Unable to store data in a matrix
I am using the following code to check P-values of a linear trend, but it seems that the loop is not working properly as I cannot see a 2-D map of P-value but only a row
library(chron)
library(RColorBrewer)
library(lattice)
library(ncdf4)
#-------------------------------------------------------------------------------------------
options(warn=-1)
ncin <- nc_open("MOD04_10K_Winter.nc", readunlim=FALSE)
#print(ncin)
lon <- ncvar_get(ncin, varid="Longitude", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
lat <- ncvar_get(ncin, varid="Latitude", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
aod <- ncvar_get(ncin, varid="AOD", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
px <- matrix(nrow = 1:length(lon), ncol = 1:length(lat))
is.matrix(px)
for (lo in 1:length(lon)) {
for (la in 1:length(lat)) {
int1a = aod[lo, la,]
# if mean of int is finite then proceed else fill NA to all arrays
mn = mean(int1a, trim = 0, na.rm = FALSE)
if (is.finite(mn))
{
print("---------------- Reading Finite data -------------")
xs = 1:30
fn1a = lm(int1a~xs) # Function_NCP
p_val = summary(fn1a)$coefficients[2, 4] # Saving p-value
if (p_val < 0.05) {print("statisticlly significant")} else {print("statisticlly in-significant")}
print(p_val)
print(lo)
print(la)
px[lo][la] = p_val # variables in only (?)
}
} # latitude dimension
}
If I am using [lo, la] instead of [lo][la] I am having the following error
Error in
[<-(*tmp*, lo, la, value = 0.0543481042240582) :
subscript out of bounds
Sorry if the solution is very trivial, I have just started working in R.
r loops
edited Nov 22 '18 at 16:29
Ekatef
72149
asked Nov 22 '18 at 5:44
piyush bhardwajpiyush bhardwaj
194
add a comment |
I am using the following code to check P-values of a linear trend, but it seems that the loop is not working properly as I cannot see a 2-D map of P-value but only a row
library(chron)
library(RColorBrewer)
library(lattice)
library(ncdf4)
#-------------------------------------------------------------------------------------------
options(warn=-1)
ncin <- nc_open("MOD04_10K_Winter.nc", readunlim=FALSE)
#print(ncin)
lon <- ncvar_get(ncin, varid="Longitude", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
lat <- ncvar_get(ncin, varid="Latitude", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
aod <- ncvar_get(ncin, varid="AOD", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
px <- matrix(nrow = 1:length(lon), ncol = 1:length(lat))
is.matrix(px)
for (lo in 1:length(lon)) {
for (la in 1:length(lat)) {
int1a = aod[lo, la,]
# if mean of int is finite then proceed else fill NA to all arrays
mn = mean(int1a, trim = 0, na.rm = FALSE)
if (is.finite(mn))
{
print("---------------- Reading Finite data -------------")
xs = 1:30
fn1a = lm(int1a~xs) # Function_NCP
p_val = summary(fn1a)$coefficients[2, 4] # Saving p-value
if (p_val < 0.05) {print("statisticlly significant")} else {print("statisticlly in-significant")}
print(p_val)
print(lo)
print(la)
px[lo][la] = p_val # variables in only (?)
}
} # latitude dimension
}
If I am using [lo, la] instead of [lo][la] I am having the following error
Error in
[<-(*tmp*, lo, la, value = 0.0543481042240582) :
subscript out of bounds
Sorry if the solution is very trivial, I have just started working in R.
r loops
edited Nov 22 '18 at 16:29
Ekatef
72149
asked Nov 22 '18 at 5:44
piyush bhardwajpiyush bhardwaj
194
This just means that somewhere, in one of thepxa number is going in that doesn't correspond to anything inpx. Try checking the extreme values on the for loop (ie the first number that gets run through and the last) as they are usually the cause of problems like this. Also if you want more detailed help make your answer reproducible
– RAB
Nov 22 '18 at 7:18
add a comment |
I am using the following code to check P-values of a linear trend, but it seems that the loop is not working properly as I cannot see a 2-D map of P-value but only a row
library(chron)
library(RColorBrewer)
library(lattice)
library(ncdf4)
#-------------------------------------------------------------------------------------------
options(warn=-1)
ncin <- nc_open("MOD04_10K_Winter.nc", readunlim=FALSE)
#print(ncin)
lon <- ncvar_get(ncin, varid="Longitude", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
lat <- ncvar_get(ncin, varid="Latitude", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
aod <- ncvar_get(ncin, varid="AOD", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
px <- matrix(nrow = 1:length(lon), ncol = 1:length(lat))
is.matrix(px)
for (lo in 1:length(lon)) {
for (la in 1:length(lat)) {
int1a = aod[lo, la,]
# if mean of int is finite then proceed else fill NA to all arrays
mn = mean(int1a, trim = 0, na.rm = FALSE)
if (is.finite(mn))
{
print("---------------- Reading Finite data -------------")
xs = 1:30
fn1a = lm(int1a~xs) # Function_NCP
p_val = summary(fn1a)$coefficients[2, 4] # Saving p-value
if (p_val < 0.05) {print("statisticlly significant")} else {print("statisticlly in-significant")}
print(p_val)
print(lo)
print(la)
px[lo][la] = p_val # variables in only (?)
}
} # latitude dimension
}
If I am using [lo, la] instead of [lo][la] I am having the following error
Error in
[<-(*tmp*, lo, la, value = 0.0543481042240582) :
subscript out of bounds
Sorry if the solution is very trivial, I have just started working in R.
r loops
edited Nov 22 '18 at 16:29
Ekatef
72149
asked Nov 22 '18 at 5:44
piyush bhardwajpiyush bhardwaj
194
I am using the following code to check P-values of a linear trend, but it seems that the loop is not working properly as I cannot see a 2-D map of P-value but only a row
library(chron)
library(RColorBrewer)
library(lattice)
library(ncdf4)
#-------------------------------------------------------------------------------------------
options(warn=-1)
ncin <- nc_open("MOD04_10K_Winter.nc", readunlim=FALSE)
#print(ncin)
lon <- ncvar_get(ncin, varid="Longitude", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
lat <- ncvar_get(ncin, varid="Latitude", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
aod <- ncvar_get(ncin, varid="AOD", start=NA, count=NA, verbose=FALSE,
signedbyte=TRUE, collapse_degen=TRUE, raw_datavals=FALSE )
px <- matrix(nrow = 1:length(lon), ncol = 1:length(lat))
is.matrix(px)
for (lo in 1:length(lon)) {
for (la in 1:length(lat)) {
int1a = aod[lo, la,]
# if mean of int is finite then proceed else fill NA to all arrays
mn = mean(int1a, trim = 0, na.rm = FALSE)
if (is.finite(mn))
{
print("---------------- Reading Finite data -------------")
xs = 1:30
fn1a = lm(int1a~xs) # Function_NCP
p_val = summary(fn1a)$coefficients[2, 4] # Saving p-value
if (p_val < 0.05) {print("statisticlly significant")} else {print("statisticlly in-significant")}
print(p_val)
print(lo)
print(la)
px[lo][la] = p_val # variables in only (?)
}
} # latitude dimension
}
If I am using [lo, la] instead of [lo][la] I am having the following error
Error in
[<-(*tmp*, lo, la, value = 0.0543481042240582) :
subscript out of bounds
Sorry if the solution is very trivial, I have just started working in R.
r loops
r loops
edited Nov 22 '18 at 16:29
Ekatef
72149
asked Nov 22 '18 at 5:44
piyush bhardwajpiyush bhardwaj
194
edited Nov 22 '18 at 16:29
Ekatef
72149
asked Nov 22 '18 at 5:44
piyush bhardwajpiyush bhardwaj
194
edited Nov 22 '18 at 16:29
Ekatef
72149
edited Nov 22 '18 at 16:29
Ekatef
72149
edited Nov 22 '18 at 16:29
Ekatef
72149
72149
asked Nov 22 '18 at 5:44
piyush bhardwajpiyush bhardwaj
194
asked Nov 22 '18 at 5:44
piyush bhardwajpiyush bhardwaj
194
asked Nov 22 '18 at 5:44
piyush bhardwajpiyush bhardwaj
194
194
This just means that somewhere, in one of thepxa number is going in that doesn't correspond to anything inpx. Try checking the extreme values on the for loop (ie the first number that gets run through and the last) as they are usually the cause of problems like this. Also if you want more detailed help make your answer reproducible
– RAB
Nov 22 '18 at 7:18
add a comment |
This just means that somewhere, in one of thepxa number is going in that doesn't correspond to anything inpx. Try checking the extreme values on the for loop (ie the first number that gets run through and the last) as they are usually the cause of problems like this. Also if you want more detailed help make your answer reproducible
– RAB
Nov 22 '18 at 7:18
This just means that somewhere, in one of the
px a number is going in that doesn't correspond to anything in px. Try checking the extreme values on the for loop (ie the first number that gets run through and the last) as they are usually the cause of problems like this. Also if you want more detailed help make your answer reproducible– RAB
Nov 22 '18 at 7:18
This just means that somewhere, in one of the
px a number is going in that doesn't correspond to anything in px. Try checking the extreme values on the for loop (ie the first number that gets run through and the last) as they are usually the cause of problems like this. Also if you want more detailed help make your answer reproducible– RAB
Nov 22 '18 at 7:18
add a comment |
1 Answer
1
active
oldest
votes
You have just to make a small fix on the matrix px declaration. Now you set the number of rows and columns as vectors: nrow = 1:length(lon) and nrow = 1:length(lon). R silently takes only the first elements of these vectors and generates a 1 to 1 matrix. (Actually, it would generate a warning, by the warnings are supressed!)
So, the solution is
px <- matrix(nrow = length(lon), ncol = length(lat))
answered Nov 22 '18 at 13:01
EkatefEkatef
72149
add a comment |
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You have just to make a small fix on the matrix px declaration. Now you set the number of rows and columns as vectors: nrow = 1:length(lon) and nrow = 1:length(lon). R silently takes only the first elements of these vectors and generates a 1 to 1 matrix. (Actually, it would generate a warning, by the warnings are supressed!)
So, the solution is
px <- matrix(nrow = length(lon), ncol = length(lat))
answered Nov 22 '18 at 13:01
EkatefEkatef
72149
add a comment |
You have just to make a small fix on the matrix px declaration. Now you set the number of rows and columns as vectors: nrow = 1:length(lon) and nrow = 1:length(lon). R silently takes only the first elements of these vectors and generates a 1 to 1 matrix. (Actually, it would generate a warning, by the warnings are supressed!)
So, the solution is
px <- matrix(nrow = length(lon), ncol = length(lat))
answered Nov 22 '18 at 13:01
EkatefEkatef
72149
add a comment |
You have just to make a small fix on the matrix px declaration. Now you set the number of rows and columns as vectors: nrow = 1:length(lon) and nrow = 1:length(lon). R silently takes only the first elements of these vectors and generates a 1 to 1 matrix. (Actually, it would generate a warning, by the warnings are supressed!)
So, the solution is
px <- matrix(nrow = length(lon), ncol = length(lat))
answered Nov 22 '18 at 13:01
EkatefEkatef
72149
You have just to make a small fix on the matrix px declaration. Now you set the number of rows and columns as vectors: nrow = 1:length(lon) and nrow = 1:length(lon). R silently takes only the first elements of these vectors and generates a 1 to 1 matrix. (Actually, it would generate a warning, by the warnings are supressed!)
So, the solution is
px <- matrix(nrow = length(lon), ncol = length(lat))
answered Nov 22 '18 at 13:01
EkatefEkatef
72149
answered Nov 22 '18 at 13:01
EkatefEkatef
72149
answered Nov 22 '18 at 13:01
EkatefEkatef
72149
answered Nov 22 '18 at 13:01
EkatefEkatef
72149
72149
add a comment |
add a comment |
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This just means that somewhere, in one of the
pxa number is going in that doesn't correspond to anything inpx. Try checking the extreme values on the for loop (ie the first number that gets run through and the last) as they are usually the cause of problems like this. Also if you want more detailed help make your answer reproducible– RAB
Nov 22 '18 at 7:18