laravel cannot display jsondata











up vote
0
down vote

favorite












I'm try to use jsondata to display the results.

This is my output.
Now i just try to display the result



enter image description here



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$json = json_decode($justResults, true);


$aQuestions = array();
$aAnswers = array();
foreach($json as $sKey => $oItem) {
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


in pure php i just use a but in the laravel it's not work.



<div class="container"> 
<table class="table table-striped">
<thead>
<tr>
<?php foreach($aQuestions as $aQuestionsn){?>
<th scope="col"><?php echo $aQuestionsn; ?></th>
<?php }?>
</tr>
</thead>
<tbody>
<tr>
<?php foreach($aAnswers as $aAnswersn) {?>
<td><?php echo $aAnswersn;?></td>
<?php }?>
</tr>
</tbody>
</table>
</div>


How i can display the jsonstring ?



All i need look like this



enter image description here










share|improve this question
























  • use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.
    – Istiaque Ahmed
    2 days ago












  • look at my edit It's will answer your questions
    – Bunyarit Toshuko
    2 days ago










  • How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.
    – Yoram de Langen
    2 days ago










  • I just saved the string.
    – Bunyarit Toshuko
    2 days ago















up vote
0
down vote

favorite












I'm try to use jsondata to display the results.

This is my output.
Now i just try to display the result



enter image description here



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$json = json_decode($justResults, true);


$aQuestions = array();
$aAnswers = array();
foreach($json as $sKey => $oItem) {
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


in pure php i just use a but in the laravel it's not work.



<div class="container"> 
<table class="table table-striped">
<thead>
<tr>
<?php foreach($aQuestions as $aQuestionsn){?>
<th scope="col"><?php echo $aQuestionsn; ?></th>
<?php }?>
</tr>
</thead>
<tbody>
<tr>
<?php foreach($aAnswers as $aAnswersn) {?>
<td><?php echo $aAnswersn;?></td>
<?php }?>
</tr>
</tbody>
</table>
</div>


How i can display the jsonstring ?



All i need look like this



enter image description here










share|improve this question
























  • use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.
    – Istiaque Ahmed
    2 days ago












  • look at my edit It's will answer your questions
    – Bunyarit Toshuko
    2 days ago










  • How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.
    – Yoram de Langen
    2 days ago










  • I just saved the string.
    – Bunyarit Toshuko
    2 days ago













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I'm try to use jsondata to display the results.

This is my output.
Now i just try to display the result



enter image description here



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$json = json_decode($justResults, true);


$aQuestions = array();
$aAnswers = array();
foreach($json as $sKey => $oItem) {
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


in pure php i just use a but in the laravel it's not work.



<div class="container"> 
<table class="table table-striped">
<thead>
<tr>
<?php foreach($aQuestions as $aQuestionsn){?>
<th scope="col"><?php echo $aQuestionsn; ?></th>
<?php }?>
</tr>
</thead>
<tbody>
<tr>
<?php foreach($aAnswers as $aAnswersn) {?>
<td><?php echo $aAnswersn;?></td>
<?php }?>
</tr>
</tbody>
</table>
</div>


How i can display the jsonstring ?



All i need look like this



enter image description here










share|improve this question















I'm try to use jsondata to display the results.

This is my output.
Now i just try to display the result



enter image description here



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$json = json_decode($justResults, true);


$aQuestions = array();
$aAnswers = array();
foreach($json as $sKey => $oItem) {
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


in pure php i just use a but in the laravel it's not work.



<div class="container"> 
<table class="table table-striped">
<thead>
<tr>
<?php foreach($aQuestions as $aQuestionsn){?>
<th scope="col"><?php echo $aQuestionsn; ?></th>
<?php }?>
</tr>
</thead>
<tbody>
<tr>
<?php foreach($aAnswers as $aAnswersn) {?>
<td><?php echo $aAnswersn;?></td>
<?php }?>
</tr>
</tbody>
</table>
</div>


How i can display the jsonstring ?



All i need look like this



enter image description here







php json laravel






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago

























asked 2 days ago









Bunyarit Toshuko

188




188












  • use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.
    – Istiaque Ahmed
    2 days ago












  • look at my edit It's will answer your questions
    – Bunyarit Toshuko
    2 days ago










  • How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.
    – Yoram de Langen
    2 days ago










  • I just saved the string.
    – Bunyarit Toshuko
    2 days ago


















  • use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.
    – Istiaque Ahmed
    2 days ago












  • look at my edit It's will answer your questions
    – Bunyarit Toshuko
    2 days ago










  • How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.
    – Yoram de Langen
    2 days ago










  • I just saved the string.
    – Bunyarit Toshuko
    2 days ago
















use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.
– Istiaque Ahmed
2 days ago






use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.
– Istiaque Ahmed
2 days ago














look at my edit It's will answer your questions
– Bunyarit Toshuko
2 days ago




look at my edit It's will answer your questions
– Bunyarit Toshuko
2 days ago












How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.
– Yoram de Langen
2 days ago




How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.
– Yoram de Langen
2 days ago












I just saved the string.
– Bunyarit Toshuko
2 days ago




I just saved the string.
– Bunyarit Toshuko
2 days ago












2 Answers
2






active

oldest

votes

















up vote
1
down vote



accepted










well i think in your case there is another array inside your array you need to go inside that array



foreach($aAnswers as $aAnswersn)
{
foreach ($aAnswersn as $value)
{
echo $value;
}
}





share|improve this answer





















  • it's work thank you
    – Bunyarit Toshuko
    2 days ago


















up vote
0
down vote













At least your json_encode is possibly in the wrong location, try this:



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$aQuestions = array();
$aAnswers = array();
// $justResults is a collection so loop through it
foreach($justResults as $sKey => $oItem) {
// $oItem is possibly JSON encoded at this stage
$oItem = json_decode($oItem, true);
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


Please note all changes






share|improve this answer





















  • I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>
    – Bunyarit Toshuko
    2 days ago













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










well i think in your case there is another array inside your array you need to go inside that array



foreach($aAnswers as $aAnswersn)
{
foreach ($aAnswersn as $value)
{
echo $value;
}
}





share|improve this answer





















  • it's work thank you
    – Bunyarit Toshuko
    2 days ago















up vote
1
down vote



accepted










well i think in your case there is another array inside your array you need to go inside that array



foreach($aAnswers as $aAnswersn)
{
foreach ($aAnswersn as $value)
{
echo $value;
}
}





share|improve this answer





















  • it's work thank you
    – Bunyarit Toshuko
    2 days ago













up vote
1
down vote



accepted







up vote
1
down vote



accepted






well i think in your case there is another array inside your array you need to go inside that array



foreach($aAnswers as $aAnswersn)
{
foreach ($aAnswersn as $value)
{
echo $value;
}
}





share|improve this answer












well i think in your case there is another array inside your array you need to go inside that array



foreach($aAnswers as $aAnswersn)
{
foreach ($aAnswersn as $value)
{
echo $value;
}
}






share|improve this answer












share|improve this answer



share|improve this answer










answered 2 days ago









Adnan Rasheed

13913




13913












  • it's work thank you
    – Bunyarit Toshuko
    2 days ago


















  • it's work thank you
    – Bunyarit Toshuko
    2 days ago
















it's work thank you
– Bunyarit Toshuko
2 days ago




it's work thank you
– Bunyarit Toshuko
2 days ago












up vote
0
down vote













At least your json_encode is possibly in the wrong location, try this:



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$aQuestions = array();
$aAnswers = array();
// $justResults is a collection so loop through it
foreach($justResults as $sKey => $oItem) {
// $oItem is possibly JSON encoded at this stage
$oItem = json_decode($oItem, true);
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


Please note all changes






share|improve this answer





















  • I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>
    – Bunyarit Toshuko
    2 days ago

















up vote
0
down vote













At least your json_encode is possibly in the wrong location, try this:



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$aQuestions = array();
$aAnswers = array();
// $justResults is a collection so loop through it
foreach($justResults as $sKey => $oItem) {
// $oItem is possibly JSON encoded at this stage
$oItem = json_decode($oItem, true);
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


Please note all changes






share|improve this answer





















  • I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>
    – Bunyarit Toshuko
    2 days ago















up vote
0
down vote










up vote
0
down vote









At least your json_encode is possibly in the wrong location, try this:



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$aQuestions = array();
$aAnswers = array();
// $justResults is a collection so loop through it
foreach($justResults as $sKey => $oItem) {
// $oItem is possibly JSON encoded at this stage
$oItem = json_decode($oItem, true);
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


Please note all changes






share|improve this answer












At least your json_encode is possibly in the wrong location, try this:



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$aQuestions = array();
$aAnswers = array();
// $justResults is a collection so loop through it
foreach($justResults as $sKey => $oItem) {
// $oItem is possibly JSON encoded at this stage
$oItem = json_decode($oItem, true);
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


Please note all changes







share|improve this answer












share|improve this answer



share|improve this answer










answered 2 days ago









Yoram de Langen

3,82611524




3,82611524












  • I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>
    – Bunyarit Toshuko
    2 days ago




















  • I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>
    – Bunyarit Toshuko
    2 days ago


















I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>
– Bunyarit Toshuko
2 days ago






I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>
– Bunyarit Toshuko
2 days ago




















 

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