N Queens in Python using backtracking












0














I write this solution to the popular N Queens problem using backtracking algorithm. I am relatively new to Python. I would like to know what are the ways to refactor this code and also code style of Python in general.



def isSafe (board, row, col):
# check left row
for y in range(col):
if board[row][y] == 1:
return False
# check diagonal left top
for x, y in zip(range(row, -1, -1), range(col, -1, -1)):
if board[x][y] == 1:
return False
# check diagonal left bottom
for x, y in zip(range(row, N, 1), range(col, -1, -1)):
if board[x][y] == 1:
return False

return True

def generateSolution(board, col):
# terminating condition
# all columns covered
global N
if col >= N:
return True
# loop over all the rows
for i in range(N):
if isSafe(board, i, col) == True:
board[i][col] = 1
# recursively place other queens
if generateSolution(board, col + 1) == True:
return True
# unmark queen spot
board[i][col] = 0
# backtrack
return False


N = int(input())
startCol = 0
board = [[0 for i in range(N)] for j in range(N)]
# print(board)

if generateSolution(board, startCol) == False:
print("No Solution Exists")
else:
print("Solution exists")
print(board)









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    I write this solution to the popular N Queens problem using backtracking algorithm. I am relatively new to Python. I would like to know what are the ways to refactor this code and also code style of Python in general.



    def isSafe (board, row, col):
    # check left row
    for y in range(col):
    if board[row][y] == 1:
    return False
    # check diagonal left top
    for x, y in zip(range(row, -1, -1), range(col, -1, -1)):
    if board[x][y] == 1:
    return False
    # check diagonal left bottom
    for x, y in zip(range(row, N, 1), range(col, -1, -1)):
    if board[x][y] == 1:
    return False

    return True

    def generateSolution(board, col):
    # terminating condition
    # all columns covered
    global N
    if col >= N:
    return True
    # loop over all the rows
    for i in range(N):
    if isSafe(board, i, col) == True:
    board[i][col] = 1
    # recursively place other queens
    if generateSolution(board, col + 1) == True:
    return True
    # unmark queen spot
    board[i][col] = 0
    # backtrack
    return False


    N = int(input())
    startCol = 0
    board = [[0 for i in range(N)] for j in range(N)]
    # print(board)

    if generateSolution(board, startCol) == False:
    print("No Solution Exists")
    else:
    print("Solution exists")
    print(board)









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      0












      0








      0







      I write this solution to the popular N Queens problem using backtracking algorithm. I am relatively new to Python. I would like to know what are the ways to refactor this code and also code style of Python in general.



      def isSafe (board, row, col):
      # check left row
      for y in range(col):
      if board[row][y] == 1:
      return False
      # check diagonal left top
      for x, y in zip(range(row, -1, -1), range(col, -1, -1)):
      if board[x][y] == 1:
      return False
      # check diagonal left bottom
      for x, y in zip(range(row, N, 1), range(col, -1, -1)):
      if board[x][y] == 1:
      return False

      return True

      def generateSolution(board, col):
      # terminating condition
      # all columns covered
      global N
      if col >= N:
      return True
      # loop over all the rows
      for i in range(N):
      if isSafe(board, i, col) == True:
      board[i][col] = 1
      # recursively place other queens
      if generateSolution(board, col + 1) == True:
      return True
      # unmark queen spot
      board[i][col] = 0
      # backtrack
      return False


      N = int(input())
      startCol = 0
      board = [[0 for i in range(N)] for j in range(N)]
      # print(board)

      if generateSolution(board, startCol) == False:
      print("No Solution Exists")
      else:
      print("Solution exists")
      print(board)









      share|improve this question









      New contributor




      Abrar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I write this solution to the popular N Queens problem using backtracking algorithm. I am relatively new to Python. I would like to know what are the ways to refactor this code and also code style of Python in general.



      def isSafe (board, row, col):
      # check left row
      for y in range(col):
      if board[row][y] == 1:
      return False
      # check diagonal left top
      for x, y in zip(range(row, -1, -1), range(col, -1, -1)):
      if board[x][y] == 1:
      return False
      # check diagonal left bottom
      for x, y in zip(range(row, N, 1), range(col, -1, -1)):
      if board[x][y] == 1:
      return False

      return True

      def generateSolution(board, col):
      # terminating condition
      # all columns covered
      global N
      if col >= N:
      return True
      # loop over all the rows
      for i in range(N):
      if isSafe(board, i, col) == True:
      board[i][col] = 1
      # recursively place other queens
      if generateSolution(board, col + 1) == True:
      return True
      # unmark queen spot
      board[i][col] = 0
      # backtrack
      return False


      N = int(input())
      startCol = 0
      board = [[0 for i in range(N)] for j in range(N)]
      # print(board)

      if generateSolution(board, startCol) == False:
      print("No Solution Exists")
      else:
      print("Solution exists")
      print(board)






      python algorithm python-3.x backtracking n-queens






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      edited 8 mins ago









      Jamal

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      asked 14 mins ago









      Abrar

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