with your help, thanks for your valuable time. btw in Blog::with('images') is that the function that i declared? or just passing the variable?
    – Eyakub
    Nov 21 '18 at 21:34










  • @Eyakub Yes, you would need to put @foreach($blog->images as $image) under @foreach($blogs as $blog). The with() method allows you to eager load your relationships so the with('images') will load the relationship defined in the images() method in your Blog class.
    – Ross Wilson
    Nov 21 '18 at 23:40














1












1








1






This is because you're using where instead of whereIn.



If you try and pass an array or a collection to where it will only use the first value.



$blogImage = BlogImage::whereIn('blog_id', $blogs->pluck('id'))->get();


Since this will return all of the BlogImage's associated with the Blog's the in the paginated list I would imagine you'll need to do a check to make sure you're only displaying the images that are associated with the specific Blog. One way you can do this is by using `@continue():



@foreach($blogImage as $img)

@continue($blogImage->blog_id !== $blog->id)

<img src="{{asset('storage/blog_img/'.$img->blog_img)}}" alt="Image" class="img-responsive">

@endforeach




All of that being said I would recommend using a one-to-many relationship between Blog and BlogImage:



Blog



public function images()
{
return $this->hasMany(BlogImage::class);
}


BlogImage



public function blog()
{
return $this->belongTo(Blog::class);
}


Then in your controller you can Eager load the images and have something like:



$blogs = Blog::with('images')->where('user_id', $user_id)->paginate(10);


And your blade file would have:



@foreach($blog->images as $image)

<img src="{{asset('storage/blog_img/'.$image->blog_img)}}" alt="Image" class="img-responsive">

@endforeach


You could then apply the same one-to-many relationship logic between User and Blog as well.






share|improve this answer














This is because you're using where instead of whereIn.



If you try and pass an array or a collection to where it will only use the first value.



$blogImage = BlogImage::whereIn('blog_id', $blogs->pluck('id'))->get();


Since this will return all of the BlogImage's associated with the Blog's the in the paginated list I would imagine you'll need to do a check to make sure you're only displaying the images that are associated with the specific Blog. One way you can do this is by using `@continue():



@foreach($blogImage as $img)

@continue($blogImage->blog_id !== $blog->id)

<img src="{{asset('storage/blog_img/'.$img->blog_img)}}" alt="Image" class="img-responsive">

@endforeach




All of that being said I would recommend using a one-to-many relationship between Blog and BlogImage:



Blog



public function images()
{
return $this->hasMany(BlogImage::class);
}


BlogImage



public function blog()
{
return $this->belongTo(Blog::class);
}


Then in your controller you can Eager load the images and have something like:



$blogs = Blog::with('images')->where('user_id', $user_id)->paginate(10);


And your blade file would have:



@foreach($blog->images as $image)

<img src="{{asset('storage/blog_img/'.$image->blog_img)}}" alt="Image" class="img-responsive">

@endforeach


You could then apply the same one-to-many relationship logic between User and Blog as well.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 21 '18 at 20:38

























answered Nov 21 '18 at 20:32









Ross WilsonRoss Wilson

15.7k22539




15.7k22539












  • sorry for a silly question, do I have to use this @foreach($blog->images as $image) under @foreach($blogs as $blog)?
    – Eyakub
    Nov 21 '18 at 21:13












  • btw, Thanks, I guess I solved it with your help, thanks for your valuable time. btw in Blog::with('images') is that the function that i declared? or just passing the variable?
    – Eyakub
    Nov 21 '18 at 21:34










  • @Eyakub Yes, you would need to put @foreach($blog->images as $image) under @foreach($blogs as $blog). The with() method allows you to eager load your relationships so the with('images') will load the relationship defined in the images() method in your Blog class.
    – Ross Wilson
    Nov 21 '18 at 23:40


















  • sorry for a silly question, do I have to use this @foreach($blog->images as $image) under @foreach($blogs as $blog)?
    – Eyakub
    Nov 21 '18 at 21:13












  • btw, Thanks, I guess I solved it with your help, thanks for your valuable time. btw in Blog::with('images') is that the function that i declared? or just passing the variable?
    – Eyakub
    Nov 21 '18 at 21:34










  • @Eyakub Yes, you would need to put @foreach($blog->images as $image) under @foreach($blogs as $blog). The with() method allows you to eager load your relationships so the with('images') will load the relationship defined in the images() method in your Blog class.
    – Ross Wilson
    Nov 21 '18 at 23:40
















sorry for a silly question, do I have to use this @foreach($blog->images as $image) under @foreach($blogs as $blog)?
– Eyakub
Nov 21 '18 at 21:13






sorry for a silly question, do I have to use this @foreach($blog->images as $image) under @foreach($blogs as $blog)?
– Eyakub
Nov 21 '18 at 21:13














btw, Thanks, I guess I solved it with your help, thanks for your valuable time. btw in Blog::with('images') is that the function that i declared? or just passing the variable?
– Eyakub
Nov 21 '18 at 21:34




btw, Thanks, I guess I solved it with your help, thanks for your valuable time. btw in Blog::with('images') is that the function that i declared? or just passing the variable?
– Eyakub
Nov 21 '18 at 21:34












@Eyakub Yes, you would need to put @foreach($blog->images as $image) under @foreach($blogs as $blog). The with() method allows you to eager load your relationships so the with('images') will load the relationship defined in the images() method in your Blog class.
– Ross Wilson
Nov 21 '18 at 23:40




@Eyakub Yes, you would need to put @foreach($blog->images as $image) under @foreach($blogs as $blog). The with() method allows you to eager load your relationships so the with('images') will load the relationship defined in the images() method in your Blog class.
– Ross Wilson
Nov 21 '18 at 23:40


















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