Change buttons relief on click using tkinter
I want to create buttons labelled with names from a list. When you click on a button its relief shall change from groove to sunken. There is one condition, only one button is allowed to be sunken. Thus, when you click on a button while another one is already sunken, the sunken one has to go back to groove.
How it looks like
I was able to put my idea into action and coded the whole thing. However, I'm wondering if there might be a better way to implement it. What is your opinion? Here is my code:
import tkinter as tk
from functools import partial
class ButtonSunken:
def __init__(self):
self.tags = ('A','B','C','D','E','F')
self.buttons =
self.win = tk.Tk()
self.create_buttons()
self.win.mainloop()
def create_buttons(self):
for j,i in enumerate(self.tags):
self.buttons.append(tk.Button(self.win, text = i))
self.buttons[-1].grid(column=0, row=j)
ho_general = partial(self.button_pressed, self.buttons[-1])
self.buttons[-1].configure(command = ho_general)
def button_pressed(self, button):
try: # first time active_button does not exist yet
self.active_button.configure(relief = 'groove')
except:
pass
button.configure(relief = 'sunken')
self.active_button = button
t_object = ButtonSunken()
Thank you very much for your help!
python button tkinter
add a comment |
I want to create buttons labelled with names from a list. When you click on a button its relief shall change from groove to sunken. There is one condition, only one button is allowed to be sunken. Thus, when you click on a button while another one is already sunken, the sunken one has to go back to groove.
How it looks like
I was able to put my idea into action and coded the whole thing. However, I'm wondering if there might be a better way to implement it. What is your opinion? Here is my code:
import tkinter as tk
from functools import partial
class ButtonSunken:
def __init__(self):
self.tags = ('A','B','C','D','E','F')
self.buttons =
self.win = tk.Tk()
self.create_buttons()
self.win.mainloop()
def create_buttons(self):
for j,i in enumerate(self.tags):
self.buttons.append(tk.Button(self.win, text = i))
self.buttons[-1].grid(column=0, row=j)
ho_general = partial(self.button_pressed, self.buttons[-1])
self.buttons[-1].configure(command = ho_general)
def button_pressed(self, button):
try: # first time active_button does not exist yet
self.active_button.configure(relief = 'groove')
except:
pass
button.configure(relief = 'sunken')
self.active_button = button
t_object = ButtonSunken()
Thank you very much for your help!
python button tkinter
add a comment |
I want to create buttons labelled with names from a list. When you click on a button its relief shall change from groove to sunken. There is one condition, only one button is allowed to be sunken. Thus, when you click on a button while another one is already sunken, the sunken one has to go back to groove.
How it looks like
I was able to put my idea into action and coded the whole thing. However, I'm wondering if there might be a better way to implement it. What is your opinion? Here is my code:
import tkinter as tk
from functools import partial
class ButtonSunken:
def __init__(self):
self.tags = ('A','B','C','D','E','F')
self.buttons =
self.win = tk.Tk()
self.create_buttons()
self.win.mainloop()
def create_buttons(self):
for j,i in enumerate(self.tags):
self.buttons.append(tk.Button(self.win, text = i))
self.buttons[-1].grid(column=0, row=j)
ho_general = partial(self.button_pressed, self.buttons[-1])
self.buttons[-1].configure(command = ho_general)
def button_pressed(self, button):
try: # first time active_button does not exist yet
self.active_button.configure(relief = 'groove')
except:
pass
button.configure(relief = 'sunken')
self.active_button = button
t_object = ButtonSunken()
Thank you very much for your help!
python button tkinter
I want to create buttons labelled with names from a list. When you click on a button its relief shall change from groove to sunken. There is one condition, only one button is allowed to be sunken. Thus, when you click on a button while another one is already sunken, the sunken one has to go back to groove.
How it looks like
I was able to put my idea into action and coded the whole thing. However, I'm wondering if there might be a better way to implement it. What is your opinion? Here is my code:
import tkinter as tk
from functools import partial
class ButtonSunken:
def __init__(self):
self.tags = ('A','B','C','D','E','F')
self.buttons =
self.win = tk.Tk()
self.create_buttons()
self.win.mainloop()
def create_buttons(self):
for j,i in enumerate(self.tags):
self.buttons.append(tk.Button(self.win, text = i))
self.buttons[-1].grid(column=0, row=j)
ho_general = partial(self.button_pressed, self.buttons[-1])
self.buttons[-1].configure(command = ho_general)
def button_pressed(self, button):
try: # first time active_button does not exist yet
self.active_button.configure(relief = 'groove')
except:
pass
button.configure(relief = 'sunken')
self.active_button = button
t_object = ButtonSunken()
Thank you very much for your help!
python button tkinter
python button tkinter
asked Nov 20 at 21:10
Bahlsen
215
215
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Your method is pretty much good, just that it can be done without using any special functions. In my code, I just store the index of the current active button and set its relief to groove
whenever the next button is pressed whose relief is in turn changed to sunken
. Have a look at the code.
import tkinter as tk
class ButtonSunken:
def __init__(self):
self.tags = ('A','B','C','D','E','F')
self.buttons =
self.active = None
self.win = tk.Tk()
self.create_buttons()
self.win.mainloop()
def create_buttons(self):
for j,i in enumerate(self.tags):
self.buttons.append(tk.Button(self.win, text=i, command=lambda x=j: self.button_pressed(x)))
self.buttons[-1].grid(column=0, row=j)
def button_pressed(self, idx):
if self.active is not None:
self.buttons[self.active].configure(relief='groove')
self.buttons[idx].configure(relief='sunken')
self.active = idx
t_object = ButtonSunken()
Thanks for your reply. I like your solution, it's much better/easier to hand over the index than the whole object. Up to now, I was a bit reluctant towards the Lambda function, however, I realize it's pretty useful.
– Bahlsen
Nov 21 at 9:46
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your method is pretty much good, just that it can be done without using any special functions. In my code, I just store the index of the current active button and set its relief to groove
whenever the next button is pressed whose relief is in turn changed to sunken
. Have a look at the code.
import tkinter as tk
class ButtonSunken:
def __init__(self):
self.tags = ('A','B','C','D','E','F')
self.buttons =
self.active = None
self.win = tk.Tk()
self.create_buttons()
self.win.mainloop()
def create_buttons(self):
for j,i in enumerate(self.tags):
self.buttons.append(tk.Button(self.win, text=i, command=lambda x=j: self.button_pressed(x)))
self.buttons[-1].grid(column=0, row=j)
def button_pressed(self, idx):
if self.active is not None:
self.buttons[self.active].configure(relief='groove')
self.buttons[idx].configure(relief='sunken')
self.active = idx
t_object = ButtonSunken()
Thanks for your reply. I like your solution, it's much better/easier to hand over the index than the whole object. Up to now, I was a bit reluctant towards the Lambda function, however, I realize it's pretty useful.
– Bahlsen
Nov 21 at 9:46
add a comment |
Your method is pretty much good, just that it can be done without using any special functions. In my code, I just store the index of the current active button and set its relief to groove
whenever the next button is pressed whose relief is in turn changed to sunken
. Have a look at the code.
import tkinter as tk
class ButtonSunken:
def __init__(self):
self.tags = ('A','B','C','D','E','F')
self.buttons =
self.active = None
self.win = tk.Tk()
self.create_buttons()
self.win.mainloop()
def create_buttons(self):
for j,i in enumerate(self.tags):
self.buttons.append(tk.Button(self.win, text=i, command=lambda x=j: self.button_pressed(x)))
self.buttons[-1].grid(column=0, row=j)
def button_pressed(self, idx):
if self.active is not None:
self.buttons[self.active].configure(relief='groove')
self.buttons[idx].configure(relief='sunken')
self.active = idx
t_object = ButtonSunken()
Thanks for your reply. I like your solution, it's much better/easier to hand over the index than the whole object. Up to now, I was a bit reluctant towards the Lambda function, however, I realize it's pretty useful.
– Bahlsen
Nov 21 at 9:46
add a comment |
Your method is pretty much good, just that it can be done without using any special functions. In my code, I just store the index of the current active button and set its relief to groove
whenever the next button is pressed whose relief is in turn changed to sunken
. Have a look at the code.
import tkinter as tk
class ButtonSunken:
def __init__(self):
self.tags = ('A','B','C','D','E','F')
self.buttons =
self.active = None
self.win = tk.Tk()
self.create_buttons()
self.win.mainloop()
def create_buttons(self):
for j,i in enumerate(self.tags):
self.buttons.append(tk.Button(self.win, text=i, command=lambda x=j: self.button_pressed(x)))
self.buttons[-1].grid(column=0, row=j)
def button_pressed(self, idx):
if self.active is not None:
self.buttons[self.active].configure(relief='groove')
self.buttons[idx].configure(relief='sunken')
self.active = idx
t_object = ButtonSunken()
Your method is pretty much good, just that it can be done without using any special functions. In my code, I just store the index of the current active button and set its relief to groove
whenever the next button is pressed whose relief is in turn changed to sunken
. Have a look at the code.
import tkinter as tk
class ButtonSunken:
def __init__(self):
self.tags = ('A','B','C','D','E','F')
self.buttons =
self.active = None
self.win = tk.Tk()
self.create_buttons()
self.win.mainloop()
def create_buttons(self):
for j,i in enumerate(self.tags):
self.buttons.append(tk.Button(self.win, text=i, command=lambda x=j: self.button_pressed(x)))
self.buttons[-1].grid(column=0, row=j)
def button_pressed(self, idx):
if self.active is not None:
self.buttons[self.active].configure(relief='groove')
self.buttons[idx].configure(relief='sunken')
self.active = idx
t_object = ButtonSunken()
answered Nov 20 at 21:44
Miraj50
2,2101623
2,2101623
Thanks for your reply. I like your solution, it's much better/easier to hand over the index than the whole object. Up to now, I was a bit reluctant towards the Lambda function, however, I realize it's pretty useful.
– Bahlsen
Nov 21 at 9:46
add a comment |
Thanks for your reply. I like your solution, it's much better/easier to hand over the index than the whole object. Up to now, I was a bit reluctant towards the Lambda function, however, I realize it's pretty useful.
– Bahlsen
Nov 21 at 9:46
Thanks for your reply. I like your solution, it's much better/easier to hand over the index than the whole object. Up to now, I was a bit reluctant towards the Lambda function, however, I realize it's pretty useful.
– Bahlsen
Nov 21 at 9:46
Thanks for your reply. I like your solution, it's much better/easier to hand over the index than the whole object. Up to now, I was a bit reluctant towards the Lambda function, however, I realize it's pretty useful.
– Bahlsen
Nov 21 at 9:46
add a comment |
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