TEI-XML dictionary to simple HTML table using XSL
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Need to put "entryFree" words in a first column (leaving <form>
content for second), and "sense" and other as a second, every pair in the same row, with borders. Sample XSL stylesheet contains formatting only.
sample XML: https://drive.google.com/file/d/1sNAbWw5xo1pgwK2QfQwPrbZtZt8uV48T/view?usp=sharing
fancy XSL (licence permits modification): https://github.com/michmech/tei-dictionary.xsl
xml xslt tei
add a comment |
up vote
0
down vote
favorite
Need to put "entryFree" words in a first column (leaving <form>
content for second), and "sense" and other as a second, every pair in the same row, with borders. Sample XSL stylesheet contains formatting only.
sample XML: https://drive.google.com/file/d/1sNAbWw5xo1pgwK2QfQwPrbZtZt8uV48T/view?usp=sharing
fancy XSL (licence permits modification): https://github.com/michmech/tei-dictionary.xsl
xml xslt tei
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Need to put "entryFree" words in a first column (leaving <form>
content for second), and "sense" and other as a second, every pair in the same row, with borders. Sample XSL stylesheet contains formatting only.
sample XML: https://drive.google.com/file/d/1sNAbWw5xo1pgwK2QfQwPrbZtZt8uV48T/view?usp=sharing
fancy XSL (licence permits modification): https://github.com/michmech/tei-dictionary.xsl
xml xslt tei
Need to put "entryFree" words in a first column (leaving <form>
content for second), and "sense" and other as a second, every pair in the same row, with borders. Sample XSL stylesheet contains formatting only.
sample XML: https://drive.google.com/file/d/1sNAbWw5xo1pgwK2QfQwPrbZtZt8uV48T/view?usp=sharing
fancy XSL (licence permits modification): https://github.com/michmech/tei-dictionary.xsl
xml xslt tei
xml xslt tei
edited Nov 17 at 15:17
asked Nov 17 at 13:51
Rimdar
32
32
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add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
If you want to map all entryFree
elements to HTML table rows (i.e. HTML tr
elements in an HTML table
) then set up the table
as needed and in a tbody
process all entryFree
elements, mapping them with a template to a tr
:
<xsl:output method="html" doctype-system="about:legacy-doctype"/>
<xsl:template match="/">
<html>
<head>
<title>Test</title>
</head>
<body>
<h1>Table</h1>
<table>
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
</body>
</html>
</xsl:template>
<xsl:template match="tei:entryFree">
<tr>
<td>
<xsl:value-of select="@sortKey"/>
</td>
<td>
<xsl:apply-templates/>
</td>
</tr>
</xsl:template>
You will need to remove the template matching tei:entryFree
obviously.
As for formatting the table, that is a HTML/CSS problem, HTML 4 https://www.w3.org/TR/html401/struct/tables.html#h-11.3.1 allows e.g.
<table rules="all" frame="border">
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
in HTML5 I think using CSS is preferred:
<xsl:template match="/">
<html>
<head>
<title>Test</title>
<style>
table.dict {
border: 1px solid black;
border-collapse: collapse;
}
table.dict th, table.dict td {
border: 1px solid black;
}
</style>
</head>
<body>
<h1>Table</h1>
<table class="dict">
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
</body>
</html>
</xsl:template>
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
If you want to map all entryFree
elements to HTML table rows (i.e. HTML tr
elements in an HTML table
) then set up the table
as needed and in a tbody
process all entryFree
elements, mapping them with a template to a tr
:
<xsl:output method="html" doctype-system="about:legacy-doctype"/>
<xsl:template match="/">
<html>
<head>
<title>Test</title>
</head>
<body>
<h1>Table</h1>
<table>
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
</body>
</html>
</xsl:template>
<xsl:template match="tei:entryFree">
<tr>
<td>
<xsl:value-of select="@sortKey"/>
</td>
<td>
<xsl:apply-templates/>
</td>
</tr>
</xsl:template>
You will need to remove the template matching tei:entryFree
obviously.
As for formatting the table, that is a HTML/CSS problem, HTML 4 https://www.w3.org/TR/html401/struct/tables.html#h-11.3.1 allows e.g.
<table rules="all" frame="border">
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
in HTML5 I think using CSS is preferred:
<xsl:template match="/">
<html>
<head>
<title>Test</title>
<style>
table.dict {
border: 1px solid black;
border-collapse: collapse;
}
table.dict th, table.dict td {
border: 1px solid black;
}
</style>
</head>
<body>
<h1>Table</h1>
<table class="dict">
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
</body>
</html>
</xsl:template>
add a comment |
up vote
0
down vote
accepted
If you want to map all entryFree
elements to HTML table rows (i.e. HTML tr
elements in an HTML table
) then set up the table
as needed and in a tbody
process all entryFree
elements, mapping them with a template to a tr
:
<xsl:output method="html" doctype-system="about:legacy-doctype"/>
<xsl:template match="/">
<html>
<head>
<title>Test</title>
</head>
<body>
<h1>Table</h1>
<table>
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
</body>
</html>
</xsl:template>
<xsl:template match="tei:entryFree">
<tr>
<td>
<xsl:value-of select="@sortKey"/>
</td>
<td>
<xsl:apply-templates/>
</td>
</tr>
</xsl:template>
You will need to remove the template matching tei:entryFree
obviously.
As for formatting the table, that is a HTML/CSS problem, HTML 4 https://www.w3.org/TR/html401/struct/tables.html#h-11.3.1 allows e.g.
<table rules="all" frame="border">
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
in HTML5 I think using CSS is preferred:
<xsl:template match="/">
<html>
<head>
<title>Test</title>
<style>
table.dict {
border: 1px solid black;
border-collapse: collapse;
}
table.dict th, table.dict td {
border: 1px solid black;
}
</style>
</head>
<body>
<h1>Table</h1>
<table class="dict">
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
</body>
</html>
</xsl:template>
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
If you want to map all entryFree
elements to HTML table rows (i.e. HTML tr
elements in an HTML table
) then set up the table
as needed and in a tbody
process all entryFree
elements, mapping them with a template to a tr
:
<xsl:output method="html" doctype-system="about:legacy-doctype"/>
<xsl:template match="/">
<html>
<head>
<title>Test</title>
</head>
<body>
<h1>Table</h1>
<table>
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
</body>
</html>
</xsl:template>
<xsl:template match="tei:entryFree">
<tr>
<td>
<xsl:value-of select="@sortKey"/>
</td>
<td>
<xsl:apply-templates/>
</td>
</tr>
</xsl:template>
You will need to remove the template matching tei:entryFree
obviously.
As for formatting the table, that is a HTML/CSS problem, HTML 4 https://www.w3.org/TR/html401/struct/tables.html#h-11.3.1 allows e.g.
<table rules="all" frame="border">
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
in HTML5 I think using CSS is preferred:
<xsl:template match="/">
<html>
<head>
<title>Test</title>
<style>
table.dict {
border: 1px solid black;
border-collapse: collapse;
}
table.dict th, table.dict td {
border: 1px solid black;
}
</style>
</head>
<body>
<h1>Table</h1>
<table class="dict">
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
</body>
</html>
</xsl:template>
If you want to map all entryFree
elements to HTML table rows (i.e. HTML tr
elements in an HTML table
) then set up the table
as needed and in a tbody
process all entryFree
elements, mapping them with a template to a tr
:
<xsl:output method="html" doctype-system="about:legacy-doctype"/>
<xsl:template match="/">
<html>
<head>
<title>Test</title>
</head>
<body>
<h1>Table</h1>
<table>
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
</body>
</html>
</xsl:template>
<xsl:template match="tei:entryFree">
<tr>
<td>
<xsl:value-of select="@sortKey"/>
</td>
<td>
<xsl:apply-templates/>
</td>
</tr>
</xsl:template>
You will need to remove the template matching tei:entryFree
obviously.
As for formatting the table, that is a HTML/CSS problem, HTML 4 https://www.w3.org/TR/html401/struct/tables.html#h-11.3.1 allows e.g.
<table rules="all" frame="border">
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
in HTML5 I think using CSS is preferred:
<xsl:template match="/">
<html>
<head>
<title>Test</title>
<style>
table.dict {
border: 1px solid black;
border-collapse: collapse;
}
table.dict th, table.dict td {
border: 1px solid black;
}
</style>
</head>
<body>
<h1>Table</h1>
<table class="dict">
<thead>
<tr>
<th>free entry</th>
<th>forms/senses</th>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="//tei:entryFree"/>
</tbody>
</table>
</body>
</html>
</xsl:template>
answered Nov 20 at 9:12
Martin Honnen
110k65876
110k65876
add a comment |
add a comment |
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